union-type | small JavaScript library for defining and using union types | Validation library
kandi X-RAY | union-type Summary
kandi X-RAY | union-type Summary
union-type exports a single function Type. Union types are created by passing the Type function a definition object. The easiest way to define a Type is as follows:. The keys of the object are the names of the values that the type can have. The values of the object are arrays describing the fields of the value. The fields can be described by a validator function. When a value of the type is constructed the values passed to the constructor will have to pass the validator predicate.
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Top functions reviewed by kandi - BETA
- Creates a new class
- Apply a raw method to a case
- Create a Type instance .
- Create a new validator object .
- Creates iterator
- Converts value to an array .
- Extracts values from an object .
- Find a module .
union-type Key Features
union-type Examples and Code Snippets
Community Discussions
Trending Discussions on union-type
QUESTION
I would like to define a TypeScript type, which would suggest (preferred) object keys in editor, but I do not want to restrict user to define arbitrary keys.
So I have defined following type:
...ANSWER
Answered 2022-Apr-01 at 13:12I dont know if exists any better solution but this way works:
QUESTION
I've stumbled upon a weird behavior when using union types in TypeScript. When passing a reference of a function, without invoking it, there is no type error:
...ANSWER
Answered 2022-Apr-01 at 15:22one solution for this would be to use strict unions:
QUESTION
This is a follow-up question to this question.
The following code is on Compiler Explorer.
...ANSWER
Answered 2022-Mar-15 at 22:13The question is, are the arguments passed to my_copy an issue? If this was just to copy a single union my_type, I believe that it would be ok. I don't know if that is valid to copy an array, though.
I'm not sure whether to blame it on the arguments, exactly, but you pass pointers derived from two arrays, and then use them to overrun the bounds of those arrays. Undefined behavior results. That the storage thereby accessed can be considered to stay within the bounds main()
's src
and dst
arrays does not formally matter.
In practice, the program probably behaves as you expect, though I find the particular calling idiom extremely obscure. Why is sizeof(union mytype)
involved? Why is the corresponding parameter named count
, when it is actually eight times the number of loop iterations? I think I have figured it out, but I shouldn't have to be uncertain about that.
If you want to copy between two disjoint arrays of union my_type
, using the 2x32-bit access pattern of the example, then I would write it like this:
QUESTION
What is the correct way to access attributes of a union type that is not present on all of the types? I seem to always get a typescript "property ... does not exist on type..." error, even if I do a check to make sure the attribute exists (see example below)
...ANSWER
Answered 2022-Feb-14 at 07:47You can use in
operator like this:
QUESTION
I am a bit confused about the name Intersection Types in Typescript.
In set theory, intersection would imply that only properties that are common to both types would be available in the intersection of the two.
In fact, that is how Typescript behaves if I create an intersection between primitives.
...ANSWER
Answered 2022-Jan-23 at 07:34An intersection between two sets would yield elements that are in both sets.
Types are just descriptions of sets of values.
So for the intersection of primitives string & number
, what value is in both the string
set and the number
set, ie. can be both a string
and number
at the same time. The answer is there is no such value. So we get never
(the empty set)
For object types the result is a bit different. Object types describe sets where the value must have at least the properties described by the type. So values in the set { name: string, onlyA: string[] }
could have a property onlyB
, but they are not required to have it (ex).
Going back to the intersection ObA & ObB
, values in this intersection must satisfy both the description of ObA
and ObB
. So the values in this set will be the values from ObA
that also have an onlyB
property, and the values from ObB
that also have an onlyA
property. Basically values that satisfy both set descriptions, which for object types unlike for primitives we can construct by creating objects with properties from both types.
My tsconf workshop starts with a "Types as sets" section you might find interesting.
QUESTION
A bit of a followup to this question on NoUnion types -- Is there a way to prevent union types in TypeScript?
Is it possible to construct a Record type such that the value of each property can be a primitive type but not a union of primitive types?
I.e., that these object would be valid:
...ANSWER
Answered 2022-Jan-12 at 00:18I would say that specific ask is impossible, because boolean
itself I believe is not a primitive, but a union itself of type true | false
.
QUESTION
I'm designing a lib API which involves some finite state-machines, so let's say that the lib exports the following interface:
...ANSWER
Answered 2021-Aug-30 at 20:27UPD: by the way, if you can do it, it doesn't mean you should. Maybe the suggestion in comments to reframe the problem and use BaseState & TStates
for state
is a better one. Although you cannot define your own enum with these properties in such case.
Anyway
First with unions. As you've already understood, you cannot constrain the TStates
type argument to extend 'started' | 'finished'
, because then you won't be able to add extra fields. You can however require that 'started' | 'finished'
extend TStates
. One way is as such:
QUESTION
I believe this may be along the same lines of Typescript - union types, Issue with TypeScript typing, and Typescript property does not exist on union type but none of them are the exact same. When a union type is created from Object.entries...map
it seems to remove keys that aren't shared. Here's some example code:
ANSWER
Answered 2021-Aug-23 at 02:26It's not a bug, although it has effects you don't like in this situation. When the compiler has to infer a single type from several other types, it will try to synthesize what is called "the best common type". Often this will be a direct union of all the types involved:
QUESTION
I'm having issues with a mapped type converting to a union-type array rather than a tuple type.
I'm seeing an error that indicates that fn
expects a signature of
'(...values: (string | boolean)[]) => void'
vs my preferred
'(a: string, b: boolean) => void'
It's likely my misunderstanding of this change, but is there something missing that would type RawValues
to a tuple rather than a union-type array to allow me to strongly type the arguments of the fn
I pass in?
Thanks!
...ANSWER
Answered 2021-Jul-14 at 21:05The problem is that Typescript weakens the type of your tuple to an array of unions, before it is used to infer T
. There are two solutions: either ensure that the type is not weakened by using as const
, or have a generic type which is inferred from the callback function's parameters instead of the array.
Solution 1: the upper bound of T
is readonly
to accommodate the as const
assertion, and RawValues
removes this modifier. Note that the result is inferred with literal types as ['string', true]
instead of [string, boolean]
.
QUESTION
I have an array that contains objects of different types. I learned from the documentation that TypeScript can deduce union types such as string | number
and number | number[]
based on the code structure, but it can't seem to deal with more complex interfaces.
ANSWER
Answered 2021-Jul-11 at 23:29Is it possible you just need to adjust your types a bit:
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