maren | A simple , fast , customizable , theme-based static site | Static Site Generator library
kandi X-RAY | maren Summary
kandi X-RAY | maren Summary
A simple, fast, customizable, theme-based static site generator written in Nodejs.
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QUESTION
Task explained shortly: Making a datingsite, that need 4 outcomes. Woman 25 and above, Woman 24 and below. Man 25 and above, Woman 24 and below. Now I want to have 4 more outcomes; all womans, all men, all 25 and above, all 24 and below.
I just started on my bachelor degree in August and have not coded anything before. I am now working on a few tasks that we got, this is a task that we had to deliver that was work requierment. I delivered it with arrays and got the job done with it, and with one else if statement more. Everything good so far. But now later on, we just learned about object literals, and I wanted to check if I could do the code somehow shorter. I actually did with only 1x if statement below.
I am struggling with OR || and && combinations. I've seen some threads on it, saying that parantheses should be placed before and after &&, but I can't seem to get it. The below code does work with the 4 possible combinations, I wanted to check if someone can see how I can add || && combinations more smarter to get the 4 more combinations that I want, in the same if-statement? Or do I have to make a new else if statement? Also, how would you solve this, what type of storing variables would you go for? I have thougth about using some parameters in the function, to shorten something, but I could not come up with something, yet.
...ANSWER
Answered 2020-Oct-18 at 13:04You have one common part with gender and another with age which is either smaller than 25 or equal or greater than 25.
You need no parenthese around comparisons.
QUESTION
This code is supposed to return the first names form the data and the return the first name and how many #times a particular name exists.
It works fine but David, the first name, comes out as David 1 David 1 , when it obviously should be # #David 2!!!!
...ANSWER
Answered 2020-Jun-04 at 11:56Split each element of the input list separately. Also, use collections.Counter to count the names.
QUESTION
I have a list:
...ANSWER
Answered 2018-Dec-21 at 17:08As Patrick Artner suggested in the comments, use defaultdict. How about this:
QUESTION
So, the goal of this project was to scrape the results of the top 100 list, query a database to see if those titles were within it, and return back information of all top 100 songs not contained within said database. The datasets are as follows:
...ANSWER
Answered 2019-Jul-01 at 02:14A str.lower for both columns would work:
QUESTION
I've been trying to parse a dictionary, which is returned by a database I'm working on, but I'm not sure about the best approach to take. I think the difficulty is being caused by the fact that the list sizes within the dictionary are not symmetrical, so my approach doesn't seem to be able to pull out what I'm looking for.
The data structure looks like this:
...ANSWER
Answered 2019-Jun-29 at 15:04looks like a JSON structure is being returned. I would say you should use a python JSON parser liek this
QUESTION
I am trying to add values to a list inside a dictionary. I have had a look at this and tried append, but I get an error.
Code:
...ANSWER
Answered 2019-Jun-25 at 13:15def name_counts(x):
firsts = {}
for full in x:
part = full.split()
fn = part[0]
if fn not in firsts:
firsts[fn] = []
firsts[fn].append(full)
return(firsts)
name_list = ["David Joyner", "David Zuber", "Brenton Joyner",
"Brenton Zuber", "Nicol Barthel", "Shelba Barthel",
"Shelba Crowley", "Shelba Fernald", "Shelba Odle",
"Shelba Fry", "Maren Fry"]
print(name_counts(name_list))
QUESTION
def name_counts(alist):
split = []
for listitem in alist:
split.extend(listitem.split())
dicti = {}
for word in split:
if word in dicti:
dicti[word] +=1
else:
dicti[word] = 0
print(split)
return dicti
name_list = ["David Joyner", "David Zuber", "Brenton Joyner",
"Brenton Zuber", "Nicol Barthel", "Shelba Barthel",
"Shelba Crowley", "Shelba Fernald", "Shelba Odle",
"Shelba Fry", "Maren Fry"]
print(name_counts(name_list))
ANSWER
Answered 2019-Feb-03 at 00:03The counts are off by 1, because the first time you see the name, you initialize that name's count to 0. If you're going to keep the current flow-control structure, you should initialize the count to 1 at that point instead of 0.
But here's a more compact version that avoids luring you into that mistake:
QUESTION
I have sample data here:
...ANSWER
Answered 2017-Oct-13 at 08:37Try this:
QUESTION
I have to create a Lingo (*) game as an assignment for my school.
I finally finished it, but sometimes the letter bug and don't get a color or the wrong color.
...ANSWER
Answered 2017-Feb-16 at 14:51If I understood right how Lingo goes, the letter what you typed (like 4th) should get green/yellow/red background. Now, the place where the letter should be gets the yellow background. Because of this, the yellow color is sometimes in wrong place (and in some cases some letters' background stays white).
Fixed code:
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