sammy | tiny javascript framework built on top of jQuery | Frontend Framework library
kandi X-RAY | sammy Summary
kandi X-RAY | sammy Summary
Sammy is a tiny javascript framework built on top of jQuery inspired by Ruby's Sinatra.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of sammy
sammy Key Features
sammy Examples and Code Snippets
sudo htpasswd -c .htpasswd sammy
COPY .htpasswd /etc/nginx
public static void main(String argv[]) {
//Input
String[] a = { "Anne", "Anne", "Afrid", "vacant", "vacant", "Sammy", "Dora", "vacant" };
List list = Stream.of(a) //Convert to Stream
.filter(Obje
$ pm2 startup systemd
sudo env PATH=$PATH:/usr/bin /usr/lib/node_modules/pm2/bin/pm2 startup systemd -u sammy --hp /home/sammy
SQL> with
2 table_a (fname, sname, dob, ssn) as
3 (select 'David', 'Sam' , date '1980-01-01', '123-45-6789' from dual union all
4 select 'David', 'Lieser', date '1940-10-07', '987-65-4321' from dual union all
5 sel
-
name: Mark McGwire
hr: 65
avg: 0.278
-
name: Sammy Sosa
hr: 63
avg: 0.288
Block style: !!map
Clark : Evans
Ingy : döt Net
Oren : Ben-Kiki
First Site:
site: Fir
-
name: Mark McGwire
hr: 65
avg: 0.278
-
name: Sammy Sosa
hr: 63
avg: 0.288
mappings:
-
partnerId: partner1
stagePolicyMapping:
-
stage: Assignment Call
mask = df1 == df2
diff_output = df1.where(mask, df1.astype(str) + ' ---> ' + df2.astype(str))
print (diff_output)
dbSymbol Alias
0 UQ_121 mike
1 UQ142 Sam ---> sammy
2 UQ143 john ---> johnny
NODE_ENV=production # updates from 'development' to 'production'
pm2 start hello.js
pm2 startup systemd
sudo env PATH=$PATH:/usr/bin /usr/lib/node_modules/pm2/bin/pm2 startup
systemd -u sammy --hp /home/sammy
Community Discussions
Trending Discussions on sammy
QUESTION
I've created a multi-sheet workbook that has Manifest Data (Sheet1), Sammy (Sheet2), Trev (sheet3), Scan Data In (Sheet4). On each of the worksheets is a column labeled Connote and the data within cells of the column relates to a barcode on the paperwork we use. When I open a drivers worksheet i will scan the barcode from the paperwork and information will be pulled from the Manifest Sheet as well Time/Date Stamping using VBA. But what I'm trying to do is pull the drivers name which is in a cell on their worksheet back to the Manifest Data sheet which relates to the connote they have just scanned. I'm happy to upload the working sheet if required. Manifest Data Sheet Drivers Sheet https://1drv.ms/x/s!AiXQNwMzQ3OrnCxn4D54gpnBH9V0?e=fxsTnz
...ANSWER
Answered 2021-Jun-13 at 06:31QUICK & DIRECT but limited (update)
Include following function in Manifest under the driver column (assuming driver names are Sammy, Jose, Ian, Tame, etc.):
QUESTION
I am a newbie so please be kind, working on a blog app within my django project the idea is to check if there are articles , if there is list each article. if there is not articles show no articles found
below is my view function, however when I test this it only list the first item in my list which mike, other names are not showing on the page or on source like they do not exist ??? any help with this would be great. thanks in advance
...ANSWER
Answered 2021-Apr-27 at 03:24This view will always return the first element of the list because you return the first element in the first iteration.
Views don't generally return an HttpResponse instance, but more frequently use the render
method.
This is probably what you wanted to do with your view and how it should look like.
QUESTION
So I am trying to get my dictionary of lists to match up with my list of tuples. (hopefully that makes sense). I have a dictionary with lists as the values, my values are individual scores for each book, ex: the value 5 on bob would equal the first book in the book list, :
...ANSWER
Answered 2021-Apr-13 at 23:59You can try something like this. Basically enumerate the dictionary values and use it's index to access the books array.
QUESTION
I have a simple filter().map() function:
...ANSWER
Answered 2021-Apr-09 at 14:44The book.volumeInfo
object doesn't have a matureRating
. I think you meant to put maturityRating
. You're probably getting an empty filtered list as a result.
Change
QUESTION
My goal is it to let my DataGrid look like Picture2. So I created two DataGrids to realize this because i didnt find a better way to do this, but the solution is not very clean and I run into more and more problems. So in the first DataGrid I have the heading normal and in the second I have textBoxes in the heading that should act as a search bar. It looks like this with 2 DataGrid:
Because my goal is that my DataGrid will look like this in the end:
The problem now is that when I click on the first header, my data cannot be sorted in ascending or descending order. This only works if I click the second header on the second datagrid. But the button for sorting in ascending or descending order should not be in the second header, but in the first header. The best thing would be to use a DataGrid for this, but I don't know how to implement it so that the headings are in the first header and when I click in the first header that everything is sorted in ascending or descending order. And with the second header directly below then the TextBoxes that should serve as a search bar and below then the values. How do I manage that when I want to cut everything into a DataGrid. First of all, here is my code:
...ANSWER
Answered 2021-Apr-07 at 14:55So I created two DataGrids to realize this because i didnt find a better way to do this, but the solution is not very clean and I run into more and more problems.
Yes, trying to synchronize two DataGrids
is certainly going to be problematic.
What you should do is to add the TextBox
to the header of the (single) DataGrid
:
QUESTION
So I have 2 DataGrid
s (because I haven't found a better way to do it the way I want it) and I have the following code in the .cs:
ANSWER
Answered 2021-Apr-07 at 13:10You use a DataGridTemplateColumn
but you do not supply data templates for displaying and editing.
QUESTION
I'm creating a database that keeps track of books, users, and what books each user owns. A user can have several copies of a certain book, specified by their book id. What I'm trying to calculate in particular is show for each username the number of all books they own and the number of non-duplicated books they own. I have an attempt below but the numbers do not appear to be correct. For example after doing my select statement, it says that Sammy's total number of duplicated books is 4 and his total number of non-duplicated books is 3.
When you actually look at the data in the owns table, you can see the real values are that Sammy's total duplicated books is 3+2+1+1 = 7 books, and his total number of non-duplicated books would just be the total number of unique book_ids he has in his collection which is just 4.
I'm not sure what's wrong with the logic of my query and would appreciate some help.
Schema:
...ANSWER
Answered 2021-Mar-31 at 17:28You need for each user the sum of the column quantity
and the number of distinct book_ids
:
QUESTION
The number of np.where()
's I would assume is the issue since removing 1 will allow the function to work. I'm not aware of another way to edit a name other than an if else
. I figured this would be faster. Mapping comes to mind as well, but I'm not sure how to return the names that are not changed. Any help understanding the best practice for this desired outcome would be very much appreciated!
ANSWER
Answered 2021-Mar-20 at 12:48When you are dealing with more than two choices, use np.select
.
QUESTION
I wrote this code to compute student quiz scores and I got this part to work.
...ANSWER
Answered 2021-Mar-14 at 03:04The problem is that index
is leftover from your previous while loop. Your data structure is really not conducive to what you want to do. The total_score
should be stored in each Student object, not salted away in a dictionary that is global to the class. Your sorted list is just the name and the final grade. The best you can do write now is to scan through the student_objs
list by hand, looking for the object that matches the name you want.
QUESTION
The user (Ben) has joined group 2 and group 3. How can I write this in a select query... I want to select from groups I haven't joined and groups I didn't create.
...ANSWER
Answered 2021-Feb-27 at 20:51You can do it if you do a LEFT
join of group_tbl
to users_tbl
and return the unmatched rows of group_tbl
:
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