node6 | polyfills together to transparently support much es6 | User Interface library
kandi X-RAY | node6 Summary
kandi X-RAY | node6 Summary
[DEPRECATED] hacking all the transpilers and polyfills together to transparently support much es6 in node
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of node6
node6 Key Features
node6 Examples and Code Snippets
Community Discussions
Trending Discussions on node6
QUESTION
I am using Dynamic memory allocation in this code for deleting for nodes. Upon encountering a delete someVar
I am getting an error in the VSCode debugger.
ANSWER
Answered 2021-May-17 at 23:56delete
should only be used with an object that has been created with new
.
You create objects on the stack and set lsptr
to point to them. Note that the list nodes were not created by new
. You then delete lsptr
, which is invalid because they were not created by new
. This causes an exception. The exception is not handled by the program, so it notifies the operating system that the program has failed. This is called trapping into the operating system. The OS then handles the failure by either: stopping the program and jumping to a debugger (if setup), aka breakpoint trap, or kills your program.
To fix the program, remove the deletes. You don't need to delete stack allocations, only heap allocated objects (new
).
QUESTION
I have a different request than what I saw on stackoverflow. Say my binary tree is of the form tree(Node, Leafs)
. There is no left or right leafs, only the attribute leafs
.
How would you go about counting the node in that tree?
For example the tree could be:
...ANSWER
Answered 2021-May-04 at 00:50An unordered binary tree is a tree where each node can have up to two children, but the order between the children is not important. Thus, each node in a non-empty unordered binary tree can be represented as a term of the form tree(Node,Children)
, where Children
is an empty set (if Node
is a leaf), or a set of one or two trees (if Node
is an internal node). An empty unordered tree can be represented as nil
. To simplify the implementation, we can represent sets as lists. For example, the unordered binary tree:
QUESTION
Background:
I have a bare metal Kubernetes cluster. The master node is diskful, however all of the worker nodes are diskless, and PXE boot off of a machine which provides their OS image and non-volatile NFS mount points.
We found early on that we needed some kind of non-volatile storage so that the diskless nodes could store their configurations, kubernetes secrets, SSL keys, etc... Without the non-volatile storage, the nodes would have to be deleted and rejoined to the cluster every time they rebooted, which is obviously a pain.
So we created NFS mount partitions for /etc/kubernetes and /var/lib/kubelet so that the nodes could remember who they were and rejoin the cluster after a reboot.
The Problem:
However, we have run into a problem with kubeadm: It unmounts/remounts /var/lib/kubelet whenever you run kubeadm join. This leads to kubelet puking and dying because it can't find the appropriate device. The specific error is:
...ANSWER
Answered 2021-Jan-26 at 08:48This is a known issue but fortunately this is fixed just couple of days back - https://github.com/google/cadvisor/pull/2787.
This hasn't been cut into a release yet. While this might make into 1.20.x, not really sure about previous versions. Might want to request for a backport on the issue at https://github.com/kubernetes/kubernetes/issues/98009 if required.
QUESTION
I am including some tasks like shown below in my main.yml (as one of the tasks in a list of several other tasks)
...ANSWER
Answered 2020-Dec-27 at 14:23The behaviour seems normal, and you probably don't have any tasks tagged with never
in swarm.undo.yml
.
As per the documentation the tags are applicable for tasks and plays. So when you specify --tags never
, the include_tasks
(which is a task) gets included as expected. But only the tasks inside swarm.undo.yml
that have the never
tag will run.
Quoting from the above link:
Ansible reserves two tag names for special behavior:
always
andnever
. If you assign thealways
tag to a task or play, Ansible will always run that task or play, ...
Option 1: So one way is to make sure the relevant tasks in swarm.undo.yml
have the never
tag.
Option 2: If there are lot of tasks and all should be tagged with never
, you can consider converting this task file as a playbook (with tag at play level) and use import_playbook
.
Example swarm.undo.yml
:
QUESTION
We are looking into addressing some performance issues with our ES cluster. We were looking into shard distribution on data nodes. I know that there is an advice to have shards evenly distributed between nodes - and here is my question:
For the cluster with 8 data nodes - we have some indexes that have 2 primary shards and 3 replicas (so 8 shards in total). We have also some indexes that have 1 primary shard and 3 replicas (so 4 in total).
My question is - is that setup can be consider "evenly distributed"? We were thinking that it is not and we were thinking about having indexes with 1 primary shard - 7 replicas (so every index will be hosted on 8 nodes) - but we don't know if such setup has any sense? If not - what would you recomend instead to distirbute shards more evenly?
Here is the result of shard cat query:
...ANSWER
Answered 2020-Dec-14 at 13:59Distributing all shards on all ES data nodes for every index doesn't make sense for various reasons, please refer to opster's shards and replica for more info.
- Number of primary shards should be chosen based on their size and helps you to horizontally scale the index.
- Number of replica shards helps you in high availability and increasing search performance.
It's really difficult to achieve the perfect shards balance in the ES cluster(based on a number of shards, size, and traffic), Although based on your shards size which is really small(lesser than 100MB), you can go with 1 shard and 7 replicas for your all indices, having said this you need to benchmark and choose the correct number of shards and replica based on your cluster setup and use-cases.
QUESTION
I have this code, and I have an algorithm to put the line between two nodes
. I want this line to join the #nodo4
with the #nodo6
, the rectangles
are the nodes
and each one has the same name as its id
.
The code is a bit long but the important part to achieve this is here:
...ANSWER
Answered 2020-Oct-03 at 19:31Don't override the datum
of source and target. That means you will not be able to redraw the tree, because you override all the values you need for it.
Also, don't use getBoundingClientRect()
. What if you zoom, or pan? It distorts and the line will never be at the correct place.
Instead, rely on the data you already gave the nodes, you have it already, and you can access it by calling .datum()
with no arguments! Then, it's no problem to calculate the positions the nodes will have, and also no problem to add a line exactly where you want it, regardless of zooming or scrolling.
QUESTION
I have the following XML:
...ANSWER
Answered 2020-Sep-06 at 19:41What I need to do is to remove the NODE5, NODE6, NODE8.
below
QUESTION
I want to find nodes who should be linked to a given node, where the link is defined by some logic, which uses the nodes' and existing edges' attribute with the following logic:
A) (The pair has the same zip (node attribute) and name_similarity (edge attribute) > 0.3 OR
B) The pair has a different zip and name_similarity > 0.5 OR
C) The pair has an edge type "external_info" with value = "connect")
D) AND (the pair doesn't have an edge type with "external info" with value = "disconnect")
In short: (A | B | C) & (~D)
I'm still a newbie to gremlin, so I'm not sure how I can combine several conditions on edges and nodes.
Below is the code for creating the graph, as well as the expected results for that graph:
...ANSWER
Answered 2020-Aug-07 at 12:17Something seemed wrong in your data given the output you expected so I had to make corrections:
- Vertex D wouldn't appear in the results because "score" was less than 0.5
- "external_info" edges seemed reversed
Here's the data I used:
QUESTION
I've created nodes in Neo4j with the following code,
...ANSWER
Answered 2020-Jul-31 at 16:46Py2neo supports making Cypher queries, and here is a nice hello-world tutorial on how to do that.
So, I will provide a commented Cypher query that will hopefully work for you.
But first, a few notes:
- You should not give relationships that serve the same purpose a virtually infinite number of types (like "0.2", "0.5", etc.), as that is VERY unhelpful when you want to search for specific relationships by type (which is one of the most common things you will want to do) and will cause an enormous number of relationship types. So I assume in my answer that the relationships of interest all actually have the
TO
type. - My query uses a temporary
Temp
node to store the temporary state of the query as it iterates through the relationships in a random path. TheTemp
node will be deleted at the end of the query.
The query is as follows:
QUESTION
I have a project which contains 3 containers : reverse proxy container (jwilder-nginx-proxy image), fontend container (nginx container serving an application developed and bundled by Vue js) and a backend container (a node6 container serving a NodeJs+ExpressJs app). Both Backend and frontend are behind the reverse proxy. Here is how it should work in my local host:
- Access http://localhost:80/ and serve the gui
- The gui should retrieve data from the backend via http://localhost:3500
Everything seems to be working perfectly fine, Except for the backend container. When I try to access the backend, I get a '502 bad gateway' error. here is what nginx logs:
...ANSWER
Answered 2020-May-23 at 22:22To everyone having the same problem, here is the solution:
- Delete the access control settings from the nginx config. And Hande the cors within the Nodejs App.
- If you work with 'localhost' in your nginx.conf configure your NodeJs Express app to work with ipv6 ( instead of .listen('localhost') put .listen('::')).
- If this problem persist, make sure that you made the first two steps and switch your network mode to host: If you are using Docker compose v2 add 'network_mode : host' for each container. or --network=host for docker run.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install node6
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page