class-names | Conditionally join CSS class names together - Especially useful with React | Frontend Framework library
kandi X-RAY | class-names Summary
kandi X-RAY | class-names Summary
Conditionally join CSS class names together - Especially useful with React
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of class-names
class-names Key Features
class-names Examples and Code Snippets
def load_class_names(namesfile):
# Create an empty list to hold the object classes
class_names = []
# Open the file containing the COCO object classes in read-only mode
with open(namesfile, 'r') as fp:
# The
public static Set getClassNamesFromJarFile(File givenFile) throws IOException {
Set classNames = new HashSet<>();
try (JarFile jarFile = new JarFile(givenFile)) {
Enumeration e = jarFile.entries();
while
protected List getEntityClassNames() {
return Arrays.asList(getEntities())
.stream()
.map(Class::getName)
.collect(Collectors.toList());
}
Community Discussions
Trending Discussions on class-names
QUESTION
There are several div classes "jadejhlu" containing a a=href link. How can I select only the first div class to get only one link? I tried
...ANSWER
Answered 2022-Jan-20 at 09:10You can use nth-child
method to select the first element only.
Something like this:
QUESTION
I am trying to extract data from https://invictusdao.fi/#/dashboard However, I'm stuck in this.
There are no helpful class-names in the HTML. Sample here:
...ANSWER
Answered 2022-Jan-05 at 21:31At a glance, your selectors seem fine. The problem appears to be that the elements are rendered but without data, so you're scraping the empty text contents without waiting for them to be filled in asynchronously.
I tried using a waitForFunction
that polls on whether the text contents you want are empty. When they're not empty, then go ahead and scrape:
QUESTION
I’m programmatically creating multiple house images that look like this:
I'm doing this by simply iterating through a loop which:
- Creates a new Canvas object at each iteration
- Draws an SVG of the house onto this new Canvas object
- Creates a PNG file from that Canvas
To get some variety going, I’m also programmatically changing the colors of each house at each iteration by simply looking up color-schemes from an Array of color-schemes I created.
All this works great.
But what I’m struggling with is getting my script to AUTOMATICALLY DOWNLOAD each newly created House ".PNG" file to my hard-drive.
I’m trying to do this by creating an ANCHOR tag for each of my canvas/PNG’s and then calling the
“.click()”
method on each (code is below) - but it’s not working.
Chrome is giving me this error:
And Firefox gives me this error:
Any idea what needs to be done here?
My code is below.
Here's the basic House SVG:
...
ANSWER
Answered 2022-Jan-02 at 03:42If I understand you correctly, you should take a closer look at FileSaver.js - a convenient library for downloading files generated on the client. There is even an example of saving canvas in png file.
QUESTION
I am building a project and I am trying to declare class's name in variable before declaring variable.
But when I declare variable like :-
...ANSWER
Answered 2021-Dec-29 at 08:43in your example:
QUESTION
ANSWER
Answered 2021-Nov-17 at 04:41Below is one way to produce your desired result.
- The approach below has the
element in the HTML to be used as a template. That template is cloned, colors applied, converted into an Image and placed into the canvas for each house that has colors.
- Note: the structure of the SVG changed. The
class
attributes are replaced by a customdata-
attributedata-part
that is used to apply the fill style through a normal CSS selector.
- Note: the structure of the SVG changed. The
- The coordinate positions of each house are in an array of space separated
x y
coordinates. The array also indicates how many houses are to be drawn - The colors for the house 'parts' are included in an Object that lists the house 'part' and its corresponding color (the count of colors should match the number of houses)
- All
CSS is moved to the stylesheet.
I'll let you deal with sizing the image on the canvas.
QUESTION
I have a file mycomponent.module.css
ANSWER
Answered 2021-Aug-16 at 09:27If you want to style a current button, you should give a className or Id to your button. In this case it was global, for all butons.
QUESTION
The class
statement takes keyword arguments for various features. For example, the __init_subclass__
function receives keyword arguments passed at the class declaration:
ANSWER
Answered 2021-Apr-13 at 10:49The bare type
is not the equivalent of class
statements in Python3. Use types.new_class
as a functional equivalent of class
statements.
QUESTION
I am working on a project, where I have a main function, a class called simulator
and a class called vehicle
. In the main function I call: simulator.run()
which calls vehicle.run()
for all vehicles in simulator.vehicle_list[]
.
The vehicles have to calculate a trajectory, which is time-consuming process. These processes are independent of each other and I want the vehicle.run()
calculations to run on multiple CPU cores.
As starter I have created a simple project (with different class-names, than above, but intuitive enough I hope) but I cannot get it to work.
My code doesn't call self.calculate()
in the subclass. When I remove the if __name__ == '__main__':
statement from the master class, I get the error:
ANSWER
Answered 2021-Jan-21 at 12:05Ok, so this statement if __name__ == '__main__':
is put in place so that if the main process spawns up new processes, those new processes won't spawn new processes as well.
So, your entry point should have that.
multi_main.py
QUESTION
I'm porting over some Drupal 7 code to 8 and am stuck with one thing. In D7, I built some custom modules with a special hook function that would provide some debug information. To get a list of them, I can call module_implements('debugInfo'). For D8, I want to search, starting in the modules/custom directory, and return a list of modules with a class that has a public member function named 'debugInfo'. Is there a way to do this? I found an example, the first answer at PHP - get all class names inside a particular namespace, but if I have a base class with the method I'm looking for, it also reports all child classes inheriting the base class.
Since I'm only concerned with my custom modules, I can't use composer to do this. What I want is a way to get a dictionary of implemented classes from a starting directory, and get a list of available methods from the classes.
...ANSWER
Answered 2020-Nov-18 at 02:07Sounds like you probably want a custom plugin manager.
In Drupal 8 (and now 9) instead of implementing custom hooks and searching, you can instead create a plugin manager service and then implement plugins in each module to call the information when you need it. The manager service will automatically discover the plugins and you can call on them as appropriate.
To create a plugin is a bit more work than custom hooks were but also more flexible and gives you options. These resources can help you work through the details:
- https://www.drupal.org/docs/drupal-apis/plugin-api/creating-your-own-plugin-manager
- https://spinningcode.org/2017/01/drupal-8-plugins-are-addictive/
- https://medium.com/@uditrawat/custom-plugin-type-in-drupal-8-5c243b4ed152
To help you short cut you're reading a little: start with an Annotated plugin.
QUESTION
Very similar to this question: Sort table rows based on their Class Names - but need it to be in pure javascript instead of JQuery.
It needs to be able to sort by class names.
Consider the following table:
...ANSWER
Answered 2020-Nov-01 at 19:10You can do this as follows:
- get the rows of the table body
- sort the array according to the
className
of the first column of each row - update the
innerHTML
of the table body by joining thehtml
content of the resulted sorted list of row elements
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