psswrd | Show/hide toggling for password inputs | Identity Management library
kandi X-RAY | psswrd Summary
kandi X-RAY | psswrd Summary
Show/hide toggling for password inputs. Psswrd is a super simple JavaScript drop in that allows the user to toggle their password before submitting the form. This saves the user typing in their password a second time which aims to enhance the experience. Psswrd is 1KB minified and an Immediate-Invoked-Data-Expression (IIDE).
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of psswrd
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Community Discussions
Trending Discussions on psswrd
QUESTION
I'm trying to make a program in javascript that will lock a site. All that you'll have to do is type it into the console in chrome dev tools, and an alert will pop up asking for a password. If the password is correct, it will get rid of the alert. If the password is incorrect, the alert will pop up again. The alert popping up part is working correct, but even when the password is correct, the alert pops up again.
...ANSWER
Answered 2021-Apr-08 at 20:28Try this:
QUESTION
I am trying to automate the start of day procedures using selenium, I am trying to select and click a "tag" button, but no matter what way I do it there is a no element error.
I have tried XPath, css selector, class name, tag name, id, checking for iframe, checking if element is loaded. I just cant seem to get it.
This is the HTML of the website
...ANSWER
Answered 2020-Oct-19 at 08:25Your element target inside a </code> tag, you need switch it first.</p>
<p>Please use <code>.frame_to_be_available_and_switch_to_it</code> method to handle. And for your element, you can use this xpath <code>//span[text()="call"]</code></p>
<pre><code>#go to contacts
driver.get('https://app.nimble.com/#app/contacts/list')
wait = WebDriverWait(driver, 20)
wait.until(EC.frame_to_be_available_and_switch_to_it((By.ID, 'reactContactListFrame')))
element = wait.until(EC.element_to_be_clickable((By.XPATH, '//span[text()="call"]')))
element.click()
</code></pre>
QUESTION
I'm trying fix the Log-In & registration form. When you click on "Register" on my menu, you can see that the labels are perfectly formatted in the form but the input box are offset. I tried to fix it with float:left but it didn't work out too well. If somebody could help me with that, that would be awesome.
...ANSWER
Answered 2020-Sep-06 at 18:01A simple fix would be to give the label elements a display: inline-block;
and give them a defined width such as width: 100px;
.
I quickly created a JSFiddle to illustrate.
Hope this helped.
QUESTION
ANSWER
Answered 2020-Jul-29 at 14:55As I responded to your github issue:
You need to use playhouse.mysql_ext.MySQLConnectorDatabase
to connect using the mysql-connector driver. That will resolve your issue.
QUESTION
Hello,
What I am actually trying to do is the following:
I want to create this login screen where if you have the correct mail (which in this case is only test@test.com) to trigger the inapp screen from the KV file and this is my actual problem.
I cannot trigger the "inapp" screen
The reason why I don't have my screenmanager and my screens classes in the PY file is because it gets bugged and when I switch screens it overlaps Here is an example of the buggy UI
What am I doing wrong in my case?
This is my PY file:
...ANSWER
Answered 2020-Jul-22 at 17:06You just need to access the ScreenManager
to set the current
Screen
, like this:
QUESTION
How can I access a single row in sqlite database and return the data in a list. I have tried this
...ANSWER
Answered 2020-Jul-21 at 19:19If you want to access a single row, you don't need to use QSqlRecord
. Just use QSqlQuery::first
instead. Example:
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