lola | Code release for Learning with Opponent-Learning Awareness | Machine Learning library
kandi X-RAY | lola Summary
kandi X-RAY | lola Summary
Implements the LOLA ([AAMAS'18] and LOLA-DiCE ([ICML'18] algorithms. Further resources: - A pytorch implementation of LOLA-DiCE is available at - A colab notebook with the nummerical evalution for DiCE is available at
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Trending Discussions on lola
QUESTION
I have this array of objects in a react component and want to map only those whose owner is logged in the website
...ANSWER
Answered 2022-Feb-18 at 12:09Use the filter method:
QUESTION
I am back from taking a few years break in programming. Today I am trying to access my webserver from android and I have some code I recycled from back in the day. The code used to work, but, lo and behold, today it has an error. Can someone help me figure this out?
Here is my main class:
...ANSWER
Answered 2021-Dec-17 at 21:16You have a syntax error. Use
QUESTION
We can use jsonpath to select values for given expressions, for the following example and question:
...ANSWER
Answered 2021-Nov-29 at 08:22If you are using Jayway JSONPath you can use filter operators.
contains
filter operator
QUESTION
Im working through some self-join examples and I am drawing a blank on the following example. Its the last example at the following link Self-Join Example
...ANSWER
Answered 2021-Nov-26 at 15:51If you didn't have any condition on employee ID at all you'd end up with records where a self-match had occurred, e.g. the results would show "Gracie Gardner was hired on the same day as Gracie Gardner"
We could then put ON e1.employee_id <> e2.employee_id
- this would prevent Gracie matching with Gracie, but you'd then find "Gracie Gardner was hired on the same day as Summer Payne" and "Summer Payne was hired on the same day as Gracie Gardner" - i.e. you'd get "duplicate records" in terms of "person paired with person", each name being mentioned both ways round
Using greater than prevents this, and effectively means that any given pair of names only appears once. Because Gracie's ID is less than Summer's, you'll get Gracie in e1
paired with Summer in e2
but you won't get Summer in e1
paired with Gracie in e2
Another way of visualizing it is with a square/matrix
QUESTION
I have a table that stores employees (id, name, and gender). I need to randomly get two men and two women.
...ANSWER
Answered 2021-Sep-25 at 13:55Why not just use row_number()
? One method without a subquery is:
QUESTION
This is my folder structure:
This is how page looks like:
I have got all necessary data from props, but I fail to understand how to generate dynamic id pages. I want to generate dynamic ~/movies/_id pages, based on the id pulled from an array from API. And that pages just have to get Title, picture and overview from API object. So those two are questions.
Movies.vue is parent page. movieComp is component I have used to v-for on, to display list of a movies received from the array from API. Below every movie picture is a details button that should lead to that movie details (based on the id received from API).
_id.vue is a page that I want to display based on the id received from API.
This is code in movies.vue (parent).
...ANSWER
Answered 2021-Aug-13 at 14:30What you need is to create a movies subfolder in which you add _id.vue and movies.vue (renamed index.vue).
You should have the folowing folder structure:
QUESTION
I have following boolean dataframe in pandas:
...ANSWER
Answered 2021-Aug-06 at 14:27If you're looking for a "oneliner" solution using pandas....Have a look at pandas.crosstab
:
QUESTION
I am working on a regex problem from coursera and it has provided a data file of names followed by ": grade". We have to find and return the names of all the students who have a B. What I did was use this regex code
...ANSWER
Answered 2021-Aug-05 at 14:04You can use positive lookahead: [\w ]+(?=: B)
See Demo
QUESTION
What I am trying to do is that when a user clicks on an option in the dropdown list, it acts as a filter and takes them to a page with the specific query params matching their filtering. In theory, when a user selects an option, it should use the target.value of that option to take them to that specific page. But when I click on the different options, it does nothing to the URL. It doesn't take the user anywhere, it just stays on the same page. If you manually type in those query params, it will take you to the needed page, but the method with this.props.history.push simply does nothing. And there are no errors that come up either. How can I make it take me to the needed page?
App.js -
...ANSWER
Answered 2021-Jul-19 at 17:45You function definition is incorrect, Its function inside function..
QUESTION
Suppose I have two dataframe
...ANSWER
Answered 2021-Jul-16 at 02:04Join df
by df2
by ID
, meat
and Date
, keep only the rows where time_received > time_ordered
arrange the data by time_received
and keep only unique rows.
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