metaheuristics | art meta-heuristic algorithms using python | Machine Learning library
kandi X-RAY | metaheuristics Summary
kandi X-RAY | metaheuristics Summary
Implement the-state-of-the-art meta-heuristic algorithms using python (numpy)
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Top functions reviewed by kandi - BETA
- Train the model
- Create a random solution
- Gets the global best best solution for a population
- Returns the fitness for a given position
- Compute CEC coefficient
- Compute the CEC coefficient
- Calculate the CEC coefficient
- Computes the CEC_7
- Calculates the C25 coefficient
- Calculate CEC_4
- Calculates C12
- Calculate the C16 coefficient
- Calculate C 13
- Calculates the C11 coefficient
- Calculates a CEC coefficient
- Calculates the center of a given solution
- Calculates the C17 coefficient for a given solution
- Calculates the CEC19 coefficients
- CEC coefficient
- Train the model
- Calculate C30 coefficient
- Calculates the coefficient for a given solution
- Calculate C26 coefficients
- This function calculates the center of a solution
- Calculates the C3 coefficients for a given solution
- Calculates the C28 equation
metaheuristics Key Features
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Trending Discussions on metaheuristics
QUESTION
I am using Google OR-Tools to optimize the routing of a single vehicle over the span of a several day.
I am trying to:
- Be able to specify the number of days over which to optimize routing.
- Be able to specify the start location and end location for each day.
- Be able to specify the start time and end time for each day.
I have a set of 40 locations. For each day I want to include in my range of days for optimization, I prepend the start and end location to the matrix. So if I want to optimize for one day, I would have a total of 42 locations in my matrix. If I want to optimize for two days, I would have a total of 44 locations in my matrix. And so on. The pattern would like like this:
...ANSWER
Answered 2020-Dec-03 at 13:59You may have something like that:
QUESTION
I have a working Vehicle Routing Problem solution implemented using Google's OR-Tools in Python. I have a time matrix of 16 locations, time windows for each location, and penalties for dropping each location. All values are in units of seconds. I am intentionally solving this with just one vehicle (essentially solving a Traveling Salesperson Problem). I am allowing the vehicle to wait at any location for as long as is needed. I have set the drop penalty extremely high for some locations because I do not want them to ever be dropped.
Each location that is represented in the Time Matrix will have a time window, which indicates the time since the beginning of the day (28800 is the equivalent of 8:00am, and 64800 is the equivalent of 6:00pm, etc.) I set the upper bound maximum value as 64800 because there I want the vehicle to be done by 6:00pm.
I have designated the the first location in the matrix as the start location.
Now, I want the second location in the matrix to be the end location.
I have referenced the OR-Tools documentation for this, but have not found success. I have also found a similar question posted on Stack Overflow, but did not find any particularly helpful responses.
Below is my source code - it runs successfully, but does use the second location in the matrix as the end location in the solution it creates.
Source
...ANSWER
Answered 2020-Aug-21 at 14:29I received an answer for this question in the OR-Tools Google Groups forums.
First, properly change the manager constructor code.
QUESTION
I have a working Vehicle Routing Problem (with Time Windows) solution implemented using Google's OR Tools python library. I have a time matrix of 15 locations and time windows for each location. I also have the duration of a visit to each location baked into the cost of each visit. All values are in units of seconds. I am intentionally solving this with just one vehicle (essentially solving a Traveling Salesperson Problem).
I am not trying to add the ability to drop locations from a solution if they are preventing a valid solution from being created. Right now, if I have the duration for each visit set to 3600 seconds, it won't be possible to visit all 15 locations. However, if I instead set the duration for each visit to 900 seconds, then a solution will be possible for all 15 locations. I want to add a disjunction to allow for a solution to be created with these large durations in place, and instead of failing, simply drop a location from the solution.
I have some locations that I do not want to be dropped from the solution, so I have given them absurdly large penalties to ensure that they won't be dropped, while others I assign a penalty of zero. But now, all the other locations are being dropped because their penalty is zero - I assume that this is because the penalty is less than the cost of transit, but I am not completely sure if this is indeed the reason. How should I allow locations to be dropped from the solution, but prevent other locations from being droppable?
Right now the only code I have added is:
...ANSWER
Answered 2020-Aug-06 at 08:26To make location "mandatory" you must use the max int64 value (
0x7FFFFFFFFFFFFFF
) since solver can't overflow it will forbid it to drop this location.Since you are using your time matrix to feed the arc cost evaluator you should set your penalty around 10k otherwise solver has incentive to drop node and paying the cost than paying the transit cost.
All your time window ranges should be in
[0, max dimension value]
, here you set it to64800
BUT you have some Time Windows with79200
as upper bound, this can make the problem infeasible from the solver point of view so you should set the time dimension upper bound to at least79200
IMHO.
QUESTION
I have a working Vehicle Routing Problem solution implemented using Google's OR Tools python library. I have a time matrix of 9 locations, and time windows for each location. All values are in units of seconds.
(For example, the first time window is from 28800 to 28800. 28800 seconds is equivalent to 8:00am. I want this location, the depot, to be visited at exactly 8:00am)
I am intentionally solving this with just one vehicle (essentially solving a Traveling Salesperson Problem). I believe that I have added my dimension correctly, but I could certainly have made a mistake with that - my intention is to allow the vehicle to wait at any location for as long as it would like, as along as it allows it to solve the vehicle routing problem. I set the upper bound maximum value as 86400 because there are 86400 seconds in a day, and I figure that would be a sufficiently high number given this data.
Source
...ANSWER
Answered 2020-Jul-30 at 05:06What I understand of this tuples is that you have
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