propCheck | Property based testing for kotlintest ported from quickcheck | Testing library
kandi X-RAY | propCheck Summary
kandi X-RAY | propCheck Summary
Never write test data by hand again. Generate it!.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of propCheck
propCheck Key Features
propCheck Examples and Code Snippets
Community Discussions
Trending Discussions on propCheck
QUESTION
I have two different objects and I want to if at least one property of second objects' matches with the first one, I want to return true. If not, return false. I've tried .hasOwnProperty and .keys methods but couldn't handle it. Here an example code below. Thanks.
...ANSWER
Answered 2019-Jun-21 at 16:36You can get the keys of one object using Object.keys()
and then use some()
on it.
QUESTION
This is a hack (cogsRpm
is a user supplied function which is supposed to match the output of go):
ANSWER
Answered 2018-Aug-09 at 19:01QuickCheck comes bundled with a NonEmptyList
newtype, whose Arbitrary
instance only generates non-empty lists. You can combine this with NonZero
to get a non-empty list of non-zero integers:
QUESTION
I'm having an issue with a component that has some required propTypes.
The error I'm getting is:
...ANSWER
Answered 2017-Oct-16 at 13:32You are NOT modifying the state before render
, because you are using a setTimeout. Render does not wait for your setTimeout
and is directly called after componentWillMount
is called.
You have to set some default values in the redux reducer. You can just set in the reducer
QUESTION
OK, this most probably is a rather dumb question but I am having difficulty wrapping my head around this...
On page load / generation I am adding checked="checked"
to my via PHP based on the actual database entry.
Upon acting with the form I am reading the input's checked status via Javascript / jQuery in order to (AJAX-)submit the form and update the database entry.
The issue is that even when my JS-evaluation _this.is(':checked')
returns false
the actual HTML / DOM representation still show the checked attribute .
I know that I could .removeAttr('checked')
but that doesn't make sense (everything works) and is also not recommended (see this SO question...)
My question(s) would be: Is this normal behaviour? Should I simply disregard the inconsistence? What am I not getting here?
Thanks for your time + effort!
...ANSWER
Answered 2017-May-17 at 08:43This is completely normal. The attribute you see in the source is the original state of the element. The underlying property - which is what prop()
gets/sets - can be different.
Here's an example:
QUESTION
From what I've read ES6 symbols "only use is to avoid name clashes between properties"..
If this is the case and I wanted to check for name collisions on an object, why not just use a simple function to check, and then use a different property name if the check returns true? Why the introduction to an entire new data type ? (I'm sure I'm naive in asking this, but I don't understand)
Example:
...ANSWER
Answered 2017-Mar-23 at 01:11Why not just use a simple function to check, and then use a different property name if the check returns true?
Because that would mean everyone needed to do these checks. And there needed to be a protocol on how to use a different property name.
Also, one needs to assume that existing code already uses all possible property names. If you want to introduce a new, standard method name to use in an iteration protocol, which one could you choose? There is no name that you can pick where it is assured that it doesn't collide with anything.
I'm guessing the "real" use of symbols is that of a tool to help those connected to the standards body implement new features without breaking preexisting code.
No, you don't have to be connected to the standards body to use symbols. Everyone can introduce his own property names that don't clash with other code. They're useful for all kinds of libraries that need to work with arbitrary objects and don't want to break encapsulation.
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