Prefekt | Prefekt is an Android SharedPreferences library for Kotlin | Android library

 by   StylingAndroid Kotlin Version: 1.0.0 License: Apache-2.0

kandi X-RAY | Prefekt Summary

kandi X-RAY | Prefekt Summary

Prefekt is a Kotlin library typically used in Mobile, Android applications. Prefekt has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Prefekt is an Android SharedPreferences library for Kotlin. It is typesafe, easy to consume, and efficient thanks to in-memory caching. You can subscribe for updates so that if the underlying SharedPreference value is changed you receive a callback even if the change was made directly to the SharedPreference value is changed outside of Prefekt.
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              Prefekt has a low active ecosystem.
              It has 204 star(s) with 10 fork(s). There are 7 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 2 open issues and 2 have been closed. On average issues are closed in 1 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Prefekt is 1.0.0

            kandi-Quality Quality

              Prefekt has no bugs reported.

            kandi-Security Security

              Prefekt has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Prefekt is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Prefekt releases are available to install and integrate.
              Installation instructions are not available. Examples and code snippets are available.

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            Prefekt Key Features

            No Key Features are available at this moment for Prefekt.

            Prefekt Examples and Code Snippets

            No Code Snippets are available at this moment for Prefekt.

            Community Discussions

            QUESTION

            Pisarze - Data analysis task from Polish Olimpiad in Informatics
            Asked 2020-Jan-25 at 18:20

            You are given 3 well known Polish Books and based on some fragment of text you have to decide whether it's the first one, second or third. Your points are measured by some formula and to achieve 100 points you need to get accuracy greater than 90%.

            My solution to solve this problem was to map the most common words and based on that answer, for that solution I've got 70 points but still, I don't know how to approach this problem. Your code may be in Python or C++, you are given 3 books and program to test your solution Inputs are separated with different lengths based on sentences or some amount of words. You are also sure you will not get half-word. Problem statement (only in Polish currently). You can also submit your code there. How can I approach this problem differentlt to get 100 points, are there some Data Sciece algorithms which will help me with that problem.

            ...

            ANSWER

            Answered 2020-Jan-25 at 18:20

            For non-polish readers: you are given those books only when preparing your solution, you won't have access to them during test. If you try to bundle them with binary somehow those would exceed 10kb limit hence you need to compress information somehow.

            I would go for Naive Bayes classifier by default for a simple solution .

            Due to time constraint I would go a little bit different route though.

            Data preparation

            Read all files in and tokenize them. Would be easiest with Python's split functionality (and whole program would be easiest, time constraint probably won't be a problem). Split on whitespace and punctuation as those are mostly noise and are not representative of texts.

            Now calculate how often each of the tokens (words) occurs in each text, e.g. dog occured 15 times in first text and 3 times in another. Save those in three separate dictionaries, if the size of dict exceeds 10kb remove words occurring least frequently and adjust accordingly.

            Classifier for test phase

            Use 3 unsigned long variables to keep results for each texts to keep overflow in check (it should be enough).

            For every input text split it just like above.

            For every word check in dictionaries how often those occured for each text and add this to one of 3 result variables. If it doesn't exist just add 0.

            Finally return text which gathered "most points" this way. This should get quite a good score.

            Better solution

            Naive Bayes with probabilities would work much better but given competition constraints I don't think it is a viable solution.

            To do it, you would have to calculate probability of each word for each text and use log operstions during summation to avoid aforementioned overflow, just throwing it out for you to consider, doable but probably overkill.

            Source https://stackoverflow.com/questions/59911373

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Prefekt

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            gh repo clone StylingAndroid/Prefekt

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            git@github.com:StylingAndroid/Prefekt.git

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