Coffee | Android Quick Tile To Keep Screen | Android library
kandi X-RAY | Coffee Summary
kandi X-RAY | Coffee Summary
This Android app allows you to keep the display awake without having to change the device settings. It can be toggled at various places:. Coffee can be set as assist app (Device settings => Apps => Default apps => Assist app) and changes it's state when assist is called.
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QUESTION
I want to able to loop my arrays and calculate the total price and display it in the console. this is suppose to be a cart application. I assign all the anchor tags to cart variable that loops through the anchors tag and assign the the tags to the values in my beverages array to be able to display it but i cant display the total amount of all the prices.
html
...ANSWER
Answered 2021-Jun-15 at 18:46Instead of writing too much and looping .... See this , it might help you build what you are willing too
HTML
QUESTION
I am trying to contribute to a Github Page/Jekyll site and want to be able to visualise changes locally but when I run bundle exec jekyll serve
but I get this output:
ANSWER
Answered 2021-Feb-02 at 16:29I had the same problem and I found a workaround here at https://github.com/jekyll/jekyll/issues/8523
Add gem "webrick"
to the Gemfile in your website. Than run bundle install
At this point you can run bundle exec jekyll serve
For me it works!
QUESTION
I'm trying to design a simple page for practicing with just html and css. I used a hover pseudo class for the croissant image. It works but when I hover the mouse over the croissant the coffee cup image will move to right a little(almost 50 or 100 pixels) and when I hover off of the croissant the coffee cup will back in its position before. meanwhile I'm new in web design and just start learning few days. here's my code:
...ANSWER
Answered 2021-Jun-15 at 01:41In details:
- relative
...
if you do give it some other positioning attribute, say, top: 10px;, it will shift its position 10 pixels down from where it would normally be.
... - absolute
...
use the positioning attributes top, left, bottom, and right to set the location. Remember that these values will be relative to the next parent element with relative (or absolute) positioning. If there is no such parent, it will default all the way back up to the element itself meaning it will be placed relative to the page itself
...
Muhammad Zaib has the answer, and there is a demo:
QUESTION
zebra_owner(Owner) :-
houses(Hs),
member(h(Owner,zebra,_,_,_), Hs).
water_drinker(Drinker) :-
houses(Hs),
member(h(Drinker,_,_,water,_), Hs).
houses(Hs) :-
length(Hs, 5), % 1
member(h(english,_,_,_,red), Hs), % 2
member(h(spanish,dog,_,_,_), Hs), % 3
member(h(_,_,_,coffee,green), Hs), % 4
member(h(ukrainian,_,_,tea,_), Hs), % 5
adjacent(h(_,_,_,_,green), h(_,_,_,_,white), Hs), % 6
member(h(_,snake,winston,_,_), Hs), % 7
member(h(_,_,kool,_,yellow), Hs), % 8
Hs = [_,_,h(_,_,_,milk,_),_,_], % 9
Hs = [h(norwegian,_,_,_,_)|_], % 10
adjacent(h(_,fox,_,_,_), h(_,_,chesterfield,_,_), Hs), % 11
adjacent(h(_,_,kool,_,_), h(_,horse,_,_,_), Hs), % 12
member(h(_,_,lucky,juice,_), Hs), % 13
member(h(japanese,_,kent,_,_), Hs), % 14
adjacent(h(norwegian,_,_,_,_), h(_,_,_,_,blue), Hs), % 15
member(h(_,_,_,water,_), Hs), % one of them drinks water
member(h(_,zebra,_,_,_), Hs). % one of them owns a zebra
adjacent(A, B, Ls) :- append(_, [A,B|_], Ls).
adjacent(A, B, Ls) :- append(_, [B,A|_], Ls).
...ANSWER
Answered 2021-Jun-14 at 21:46The houses list Hs
is not empty at all, ever. It is created right at the very beginning with
QUESTION
Is there a way to make a link inside a snippet description clickable/styled?
I know about descriptionMoreURL
but I am interested in adding a second link.
This does not work:
...ANSWER
Answered 2021-Jun-14 at 02:10It's not possible, unfortunately. The description
doesn't seem to support any formatting whatsoever.
You can add HTML via parameters leftLabelHTML
and rightLabelHTML
, but if you click the link, it inserts the snippet, which is not ideal.
For reference, here's the documentation for the underlying autocomplete-plus
suggestion parameters.
QUESTION
I am currently working on a project in React Native and upon trying to create the first set of screens I began receiving this Error...
"Error: Element type is invalid: expected a string (for built-in components) or a class/function (for composite components) but got: undefined. You likely forgot to export your component from the file it's defined in, or you might have mixed up default and named imports."
I am not a beginner in React Native, but am also not an expert and this is my first time working on a RN build on my Macbook. I am not sure if there is a typo I have missed somewhere, if my path is not defined correctly, or if I am simply in need of another coffee - either way, I would love another set of eyes on it and any help is greatly appreciated. I will post the code of my Welcome Screen component and App.js below. Aside from the assets, these are the only files I am working in. I will also post a screenshot of my file structure. Thank you again!
...ANSWER
Answered 2021-Jun-10 at 20:57Try to use ImageBackground instead of ImageBackgroundComponent
QUESTION
I built a counter to count up to a target number. All the four counter are counting at the same time. Is there any possibility that (from left to right) that the first counter counts, when it is finished then the second counter counts etc., respectively not all at the same time? Here is my code:
...ANSWER
Answered 2021-Jun-09 at 14:02I think you need to include .queue(), .dequeue(), .next()
function of jQuery to run your counters sequentially. Below is the similar kind of implementation, try and plug it with your code:
QUESTION
I would like to match a specific pattern with regex but I am running into catastrophic backtracking. I wonder if there's a way it would be possible to match what I would like and not get an error. I start with a simple assumption; I want my string to contain only one specific number e.g. 7 and only that specific number:
^\D*7\D*$
Only if I find this pattern do I want to look for another word in the same text such as "Coffee"; I put my condition into a group (^\D*7\D*$)
and reference the group in my conditional and the then part will contain "Coffee":
(?(1)Coffee|)
Is there another phrasing that would avoid the the catastrophic backtracking?
...ANSWER
Answered 2021-Jun-09 at 20:37Left to right checking is more traditional:
QUESTION
I have to write a python program for the following problem
Write a complete and syntactically correct Python program to solve the following problem: Write a program for the local coffee shop owner who wants to be able to control his inventory. The program must be written in accordance with the following specs:
- Write the following data to an external file, name the file coffeeInventory.txt Description Pounds Blonde Roast 15 Medium Roast 21 Flavored Roast 10 Dark Roast 12 Costa Rica Tarrazu 18
- You do not need to write the table, just the data
- Read in the records you just wrote to coffeeInventory.txt and display them on the screen and sum the total pounds of coffee
- Append these records to the file Guatemala Antigua 22 House Blend 25 Decaf House Blend 16
- Modify the file by allowing the owner to remove data from the file: a. Ask the owner to enter a description to remove b. If the description exists, remove the coffee name and the quantityc. If the description is not found, display the message: That item was not found in the file.
- Modify the file by allowing the owner to delete data from the file: a. Ask the owner to enter a description to delete b. If the description exists, delete the coffee name and the quantity c. Replace the name and quantity of the coffee removed in step b by asking the user to enter a new coffee name and quantity d. If the description is not found, display the message: That item was not found in the file.
this is what I have so far
...ANSWER
Answered 2021-Jun-09 at 04:13All you need is a flag to save whether the Coffee was found.
QUESTION
import threading
import time
def eat_breakfast():
time.sleep(3)
print('You eat breakfast')
def drink_coffee():
time.sleep(4)
print('You drink coffee')
def study():
time.sleep(5)
print('You finish studying')
x = threading.Thread(target=eat_breakfast(), args=())
x.start()
y = threading.Thread(target=drink_coffee(), args=())
y.start()
z = threading.Thread(target=study(), args=())
z.start()
print(threading.active_count())
print(threading.enumerate())
print(time.perf_counter())
...ANSWER
Answered 2021-Jun-06 at 01:10You are calling the functions instead of passing them to the Thread
object
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