Prolog | Warren Abstract Machine - A embedded Prolog compiler | Translation library
kandi X-RAY | Prolog Summary
kandi X-RAY | Prolog Summary
I went through a lot a trouble thanks the "soft-typing" of PHP and the damned "===" but even if I still prefer Java and strong typing, the managing of strings and arrays in PHP is awsum. There's probably much optimizations to do since the design was not thought for PHP. The good thing is my knowledge of PHP internals has improved.
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Top functions reviewed by kandi - BETA
- convert structure to code
- Run a query
- Executes the WAM command .
- Read a Program .
- Update the labels of the statements
- Returns an integer representation of a function
- Returns the value as an array .
- Update names of processors
- compile a query
- Undo a reference
Prolog Key Features
Prolog Examples and Code Snippets
Community Discussions
Trending Discussions on Prolog
QUESTION
zebra_owner(Owner) :-
houses(Hs),
member(h(Owner,zebra,_,_,_), Hs).
water_drinker(Drinker) :-
houses(Hs),
member(h(Drinker,_,_,water,_), Hs).
houses(Hs) :-
length(Hs, 5), % 1
member(h(english,_,_,_,red), Hs), % 2
member(h(spanish,dog,_,_,_), Hs), % 3
member(h(_,_,_,coffee,green), Hs), % 4
member(h(ukrainian,_,_,tea,_), Hs), % 5
adjacent(h(_,_,_,_,green), h(_,_,_,_,white), Hs), % 6
member(h(_,snake,winston,_,_), Hs), % 7
member(h(_,_,kool,_,yellow), Hs), % 8
Hs = [_,_,h(_,_,_,milk,_),_,_], % 9
Hs = [h(norwegian,_,_,_,_)|_], % 10
adjacent(h(_,fox,_,_,_), h(_,_,chesterfield,_,_), Hs), % 11
adjacent(h(_,_,kool,_,_), h(_,horse,_,_,_), Hs), % 12
member(h(_,_,lucky,juice,_), Hs), % 13
member(h(japanese,_,kent,_,_), Hs), % 14
adjacent(h(norwegian,_,_,_,_), h(_,_,_,_,blue), Hs), % 15
member(h(_,_,_,water,_), Hs), % one of them drinks water
member(h(_,zebra,_,_,_), Hs). % one of them owns a zebra
adjacent(A, B, Ls) :- append(_, [A,B|_], Ls).
adjacent(A, B, Ls) :- append(_, [B,A|_], Ls).
...ANSWER
Answered 2021-Jun-14 at 21:46The houses list Hs
is not empty at all, ever. It is created right at the very beginning with
QUESTION
Here is what I'm searching for. I want to concat a given list for example:
...ANSWER
Answered 2021-Jun-14 at 12:09You are looking for an "intersperse" or "join" function, which is hidden behind the atomic_list_concat/3
predicate:
atomic_list_concat(+List, +Separator, -Atom)
or alternatively to create SWI-Prolog "strings" (which are supposed to be used in scenarios where you process text):
atomics_to_string(+List, +Separator, -String)
QUESTION
I am trying to understand the usage of existentially quantifying. What I know by now is this technique is used with setof
, findall
, bagof
. Further, I found a tutorial. However, I am not sure when and how I do the Vars^Goal
(existentially quantifying) in Prolog.
Here is the example, my goal is to find two employees who know each other but work at different companies, binding the result with L
showing Name1-Name2
:
ANSWER
Answered 2021-Jun-14 at 12:48I am not sure when and how I do the Vars^Goal (existentially quantifying) in Prolog.
The easiest answer is: Don't do it, ever. You can always introduce an auxiliary predicate that captures exactly the query you want, exposing exactly the arguments you want and nothing else (that would require quantification), and with a nice self-documenting name.
In your example, you can define:
QUESTION
I was trying to practice Prolog, as suggested by my TA, I am trying to create the rule append3(A,B,C,D)
which means D is the result of the append of A,B and C.
The definition of append(A,B,C)
is given
ANSWER
Answered 2021-Jun-12 at 04:06You need to flip the predicates append(A, B, X), append(X, C, D)
. Since all three variables A
, B
, and X
are unbound in append(A, B, X)
prolog tries to satisfy it and then constrain it with append(X, C, D)
which will always fail after giving you existing solutions. So it enters an infinite loop.
Try just executing append(A, B, X).
all of them unbound. Prolog should show you an infinite sequence of solutions, these fail in the next clause append(X, C, D)
.
Flip the predicates and you should be fine.
QUESTION
I am implementing a words/2
predicate in which a list of characters can be rendered to a list of the character as a word inside a list. I use the mathematical symbol <=>
to denote that they're working in any mode. Please advise if there's a better expression.
The example:
...ANSWER
Answered 2021-Jun-07 at 14:32split(_, [], [[]]).
split(C, [C|Xs], [[]|Ys]) :-
split(C, Xs, Ys).
split(C, [X|Xs], [[X|Y]|Ys]) :-
split(C, Xs, [Y|Ys]).
QUESTION
I am new to prolog and I would like to convert a string: 'test string'
to an array with a single element: ['test string']
so I can append it to an existing list.
ANSWER
Answered 2021-Jun-08 at 16:17Just write it as is:
QUESTION
I'm totally new to Prolog. So please excuse this possibly extermely simple qiuestion: I have a few facts like
...ANSWER
Answered 2021-Jun-11 at 01:12The operator you are using #\/
is a Boolean Finite Domain operator used in constraint programming clp(b)
.
If you just want a conjunction of two facts A and B, use A, B
. If you want a disjunction of them use A; B
.
In your case you can just type likes(paul, bikes), likes(paul, cars).
.
QUESTION
convertBinToDec(B,D):- atom_number(S,B),
atom_length(S,L),
sub_atom(S, 0, 1, After,S1),
atom_number(S1,N),
L1 is L-1,
sub_atom(S, 1,L1, After ,S2),
atom_number(S2,B2),
convertBinToDec(B2,D1),
D is D1+((2*N)**L1).
convertBinToDec(0,0).
convertBinToDec(1,1).
...ANSWER
Answered 2021-Jun-04 at 15:42You have used After
two times. Any usage of a variable in the clause can be instantiated to a only a single value. After
cannot take two different values in two calls to the procedure sub_atom
. This will work, try figuring out why?
QUESTION
I've implemented the following meta-predicate that use SWI-Prolog engines to simultaneously enumerate solutions to two or more backtrackable predicates.
...ANSWER
Answered 2021-May-29 at 06:31I think it should be
QUESTION
I'm working through the exercises on Learn Prolog Now! and I'm stumped on the very last question. Given the following facts:
...ANSWER
Answered 2021-May-29 at 03:43Your are not changing G
appropriately in the travel/3
predicate.
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Install Prolog
PHP requires the Visual C runtime (CRT). The Microsoft Visual C++ Redistributable for Visual Studio 2019 is suitable for all these PHP versions, see visualstudio.microsoft.com. You MUST download the x86 CRT for PHP x86 builds and the x64 CRT for PHP x64 builds. The CRT installer supports the /quiet and /norestart command-line switches, so you can also script it.
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