axiom | A package that provides a library of reusable Laravel | Validation library

 by   mattkingshott PHP Version: v3.2.1 License: MIT

kandi X-RAY | axiom Summary

kandi X-RAY | axiom Summary

axiom is a PHP library typically used in Utilities, Validation, Laravel applications. axiom has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

This package provides a library of reusable validation rules for your Laravel projects. Use them to augment the existing set provided by Laravel itself. Axiom is a re-release of the original alphametric/laravel-validation-rules package, which was also created by myself. This new version includes a rewrite to support PHP 7.4+ and also includes type hinting as well as some additional refactoring.
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            kandi-support Support

              axiom has a low active ecosystem.
              It has 407 star(s) with 41 fork(s). There are 14 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 0 open issues and 14 have been closed. On average issues are closed in 3 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of axiom is v3.2.1

            kandi-Quality Quality

              axiom has 0 bugs and 0 code smells.

            kandi-Security Security

              axiom has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              axiom code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              axiom is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              axiom releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.
              axiom saves you 914 person hours of effort in developing the same functionality from scratch.
              It has 2113 lines of code, 104 functions and 56 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed axiom and discovered the below as its top functions. This is intended to give you an instant insight into axiom implemented functionality, and help decide if they suit your requirements.
            • Verify Brazilian number .
            • Create temporary file .
            • Verify Vietnam .
            • Create the users table .
            • Check if the user has a valid value .
            • Get the error message .
            • Returns a random example .
            • Migrate posts .
            Get all kandi verified functions for this library.

            axiom Key Features

            No Key Features are available at this moment for axiom.

            axiom Examples and Code Snippets

            Generate an axiom .
            pythondot img1Lines of Code : 20dot img1no licencesLicense : No License
            copy iconCopy
            def generate(self, axiom, iterations):
                    '''
                    Method to apply all production rules on an initial axiom string
                    over a number of iterations.
            
                    @param axiom: data or symbol string to be processed
                    @type axiom: string
               

            Community Discussions

            QUESTION

            Using the commutativity of the AND operator in Coq
            Asked 2022-Apr-01 at 12:11

            I’m trying to prove something in Coq using the commutativity of the logic AND operator. I coded this short example:

            ...

            ANSWER

            Answered 2022-Apr-01 at 10:16

            The symmetry tactic is specifically for reasoning about equalities (a = b iff b = a).

            I don't know of general machinery for commutative operators, but you can find the lemma you need with something like this:

            Source https://stackoverflow.com/questions/71704443

            QUESTION

            Tactic for existential hypothesis
            Asked 2022-Feb-28 at 13:16

            Say we have a proposition P1 n, and there exists n for which it holds. Furthermore we have a proposition P2, where P1 n implies P2 for any n. How do we prove P2?

            ...

            ANSWER

            Answered 2022-Feb-28 at 13:14

            You may eliminate some_p1to get a witness nand a hypothesis Hn.

            Source https://stackoverflow.com/questions/71295035

            QUESTION

            OWL API NoSuchMethodError in saveOntology() call
            Asked 2022-Jan-31 at 10:43

            I am trying to call an OWL API java program through terminal and it crashes, while the exact same code is running ok when I run it in IntelliJ.

            The exception that rises in my main code is this:

            ...

            ANSWER

            Answered 2022-Jan-31 at 10:43

            As can be seen in the comments of the post, my problem is fixed, so I thought I'd collect a closing answer here to not leave the post pending.

            The actual solution: As explained here nicely by @UninformedUser, the issue was that I had conflicting maven package versions in my dependencies. Bringing everything in sync with each other solved the issue.

            Incidental solution: As I wrote in the comments above, specifically defining 3.3.0 for the maven-assembly-plugin happened to solve the issue. But this was only chance, as explained here by @Ignazio, just because the order of "assembling" things changed, overwriting the conflicting package.

            Huge thanks to both for the help.

            Source https://stackoverflow.com/questions/70854565

            QUESTION

            Explanations in Consistent OWL Ontologies
            Asked 2022-Jan-08 at 19:43

            I want to programmatically get explanations for inferred axioms in consistent ontologies, in a similar manner that one can do in the Protégé UI. I cannot find any straightforward way. I have found the owlexplanation repo, but I cannot for the life of me solve the dependency issues to set up the owlexplanation environment. I have also browsed the javadoc of owlapi regarding explanations (to avoid the other repo altogether), but I don't see anything useful beyond what I can already see browsing the Java source code.

            I have thought of simply negating the inferred axiom, to get explanations through inconsistencies, but I would prefer something cleaner, and I am not sure this approach is correct anyway.

            Other (possibly) useful context:

            • I had used some Java years ago, but I now primarily use Python (I try to use OWL API with JPype and OWL in general with Owlready2).
            • I am using HermiT reasoner (again through JPype) (according to build.xml file, latest stable version 1.3.8).
            • I have managed to get explanations for unsatisfiability and inconsistency in my setup, without owlexplanation, following this example from the HermiT source code.
            • I fell in the rabbit hole wanting to make a usable .jar file for owlexplanation, in order to add it in my JPype classpath. My plan went sideways when I couldn't get the Java project to build in the first place.
            • I am using Intellij IDE.

            I would appreciate any insight or tips.

            UPDATE Jan 6, 2022:

            I decided to try once more with the owlexplanation code with a clean head so here is where I am at:

            • Downloaded the source code from github and extracted the zip.
            • Started IntelliJ and instead from "Creating a project from Existing sources", I clicked "Open" and selected the extracted directory.
            • I built the project and it did successfully.
            • From Maven tools, I run clean, validate, compile and test succesfully.
            • If I run "package" Maven action, it throws as error that "The environment variable JAVA_HOME is not correctly set". The thing is that if I go File>Project Structure, I see that SDK is set to 11, it's not empty.
            • Additionally, from the pom.xml file I get these problems:
              • Plugin 'org.apache.maven.plugins:maven-gpg-plugin:1.5' not found
              • Plugin 'org.sonatype.plugins:nexus-staging-maven-plugin:1.6.6' not found

            UPDATE Jan 8, 2022: (Trying @Ignazio's answer)

            I created a new IntelliJ project, and added the Maven dependencies @Ignazio mentioned (plus some others like slf4j etc) and I got a working example (I think). Moving to my main project (using JPype), I had to manually download some .jars to include in the classpath (as maven can't be used here). These are the ones downloaded so far:

            ...

            ANSWER

            Answered 2022-Jan-07 at 20:52

            You're not just using the projects but actually building them from scratch, which requires more setup than using the published artifacts.

            Shortcut that uses Maven available jars (via Maven Central, although other public repositories should do just as well)

            Java code:

            Source https://stackoverflow.com/questions/70593249

            QUESTION

            Why is UIP unprovable in Coq? Why does the match construct generalize types?
            Asked 2021-Dec-22 at 20:18

            UIP (and equivalents like axiom K) must be added axiomatically in Coq if it is desired:

            ...

            ANSWER

            Answered 2021-Dec-22 at 20:15

            As hinted in my previous answer, the eliminator for equality in Coq inherits this behavior from intensional type theory, where it was introduced to keep type checking decidable. However, later people realized that it is possible to have an elimination principle for equality that validates axiom K without ruining decidability. This is not implemented in Coq, but it is implemented in Agda:

            Source https://stackoverflow.com/questions/70451578

            QUESTION

            Is there a shorter proof to this Coq theorem?
            Asked 2021-Dec-18 at 15:26

            I'm learning to use Coq and I try to prove the theorems of a paper I'm reading. The paper is Having a Part Twice Over of Karen Bennett, published in 2013. The paper propopes a mereological theory composed of two primitives F and Ps and defines the parthood relation P using the two primitives.

            I coded it as follows:

            ...

            ANSWER

            Answered 2021-Dec-17 at 22:19

            Yes, your Coq code is OK. But there are shorter proofs. This theorem is simple enough that it can be solved with Coq's automation tactics. E.g.,

            Source https://stackoverflow.com/questions/70399323

            QUESTION

            Alloy assertion on implies command
            Asked 2021-Dec-17 at 22:18

            I try to implement on Alloy the axiomatic system described in a paper on mereology: "Bennett, Having a Part Twice Over, 2013".

            I implemented all the axioms, and I thought that if I implemented them correctly, I could assert and check the theorems.

            I try to code theorem (T9). This is the theorem in the paper:

            And this is how I coded it:

            ...

            ANSWER

            Answered 2021-Dec-17 at 22:18

            As explained by Hovercouch, it was a precedence issue :

            you got AE(p impl q) when you wanted A((Ep) impl q)

            Adding parentheses fixed the issue.

            Source https://stackoverflow.com/questions/70221753

            QUESTION

            Tailwind 3 in Laravel gives: Error: PostCSS plugin tailwindcss requires PostCSS 8
            Asked 2021-Dec-10 at 09:46

            I am trying to upgrade tailwind to version 3 in my Laravel application.

            I followed the installation as instructed in

            https://tailwindcss.com/docs/upgrade-guide#upgrade-packages

            npm install -D tailwindcss@latest postcss@latest autoprefixer@latest

            This worked fine. But when I run npm run dev I get this error:

            ERROR in ./resources/assets/css/tailwindcore.css Module build failed (from ./node_modules/css-loader/index.js): ModuleBuildError: Module build failed (from ./node_modules/postcss-loader/src/index.js): Error: PostCSS plugin tailwindcss requires PostCSS 8.

            I have read from the docs that PostCSS 8 is now required with tailwind 3. However, PostCSS 8 has been installed. Why would I still receive this error? I also tried to remove node_modules folder and reinstall, but got same error.

            This is my package.json:

            ...

            ANSWER

            Answered 2021-Dec-10 at 09:46

            The issue is that you're running an old version of Laravel Mix. Another issue you will face is the @tailwindcss/form plugin will need to be updated as well.

            Update the packages with:

            Source https://stackoverflow.com/questions/70301843

            QUESTION

            Can release+acquire break happens-before?
            Asked 2021-Nov-15 at 13:23

            Many programming languages today have happens-before relation and release+acquire synchronization operations.

            Some of these programming languages:

            I would like to know if release+acquire can violate happens-before:

            • if it's possible, then I would like to see an example
            • if it's impossible, then I would like to get simple and clear explanations why
            What is release+acquire and happens-before

            Release/acquire establishes happens-before relation between different threads: in other words everything before release in Thread 1 is guaranteed to be visible in Thread 2 after acquire:

            ...

            ANSWER

            Answered 2021-Nov-01 at 04:59

            I would like to know if release+acquire can violate happens-before.

            Happens-before relationship cannot be "violated", as it is a guarantee. Meaning, if you established it in a correct way, it will be there, with all its implications (unless there is a bug in the compiler).

            However, establishing just any happens-before relationship doesn't guarantee that you've avoided all possible race conditions. You need to establish carefully chosen relationships between relevant operations, that will eliminate all scenarios when data race is possible.

            Let's review this code snippet:

            Source https://stackoverflow.com/questions/69791898

            QUESTION

            Is CoInductive "extensionality" sound in Coq? Is it generalizable?
            Asked 2021-Nov-11 at 06:16

            My understanding is that the typical notion of equality is too weak to prove many intuitive equalities on possibly infinite coinductive terms. Therefore it is necessary to introduce a coinductive equality for the specific coinductive type in question.

            For instance, I have the following coinductive definitions concerning infinite relation transition sequences:

            ...

            ANSWER

            Answered 2021-Nov-11 at 06:16

            While this axiom makes sense intuitively, are such coinductive extensionality principles known to be sound in general?

            Yes. There's an isomorphism between coinductive types and function types. A coinductive type modulo coinductive extensionality is isomorphic to the type of functions from it's index type to its data type modulo function extensionality. So, for example, Stream A modulo EqSt (from Coq.Lists.Streams) is isomorphic to nat -> A modulo function extensionality. Your datatype modulo path_extensionality is roughly isomorphic to { st : nat -> state | forall n, R (st n) (st (S n)) } modulo function extensionality. The trick I'm pulling with your datatype here is to transform it into one that is parameterized instead of indexed; your datatype is morally parameterized over Stream state.

            There's unfortunately no way to introduce all the extensionality axioms at once, unless you want to give up coinductives and switch to functions (in which case you can just use the standard library axiom Coq.Logic.FunctionalExtensionality.functional_extensionality_dep). However, you could use a weaker axiom combined with function extensionality: the weaker axiom for a given coinductive type would say that if you go from the coinductive to the corresponding function and then back, you get back what you started with. Another way of phrasing this is that you can axiomatize only one direction of the isomorphism, rather than both directions. This is weaker in the sense that each coinductive extensionality axiom implies function extensionality for the corresponding function type, but this axiom does not.

            In case you want some code, here's some code showing the formal isomorphism for standard library streams and for your type (works in Coq 8.13):

            Source https://stackoverflow.com/questions/69773840

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install axiom

            Pull in the package using composer.

            Support

            Thank you for considering a contribution to Axiom. You are welcome to submit a PR containing improvements, however if they are substantial in nature, please also be sure to include a test or tests.
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