cpx | Quickly execute Composer package binaries | Build Tool library
kandi X-RAY | cpx Summary
kandi X-RAY | cpx Summary
Help support the maintenance of this package by sponsoring me. Quickly execute Composer package binaries from anywhere. ️.
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Top functions reviewed by kandi - BETA
- Localize package .
- Install temporary package .
- Find the package s binary .
- Remove package .
- Get global directory .
- Get the composer . json file .
- Print an error
- Show debug info
- Returns whether a string starts with a given query string .
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cpx Examples and Code Snippets
Community Discussions
Trending Discussions on cpx
QUESTION
I need help selecting an element on a webpage with Selenium. I have been using Selenium on this website for about 3 weeks and so far, I can usually find an element by css selector or XPath. However, this specific section of the website is giving me a very hard time. After I click on “reset office 365 password” a window comes up and I want to programmably put in the new password but it can’t find anything in the popup window. Here is what the page looks like: (I am too low of score to post pictures here) https://cdn.discordapp.com/attachments/768594779344470022/845811910577881098/unknown.png
Here is the whole element’s information:
...ANSWER
Answered 2021-May-23 at 03:54Because of no webpage code, right now I can't say why the element is not detectable by Selenium but you can try one thing. Right click on the element(input tag in dom shown in picture) and go to "Copy to" option and select "Copy JS Path". Then go to console tab in dev tools and paste it. Then try to set it's value to some dummy text and see if it sets the password.
QUESTION
I am performing the following calculation which is verrryyy slow (mostly because the DataFrame that I am looping through (PM_mix
) is very large). I know you're not supposed to loop through DataFrames if at all possible, but I don't know the best way to avoid this. I feel like the solution may be to execute the calculation using numpy and then convert the output array to a DataFrame, but I don't know the best way to go about this. Since I am essentially trying to multiply each DataFrame column by an array (F_range
), would it be worth trying to calculate a multidimensional array, and then flatten? I would appreciate any of your suggestions - thanks!
ANSWER
Answered 2021-Mar-21 at 20:49This could be faster.
QUESTION
I am getting some errors while trying to run a Perl file which is I need to run. (I usually use Python but I do not know any other programming languages including Perl.) I will show errors firstly, then I will attach the whole code in the end.
The error:
...ANSWER
Answered 2021-Jan-20 at 03:56QUESTION
i have the following code developed in python using the library Docplex to solve an optimal model:
...ANSWER
Answered 2020-Dec-10 at 15:19in your model if you add
QUESTION
I created a simple catalog item component using stencil.js. In the component there is canvas tag that on it I painted animating curved lines. At the componentDidLoad function, I define the canvas, initialize it and call the animate function. This is the code of the component itself:
...ANSWER
Answered 2020-Nov-23 at 13:04The problem is that some variables are defined outside the initCanvas
function and therefore shared between all the components (line1
, line2
, ctx
and canvasElem
). So each time you call initCanvas
they are overwritten.
A quick solution would be to wrap it in a class:
QUESTION
I am getting this error all of sudden in Jenkins build, i tried upgrading to latest Angular that is 10.1 but even after upgrading issue is not resolved. So i rolled back to Angular 10.0, package.json dependencies below
[09/11/2020 03:26:56.420] - Build:: Compiling @angular/platform-browser-dynamic/testing : es2015 as esm2015 [09/11/2020 03:27:09.120] - Build:: Error: Error on worker #5: TypeError: dir[ioType].hasBindingPropertyName is not a function [09/11/2020 03:27:09.120] - Build:: at Project_folder/node_modules/@angular/compiler/bundles/compiler.umd.js:30061:79 [09/11/2020 03:27:09.120] - Build:: at Array.find () [09/11/2020 03:27:09.120] - Build:: at setAttributeBinding
Package.json
...ANSWER
Answered 2020-Sep-11 at 19:04It seems there is an issue in @angular/compiler 10.1.1.
This isn't a solution for that problem, but I was able to workaround the issue by downgrading both @angular/compiler and @angular/compile-cli to 10.0. An update to package.json alone wasn't sufficient. I also needed to clean up node_modules to revert the code.
The steps I took that resulted in a successful build...
- Update package.json
QUESTION
I am currently making an emulator for the NES (like many others) , and while testing my emulation against the nestest rom by Kevtris (found here : https://wiki.nesdev.com/w/index.php/Emulator_tests), there is a weird bug I've encountered , at the instruction 877 on the nestest log (this one : http://www.qmtpro.com/~nes/misc/nestest.log , at line CE42) .
The instruction is a PLA , which pulls the accumulator from the stack , while having the stack pointer at $7E at the beginning. (I'm using a 1 byte value for the stack pointer , since it goes from 0x0100 to 0x01FF , so when I write $7E talking about the stack , it's 0x017E , not zeropage ;) )
So , when PLA is executed at line 877, the stack pointer moves to $7F and retrieve the first byte and store into the accumulator .
The problem is here : on the nestest log , this byte is 0x39 , then , on instruction 878 which is also a PLA , the retrieved byte at $80 (stack pointer incremented + 1) , is 0xCE, and this has inverted the low byte and high byte.
The values written on the stack (0xCE39) have their origin in the JSR instruction at line CE37 and here is my implementation of the JSR opcode :
...ANSWER
Answered 2020-Sep-14 at 14:17The mistake is not in nestest; the mistake is in your implementation of JSR and RTS!
You need to push the high byte first, and then the low byte. (This is so that the low byte can be retrieved first, and incremented while the high byte is being fetched)
QUESTION
I want to make multiple circles travel along the path. I made from the reference here
...ANSWER
Answered 2020-Jul-09 at 10:53I am the author of the answer you linked. Just as I explained in that answer, the solution is just using the circles' indices to select the path:
QUESTION
I've been struggling with a topic related to IRQ (interrupts itself); i'm using an old MC68HC11
Been practicing for a while; i decided to move on and check the hardest exercises showed in this chapter that's why i found an interesting one (and a little tricky tbh)
Take a look at this:
This is what i tried so far (This is just an outline):
...Do NOTE:
FLAGNMI means XIRQ
FLAGIQR means IRQ
ANSWER
Answered 2020-Jun-30 at 23:21OK, here it is, TOTALLY UNTESTED but should give you the idea!
Assumptions: IRQ input is debounced, IRQ is edge triggered (so it won't repeat for the same key press), and XIRQ pulse will be shorter than the time it takes to execute the corresponding handler to avoid counting the same money twice or more.
Like I said in the comment, the design is somewhat flawed as given, but if we ignore this and assume corner cases won't happen, here's one possibility:
QUESTION
Write an assembly language program that searches backwards through memory locations F454h - F503h for memory locations that contain the ASCII value for a lower case 'a' and places the total into location 0500h. Have the program start at 0200h in memory. Assemble the program, load it into the emulator, run it, and verify that it works correctly.
...ANSWER
Answered 2020-Jun-16 at 11:48There are two things to take into consideration.
- You want the starting address to be F503h and the ending address to be F454h.
- Ideally your loop exit condition should test either for the index being zero or negative (BNE or BPL). This is so that you can avoid using a compare (CPX).
If you test for negative, that basically means the top bit is set. The top bit gets set when the index (X) decrements from 00h to FFh.
Testing for negative would be preferable because the last value of the index (X) would be zero - which makes calculating the address to use (for LDA address,X) more obvious.
However, testing for negative means that the highest value X can be is 80h (128). This is because all values above 7Fh (127) have their top bit set. If you start at 80h then the first decrement (DEX) will take the index to 7Fh which is not negative, so the loop is good. If you start at say 81h, then the DEX will take the index to 80h, and this is negative (top bit set), so the loop exits immediately, which is bad.
So can we test for negative? In this case it's not possible. This is because the range of values for the index is F503h - F454h + 1= 176 (distinct addresses). And, this is above 128.
So we a forced to check for zero. That means the last value of the index (X) before we exit the loop will be 1.
In turn since we want to land on address F454h at the end of the loop, we must subtract 1 from this - since we are adding 1 from the index (X). So we need:
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