generator | Laravel 5.3 Scaffold Generator | Generator Utils library

You should separate creating your menu from your content. Please review the following example. I decoupled your menu, component, and event logic into meaningful phases.

Put everything in an object.

This way the 2 defs that depends on each other will be available at the same time.

IntelliJ worksheets do not like such definitions as they are "evaluated" one by one. You cannot define 2 depending on one the other at the top-level, they need to be encapsulated.

Yes I can see what you mean, I have done this integration before you only forget the priority statement otherwise should run well, please add this to your code;

after

apply { ipv4_lpm.apply();

ADD:

Send your data to separate processes. I used concurrent.futures because I like the simple interface.

This runs in about 11 seconds on my computer.

I'm assuming you have missing dependencies on your code generation class path. Once you update your question, I'll update my answer.

jOOQ won't support your generated composite types in generated code out of the box, you'll still have to add forced type configurations for that, possibly embeddable type configurations:

• https://www.jooq.org/doc/latest/manual/code-generation/codegen-advanced/codegen-config-database/codegen-database-forced-types/
• https://www.jooq.org/doc/latest/manual/code-generation/codegen-embeddable-types/

Note that the JPADatabase offers a quick win by integrating with simple JPA defined schemas very quickly. It has its caveats. For best results, I recommend going DDL first (and generate both jOOQ code and JPA model from that), because it will be much easier to put your schema change management under version control, e.g. via Flyway or Liquibase.

Change your code as follows.

The way you're encrypting data makes no sense. Asymmetric encryption can only encrypt a small, fixed amount of data. Never use asymmetric encryption such as RSA-OAEP for anything other than a symmetric key, and use that symmetric key to encrypt the actual data. For the symmetric encryption, use a proper AEAD mode such as AES-GCM or ChaCha20-Poly1305. This is called hybrid encryption.

Other things that are wrong with your code:

• A 1024-bit RSA key is not enough for security: 2048-bit is a minimum, and you should prepare to move away from RSA because its key sizes don't scale well. (Feel free to use 1024-bit keys for testing and learning, just don't use anything less than 2048-bit for RSA in production.)
• The encryption is a binary format, but you join up lines as if they were text. Text or binary: pick one. Preferably use a well-known format such as ASN.1 (complex but well-supported) for binary data or JSON for text. If you need to encode binary data in a text format, use Base64.

If this is for real-world use, scrap this and use NaCl or libsodium. In Python, use a Python wrapper such as libnacl, PyNaCl, pysodium or csodium. Use a public-key box. The Python APIs are slightly different for each Python wrapper, but all include a way to export the keys.

If this is a learning exercise, read up on hybrid encryption. Look inside libsodium to see how to do it correctly. Key import and export is done with the methods import_key and export_key. Symmetric encryption starts with Crypto.Cipher.AES.new(key, Crypto.Cipher.AES.MODE_GCM) or Crypto.Cipher.ChaCha20_Poly1305.new(key) (Crypto.Cipher.AES.new(key, Crypto.Cipher.AES.MODE_GCM, nonce=nonce) or Crypto.Cipher.ChaCha20_Poly1305.new(key, nonce=nonce) for decryption).

The error says it all. You can't use ctx in events since ctx represents the Context where command is provoked. Read the docs about ctx here: https://discordpy.readthedocs.io/en/stable/ext/commands/api.html

In order to send a message to a specific channel use bot.get_channel(id) which will return a discord.Channel object and then you can use discord.Channel.send() to send a message to that channel.

Unity's Random.Range with (int, int) overload (NOT float, float) generates random number in range [min; max), max is exclusive, so if you call var randomInt = Random.Range(0, 1) result will be always 0. var randomInt = Random.Range(0, 2) would be 0 or 1, e.t.c