CalendR | The missing PHP 5.3 calendar management library | Calendar library

 by   yohang PHP Version: 1.0.5 License: MIT

kandi X-RAY | CalendR Summary

kandi X-RAY | CalendR Summary

CalendR is a PHP library typically used in User Interface, Calendar applications. CalendR has no vulnerabilities, it has a Permissive License and it has low support. However CalendR has 5 bugs. You can download it from GitHub.

CalendR is an Object Oriented Calendar management library on top of PHP5.3+ Date objects. You can use it to deal with all your needs about calendars and events.
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            kandi-support Support

              CalendR has a low active ecosystem.
              It has 461 star(s) with 59 fork(s). There are 26 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 11 open issues and 17 have been closed. On average issues are closed in 191 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of CalendR is 1.0.5

            kandi-Quality Quality

              CalendR has 5 bugs (0 blocker, 0 critical, 5 major, 0 minor) and 46 code smells.

            kandi-Security Security

              CalendR has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              CalendR code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              CalendR is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              CalendR releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.
              CalendR saves you 1052 person hours of effort in developing the same functionality from scratch.
              It has 2385 lines of code, 284 functions and 54 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed CalendR and discovered the below as its top functions. This is intended to give you an instant insight into CalendR implemented functionality, and help decide if they suit your requirements.
            • Get event query builder .
            • Get the config tree builder .
            • Find events in the collection .
            • Loads the service configuration .
            • Build the event provider .
            • Registers all service providers .
            • Remove an event .
            • Get the previous range .
            • Get the next range .
            • Get events .
            Get all kandi verified functions for this library.

            CalendR Key Features

            No Key Features are available at this moment for CalendR.

            CalendR Examples and Code Snippets

            No Code Snippets are available at this moment for CalendR.

            Community Discussions

            QUESTION

            Mark vector of dates using calendR (or other package?)
            Asked 2021-Apr-13 at 13:15

            I have a vector of dates with a certain amount of visits per date and the specific type of visit.

            Data (the 'ficol' column can be ignored):

            ...

            ANSWER

            Answered 2021-Apr-13 at 13:15
            library(tidyverse)
            library(lubridate)
            library(assertr)
            library(calendR)
            
            
            df <- structure(c("2021-06-15", "15", "60", "T0s", "2021-06-16", "15", 
                              "60", "T0s", "2021-06-17", " 8", "32", "T0s", "2021-06-21", "15", 
                              "60", "T0s", "2021-06-22", "15", "60", "T0s", "2021-06-23", "15", 
                              "60", "T0s", "2021-06-24", "15", "60", "T0s", "2021-06-28", "15", 
                              "60", "T0s", "2021-06-29", "15", "60", "T0s", "2021-06-30", "15", 
                              "60", "T0s", "2021-07-01", "15", "60", "T0s", "2021-07-05", "15", 
                              "60", "T0s", "2021-07-06", "15", "60", "T0s", "2021-07-07", "15", 
                              "60", "T0s", "2021-07-08", "15", "60", "T0s", "2021-07-12", "15", 
                              "60", "T0s", "2021-07-13", "15", "60", "T0s", "2021-07-14", "15", 
                              "60", "T0s", "2021-07-15", "15", "60", "T0s", "2021-07-19", "15", 
                              "60", "T0s", "2021-07-20", "15", "60", "T0s", "2021-07-21", "15", 
                              "60", "T0s", "2021-07-22", "15", "60", "T0s", "2021-07-26", "15", 
                              "60", "T0s", "2021-07-27", "15", "60", "T0s", "2021-07-28", "15", 
                              "60", "T0s", "2021-07-29", "15", "60", "T0s", "2021-06-30", "30", 
                              "60", "T1s", "2021-07-01", " 8", "16", "T1s", "2021-07-05", "26", 
                              "52", "T1s", "2021-07-06", "30", "60", "T1s", "2021-07-07", "30", 
                              "60", "T1s", "2021-07-08", " 4", " 8", "T1s", "2021-07-12", " 4", 
                              " 8", "T1s", "2021-07-13", "29", "58", "T1s", "2021-07-14", "27", 
                              "54", "T1s", "2021-07-20", "30", "60", "T1s", "2021-07-21", "30", 
                              "60", "T1s", "2021-07-26", "30", "60", "T1s", "2021-07-27", "30", 
                              "60", "T1s", "2021-07-28", "30", "60", "T1s", "2021-08-02", "30", 
                              "60", "T1s", "2021-08-03", " 8", "16", "T1s", "2021-08-23", "12", 
                              "60", "T3s", "2021-08-24", "12", "60", "T3s", "2021-08-25", "12", 
                              "60", "T3s", "2021-08-26", " 2", "10", "T3s", "2021-08-30", "12", 
                              "60", "T3s", "2021-08-31", "12", "60", "T3s", "2021-09-01", "12", 
                              "60", "T3s", "2021-09-06", "12", "60", "T3s", "2021-09-07", "12", 
                              "60", "T3s", "2021-09-08", "12", "60", "T3s", "2021-09-13", "12", 
                              "60", "T3s", "2021-09-14", "12", "60", "T3s", "2021-09-15", "12", 
                              "60", "T3s", "2021-09-16", "12", "60", "T3s", "2021-09-20", "12", 
                              "60", "T3s", "2021-09-21", "12", "60", "T3s", "2021-09-22", "12", 
                              "60", "T3s", "2021-09-23", "12", "60", "T3s", "2021-09-27", "12", 
                              "60", "T3s", "2022-01-10", "15", "60", "T5s", "2022-01-11", "15", 
                              "60", "T5s", "2022-01-12", " 8", "32", "T5s", "2022-01-17", "15", 
                              "60", "T5s", "2022-01-18", "15", "60", "T5s", "2022-01-19", " 6", 
                              "24", "T5s", "2022-01-24", "15", "60", "T5s", "2022-01-25", "15", 
                              "60", "T5s", "2022-01-26", " 6", "24", "T5s", "2022-01-31", "15", 
                              "60", "T5s", "2022-02-01", "15", "60", "T5s", "2022-02-02", " 6", 
                              "24", "T5s", "2022-02-03", "12", "48", "T5s", "2022-02-07", "15", 
                              "60", "T5s", "2022-02-08", "15", "60", "T5s", "2022-02-09", " 6", 
                              "24", "T5s", "2022-02-10", "15", "60", "T5s", "2022-02-14", " 9", 
                              "36", "T5s"), .Dim = c(4L, 80L), .Dimnames = list(c("Var1", "Freq", 
                                                                                  "ficol", "visit"), NULL))
            df1 <- df %>%
              t() %>%
              as_tibble() %>%
              mutate(
                Var1 = ymd(Var1),
                Freq = as.integer(Freq),
                ficol = as.integer(ficol)) %>%
              rename(date = Var1) %>% 
              arrange(date)
            
            df2 <- df1 %>%
              filter(year(date) == 2021) # choose only 1 year
            df2
            #> # A tibble: 62 x 4
            #>    date        Freq ficol visit
            #>           
            #>  1 2021-06-15    15    60 T0s  
            #>  2 2021-06-16    15    60 T0s  
            #>  3 2021-06-17     8    32 T0s  
            #>  4 2021-06-21    15    60 T0s  
            #>  5 2021-06-22    15    60 T0s  
            #>  6 2021-06-23    15    60 T0s  
            #>  7 2021-06-24    15    60 T0s  
            #>  8 2021-06-28    15    60 T0s  
            #>  9 2021-06-29    15    60 T0s  
            #> 10 2021-06-30    15    60 T0s  
            #> # ... with 52 more rows
            
            # some days have many types of visits, so it's necessary to group them
            df3 <- df2 %>%
              group_by(date) %>%
              summarise(visits = str_c(sort(visit), collapse = ", "),
                        .groups = "drop")
            df3
            #> # A tibble: 48 x 2
            #>    date       visits  
            #>            
            #>  1 2021-06-15 T0s     
            #>  2 2021-06-16 T0s     
            #>  3 2021-06-17 T0s     
            #>  4 2021-06-21 T0s     
            #>  5 2021-06-22 T0s     
            #>  6 2021-06-23 T0s     
            #>  7 2021-06-24 T0s     
            #>  8 2021-06-28 T0s     
            #>  9 2021-06-29 T0s     
            #> 10 2021-06-30 T0s, T1s
            #> # ... with 38 more rows
            df3 %>%
              count(visits)
            #> # A tibble: 4 x 2
            #>   visits       n
            #>       
            #> 1 T0s         13
            #> 2 T0s, T1s    14
            #> 3 T1s          2
            #> 4 T3s         19
            
            df4 <- df3 %>%
              mutate(color = case_when(
                visits == "T0s" ~ "red",
                visits == "T0s, T1s" ~ "orange",
                visits == "T1s" ~ "yellow",
                visits == "T3s" ~ "green"
              )) %>%
              assertr::verify(!is.na(color)) %>%
              full_join(
                tibble(date = seq(as.Date("2021-01-01"), as.Date("2022-01-01") - 1, by = "days")),
                by = "date"
              ) %>%
              mutate(yday = lubridate::yday(date)) %>%
              arrange(date)
            df4 %>%
              filter(!is.na(visits))
            #> # A tibble: 48 x 4
            #>    date       visits   color   yday
            #>               
            #>  1 2021-06-15 T0s      red      166
            #>  2 2021-06-16 T0s      red      167
            #>  3 2021-06-17 T0s      red      168
            #>  4 2021-06-21 T0s      red      172
            #>  5 2021-06-22 T0s      red      173
            #>  6 2021-06-23 T0s      red      174
            #>  7 2021-06-24 T0s      red      175
            #>  8 2021-06-28 T0s      red      179
            #>  9 2021-06-29 T0s      red      180
            #> 10 2021-06-30 T0s, T1s orange   181
            #> # ... with 38 more rows
            
            calendR::calendR(year = 2021,
                             start = "M",
                             special.days = df4$visits,
                             special.col = unique(na.omit(df4$color)),
                             legend.pos = "right")
            

            Source https://stackoverflow.com/questions/67075027

            QUESTION

            How to get dates for every Friday between two dates?
            Asked 2019-Oct-24 at 05:19

            I currently use the following code to return an array of dates for every single day between two dates, including today's date and the last date itself. This works great.

            • However, how would I go about modifying what I'm already doing in order to do the same exact thing otherwise, but instead return an array of the date of every Friday between the dates? For example, if the function was called on Wed Oct 23rd 2019 to return every Friday until November 10th, the first date would be Fri the 25th, Nov 1st, and then Nov 8th.
            • How would I do the same thing as above but for the 1st of every month? If I called the function on Wed Oct 23rd 2019 to return the first of every month until December 16th. The array should have Nov 1st and Dec 1st in it.
            ...

            ANSWER

            Answered 2019-Oct-24 at 05:19

            You just need to add a weekday parameter to your method and check if the weekday of the date inside the loop before adding it to your array:

            Source https://stackoverflow.com/questions/58532307

            QUESTION

            VBA will no longer send appointment to outlook
            Asked 2019-Mar-06 at 09:13

            My program iterates through an excel table and inputs them as an appointment into an outlook calendrer titled "Test". It was working fine but now I get error 91 (Object variable or With block variable not set).

            This occurs where the venous aspects for the appointment are defined; subject, start, finish, body and save.

            I have rebooted since but that shouldn't have changed anything.

            I wondered if it was because my references reset but that also doesn't seem to be the issue.

            ...

            ANSWER

            Answered 2019-Mar-05 at 13:49

            You use OLAppointment everywhere, but it seems that this variable is not defined anywhere. You do however use objAppointment. I think you should change OLAppointment to objAppointment

            Source https://stackoverflow.com/questions/55002996

            QUESTION

            PHP Julian date converter algorithms
            Asked 2018-Sep-14 at 22:44

            Algorithms for the following:

            JD 1099114.5

            PHP: 3 Mar -1704 12:00:00 (PHP Internal convertor)

            ...

            ANSWER

            Answered 2017-Aug-15 at 11:26

            I did not look at the Fliegel-Van Flandern algorithm. I tested the remaining algorithm for the test cases Danny F requested, and added the last noon the Julian calendar was observed in Rome (JD 2299160) and the first noon of the Gregorian calendar in Rome (JD 2299161). For non-integer Julian days, I only used the Meeus algorithm since that's the only one that says it supports non-integers.

            The internal algorithm was correct, when you allow for considering year 0 to not exist, and it always converts to Gregorian. The Meeus algorithm is correct, when you allow for it assuming the existence of year 0, and converting to Julian for October 4, 1582 and earlier, and to Gregorian for dates after that.

            The Richards algorithm required corrections. Rather than using the floor function at certain points, I used the intdiv function in place of every "/" operator, which more closely follows Richard's description of the algorithm. After these corrections, the test cases were successful. (Richards considers the year 0 to exist and always converts to Gregorian.)

            Source https://stackoverflow.com/questions/45586444

            QUESTION

            Before 1 CE/AD Algorithms make calendar calculations tricky
            Asked 2018-Sep-09 at 22:04

            I did some more research the following is the output for the respective algorithms:

            JD 1099114.5

            PHP: 3 Mar 1704 B.C.E. 12:00:00 (PHP Internal convertor) FLN: 0 Mar 1703 B.C.E. 12:00:00 (Fliegel-Van Flandern) MEU: 18 Mar 1703 B.C.E 12:00:00 (Jean Meeus "Astronomical Algorithms, 2nd ed., corrected) RICH: 4 Mar 1703 B.C.E. 12:00:00 (Richards in Explanatory Supplement 3rd Ed.)

            Each Algorithm has its issues and quirks about starting times etc.

            Meeus assumes that there is a Gregorian year 0 (between -1 and 1), even if this is astronomically correct, it makes little sense from a calendrical perspective. Technically then all the results to convert into Gregorian dates is just wrong?

            ...

            ANSWER

            Answered 2017-Aug-08 at 12:46

            Meeus' Algorithm is actually in error (thank you Paul for pointing this out) there should be no 0 in Gregorian years, which means that all dates prior to Gregorian year 1 (i.e. Gyr < 0) are in error. Post Gyr (Gyr >= 1) are correctly converted. Also, he only has the convertor for dates post 1582G.

            It seems therefore that the correct date is that listed by the jdtogregorian converter supplied by PHP.

            Source https://stackoverflow.com/questions/45528669

            QUESTION

            Calculating Age from Birthday - TSQL, Oracle, and any others
            Asked 2018-Feb-14 at 12:55

            I frequently see people who assume that DATEDIFF(YEAR, date_of_birth, GETDATE()) will produce the current age of the person.

            Unfortunately this is not correct. The DATEDIFF function, at least in SQL Server, does not count the number of full years between two dates - it counts the number of calendrical boundaries crossed.

            That is, in the case of the YEAR parameter, DATEDIFF counts the number of 1-Januaries crossed. With the MONTH parameter, it would count the number of 1sts of the month crossed.

            So for example, a baby born on 31-Dec-17 would already be "1 years old", when in fact they do not turn 1 years old until 31-Dec-18, and they are currently 0 years old.

            The use of the DATEDIFF function in this way is equivalent to writing YEAR(GETDATE()) - YEAR(date_of_birth), which of course takes no account of where the person's birthday falls inside the year.

            Having reviewed a good sample of other questions here, there does not appear to be a definitive answer, and there are many answers that are quite wrong.

            So my question is, what is the simplest expression that, given a person's date of birth and a reference date, calculates the age of a person as of that reference date?

            I'm looking for an answer in the following terms:

            • The answer should be an inline expression - capable of being selected or incorporated into a where-clause.

            • The answer should be robust and have no erroneous corner cases - however infrequent or implausible those cases are. It should work for newborn babies and for persons that would be centuries old, should cope with leap years, and ideally should be capable of representing the period prior to birth as a minus number (with the person becoming -1 years old on the day before they were born).

            • The answer should be numerically precise - it should not rely on using an average number of days per year or dividing by magic numbers, and rounding off the error. I believe all trivial approaches which use rounding, have corner cases and are therefore not robust, but I stand to be corrected.

            • For those with birthdays falling on the 29-Feb, it should treat their age as incrementing on 29-Feb if the reference year is a leap year, or it should treat their age as incrementing on 1-Mar if the reference year is not a leap year.

            • The answer should disregard any time component of either the birthdate or the reference date - that is, the person should be assumed to have been born at midnight, and their age should increment at midnight on subsequent birthdays.

            I'm interested in an answer for SQL Server particularly, but would also be interested to see answers for any other database platform.

            EDIT: I appreciate the answers that have been given and the links to previous questions. This question has now been marked as a duplicate.

            What strikes me is that the accepted answer to the link given, is cluttered and begins with an incorrect implementation, and the comments on it refer to its implementation being incorrect - it was only after I read it carefully that I saw it had been updated with a correct implementation (sandwiched between a treatment of "decimal age" which is not related to my question). The third answer, which has also attracted a substantial number of up-votes, is also incorrect. There are also a myriad of other answers of varying quality.

            I've also asked for an answer that, ideally, correctly handles "negative ages" in some way (where the reference date is before the birth date), and the linked answers do not. Therefore, whilst my question treats the same subject, it is not a duplicate, as I've imposed several additional constraints that are not present in that question, and which would invalidate (in one way or another) all the answers given on that older question.

            To be honest, given how many subtly wrong answers abound (as I alluded to above in my first paragraph), I would have thought this question would get more upvotes and more interest, rather than a downvote and 3 votes to close.

            ...

            ANSWER

            Answered 2018-Feb-12 at 22:50

            QUESTION

            How to read comment text with SAX Java parser
            Asked 2017-Jan-11 at 19:31

            I want read the comment only for the object tag in my XML file using SAX parser in Java.

            This is an abstract of my file:

            ...

            ANSWER

            Answered 2017-Jan-08 at 23:33

            The javax.xml.parsers.SAXParser does not support reading comments. It ignores them.

            The org.xml.sax.ext.LexicalHandler allows you catching comments when parsing with org.xml.sax.XMLReader. See an example at another stackoverflow post or a tutorial at Oracle.

            If you want to connect a comment to an element, which comes right after it, you can additionally pass a org.xml.sax.ContentHandler to the parser and track other XML content by it. I adapted the code that referred to above to print only that object element, which is immediately preceded by a comment:

            Source https://stackoverflow.com/questions/41535757

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install CalendR

            CalendR is hosted on packagist, you can install it with composer. Create a composer.json file. Install composer and run it.

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