karen | open-source voice assistant | Chat library

by AlfredoSequeida Python Version: Current License: GPL-3.0

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | karen Summary

karen is a Python library typically used in Messaging, Chat applications. karen has no bugs, it has no vulnerabilities, it has build file available, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

Click here to see the video series for how Karen was made.

Support

Quality

Security

License

Reuse

Support

karen has a low active ecosystem.

It has 14 star(s) with 2 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

There are 1 open issues and 0 have been closed. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of karen is current.

Quality

karen has no bugs reported.

Security

karen has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

karen is licensed under the GPL-3.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

karen releases are not available. You will need to build from source code and install.

Build file is available. You can build the component from source.

Installation instructions are not available. Examples and code snippets are available.

Top functions reviewed by kandi - BETA

kandi has reviewed karen and discovered the below as its top functions. This is intended to give you an instant insight into karen implemented functionality, and help decide if they suit your requirements.

Runs the recognizer
Execute a command
Parse command arguments
Say voice output
Install an addon
Create the addon directory
Return installed python packages
Install required python packages
Load addon configuration files
Load config from file
Load all configuration files in addons directory
Append config to config file
Uninstall an addon
Uninstall required_packages
Uninstall a python package
Update an addon setting
Write config to file
Clone a github project
Check if github URL is valid
Check if karen is running
Get addon settings
Check the global config file
Add an upstream package to the config

Get all kandi verified functions for this library.

karen Key Features

No Key Features are available at this moment for karen.

karen Examples and Code Snippets

No Code Snippets are available at this moment for karen.

Community Discussions

Trending Discussions on karen

Combine values from duplicated rows into one based on condition (in R)

Move 2nd level sub-array to the top of the 1st level multidimentional array based on value of the sub-array

Shared folder permission anomaly with linux

How to fix Traceback module error in Python?

Delete rows with respect a time constraint

MySQL database re-orders entries automatically

Using the first row of a CSV as the keys in nested dictionaries?

How to group data based on conditional on datetimes (first record or last record) and count of events over time

How to count events over time and group by conditions based on datetimes with Dataframes in R

YAML format from JSON in Linux

QUESTION

Combine values from duplicated rows into one based on condition (in R)

Asked 2021-Jun-15 at 16:51

I have a dataset with the name of Danish ministers and their position from 1990 to 2020 (data comes from dataset called WhoGovern; https://politicscentre.nuffield.ox.ac.uk/whogov-dataset/). The dataset consists of the ministers name, the ministers position, the prestige of that position, and the year in which the minister had that given position.

My problem is that some ministers are counted twice in the same year (i.e., the rows aren't unique in terms of name and year). See the example in the picture below, where "Bertel Haarder" was both Minister of Health and Minister of Interior Affairs in 2010 and 2021.

I want to create a dataset, where all the rows are unique combinations of name and year. However, I do not want to remove any information from the dataset. Instead, I want to use the information in the prestige column to combine the duplicated rows into one. The observations with the highest prestige should be the main observations, where the other information should be added in a new column, e.g., position2 and prestige2. In the example with Bertel Haarder the data should look like this:

(PS: Sorry for bad presenting of the tables, but didn't know how to create a nice looking table...)

Here's the dataset for creating a reproducible example with observations from 2010-2020:

...

ANSWER

Answered 2021-Jun-08 at 14:04

Reshape the data to wide format twice, once for position and the other for prestige_1, and join the two results.

Source https://stackoverflow.com/questions/67888166

QUESTION

Move 2nd level sub-array to the top of the 1st level multidimentional array based on value of the sub-array

Asked 2021-Jun-14 at 21:35

I'm looping through a multidimensional array and am left with some values.

This is the complete PHP code.

...

ANSWER

Answered 2021-Jun-09 at 18:41

This will reorder $array2 (into a new variable $final). First it assembles a simple array $people of the names, then it reassembles $array2 by prioritizing based on the $people array. Was this what you wanted to accomplish?

Source https://stackoverflow.com/questions/67909656

QUESTION

Shared folder permission anomaly with linux

Asked 2021-Jun-09 at 09:43

So, i have this shared folder symbolically linked to 'shared'. The folder is associated to 2 user (bill and karen) who both has membership of 'bill-karen' group. Problem is, i can't seem to create a new file from both user unless I run a new shell with su - [USER]

This seems odd to me as the folder is owned by root:bill-karen while the permission for the folder is 2775 (-rwxrwsr-x). Is there any reason behind this? I'm using ubuntu 20.04 LTS anyway.

How i configured the shared folder: *Note that i already has user bill

...

ANSWER

Answered 2021-Jun-09 at 09:12

I have created the same setup as you did and could not reproduce your issue.

I ran the following as root in an empty ubuntu 20.04 docker container:

Source https://stackoverflow.com/questions/67900785

QUESTION

How to fix Traceback module error in Python?

Asked 2021-May-18 at 17:32

I am trying to making a python autogenerated Email app but there is a problem when running the code the traceback error shows up but I did write the code as my mentor write it down. This is the code that I used:

...

ANSWER

Answered 2021-May-18 at 03:10

Try and set the encoding to UTF-8

For example:

file = open(filename, encoding="utf8")

For reference check this post:

UnicodeDecodeError: 'charmap' codec can't decode byte X in position Y: character maps to

Source https://stackoverflow.com/questions/67579384

QUESTION

Delete rows with respect a time constraint

Asked 2021-May-08 at 13:22

I have the following dataset:

...

ANSWER

Answered 2021-May-08 at 13:22

Based on this answer you could try a recursive approach.

Source https://stackoverflow.com/questions/67440063

QUESTION

MySQL database re-orders entries automatically

Asked 2021-Apr-28 at 11:52

I have created a MySQL database using MySQL Workbench. In there, I have created a table, the first entries of which are:

...

ANSWER

Answered 2021-Apr-28 at 11:52

I don't want MySQL to re-order my entries. When I retrieve the entries from the database, I want them to appear exactly in the order that I have inserted them into the database.

SQL tables represent unordered (multi)sets. Period. When you query a table in any database, the ordering is not guaranteed unless you include an order by. This is even true in SQLite, as this DB fiddle demonstrates.

In most databases, if you want to capture the insertion order, then you need some sort of column that captures the ordering. There are two common methods:

An identity or auto_increment column that captures the insertion order.
A datetime/timestamp column that captures the date time. This does not always work, because there can be ties.

Then, when you query the table, you need to use order by on the column.

If your first column represents the ordering but happens to be stored as a string, then you can simply use:

Source https://stackoverflow.com/questions/67295752

QUESTION

Using the first row of a CSV as the keys in nested dictionaries?

Asked 2021-Apr-23 at 22:50

Please don't be brutal! I'm new to coding and have looked all over the web to find answers. I have a CSV with column one listing names, column 2 listing jobs, and column 3 listing birth months. I want the output I typed below the code. I have the dictionary made, but it is in this format: {"Karen Fisher": ("IT","November"), etc.} I want the keys of the nested dictionaries to be from the header of the csv so that people know what kind of data they are looking at about each person. I'm getting this error: "TypeError: 'tuple' object does not support item assignment"

...

ANSWER

Answered 2021-Apr-23 at 22:26

The csv.DictReader class will return you a dictionary. All you have to do is store the entries by key:

Source https://stackoverflow.com/questions/67237457

QUESTION

How to group data based on conditional on datetimes (first record or last record) and count of events over time

Asked 2021-Apr-21 at 21:02

I have been given two data frames:

Data frame A: Has the information of purchases in a clothing store with the variables: name of client, date of purchase, agent and product purchased during a period of time t.

NAME PRODUCT AGENT DATE_PURCHASE Karen M_14 X_1 8-25-20021 18:21:28 Jean M_78 X_3 8-26-20021 18:11:06 Jean M_71 X_4 8-26-20021 18:21:01 Jean M_64 X_4 8-27-20021 20:21:59 Keith M_57 X_4 8-27-20021 20:21:02 Alba M_50 X_1 8-28-20021 20:21:03 Alba M_43 X_3 8-29-20021 20:21:04 Alex M_36 X_2 8-25-20021 20:21:05

Data frame B: Has the information of clients who have called the CX SERVICE line of the company during a period of time t and stores the variables name of client, date of call, and type of call.

NAME TYPE DATE_OF_CALL DATE_PURCHASE Karen COMPLAIN 8-26-20021 18:21:28 8-25-20021 18:21:28 Jean CX_SERVICE 8-27-20021 18:11:06 8-26-20021 18:11:06 Jean COMPLAIN 8-28-20021 18:21:01 8-26-20021 18:21:01 Jean CX_SERVICE 8-29-20021 20:21:59 8-27-20021 20:21:59 Keith CX_SERVICE 8-29-20021 20:21:02 8-27-20021 20:21:02 Alba COMPLAIN 8-30-20021 20:21:03 8-28-20021 20:21:03 Alex CX_SERVICE 8-25-20021 21:21:05 8-29-20021 20:21:04

I have to build a table in which It will be shown by NAME what was the very last product purchased by the customer prior to their very last call to the customer service line and it should include the variables: NAME ,LAST_PRODUCT_PURCHASED, AGENT, DATE_PURCHASE, TYPE, DATE_OF_CALL that table should look something like this:

RESULTS

NAME LAST_PRODUCT_PURCHASED AGENT DATE_PURCHASE TYPE DATE_OF_CALL Karen M_14 X_1 8-25-20021 18:21:28 COMPLAIN 8-26-20021 18:21:28 Jean M_64 X_4 8-27-20021 20:21:59 CX_SERVICE 8-29-20021 20:21:59 Keith M_57 X_4 8-27-20021 20:21:02 CX_SERVICE 8-29-20021 20:21:02 Alba M_43 X_3 8-29-20021 20:21:04 COMPLAIN 8-30-20021 20:21:03 Alex M_36 X_2 8-25-20021 20:21:05 CX_SERVICE 8-25-20021 21:21:05

For example: The second raw shows the desired result as the very last product purchased by Jean was M-78 and her very last call on the line was a TYPE= CX_SERVICE with date 8-29-20021 20:21:59

I have been thinking about doing a group by NAME and DATES or perhaps a join but I can't seen to find a way to deal with the condition of "last" product and "last" date to call on the line

PD: What if we would try to add a column that counts how many time the custumer (NAME) has called prior to their most recent call on the line.

...

ANSWER

Answered 2021-Apr-09 at 03:54

This should do it, but there is definitely room for improvement:

Source https://stackoverflow.com/questions/67014728

QUESTION

How to count events over time and group by conditions based on datetimes with Dataframes in R

Asked 2021-Apr-21 at 21:01

I am being faced with the challenge of building a table by doing some data wrangling with two different datasets.

DataSet A: Has the information of purchases in a clothing store with the variables: name of client, date of purchase, agent and product purchased during a period of time t.

...

ANSWER

Answered 2021-Apr-21 at 21:01

I believe you might have made a mistake with the year, so I removed the extra zeroes in the year (2021). I see that you are using tibbles, hence I will provide a tidyverse method of solving this problem.

The idea of the provided code is to first handle the tibbles separately, and then join them by the common denominator NAME. This should do it:

Source https://stackoverflow.com/questions/67029097

QUESTION

YAML format from JSON in Linux

Asked 2021-Mar-31 at 22:23

I am looking easy ways to clean my json in linux.

Sample Input:

...

ANSWER

Answered 2021-Mar-31 at 22:09

You are only missing the additional flag --raw-output for jq. The command should look like

Source https://stackoverflow.com/questions/66894756

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install karen

You can download it from GitHub.
You can use karen like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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