Medusa | red team arsenal platform , which currently includes XSS | Security Testing library

 by   Ascotbe Python Version: v1.0.26 License: GPL-3.0

kandi X-RAY | Medusa Summary

kandi X-RAY | Medusa Summary

Medusa is a Python library typically used in Testing, Security Testing applications. Medusa has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has medium support. However Medusa build file is not available. You can download it from GitHub.

:cat2:Medusa is a red team arsenal platform, which currently includes XSS platform, collaborative platform, CVE monitoring, anti-virus generation, DNSLOG, phishing email, file acquisition and other functions, which are under continuous development
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              Medusa has a medium active ecosystem.
              It has 1838 star(s) with 329 fork(s). There are 44 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 0 open issues and 49 have been closed. On average issues are closed in 9 days. There are 4 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of Medusa is v1.0.26

            kandi-Quality Quality

              Medusa has 0 bugs and 0 code smells.

            kandi-Security Security

              Medusa has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Medusa code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Medusa is licensed under the GPL-3.0 License. This license is Strong Copyleft.
              Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

            kandi-Reuse Reuse

              Medusa releases are available to install and integrate.
              Medusa has no build file. You will be need to create the build yourself to build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              Medusa saves you 9673 person hours of effort in developing the same functionality from scratch.
              It has 19729 lines of code, 970 functions and 470 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Medusa
            Get all kandi verified functions for this library.

            Medusa Key Features

            No Key Features are available at this moment for Medusa.

            Medusa Examples and Code Snippets

            Contents,Using ,Aegis
            Cdot img1Lines of Code : 95dot img1License : Permissive (BSD-4-Clause)
            copy iconCopy
            import (
                "github.com/rafael-santiago/aegis/gopkg"
            )
            
            (...)
            replace github.com/rafael-santiago/aegis/gopkg => github.com/rafael-santiago/aegis/gopkg/v1
            (...)
            
            //
            // Copyright (c) 2020, Rafael Santiago
            // All rights reserved.
            //
            // This source c  
            Contents,Using ,Debugging mitigation
            Cdot img2Lines of Code : 69dot img2License : Permissive (BSD-4-Clause)
            copy iconCopy
            /*
             * Copyright (c) 2020, Rafael Santiago
             * All rights reserved.
             *
             * This source code is licensed under the BSD-style license found in the
             * LICENSE file in the root directory of this source tree.
             */
            #include 
            #include 
            #include 
            #include 
            #incl  
            登录注销
            Pythondot img3Lines of Code : 64dot img3License : Strong Copyleft (GPL-3.0)
            copy iconCopy
            from uuid import uuid4
            
            user_secret = models.UUIDField(default=uuid4())
            
            #!/usr/bin/env python
            # _*_ Coding: UTF-8 _*_
            
            
            def get_user_secret(user):
                return user.user_secret
            
            JWT_AUTH = {
                'JWT_GET_USER_SECRET_KEY': 'applications.User.views.get_  

            Community Discussions

            QUESTION

            Why do I get this error when I'm trying to create models from database?
            Asked 2021-May-05 at 06:07

            I'm trying to create models from my Oracle database 10g using Entity Framework Core 5 dbcontext scaffold:

            ...

            ANSWER

            Answered 2021-May-05 at 06:07

            The fine manual says minimum oracle 11.2 for that provider

            Upgrade your db or change provider

            Source https://stackoverflow.com/questions/67395767

            QUESTION

            Logback in a Java modular application not working
            Asked 2021-Apr-14 at 15:43

            I am just starting to master modular applications and I have a problem with the logback.

            Before modularity was introduced into the project, Logback successfully worked with the same settings.

            As soon as I start working with the LoggerContext and add the line requires ch.qos.logback.classic to the module-info.java, the application crashes.

            Crash occurs in the line receiving the logger:

            ...

            ANSWER

            Answered 2021-Apr-14 at 14:28

            QUESTION

            How to read file into class in C++?
            Asked 2021-Apr-12 at 17:05

            I am reading File that contains

            ...

            ANSWER

            Answered 2021-Apr-12 at 17:05

            This code reads your file and stores the data in the std::vector Info using stringstreams and other things to parse.

            Source https://stackoverflow.com/questions/67061682

            QUESTION

            Error when trying to retrieve from database
            Asked 2021-Feb-17 at 13:04

            I have generated three classes from XSD schema:

            ...

            ANSWER

            Answered 2021-Feb-17 at 12:50

            We are missing the medusa initialization code, but you should do something like this:

            Source https://stackoverflow.com/questions/66242165

            QUESTION

            Extract distinct portions of long string with varying punctuation using RegEx
            Asked 2021-Jan-26 at 20:49

            I have a text file with many rows that generally follow the patterns shown below and I'd like to extract the segments numbered 1-4 in the image below. I cannot do it with Excel because the punctuation is not sufficiently consistent so I'd like to use RegEx.

            I am looking for 4 distinct RegEx expressions, corresponding to the 4 items.

            What I have so far:

            • (.+?(?=/)) gets me everything up to the / but I can't figure out how to split it in the Yellow and Cyan sections
            • (?<=\/\s)(.*) gets me everything after the / but includes the Mintmark portion

            Here is a good sample of the file contents:

            ...

            ANSWER

            Answered 2021-Jan-26 at 20:49

            You could use a single pattern with 4 capturing groups.

            Source https://stackoverflow.com/questions/65877827

            QUESTION

            Format ansible output
            Asked 2021-Jan-05 at 15:19

            I have ansible role which checks the latest backups from my databases (cassandra and elasticsearch) so i have this output

            ...

            ANSWER

            Answered 2021-Jan-05 at 15:19

            If the output of the ansible-playbook other/check_backup_status.yml -i hosts/mvd/prod/hosts.yml command goes to the standard output, I can redirect that output to awk in the next way:

            Source https://stackoverflow.com/questions/65580456

            QUESTION

            INNER JOIN SQL query includes duplicates
            Asked 2020-Nov-21 at 19:22

            I have an online store and am trying to display five similar products on the product page. There is a many-to-many relationship between products and tags which I'm trying to query (join table) using INNER JOIN. Here is the SQL query I have thus far:

            ...

            ANSWER

            Answered 2020-Nov-21 at 18:30

            You can group by product and sort the results by the number of matched tags:

            Source https://stackoverflow.com/questions/64946563

            QUESTION

            d3.js multiple relationship visual / linkHorizontal() / tangled tree
            Asked 2020-Nov-05 at 03:58

            I am trying to mimic a visual that depicts multiple relationships by time period, like this (time period = generation):

            However, my efforts have not panned out thus far; I'm still getting blank output in the browser. Hard coded data and code in the snippet:

            ...

            ANSWER

            Answered 2020-Oct-22 at 09:30

            I think a lot of what you did, specifically around data wrangling, was not necessary, especially since you called d3.hierarchy() and d3.cluster() afterwards. I've replaced this with d3.stratify (which deals with hierarchical data that is not yet in the right format).

            I've also replaced d3.cluster with d3.tree() because it was unclear to me why you'd want to use d3.cluster here. Your data has multiple parents, multiple roots and even floating nodes, and d3 is not meant to deal with that. My workaround has been to attach pseudonodes to every level, so as to make sure that there is only one node and that all nodes are at the right level at all times. To make sure the links were drawn correctly, I've written a custom getLinks function, that can deal with multiple parents.

            I've also written a custom link generator that draws the links somewhat in the way that you want them. d3 doesn't offer much of flexibility here, but you can use the source code for inspiration.

            Edit

            I've changed the logic to be more focused on which "partners" got a child, so both links to the same child are on the same level - like in your picture. I've also drawn the nodes based on how many partners they have, and have given every link an offset so the lines are more distinct.

            I've sorted the nodes so that the real pro-creators are at the top (Zeus), which gives a more balanced and less crowded view.

            Source https://stackoverflow.com/questions/64423115

            QUESTION

            How to change property of element removed from array?
            Asked 2020-Jul-20 at 18:04

            this.statues.shift(); is isolating the correct element and removing it from the array. When this happens though, person.stoned needs to be false. Any pointers? Thank you.

            Code:

            ...

            ANSWER

            Answered 2020-Jul-18 at 22:14

            You need to save shifted object and set its property, like that:

            Source https://stackoverflow.com/questions/62974294

            QUESTION

            Find longest subsequence that contains letters with the same frequency in order
            Asked 2020-Jul-14 at 18:40

            This is a question from the 2019 Australian Informatics Olympiad Competition:

            After the success of your latest research project in mythical DNA, you have gained the attention of a most diabolical creature: Medusa. Medusa has snakes instead of hair. Each of her snakes’ DNA is represented by an uppercase string of letters. Each letter is one of S, N, A, K or E. Your extensive research shows that a snake’s venom level depends on its DNA. A snake has venom level x if its DNA:

            • has exactly 5x letters • begins with x copies of the letter S

            • then has x copies of the letter N

            • then has x copies of the letter A

            • then has x copies of the letter K

            • ends with x copies of the letter E.

            For example, a snake with venom level 1 has DNA SNAKE, while a snake that has venom level 3 has DNA SSSNNNAAAKKKEEE. If a snake’s DNA does not fit the format described above, it has a venom level of 0. Medusa would like your help making her snakes venomous, by deleting zero or more letters from their DNA. Given a snake’s DNA, can you work out the maximum venom level this snake could have?

            Is it possible using binary search to obtain an algorithm with complexity O(nlogn)?

            ...

            ANSWER

            Answered 2020-Jul-14 at 14:05

            Yes you can use binary search to search for maximum venom level.

            initially: l=0 r=n

            when for some m=(l+r+1)/2 we can check in O(n) time if we can obtain such venom level m, just by taking first m letters S then next m letters N and so on. If there's not enough letters we update our search interval to r=m-1 otherwise l=m

            Example: suppose input is SNAKESSSNNAAKKE

            1. Binary search initial values: l=0 r=15
            2. l=0 r=15 m = (l+r+1)/2 = 8
            3. we cant get venom value of 8 so r=m-1 = 7
            4. l=0 r=7 m = (l+r+1)/2 = 4
            5. we cant get venom value of 4 so r=m-1 = 3
            6. l=0 r=3 m = (l+r+1)/2 = 2
            7. we can get venom value of 2 so l=m = 2
            8. l=2 r=3 m = (l+r+1)/2 = 3
            9. we cant get venom value of 3 so r=m-1 = 2
            10. now since l==r we terminate binary search and conclude that answer is 2

            Source https://stackoverflow.com/questions/62893590

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Medusa

            You can download it from GitHub.
            You can use Medusa like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

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          • HTTPS

            https://github.com/Ascotbe/Medusa.git

          • CLI

            gh repo clone Ascotbe/Medusa

          • sshUrl

            git@github.com:Ascotbe/Medusa.git

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