ultrasound-nerve-segmentation | Kaggle Ultrasound Nerve Segmentation competition | Machine Learning library

It is most certain that the author of the original wanted to concatenate on the channels dimension, not one of the image dimensions.

The tensors in convolutional networks could be in one of the two formats:

The reason is the loss function:

The corresponding layers in Keras are Deconvolution2D layers.

It's worth to mention that you should be really careful with them because they sometimes might behave in unexpected way. I strongly advise you to read this Stack Overflow question (and its answer) before you start to use this layer.

UPDATE:

1. Deconvolution is a layer which was add relatively recently - and maybe this is the reason why people advise you to use Convolution2D * UpSampling2D.
2. Because it's relatively new - it may not work correctly in some cases. It also need some experience to use them properly.
3. In fact - from a mathematical point of view - every Deconvolution might be presented as a composition of Convolution2D and UpSampling2D - so maybe this is the reason why it was mentioned in texts you provided.

UPDATE 2:

Ok. I think I found an easy explaination why Deconvolution2D might be presented in a form of a composition of Convolution2D and UpSampling2D. We would use a definition that Deconvolution2D is a gradient of some convolution layer. Let's consider three most common cases:

1. The easiest one is a Convolutional2D without any pooling. In this case - as it's the linear operation - its gradient is a function itself - so Convolution2D.
2. The more tricky one is a gradient of Convolution2D with AveragePooling. So: (AveragePooling2D * Convolution2D)' = AveragePooling2D' * Convolution2D'. But a gradient of AveragePooling2D = UpSample2D * constant - so it's also in this case when the preposition is true.
3. The most tricky one is one with MaxPooling2D. In this case still (MaxPooling2D * Convolution2D)' = MaxPooling2D' * Convolution2D' But MaxPooling2D' != UpSample2D. But in this case one can easily find an easy Convolution2D which makes MaxPooling2D' = Convolution2D * UpSample2D (intuitively - a gradient of MaxPooling2D is a zero matrix with only one 1 on its diagonal. As Convolution2D might express a matrix operation - it may also represent the injection from a identity matrix to a MaxPooling2D gradient). So: (MaxPooling2D * Convolution2D)' = UpSampling2D * Convolution2D * Convolution2D = UpSampling2D * Convolution2D'.

The final remark is that all parts of the proof have shown that Deconvolution2D is a composition of UpSampling2D and Convolution2D instead of opposite. One can easily proof that every function of a form a composition of UpSampling2D and Convolution2D might be easily presented in a form of a composition of UpSampling2D and Convolution2D. So basically - the proof is done :)