murphy | License information can be found in LICENSE
kandi X-RAY | murphy Summary
kandi X-RAY | murphy Summary
License information can be found in LICENSE.txt. To get started, read docs/introduction.html. Some up to date information can be found at A quick introductory video can be found at This work has been partially funded by Tekes (
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Top functions reviewed by kandi - BETA
- Create custom scraper
- Finds an image matching the given criteria
- Find an image matching the given criteria
- Test if the image contains the given coordinates
- Execute a single verb
- Enter parentheses
- Press key
- Get a scancode table
- Merge the coverage from the source
- Find a window by title and class
- Save the graph to disk
- Encrypt the data
- Test for a matching image
- Check if image is in view
- Clone the graph
- Handle the protocol
- Set the key
- Create the project
- Returns the intersection of two rectangles
- Decrypt data
- Decrypts the given data using the encryption key
- Suggest a suggested identifier
- Performs action
- Create a new node
- Build the graph from the given model
- Save the current object to JSON
murphy Key Features
murphy Examples and Code Snippets
Community Discussions
Trending Discussions on murphy
QUESTION
I have Customer & Order models as below:
...ANSWER
Answered 2021-Jun-15 at 12:09You can try using values
to group by customer
, and then annotate
with the Sum
of value
:
QUESTION
i am calling two different service and getting difrent response. but i want to build one common table after arranging the response of both the service.
below is my service
...ANSWER
Answered 2021-Jun-04 at 08:21You can do it with combineLatest
.
QUESTION
I am trying to create an automated Python script that goes to a webpage like this, finds the link at the bottom of the body text (anchor text "here"), and downloads the PDF that loads after clicking said download link. I am able to retrieve the HTML from the original and find the download link, but I don't know how to get the link to the PDF from there. Any help would be much appreciated. Here's what I have so far:
...ANSWER
Answered 2021-Apr-20 at 20:42Looks for the a
element with the text here
then follows the trail.
QUESTION
Reading a CSV file. Now, For each row that I read from the file, I need to check if the name already exist in the list; if exist, then I need to skip that line, but add the date on the file to the date list (under class) of the object corresponding to that name. If doesn't exist, then this is the first time I'm seeing this person. and need to create new object in the dict, This is how it looks so far:
...ANSWER
Answered 2021-Apr-19 at 01:22So this is an option if you want a dict
keyed by name:
QUESTION
I have a program that is suppose to sort an input file (seq) and then output an RPT file.
This program code should be correct, the problem should only be in the sorting of this program.
PROBLEM: The program successfully sorts the data correctly, my problem is that I can not get the sort file to continue after being sorted to be formatted and do calculations.
PLEASE: show in code and explain, this is my first time trying the sort a file.
SEQ:
...ANSWER
Answered 2021-Apr-13 at 07:49In the PERFOM UNTIL...
loop, you are reading BASEBALL-FILE-OUT
, instead of the sorted BASEBALL-FILE-SORTED
.
QUESTION
I have a program that is suppose to sort an input file (seq) and then output an RPT file.
This program code should be correct, the problem should only be in the sorting of this program.
CURRENTLY: Program will not compile.
SORT: The output records need to sort LEAGUE-S (major) in descending order. TEAM-S (intermediate) ascending order. NAME-S (minor) ascending order.
PLEASE: show in code and explain, this is my first time trying the sort a file.
SEQ:
...ANSWER
Answered 2021-Apr-12 at 19:42ARE-THERE-MORE-RECORDS = 'NO'
is still true from its use in the input procedure. At the beginning of the output procedure, insert MOVE 'YES' TO ARE-THERE-MORE-RECORDS
. You also need to replace the READ BASEBALL-FILE-IN
with RETURN SORT-FILE
, add some fields to SORT-RECORD
, and use those fields for the report.
Why do you have BASEBALL-FILE-UNSORTED-IN
? It doesn't have any of the fields you need to move to SORT-RECORD
.
If you want to use BASEBALL-FILE-UNSORTED-IN
, then don't use an input procedure. Instead change the SORT
statement from INPUT PROCEDURE 120-SORT-INPUT-PROCEDURE
to USING BASEBALL-FILE-UNSORTED-IN
. Do not OPEN
or CLOSE
the file. That will be done by the runtime. Remove the 120-
and 130-
paragraphs.
Comment everything associated with BASEBALL-FILE-IN
, except 01 BASEBALL-RECORD-IN
and its data items. That effectively allows the BASEBALL-RECORD-IN
data definition to be used as a replacement for SORT-RECORD
. That reduces the number of changes that are needed.
QUESTION
I have a program that is suppose to sort an input file (seq) and they output an RPT file.
This program code should be correct, the problem should only be in the sorting of this program. Currently, it prints is weird chunks.
SORT: The output records need to sort LEAGUE-S (major) in descending order. TEAM-S (intermediate) ascending order. NAME-S (minor) ascending order.
SEQ:
...ANSWER
Answered 2021-Apr-12 at 17:57SORT
is not being used correctly. The report is being printed in 120-SORT-INPUT-PROCEDURE
using the fields from BASEBALL-RECORD-IN
. It should be printed in 130-SORT-OUTPUT-PROCEDURE
using the fields from SORT-RECORD
.
Furthermore, no records are sorted because there is no RELEASE
statement in the input procedure. To access records after the sort, a RETURN
statement is used in the same manner as a READ
statement for a sequential file.
The input procedure should be used to move the data from selected records to the sort record, after which the record is released to sort.
The output procedure may then used to produce a report from the sorted data by returning and printing each record until the there are no more sorted records.
QUESTION
Edit : As pointed out by Madlemon, the request JSON is incorrect.
I was working on a hobby project where I am trying to create a movie review site. I have the below model classes :
Movie.class
...ANSWER
Answered 2021-Mar-01 at 10:09"cast": [...],
...
"cast": null,
QUESTION
I have a list of names and a group assigned to them as dictated by the A, B, or C letters. What I want to do is return all members of group A.
I am using a regex to find all lines that end with A, I then need to print the names of those individuals, not including the group (A, B, C)
I am running into a few issues:
- The very last entry is in group A, however this is not the end of a line but end of file and is being ignored.
- Some records contain a space before the end of line indicator and are being passed over.
- I only want to print the name and not the group.
ANSWER
Answered 2021-Mar-01 at 03:19You can try:
QUESTION
Q: Print all the students with the top marks. If multiple students have the same mark, print both students.
Sample Output:
...ANSWER
Answered 2021-Feb-04 at 14:19Use a list to store the student names:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install murphy
You can use murphy like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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