henchman | repeated use utility functions for notebook demos
kandi X-RAY | henchman Summary
kandi X-RAY | henchman Summary
A collection of repeated use utility functions for notebook demos.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Fits the adjacency matrix
- Build the graph
- Make a list of edge indices
- Build a list of edges
- Profile data
- Print a title
- Print a summary of boolean column summary
- Produce a summary of column data
- Transform features into features
- Find the number of graphs in the Dendrogram
- Returns the list of features at the given step
henchman Key Features
henchman Examples and Code Snippets
Community Discussions
Trending Discussions on henchman
QUESTION
I am struggling with how to take user input in a child class and then pass values for health based on that user input of enemy type.
class Player:
...ANSWER
Answered 2021-Mar-28 at 14:28calling a field type is going to cause problems and self is missing from the enemyhealth method.
QUESTION
The Question is:
Being a henchman isn't all drudgery. Occasionally, when Commander Lambda is feeling generous, she'll hand out Lucky LAMBs (Lambda's All-purpose Money Bucks). Henchmen can use Lucky LAMBs to buy things like a second pair of socks, a pillow for their bunks, or even a third daily meal!
However, actually passing out LAMBs isn't easy. Each henchman squad has a strict seniority ranking which must be respected - or else the henchmen will revolt and you'll all get demoted back to minions again!
There are 4 key rules which you must follow in order to avoid a revolt:
- The most junior henchman (with the least seniority) gets exactly 1 LAMB. (There will always be at least 1 henchman on a team.)
- A henchman will revolt if the person who ranks immediately above them gets more than double the number of LAMBs they do.
- A henchman will revolt if the amount of LAMBs given to their next two subordinates combined is more than the number of LAMBs they get. (Note that the two most junior henchmen won't have two subordinates, so this rule doesn't apply to them. The 2nd most junior henchman would require at least as many LAMBs as the most junior henchman.)
- You can always find more henchmen to pay - the Commander has plenty of employees. If there are enough LAMBs left over such that another henchman could be added as the most senior while obeying the other rules, you must always add and pay that henchman.
Note that you may not be able to hand out all the LAMBs. A single LAMB cannot be subdivided. That is, all henchmen must get a positive integer number of LAMBs.
Write a function called solution(total_lambs), where total_lambs is the integer number of LAMBs in the handout you are trying to divide. It should return an integer which represents the difference between the minimum and maximum number of henchmen who can share the LAMBs (that is, being as generous as possible to those you pay and as stingy as possible, respectively) while still obeying all of the above rules to avoid a revolt. For instance, if you had 10 LAMBs and were as generous as possible, you could only pay 3 henchmen (1, 2, and 4 LAMBs, in order of ascending seniority), whereas if you were as stingy as possible, you could pay 4 henchmen (1, 1, 2, and 3 LAMBs). Therefore, solution(10) should return 4-3 = 1.
To keep things interesting, Commander Lambda varies the sizes of the Lucky LAMB payouts. You can expect total_lambs to always be a positive integer less than 1 billion (10 ^ 9).
My Code:
...ANSWER
Answered 2020-Nov-12 at 07:01It seems that when you're generous, you pay out 1, 2, 4, 8, 16 so that n henchman get 2**n - 1 units.
When you're stingy, you pay out 1, 1, 2, 3, 5, ... (can you say Fibonacci?), so that m henchmen get the sum of F(0), ..... F(m - 1) which is F(m + 1) - 1.
So you have to find the largest n such that 2 ** n - 1 <= lambs and the largest m such that F(m + 1) - 1 <= lambs.
This is a Google coding challenge, so you need to write the code yourself.
QUESTION
it("should know properties that are functions act like methods", function() {
var meglomaniac = {
mastermind : "Brain",
henchman: "Pinky",
battleCry: function(noOfBrains) {
return "They are " + this.henchman + " and the" +
Array(noOfBrains + 1).join(" " + this.mastermind);
}
};
var battleCry = meglomaniac.battleCry(4);
expect('They are Pinky and the Brain Brain Brain Brain').toMatch(battleCry);
});
ANSWER
Answered 2020-Mar-04 at 04:26battleCry(4) means that Array(noOfBrains + 1) will indeed have a length of 5:
QUESTION
I have the following script,
...ANSWER
Answered 2020-Feb-09 at 19:18Simple answer: The function guild.create_role() expects as discord.Permissions object for the parameter permissions, and you are passing a string.
Perhaps this will work:
QUESTION
Okay so I for the life of me haven't been able to figure out hot to make this snippet work. My thinking is that since we are working with level in levels we are already in the first dictionary so it should be level[second dictionary]
My current output is an error name not defined. What I am looking to do is to be able to print the name from each dictionary, the hoist value, etc. Ultimately it I will be querying these into statements. Such as print(level[colour]) should print the colour of the current level in a for statement or print(levels[Admin][colour]) should output the colour of admin.
...ANSWER
Answered 2020-Feb-07 at 18:40Your keys are all strings, so you need to wrap name with quotations.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install henchman
You can use henchman like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
