Django-Styleguide | Django styleguide used in HackSoft projects

by HackSoftware Python Version: Current License: MIT

X-Ray Key Features Code Snippets(1)Community Discussions(2)Vulnerabilities Install Support

kandi X-RAY | Django-Styleguide Summary

Django-Styleguide is a Python library. Django-Styleguide has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. However Django-Styleguide build file is not available. You can download it from GitHub.

The core of the Django Styleguide can be summarized as follows:. The general idea is to "separate concerns" so those concerns can be maintainable / testable.

Support

Quality

Security

License

Reuse

Support

Django-Styleguide has a medium active ecosystem.

It has 3671 star(s) with 381 fork(s). There are 104 watchers for this library.

It had no major release in the last 6 months.

There are 3 open issues and 68 have been closed. On average issues are closed in 280 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of Django-Styleguide is current.

Quality

Django-Styleguide has 0 bugs and 0 code smells.

Security

Django-Styleguide has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

Django-Styleguide code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

Django-Styleguide is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

Django-Styleguide releases are not available. You will need to build from source code and install.

Django-Styleguide has no build file. You will be need to create the build yourself to build the component from source.

Installation instructions are not available. Examples and code snippets are available.

Django-Styleguide saves you 70 person hours of effort in developing the same functionality from scratch.

It has 26 lines of code, 5 functions and 1 files.

It has low code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed Django-Styleguide and discovered the below as its top functions. This is intended to give you an instant insight into Django-Styleguide implemented functionality, and help decide if they suit your requirements.

Replace the contents of the README file .
Returns the new README . md file .
Return the contents of the README . md file .
Save the README . md file .
Main entry point .

Get all kandi verified functions for this library.

Django-Styleguide Key Features

No Key Features are available at this moment for Django-Styleguide.

Django-Styleguide Examples and Code Snippets

Contributing

Python

Lines of Code : 15

License : Strong Copyleft (GPL-3.0)

Copy

aecworks-api/
├── api
│   ├── aecworks   -> django project config (urls, settings, etc)
│   ├── common     -> shared resources (utils, exceptions, mixins, etc)
│   ├── community  -> Django App: Community Domain (Posts, Companies, Articles, E

Community Discussions

Trending Discussions on Django-Styleguide

DRF: UpdateAPI > 'int' object has no attribute 'save'

Joining Models in Python DRF Serializer without introducing Foreign key

QUESTION

DRF: UpdateAPI > 'int' object has no attribute 'save'

Asked 2021-Jul-05 at 13:37

I am trying to create an UpdateAPI to update my model. I need to comply with this API schema.

I have tried the following:

api.py

...

ANSWER

Answered 2021-Jul-05 at 13:37

The .update(…) method [Django-doc] returns the number of updated records, not (list of) a records, so you should omit the .save() part:

Source https://stackoverflow.com/questions/68257023

QUESTION

Joining Models in Python DRF Serializer without introducing Foreign key

Asked 2020-May-29 at 13:53

So I am relatively new to Django, and DRF. I recently started a project to learn more about the platform.

I also found best practice guide line which I am following at the moment. Here is the Django Style Guide

The guild line says that every App should completely decouple itself and use UUID instead of foreign key, And every business rule should go into services.py (Which I like btw.)

Here comes the problem. I am not sure how I can construct two models together to produce a nested JSON Output.

Ex: I have Post() model and Comments() model. and Comment model uses uuid of Post model as a referential id.

Now in my API.py, I am not sure how I can join these two together in the Serializer.py

FYI the code below is only for demo purposes, may not be executable

Model

...

ANSWER

Answered 2020-May-29 at 13:35

You could create one serializer called OutputSerializer and include the comments as its own field? if you change comments = OutputCommentSerializer to comments = CommentsSerializer(many=True, read_only=True) I believe that will depict what you want...(example below). You already defined CommentSerializer, thus you can use it.

Source https://stackoverflow.com/questions/62085736

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install Django-Styleguide

You can download it from GitHub.
You can use Django-Styleguide like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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