bilibili | 代码长大了，会帮up主做视频了 | Video Sharing library
kandi X-RAY | bilibili Summary
kandi X-RAY | bilibili Summary
代码长大了，会帮up主做视频了
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Top functions reviewed by kandi - BETA
- Convert notes to music format
- Calculate wave function
- Get the frequency of a note
- Convert a face
- Creates a Delaunay triangle
- Change a triangle list
- Find peaks in an array
- Compute the difference of a 1D array
- Compute the bounding box of a given mask
- Returns the area of a mask
- Get parse options
- Convert a video to an image2 image
- Find the closest point in src to dst
- Create a dataset from target image
- Convert video to audio
- Play a numpy array
- Check if paths are videos
- Downsample a signal
- Compute the energy of a signal
- Correct pitch correction
- Replace mosaic with given position
- Calculate the energy correction of an image
- Calculate the frequency features of a signal
- Read a score from a file
- Get video info
- Crop data
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QUESTION
I'm trying to store the JSON bytes to PostgreSQL, but there's a problem.
\u0000 cannot be converted to text.
As you can see below, the JSON contains escape sequences such as \u0000, which it seems PostgreSQL is interpreting as unicode characters, not JSON strings.
ANSWER
Answered 2021-Jul-08 at 16:05Well, I solved it by:
QUESTION
So I want to extract "bilibili-player-video-info-people-number" from this link: https://www.bilibili.com/video/BV1a44y167wK. When I create my beautifulsoup object and search it, this class is not there. Is it due to the parser? I did try lxml and html5lib but neither did any better.
...ANSWER
Answered 2021-Jun-13 at 07:24Almost the entire site is behind JavaScript so bs4 is useless, unless the element you want is in the requested HTML. In your case, it's not.
However, there's an API endpoint that you can query that carries this data (and much more).
With a bit of regex and requests you can get the online count (of viewers).
Here's how:
QUESTION
I put three arrays in an object, and I want to get each one of them to set the value, and I try Object.keys(obj).forEach(function(key){ to traverse it, it gets the value of an object, but I can not get the third level of the item.
And also, I try const iterate = (obj), it does not work well.
Whether the iterate function can get the item then set the value or use .forEach to get it.
...ANSWER
Answered 2020-Dec-10 at 19:34Object.keys(object) return an array of property names of the provided object and in your case it will return [iconArraya,iconArrayb,iconArrayc] if want to do it this way you'll have reference the object i.e for each value in the array you need to do this object[value] by the way this is called bracket notation you can search it if you're unfamiliar it the same using a dot like object.value
here's how ===
QUESTION
This code download deflated XML document https://api.bilibili.com/x/v1/dm/list.so?oid=162677333 and save it to temp.Z, which however seems broken. How is that?
ANSWER
Answered 2020-Jul-30 at 06:03It is something between deflate, zlib and gzip. I don't know. But I can decode it now.
Just use zlib, with inflateInit2(&strm, -MAX_WBITS) instead of inflateInit(&strm).
Yes, it is totally good. But why did I think it broken? Because my archive manager don't decode this! Anyway, I need to call zlib by my own. I have suggested the archive manager developers add this feature - which is useful, no?
QUESTION
I first tried:
...ANSWER
Answered 2020-Jul-24 at 17:51Problems with your command #2:
- Frame rate is too low. Most players are unable to play 1 fps. Use 10 fps or higher for output, or set input
-framerateto 10 fps or higher. - Chroma subsampling. Most players can only play 4:2:0, so use the format filter to force it to 4:2:0.
- MP3 in MP4. Some players are unable to play MP3 in MP4. For highest compatibility use AAC.
ffmpegwill choose AAC by default for MP4. - Faststart (optional). Add
-movflags +faststartso MP4 can begin playback faster.
Command:
QUESTION
I am new to web scraping and I am trying to scrape all the video links from each page of this specific site and writing that into a csv file. For starters I am trying to scrape the URLs from this site:
and going through all 19 pages. The problem I'm encountering is that the same 20 video links are being written 19 times(because I'm trying to go through all 19 pages), instead of having (around) 19 distinct sets of URLs.
...ANSWER
Answered 2020-Jun-04 at 03:16Try
QUESTION
I can download the first episode of a series.
...ANSWER
Answered 2020-Mar-06 at 20:17This error occurs because youtube-dl ignores URI parameters after ? for the filename, so the next file it tries to download has the same name with the previous one and it fails because a file already exists with that name. The solution is to use the --output template filesystem option to set a filename which it'll have an index in its name using the variable i.
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