hypothesis | use library for property-based testing | Testing library
kandi X-RAY | hypothesis Summary
kandi X-RAY | hypothesis Summary
Hypothesis is a powerful, flexible, and easy to use library for property-based testing.
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Top functions reviewed by kandi - BETA
- Return a pandas DataFrame containing a subset of rows
- Check if argument is a SearchStrategy
- Return a sequence of elements and dtype
- Warns a deprecation warning
- Construct a search strategy
- Return a floating point value
- Run a function in a process
- Identify that the FTZ module is imported
- Create a search strategy for complex numbers
- Specify a search strategy
- Normalize a test function
- Define function signature
- Create a ndarray from a dtype
- Generate a searchStrategy for a given shape
- Define a function signature
- Generates a test magic string
- Runs all the examples in the pareto front
- Updates the changelog and version information
- Create a search strategy for integer indices
- Return an example
- Shrink the buffer
- Construct a search strategy for a given shape
- Reduce the lexical blocks
- Execute only once
- Creates a searchStrategy for mutually - broadcastable shapes
- Draw a numpy array
- Performs random selection
- Convert an object into a list
hypothesis Key Features
hypothesis Examples and Code Snippets
def heapnew():
return []
def heapempty(heap):
return not heap
def heappush(heap, value):
heap.append(value)
index = len(heap) - 1
while index > 0:
parent = (index - 1) // 2
if heap[parent] > heap[index]:
class TestData:
def draw_bytes(self, n):
...
class SearchStrategy:
def do_draw(self, data):
raise NotImplementedError()
class Int64Strategy:
def do_draw(self, data):
return int.from_bytes(data.draw_bytes(8), byte
from hypothesis import given
from hypothesis.strategies import floats
@given(floats(), floats())
def test_floats_are_commutative(x, y):
assert x + y == y + x
python -m pytest test_floats.py
@given(floats(), floats())
def test_floats_a
def edit_distance(hypothesis, truth, normalize=True, name="edit_distance"):
"""Computes the Levenshtein distance between sequences.
This operation takes variable-length sequences (`hypothesis` and `truth`),
each provided as a `SparseTensor`, a
private static void test(final Integer[] preorder, final Integer[] inorder) {
System.out.println("\n====================================================");
System.out.println("Naive Solution...");
BinaryTree root = new BinaryT
def _hypothesis_value(data_input_tuple):
"""
Calculates hypothesis function value for a given input
:param data_input_tuple: Input tuple of a particular example
:return: Value of hypothesis function at that point.
Note that there
Community Discussions
Trending Discussions on hypothesis
QUESTION
I would like to know whether there is a recommended way of measuring execution time in Tensorflow Federated. To be more specific, if one would like to extract the execution time for each client in a certain round, e.g., for each client involved in a FedAvg round, saving the time stamp before the local training starts and the time stamp just before sending back the updates, what is the best (or just correct) strategy to do this? Furthermore, since the clients' code run in parallel, are such a time stamps untruthful (especially considering the hypothesis that different clients may be using differently sized models for local training)?
To be very practical, using tf.timestamp()
at the beginning and at the end of @tf.function
client_update(model, dataset, server_message, client_optimizer)
-- this is probably a simplified signature -- and then subtracting such time stamps is appropriate?
I have the feeling that this is not the right way to do this given that clients run in parallel on the same machine.
Thanks to anyone can help me on that.
...ANSWER
Answered 2021-Jun-15 at 12:01There are multiple potential places to measure execution time, first might be defining very specifically what is the intended measurement.
Measuring the training time of each client as proposed is a great way to get a sense of the variability among clients. This could help identify whether rounds frequently have stragglers. Using
tf.timestamp()
at the beginning and end of theclient_update
function seems reasonable. The question correctly notes that this happens in parallel, summing all of these times would be akin to CPU time.Measuring the time it takes to complete all client training in a round would generally be the maximum of the values above. This might not be true when simulating FL in TFF, as TFF maybe decided to run some number of clients sequentially due to system resources constraints. In practice all of these clients would run in parallel.
Measuring the time it takes to complete a full round (the maximum time it takes to run a client, plus the time it takes for the server to update) could be done by moving the
tf.timestamp
calls to the outer training loop. This would be wrapping the call totrainer.next()
in the snippet on https://www.tensorflow.org/federated. This would be most similar to elapsed real time (wall clock time).
QUESTION
Using Aids2
dataset from package MASS
, I am applying Ansari-Bradley Non-Parametric Test to test Group Independency by this snippets
ANSWER
Answered 2021-Jun-13 at 04:26Since object like "QuadTypeIndependenceTest"
and "ScalarIndependenceTest"
are created from the results of coin
packages, there is specific function to extract the pvalue, using coin::pvalue(obj)
, Special thanks for pointing @AntoniosK
QUESTION
I have a form with multiple form fields organized in rows and columns and a delete row button at the end of each row. When the user enter a value in on the form fields if the press the Enter/Return key, instead of "entering" the value, it delete the row, as if the focus of the user was on the delete button and he'd pressed enter.
Here's a screen shot of the form:
Here is the html code for this part of the application:
...ANSWER
Answered 2021-Jun-11 at 17:23Buttons inside forms are by default submit
in Angular unless you specify otherwise. Pressing enter in a field fires a submit event. So your removeHypothesis
is considered a submit function and thus it is fired on enter press.
Make the button type="button"
and it will no longer be considered as a submit button:
QUESTION
So, I'm pretty sure this should be possible without choice. Maybe I am wrong.
Here is a minimal reproducible example of what I'm trying to do:
...ANSWER
Answered 2021-Jun-11 at 09:25In the two links you mention, the problem is the segregation enforced by Coq between propositions (those types of type Prop
) and other types (those with type Set
or Type
), with the idea being that proofs should not be needed for programs to run. However, in your case both set M
and subset M
are propositions, so this separation is not a problem: as you saw when defining fn0
, Coq is perfectly happy to use the first component of your existential type to build the function you are looking for. This is a good point of constructive mathematics: modulo the separation between Prop
and Type
, choice is simply true!
Rather, the problem comes from the second part of the proof, i.e. the proof of equality of functions. It is a subtle issue of Coq that equality of functions is not extensional, that is the following axiom cannot, in general, be proven
QUESTION
This is a follow-up question from this thread.
As per advised from the thread, the possible cause for why my Python code is not working is because I was to connect to a remote server in WSL2. And there could be unknown issues with WSL2 Ubuntu.
So I am testing that hypothesis with the following two approaches of communicating within WLS2 Ubuntu locally (i.e. via localhost:9092
):
Note that, for both approaches below, I already have zookeeper running in one terminal (T1
) with:
ANSWER
Answered 2021-Jun-09 at 22:12produce the message through a command ... I surprisingly receive it in the consumer terminal T7
No surprise here since you've not called producer.flush()
or producer.close()
in your Python producer app after starting the consumer loop.
The console producer blocks on every record by calling get() on the future - source, effectively flushing its buffer
Alternatively, you are missing the matching option for --from-beginning
in the Python consumer if you wanted to see the previously sent records
Ultimately, testing a local client/server within the same network adapter/subnet isn't going to help resolve an external network connection
QUESTION
I was trying to write my first ultra-simple numpy testcase, but the first thing I thought of seems to hit a roadblock.
So I did this:
...ANSWER
Answered 2021-May-25 at 13:18Hypothesis is showing you that Numpy datatypes have distinct byte orders. Expanding your test,
QUESTION
If my understanding is correct, both np.sum
and np.cumsum
will take O(n)
time. However, when I do both operations to the same matrix sequentially (on different axis), it seems the sequence of np.sum
and np.cumsum
makes the overall performance quite different, though the result is the same as expected.
If I do the np.cumsum
along column direction (axis=1
) for each row first, and then do np.sum
for all the rows (axis=0
), it will take longer time.
If I do the np.sum
along rows (axis=0
) first, then do np.cumsum
for the one dimension array, it will take shorter time.
My hypothesis is that the np.cumsum
will take more time on the data allocation/manipulation since it will yield more data than np.sum
, so it will take longer time if there are more operations of np.cumsum
.
Here is my testing code and result
...ANSWER
Answered 2021-Jun-02 at 21:55If my understanding is correct, both np.sum and np.cumsum will take O(n) time.
Correct (assuming the input is the same)!
it seems the sequence of np.sum and np.cumsum makes the overall performance quite different
np.cumsum
is more expensive than np.sum
on the same input since np.cumsum
needs to allocate and write an output array (which can be pretty big). Moreover, assuming floating-point operations are associative, the implementation of np.sum
can be easily optimized while it is quite hard to optimize np.cumsum
.
My hypothesis is that the np.cumsum will take more time on the data allocation/manipulation since it will yield more data than np.sum, so it will take longer time if there are more operations of np.cumsum.
The thing is that the first implementation have much more work to do than the second. This is mainly why it is slower, especially because of the memory reads/writes. Indeed, np.cumsum
produces a big 2D array in the first implementation that must be computed by np.sum
. Writing and reading this temporary array is expensive. In the example, the first implementation require to move 14.9 GiB from/to the memory hierarchy (likely in RAM) just for the temporary array. Note that building a temporary array also make the computation less cache-friendly as it requires more space and thus b
and c
may not both fit in the cache any more (b
and c
takes 8 MiB each on my machine and my CPU have a L3 cache of 9 MiB which mean that not both can fit in the cache) as opposed to the second implementation. The throughput of the RAM is often much smaller than the one of the CPU caches.
Note that the second implementation also produces temporary arrays. This version should allocate as much temporary arrays as the first one. However, the second implementation produces temporary arrays that are 1000 time smaller! Thus, the call to np.cumsum
is much faster in this version. On my machine, b
is mostly stored in the fast L3 cache and temporary arrays in the very fast L1 cache.
QUESTION
This is my first time using R, and I have a question regarding the output of t.test in R.
I am running the t.test function and getting an output like this:
...ANSWER
Answered 2021-Jun-01 at 02:19The t.test() function creates a list, which can be accessed like other lists:
QUESTION
Is there exist a way to manipulate C function some how
for eg - we know C printf() function return Number of character printed to the console.
So is there any way that i can get number of character but not letting printf() function print to console. using same printf() from stdio.h
I know return
is the last statement to get executed in a function hence what i am asking may be impossible but i do want to hear from the community i.e is my hypothesis i.e manipulating c function is possible or not?
ANSWER
Answered 2021-May-29 at 03:13If you have access to the source code and you're able to recompile it with your changes, then sure, you can do it. Consider this:
QUESTION
I have a schema where I'm trying to generate a nanoid to show on the front end. (The default MongoDB ObjectID is too long to display to users.)
What I've done is to insert it into my schema as a default value that generates a new string each time an instance of the model is created.
These are the instructions provided by the nanoid docs for dealing with Mongoose
...ANSWER
Answered 2021-May-28 at 04:06problem here was there was no logic to save when duplicate skip was false.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install hypothesis
You can use hypothesis like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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