psh | Process management library
kandi X-RAY | psh Summary
kandi X-RAY | psh Summary
Process management library
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Top functions reviewed by kandi - BETA
- Return the status of the worker
- Ensure that the process is terminated
- Return stderr
- Returns the raw stderr as a string
- Returns the stdout of the process
- Return the output of the command
psh Key Features
psh Examples and Code Snippets
Community Discussions
Trending Discussions on psh
QUESTION
I am trying to deploy a docker container via Kubernetes. In my DockerFile, I specify this (neuro:
...ANSWER
Answered 2021-May-02 at 01:03it's a Linux users management issue in your Dockerfile, Dockerfiles are interpreted line by line in the build process (layer per layer) in your case you have set the "neurostar" as a current user in the third line and you want to change the default user directories access permissions.
This should work for you :
QUESTION
I'm learning arctangent implementation in TMS320C55x this is the source code:
...ANSWER
Answered 2021-Apr-27 at 06:10I do not follow the assembly code, but I could guess where those magic coefficients come from.
The code comments suggest C1
, C3
, C5
are coefficients of a polynomial approximation, and arctan
is an odd function, so its Taylor expansion around 0
has indeed only odd powers of x
. Comparing C1 = 32617
to 1
in the Taylor expansion y = x - 1/3 x^3 + 1/5 x^5 - 1/7 x^7 + ...
, and given the computational context, this further suggests that the result of the calculation is scaled by 2^15 = 32768
.
It turns out that y = (32617 x - 9464 x^3 + 2596 x^5) / 32768
is in fact a pretty good approximation of arctan(x)
over the interval [-1, 1]
. As shown below (verified in wolfram alpha) the largest absolute error of the approximation is less than 1/1000
, and is negligible at the endpoints x = ±1
corresponding to y = ±π/4
, which is probably desirable in graphics calculations.
As to how the coefficients were actually derived, a crude polynomial best-fit using just 9 control points gives a polynomial y = 32613 x - 9443 x^3 + 2573 x^5
with coefficients already close to the ones used in the posted code. More control points and/or additional conditions to minimize the error at the end points would result in slightly different coefficients, but it's hard to guess how to exactly match the ones in the code without any documentation or clues about the optimization criteria being actually used there.
QUESTION
**Background **
- I am working on a code for making combos in a fighting game
- I need to take a range, then convert certain numbers and/or letters into other Numbers/and/or letters with additional characters/spacing so the program registers the combo.
Right now I have some code that gets the job done but I don't believe this is the "right" nor efficient way to do this since In all there will be about 40 "switches" to be set up:
...ANSWER
Answered 2021-Apr-24 at 05:27I believe your goal as follows.
- You want to reduce the process cost of your script.
- In your situation, you want to replace the texts with about 40 patterns.
- I think that the variables of
const 1A =
,const 2B =
and so on cannot be used. Please be careful this. - About
4D.replaceAllWith('xy's replacement');
, in this case,xy's replacement
is not enclosed. Please be careful this. - About
2B..replaceAllWith('2 B');
,..
is not correct. - In order to reduce the process cost of your script, in this answer, I would like to propose to use Sheets API. When the Sheets API is used, replacing the texts with about 40 patterns can be done by one API call. By this, I thought that the process cost will be able to be reduced.
When above points are reflected to your script, it becomes as follows.
Modified script:Before you use this script, please enable Sheets API at Advanced Google services.
QUESTION
For context, I am bringing up Kafka and Zookeeper locally on an Ubuntu machine using Kubernetes, through Helm:
...ANSWER
Answered 2021-Feb-01 at 18:06I have this working now. It appears to be because I repeatedly brought the cluster down and up and didn't properly clear the networking state, which probably led to some sort of black-holing somewhere.
It may be overkill, but what I ended up doing was simply flushing the iptables
rules and restarting all relevant services like docker
which required special iptables
rules. Now that the cluster is working, I don't envision repeatedly re-creating the cluster.
QUESTION
I have been working on an assembler in java for my VM and i dont know why this is happening because the string that is provided is a 1. I have tried trimming it and it is still throwing this error. Everything i found wont help with this issue the error is on line 117 where i set tmpa please help!
asm.java
ANSWER
Answered 2021-Jan-08 at 16:09When your code is ran on "hlt" line and examined substring contains an "l" letter which is not a digit, so the Integer.ParseInt cannot convert an "l" letter to an integer.
QUESTION
We have an old multiplayer game (no source code) which crashes any time someone sends the server unexpected packets, and many of the players use telnet to do it with ease. I'm using iptables, and I want to filter out packets (and drop the connection) that the game server will not recognize. I want to do the following to the game server's port:
Pseudocode
...ANSWER
Answered 2021-Jan-07 at 09:13I figured it out. I did it with the rules below (not all the rules), and it works wonderfully. I suppose I could have used the iptables length option, but I didn't need it. Anyone deciding to do this should make it specific to a port, and understand their program's tcp messaging protocol first, or else you may get locked out.
QUESTION
I am developing my first C project without any tutorial and I am making a VM because why not? It's an easy first project for people that know hardware and stuff(me). But for some reasons my non observant eyes can't tell why this is outputting nothing at all
(The "hello world" statement is written in hex and the SETCY is setting the amount of cycles the program runs):
main.c
ANSWER
Answered 2020-Nov-16 at 17:50You set int cycles = 0;
and never modify it. Then for(int i=0;i
will exit immediately because when i == 0
and cycles == 0
, the condition i < cycles
is false, so the loop won't execute at all.
As a side note: the stack int stack[] = {0};
contains one element, so all operations that push values to it will fail.
QUESTION
Testing out staged roll out of could auth with PSH & SSO
Current setup: I have a 3rd party Federated domain (Onelogin), Password Hash enabled & SSO disabled
Onelogin is only used as an Identity provider not used for anthing else, woud like to migrate from that to an Azure Password Hash / Passthrough currely weighing up the two: Would like to have MFA, self serving password reset and contional access setup via Azure P1, reading up this might be better with Pass Through, unless i have read wrong?
As part of staged rollout would like to enable Seemliess SSO, was wondering if I enable Seamless SSO on my domain via powershell ( Enable-AzureADSSOForest -OnPremCredentials $creds) would this cause any disruption / issues with the current federation method?
there is no current SSO with OneLogin
...ANSWER
Answered 2020-Oct-19 at 12:50I understand you were in the process of staged rollout. staged rollout doesn't switch domains from federated to managed. You still need to make the final cutover from federated to cloud authentication by using Azure AD Connect or PowerShell.
You can enable seamless SSO and it is triggered only for users who are selected for staged rollout and it won't affect your existing federation setup. Kindly go through the below documents to get a detailed information.
link1 and link2. If you have any further quires kindly let me know.
QUESTION
I am working on a high-performance TCP server, and I see the server not processing fast enough on and off when I pump high traffic using a TCP client. Upon close inspection, I see spikes in "delta time" on the TCP server. And, I see the server sending an ACK and 0.8 seconds later sending PSH,ACK for the same seqno. I am seeing this pattern multiple times in the pcap. Can experts comment on why the server is sending an ACK followed by a PSH,ACK with a delay in between?
...ANSWER
Answered 2020-Oct-09 at 23:36To simplify what ACK
and PSH
means
ACK
will always be present, it simply informs the client what was the last received byte by the server.PSH
tells the client/server to push the bytes to the application layer (the bytes forms a full message).
The usual scenario you are used to, is more or less the following:
- The OS has a buffer where it stores received data from the client.
- As soon as a packet is received, it is added to the buffer.
- The application calls the socket receive method and takes the data out of the buffer
- The application writes back data into the socket (response)
- the OS sends a packet with flags
PSH,ACK
Now imagine those scenarios:
step 4 does not happen (application does not write back any data, or takes too long to write it)
=> OS acknowledge the reception with just an
ACK
(the packet will not have any data in it), if the application decides later on to send something, it will be sent withPSH,ACK
.the message/data sent by the server is too big to fit in one packet:
- the first packets will not have
PSH
flag, and will only have theACK
flag - the the last packet will have the flags
PSH,ACK
, to inform the end of the message.
- the first packets will not have
QUESTION
First of all I apologize for my lousy explanation, I really wanted to turn the thousands and hundreds of the DataFrame into tens as the stock price data was wrong on the csv. Finally I have managed to solve it in the Close column thanks to the response of @Vincent, although I think that it is still not the most orthodox and clean way. Thank you very much for responding.
...ANSWER
Answered 2020-Sep-10 at 16:03Do you just want to modify the value of some of your data inside your file? I am no expert in CSV but from what I remember you are just manipulating a list of list isn't it?
So if your intent is to have 9.43 inside you last column instead of 943, i.e to divide all the results of you last column by 100 you could still try this I suppose:
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