upass | Console UI for pass.

by Kwpolska Python Version: 0.3.0 License: BSD-3-Clause

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | upass Summary

upass is a Python library. upass has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install upass' or download it from GitHub, PyPI.

upass. Console UI for pass.

Support

Quality

Security

License

Reuse

Support

upass has a low active ecosystem.

It has 135 star(s) with 17 fork(s). There are 9 watchers for this library.

It had no major release in the last 12 months.

There are 7 open issues and 18 have been closed. On average issues are closed in 86 days. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of upass is 0.3.0

Quality

upass has 0 bugs and 2 code smells.

Security

upass has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

upass code analysis shows 0 unresolved vulnerabilities.

There are 1 security hotspots that need review.

License

upass is licensed under the BSD-3-Clause License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

upass releases are available to install and integrate.

Deployable package is available in PyPI.

Build file is available. You can build the component from source.

Installation instructions, examples and code snippets are available.

upass saves you 189 person hours of effort in developing the same functionality from scratch.

It has 467 lines of code, 31 functions and 5 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed upass and discovered the below as its top functions. This is intended to give you an instant insight into upass implemented functionality, and help decide if they suit your requirements.

Register a new password
Recursively recurse through all subdirectory
Clears the home directory
Generate a password
Set up the header of upass
Handles keyboard events
Show search results
Adds the password buttons to the box
Display help
Load directory
Load the named dispatch
Creates the directory buttons
Launch search
Commit to makepkg
Copy selected password
Perform a pass pass on the current object
Return the selected password
Display the selected password
Refresh the dispatch

Get all kandi verified functions for this library.

upass Key Features

No Key Features are available at this moment for upass.

upass Examples and Code Snippets

No Code Snippets are available at this moment for upass.

Community Discussions

Trending Discussions on upass

Should I use == for string comparison?

Leaking information because of URL injection in php

Why is mb_convert_encoding returning false?

How to accept two parameter in inbuilt constructor function in javascript

Unknown POST Content-Length exceeds limit

having trouble display the name from my database

pots API [object object ] in react native

Splash Screen Not Working in Android 4.4.4

How to call a PHP function from a different page?

How to add user to Linux via Python script?

QUESTION

Should I use == for string comparison?

Asked 2021-May-11 at 19:34

sorry if this is a weird question.

I was actually curious about timing attacks, so I have done a little research and understood the concept. I understood that, code like:

...

ANSWER

Answered 2021-May-11 at 15:21

Semi-helpful answer: Im not sure about the internal implementation of ==, but as a general rule: as more operations are happening to tell apart if the two values are equal, as more vulnerable the method is to timing attacks. So in your example the equal method does among other stuff "take character by character from both values, then compare", which under-the-hood for sure expanses to way more operations than just "take two memory locations and tell if X bytes from there on are equal" (which i guess == is more or less doing). The "take out character X" is expensive here (i guess).

I think you just prove that it is not vulnerable ^^

Source https://stackoverflow.com/questions/67489572

QUESTION

Leaking information because of URL injection in php

Asked 2021-Mar-02 at 20:15

This code leaks information from the login page when a route that does not exist is being tried to navigate at.

...

ANSWER

Answered 2021-Mar-02 at 20:15

Yes, it's easily avoided by sanitizing your input. Structures such as this

Source https://stackoverflow.com/questions/66431960

QUESTION

Why is mb_convert_encoding returning false?

Asked 2020-Oct-22 at 03:05

Here is my code:

...

ANSWER

Answered 2020-Oct-16 at 04:48

According to PHP Manual

"auto" is expanded to "ASCII,JIS,UTF-8,EUC-JP,SJIS"

But in my case it did not work correctly. If I try the following code instead of 'auto' I get the expected result:

Source https://stackoverflow.com/questions/64382627

QUESTION

How to accept two parameter in inbuilt constructor function in javascript

Asked 2020-Jul-09 at 10:45

here i have my this code

...

ANSWER

Answered 2020-Jul-09 at 10:40

I would like code like this

Source https://stackoverflow.com/questions/62812899

QUESTION

Unknown POST Content-Length exceeds limit

Asked 2020-Jun-25 at 12:53

Warning: Unknown: POST Content-Length of 49 bytes exceeds the limit of 40 bytes in Unknown on line 0

Warning: Cannot modify header information - headers already sent in Unknown on line 0

...

ANSWER

Answered 2020-Jun-25 at 12:45

Update your value on the php.ini file from post_max_size=40 to a bigger value. 40m for example.

and restart your apache after the change is done.

Source https://stackoverflow.com/questions/62575437

QUESTION

having trouble display the name from my database

Asked 2020-Apr-16 at 10:42

I want to print the user name after logging in with his ID in another JFrame

I followed this method but it does not work

...

ANSWER

Answered 2020-Apr-12 at 06:23

From your error message it is clear that your query is returning resultset that contains 0 rows and 1 column. I assume that you want to compare column m_pass to returned value of JAVA function getuserName() (Or you might want to compare with user password).

You can try following:

Update your query code to this:

Source https://stackoverflow.com/questions/61151359

QUESTION

pots API [object object ] in react native

Asked 2020-Apr-15 at 10:21

I had a problem sending data to the server. when I try to submit data via postman successfully with the response below and if I activate 'Content-Type': 'application / json'

i have a problem that is JSON Parse error: Unrecognized token '<'

...

ANSWER

Answered 2020-Apr-15 at 10:21

The server probably a 404 or 500 error. Instead of response.json() use response.text() you will get the html in text.

I assume Your server is not taking JSON formatted body

Try using below code.

Option 1:

Source https://stackoverflow.com/questions/61211893

QUESTION

Splash Screen Not Working in Android 4.4.4

Asked 2020-Mar-23 at 13:50

Hi I try to create a splash screen but it's not working and also the login screen isn't working!! I test it in android 4.4.4

1.MainActivity.class

...

ANSWER

Answered 2020-Mar-23 at 13:50

You should check login activity's xml layout.

For example bottom's Login Button

Source https://stackoverflow.com/questions/60813309

QUESTION

How to call a PHP function from a different page?

Asked 2020-Mar-18 at 07:38

This is the USER class with the register and send_mail functions. The send_mail function doesn't work. I've followed other questions that were similar, but it doesn't work for me. Maybe someone can spot a mistake I've made, thanks.

...

ANSWER

Answered 2020-Mar-18 at 07:38

From what I can see you are trying to call the send_mail method of the USER class as a regular function.

Source https://stackoverflow.com/questions/60734334

QUESTION

How to add user to Linux via Python script?

Asked 2020-Mar-13 at 02:17

I've been trying to run Linux terminal commands via a Python script, and I can't seem to do anything with what I've found so far.

This is what I've done so far:

...

ANSWER

Answered 2017-Mar-20 at 04:15

One of the very dirty solution is to run

Source https://stackoverflow.com/questions/42895671

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install upass

There are also AUR packages available.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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