Encoder | Alphanumeric Encoder

 by   Leoid Python Version: Current License: No License

kandi X-RAY | Encoder Summary

kandi X-RAY | Encoder Summary

Encoder is a Python library. Encoder has no bugs, it has no vulnerabilities and it has low support. However Encoder build file is not available. You can download it from GitHub.

python encoder [4bytes shellcode].
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            kandi-support Support

              Encoder has a low active ecosystem.
              It has 26 star(s) with 8 fork(s). There are 5 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              Encoder has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Encoder is current.

            kandi-Quality Quality

              Encoder has 0 bugs and 0 code smells.

            kandi-Security Security

              Encoder has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Encoder code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Encoder does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              Encoder releases are not available. You will need to build from source code and install.
              Encoder has no build file. You will be need to create the build yourself to build the component from source.
              Encoder saves you 22 person hours of effort in developing the same functionality from scratch.
              It has 62 lines of code, 3 functions and 1 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed Encoder and discovered the below as its top functions. This is intended to give you an instant insight into Encoder implemented functionality, and help decide if they suit your requirements.
            • generate random string
            • Format a list of integers
            • Generate block
            Get all kandi verified functions for this library.

            Encoder Key Features

            No Key Features are available at this moment for Encoder.

            Encoder Examples and Code Snippets

            No Code Snippets are available at this moment for Encoder.

            Community Discussions

            QUESTION

            Preserve unicode of emojis in python
            Asked 2021-Jun-15 at 17:52

            I'm dealing with emojis Unicode and wanna save images with its corresponding Unicode like 1F636_200D_1F32B_FE0F for https://emojipedia.org/face-in-clouds/.

            But for https://emojipedia.org/keycap-digit-one/ the files end up 1_FE0F_20E3 and I need them to be 0031_FE0F_20E3 is there a way to tell the encoder to not parse the 1?

            ...

            ANSWER

            Answered 2021-Jun-15 at 17:52

            The unicode_escape codec displays the ASCII characters as characters, and only non-ASCII characters as escape codes. If you want all to be escape codes, you have to format yourself:

            Source https://stackoverflow.com/questions/67962228

            QUESTION

            .Net Core Entity Framework Email Confirmation 'Click Here' link does not update 'EmailConfirmed' DB property
            Asked 2021-Jun-15 at 11:59

            I have setup SendGrid for my user registration email confirmation in my .Net 5.0 app as per Microsofts instructions here: http://go.microsoft.com/fwlink/?LinkID=532713

            Everything works fine until the user clicks the confirmation link in their register confirmation email.

            This issue is being caused by a stray amp in my confirmation link. I am trying to understand where it is coming from and how to remove it.

            When the new user clicks 'Submit' on the Register.cshtml page they are successfully directed to the RegisterConfirmation.cshtml page and the email is received in their inbox.

            Actual behavior:

            The user clicks the link in the email and hits the ConfirmEmail page.

            The user is redirected to /Index page.

            The EmailConfirmed bool in the DB is not updated.

            If I comment out the redirect to /Index in my controller, then I get a null value error shown below.

            ...

            ANSWER

            Answered 2021-Jun-14 at 06:18

            it looks like the variable that has value is amp;code; not code. Do you have 2 ampersands somewhere by any chance? Yes you do -

            Source https://stackoverflow.com/questions/67961503

            QUESTION

            Firebase Firestore: Encoder from custom structs not working
            Asked 2021-Jun-15 at 11:48

            So I created a function in which I try to create a document in my Firestore in which user data is stored. But when upgrading my project to the Xcode 13.0 beta, the Firebase encoder has stopped working. Anyone else experiencing a similar problem?

            My model looks like this:

            ...

            ANSWER

            Answered 2021-Jun-15 at 11:48

            So I ran into a similar issue with Codables... I've made this little extension that's saved me. Maybe it works for you too :)

            Source https://stackoverflow.com/questions/67985449

            QUESTION

            JPA throws java.lang.StackOverflowError with bidirectional @OneToMany
            Asked 2021-Jun-15 at 06:17

            I have two entity classes as follows. The Parachute is the parent object and it has multiple Component objects. I need to have bidirectional @OneToMany implemented here.

            Parent Parachute.java class.

            ...

            ANSWER

            Answered 2021-Jun-15 at 06:17

            You are violating the JPA spec by accessing the persistence context in a lifecycle listener.

            See the JPA Specification 4.2 Section 3.5.2

            In general, the lifecycle method of a portable application should not invoke EntityManager or query operations, access other entity instances, or modify relationships within the same persistence context. A lifecycle callback method may modify the non-relationship state of the entity on which it is invoked.

            "a portable application should not" is the specification way of saying: Don't do that, anything might happen. Maybe the world ends.

            The fix is not to do that. Maybe be preloading the currently logged in user and reference it so you may access it in your entity listener and do not set a reference to the user, but simple store its id or similar.

            Source https://stackoverflow.com/questions/67971795

            QUESTION

            I can't pass parameters to foreach loop while implementing Structured Streaming + Kafka in Spark SQL
            Asked 2021-Jun-15 at 04:42

            I followed the instructions at Structured Streaming + Kafka and built a program that receives data streams sent from kafka as input, when I receive the data stream I want to pass it to SparkSession variable to do some query work with Spark SQL, so I extend the ForeachWriter class again as follows:

            ...

            ANSWER

            Answered 2021-Jun-15 at 04:42

            do some query work with Spark SQL

            You wouldn't use a ForEachWriter for that

            Source https://stackoverflow.com/questions/67972167

            QUESTION

            How to remove the title from yellowbrick ROCAUC
            Asked 2021-Jun-14 at 23:49

            I am using yellowbrick to plot the AUCROC. I want to remove the title from the plot, to make it empty without the plot title.

            ...

            ANSWER

            Answered 2021-Jun-14 at 23:49

            yellowbrick documentation How can I change the title of a Yellowbrick plot?

            If I use single space in title=" " then I get plot without title.
            It doesn't work with empty string title="".

            Minimal working example

            Source https://stackoverflow.com/questions/67977409

            QUESTION

            What does Tensorflow LSTM return?
            Asked 2021-Jun-14 at 14:38

            I'm writing a German->English translator using an encoder/decoder pattern, where the encoder connects to the decoder by passing the state output of its last LSTM layer as the input state of the decoder's LSTM.

            I'm stuck, though, because I don't know how to interpret the output of the encoder's LSTM. A small example:

            ...

            ANSWER

            Answered 2021-Jun-14 at 14:38

            An LSTM cell in Keras gives you three outputs:

            • an output state o_t (1st output)
            • a hidden state h_t (2nd output)
            • a cell state c_t (3rd output)

            and you can see an LSTM cell here:

            The output state is generally passed to any upper layers, but not to any layers to the right. You would use this state when predicting your final output.

            The cell state is information that is transported from previous LSTM cells to the current LSTM cell. When it arrives in the LSTM cell, the cell decides whether information from the cell state should be deleted, i.e. we will "forget" some states. This is done by a forget gate: This gate takes the current features x_t as an input and the hidden state from the previous cell h_{t-1}. It outputs a vector of probabilities that we multiply with the last cell state c_{t-1}. After determining what information we want to forget, we update the cell state with the input gate. This gate takes the current features x_t as an input and the hidden state from the previous cell h_{t-1} and produces an input which is added to the last cell state (from which we have already forgotten information). This sum is the new cell state c_t. To get the new hidden state, we combine the cell state with a hidden state vector, which is again a vector of probabilities that determines which information from the cell state should be kept and which should be discarded.

            As you have correctly interpreted, the first tensor is the output of all hidden states.

            The second tensor is the hidden output, i.e. $h_t$, which acts as the short-term memory of the neural network The third tensor is the cell output, i.e. $c_t$, which acts as the long-term memory of the neural network

            In the keras-documentation it is written that

            Source https://stackoverflow.com/questions/67970519

            QUESTION

            Bcrypt password encoding doesnt matches the input password in springBoot?
            Asked 2021-Jun-14 at 02:36

            I am using springsecurity bcrypt password encoder for encoding my password this is how I am saving my password

            ...

            ANSWER

            Answered 2021-Jun-14 at 02:36

            You are passing the parameters in the incorrect format to boolean matches = passwordEncoder.matches(encodedPassword, user.getPassword());

            The documentation says:

            boolean matches​(java.lang.CharSequence rawPassword, java.lang.String encodedPassword)

            The first parameter must be the raw password, not the encoded one.

            It should be:

            Source https://stackoverflow.com/questions/67963967

            QUESTION

            connecting to SignalR hub with basic authentication
            Asked 2021-Jun-14 at 00:14

            Hi I am trying to create chat app using xamarin app, .net core api and signalR.
            I need to get id of curent user inside of SignalR chatHub.
            I tried to get HttpContext by using IHttpContextAccessor but SignalR doesn't support it.
            I tried to get HttpContext by Context.GetHttpContext() but it only returns empty Context
            (as far as i understand to get current HttpContext with Context.GetHttpContext() project either has to be website or i need to place [Authentication] on my ChatHub )

            I am using basic authentication on my project and i don't know how to pass user credentials to SignalR hub

            Here is code from Xamarin project ChatViewModel which i use to create new connection to Signalr hub(connection without authentication part works fine)
            I don't know how to get curent users email and password instead of "email@hotmail.com" and "123"

            ...

            ANSWER

            Answered 2021-Jun-14 at 00:14
            _hubConnection = new HubConnectionBuilder()
                                //.WithUrl($"{APIService._apiUrl}/chatt")
                                .WithUrl(con, options=> options.Headers.Add("Authorization",$"Basic{credential}"))
                                .Build();
            

            Source https://stackoverflow.com/questions/67962974

            QUESTION

            'MultiOutputClassifier' object is not iterable when creating a Pipeline (Python)
            Asked 2021-Jun-13 at 13:58

            I want to create a pipeline that continues encoding, scaling then the xgboost classifier for multilabel problem. The code block;

            ...

            ANSWER

            Answered 2021-Jun-13 at 13:57

            Two things: first, you need to pass the transformers or the estimators themselves to the pipeline, not the result of fitting/transforming them (that would give the resultant arrays to the pipeline not the transformers, and it'd fail). Pipeline itself will be fitting/transforming. Second, since you have specific transformations to the specific columns, ColumnTransformer is needed.

            Putting these together:

            Source https://stackoverflow.com/questions/67958609

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Encoder

            You can download it from GitHub.
            You can use Encoder like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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