Survival-analysis | survival analysis , predictive maintenance | Machine Learning library

 by   LongxingTan Python Version: Current License: MIT

kandi X-RAY | Survival-analysis Summary

kandi X-RAY | Survival-analysis Summary

Survival-analysis is a Python library typically used in Artificial Intelligence, Machine Learning, Pytorch applications. Survival-analysis has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can download it from GitHub.

Application of survival analysis, predictive maintenance, churn analysis, remaining useful life prediction
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              Survival-analysis has a low active ecosystem.
              It has 9 star(s) with 4 fork(s). There are 1 watchers for this library.
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              It had no major release in the last 6 months.
              Survival-analysis has no issues reported. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of Survival-analysis is current.

            kandi-Quality Quality

              Survival-analysis has no bugs reported.

            kandi-Security Security

              Survival-analysis has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Survival-analysis is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

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              Survival-analysis releases are not available. You will need to build from source code and install.
              Build file is available. You can build the component from source.

            Top functions reviewed by kandi - BETA

            kandi has reviewed Survival-analysis and discovered the below as its top functions. This is intended to give you an instant insight into Survival-analysis implemented functionality, and help decide if they suit your requirements.
            • Preprocessing data
            • Calculates the timesibull prediction .
            • Evaluate an ERI .
            • Calculates the ERI .
            • Predict the prediction for the given interval .
            • Load production data .
            • Builds a function that returns a tensorflow estimator .
            • Connects the model .
            • Builds a tf . input .
            • Calculates the Kaplan -meier distribution .
            Get all kandi verified functions for this library.

            Survival-analysis Key Features

            No Key Features are available at this moment for Survival-analysis.

            Survival-analysis Examples and Code Snippets

            No Code Snippets are available at this moment for Survival-analysis.

            Community Discussions

            QUESTION

            `data` must be a data frame, or other object coercible by `fortify()`, not an S3 object with class ranger
            Asked 2021-May-20 at 11:37

            I am working with R. Using a tutorial, I was able to create a statistical model and produce visual plots for some of the outputs:

            ...

            ANSWER

            Answered 2021-May-20 at 01:23

            As per the ggplot2 documentation, you need to provide a data.frame() or object that can be converted (coerced) to a data.frame(). In this case, if you want to reproduce the plot above in ggplot2, you will need to manually set up the data frame yourself.

            Below is an example of how you could set up the data to display the plot in ggplot2.

            Data Frame

            First we create a data.frame() with the variables that we want to plot. The easiest way to do this is to just group them all in as separate columns. Note that I have used the as.numeric() function to first coerce the predicted values to a vector, because they were previously a data.table row, and if you don't convert them they are maintained as rows.

            Source https://stackoverflow.com/questions/67559175

            QUESTION

            R: Plotting "staircases" using ggplot2/plotly
            Asked 2020-Dec-25 at 23:39

            I am using the R programming language. I am trying to follow this tutorial over here: https://rviews.rstudio.com/2017/09/25/survival-analysis-with-r/ (bottom of the page).

            I have slightly modified the code for this tutorial and have plotted the "staircases" (i.e. "survival functions", in the below picture "red", "blue", "green") corresponding to 3 of the observations in the data:

            ...

            ANSWER

            Answered 2020-Dec-25 at 23:39

            The issue is that when you draw a plot in base graphics draw directly on a device. The line of your code grob= plot(r_fit$unique.death.times, pred[1,], type = "l", col = "red") creates a NULL object (unlike ggplot which would return a plot object).

            You can make the plot directly in ggplot (there are a few ways of doing this but I've done a simple example bolow) and convert it with ggplotly:

            Source https://stackoverflow.com/questions/65446162

            QUESTION

            R: Tibble vs ggplot2 (plotting graphs)
            Asked 2020-Nov-27 at 21:20

            I am trying to follow a tutorial in R (https://rviews.rstudio.com/2017/09/25/survival-analysis-with-r/).The computer I am using for work does not have a USB port or internet connection - it only has R with a few libraries installed. My work computer has "survival, ranger, ggplot2 and dplyr". However, it does not have "ggfortify". I am trying to figure out how to plot the graphs from the tutorial without 'ggfortify'. Here is the code I am using below:

            ...

            ANSWER

            Answered 2020-Nov-27 at 21:20

            You are going to have to do some detective work!

            I have time for part #2 today. So: It turns out, that the information about the strata is contained in the element km_trt_fit$strata. It looks like this:

            Source https://stackoverflow.com/questions/65042472

            QUESTION

            R: plotting graphs (ggplot vs autoplot)
            Asked 2020-Nov-27 at 09:28

            I am following a R tutorial over here https://rviews.rstudio.com/2017/09/25/survival-analysis-with-r/

            The computer I use for work does not have internet access nor a USB port - it only has R with some preinstalled libraries. The tutorial requires "survival", "ggplot2", "ranger", "dplyr" and "ggfortify". The computer I use for work has all of these libraries EXCEPT ggfortfiy. Apparently, a function called "autoplot" is required from the ggfortify library to make some of the plots in this tutorial.

            When I try to run the code from the tutorial:

            ...

            ANSWER

            Answered 2020-Nov-27 at 09:28

            Yes, this is possible, because the autoplot function uses ggplot2 under the hood:

            Source https://stackoverflow.com/questions/65033260

            QUESTION

            Making sense of gbm survival prediction model
            Asked 2020-Oct-11 at 23:45

            I am a newbie in using and making sense of ML methods and currently doing survival analysis using gbm package in R.

            I have difficulty understanding some of the output of the survival prediction model. I have checked this tutorial and this post but still, find trouble in making sense of the outputted survival prediction model.

            Here is my code for analysis based on example data:

            ...

            ANSWER

            Answered 2020-Oct-09 at 05:00

            Amer. Thx for your reading of my tutorial!

            As you mentioned that "The output returned from the predict function represents the f(x) component of the hazard function ( h(t|x)=lambda(t)*exp(f(x)) )", maybe we need to understand the hazard function, i.e. h(t|x).

            Before this, please sure that you have the basic knowledge of survival analysis. if not, it's recommended to read the great post. I think the post would help you solve the questions.

            Back to your questions:

            • Exactly, we can get the hazard ratios of log scale by invoking the predict function. Therefore, the hazard ratio can be calculated by exp() .
            • Sure! Relying on the values of hazard ratio, we can divide the population into low-risk and high-risk groups. Alternatively, you can use the median of hazard ratios as the cutoff value. I think the cutoff value should be derived from the training set, and then test in the test set. If your model is effective, KM plots for low and high-risk groups would have a significant difference (measured by log-rank test statistically).
            • Calibration curve plots are often used to evaluated the performance of model that outputs probabilities or likelihoods ranged from [0.0, 1.0]. We can calculate the survival function, and then specify a time point of interest, e.g. 5-Year. At last, we compare the survival probabilities with the actual survival state at the specified time, which is just the same as we do evaluating a binary classification model. More details of obtaining survival function can refer to my tutorial, and the principles can be found in that post aforementioned.

            Source https://stackoverflow.com/questions/64237951

            QUESTION

            SyntaxError: invalid syntax - %pylab
            Asked 2020-Apr-16 at 18:26

            Unfortunately I am not a programmer and I am encountering the error:

            ...

            ANSWER

            Answered 2020-Apr-16 at 18:26

            You should run the program in Jupyter, or at least IPython. The % is IPython-specific syntax, and pylab is an IPython magic command for using matplotlib. Also note the file extension: .ipynb is a Jupyter notebook (formerly called IPython notebook), while a Python file would have a .py extension.

            Source https://stackoverflow.com/questions/61256889

            QUESTION

            How to integrate this function to estimate a nomogram score in Shiny?
            Asked 2020-Mar-31 at 12:48

            I just recently started to learn shiny.

            Overview of this question: (1) How it works in R incl. script, (2) How it should work in Shiny, (3) Data

            Question: where to write the shiny input$ID in this function to make it calculate the nomogram/nom-score based on the UI-inputs?

            (1) How it works in R incl. script

            I am performing survival-analysis, and I have produced a rather simple nomogram using the rms-package. The nomogram can be found below and is stored in nom.

            The nomogram currently looks like this:

            The nomogram is based on some input covariates from my datasheet p ( which too is attached below [just as a sample]).

            ...

            ANSWER

            Answered 2020-Mar-31 at 12:48

            Here is something to start from.

            You will need to provide output for your score and score group somewhere. As a quick example, I used verbatimTextOutput. However, you can provide text output, a table, or plot here.

            In your server you can have a reactive expression to calculate the score based on the input values provided. As each input changes, your scores should change. A second function would calculate group based on score. You can use cut instead of multiple if/then.

            Source https://stackoverflow.com/questions/60947537

            QUESTION

            How to extract summary() to a data frame applicable for data visualization in ggplot()?
            Asked 2020-Mar-31 at 09:20

            I am doing survival-analysis with the presence of competing risks. I use the prodlim-package, which I find quite useful. However, I do not like the build-in graphics, and would like to apply ggplot instead.

            Question: how can I extract the prodlim summary()-output and load it into a data frame accessible to ggplot2?

            Perhaps a function can be written to do this? I have previously received help on StackOverflow in terms of loading a summary()-output into a dataframe, but with a different package than prodlim.

            ...

            ANSWER

            Answered 2020-Mar-30 at 19:08

            You can access the resulting list up to the level where the table for the plot is found and save it as a data.frame. You can check the structure of the list by using str.

            Source https://stackoverflow.com/questions/60937226

            QUESTION

            Appropriate censoring and truncation for customer survival analysis
            Asked 2019-Aug-30 at 01:36

            I am working on a regular customer survival analysis problem. Here I analyze customers who signed up between 2008-1-1 & 2018-1-1. Customers can register anytime during this interval and exit anytime during or after the cut-off date of 2018-1-1.

            A sample data is shown below. First column is an identifier, second column is their status as of 2018-1-1: '1 for canceled & 0 for not-cancelled'. Third column is the number of weeks between their registration date & 2008-1-1. Last column is the number of weeks between their cancellation date and 2008-1-1 (if cancelled before 2018-1-1) or number of weeks between 2008-1-1 and 2018-1-1 (if not cancelled or cancelled after 2018-1-1).

            dput() to generate the above dataset

            ...

            ANSWER

            Answered 2019-Aug-30 at 01:36

            After a bit of extra research and consulting with experts, I could sort out the issue.

            My data is indeed left truncated (as customers can sign up anytime during the 10 year time period ) and right censored (some customers are still active as on 2018-1-1 and cancel anytime any time afterwards). Below corrections helped me to fix the issue.

            1. I need to calculate the 'stopTime' as the difference between Registration date & Cancellation date (in case if cancelled before 2018-1-1) or 2018-1-1 (if not cancelled or cancelled after 2018-1-1).
            2. Cancelled status should be the status as of 2018-1-1.
            3. Code to create the survival object should be modified as below

            Source https://stackoverflow.com/questions/57687267

            QUESTION

            Overlay different ggplot2 objects
            Asked 2018-Jul-23 at 11:34

            I have previously tried to ask for help but did not actually solve my problem. More info can be found here: (you can find the data-set here) https://stackoverflow.com/questions/51442502/survival-analysis-combining-survfit-and-ggplot-objects

            Unfortunately I am unable to produce a solid example to post as my code is heavily based on external programs. I am positive though that my question can be answered regardless.

            I reach a point where I create 2 ggplot2 objects that need to be combined to a single figure, one overlayed on top of the other.

            Namely, one km.plot which is of class:

            class(km.plot$plot)
            1 "gg" "ggplot"

            and two:

            class(surv.plot)
            1 "gg" "ggplot"

            Both share same attributes

            km.plot$plot

            surv.plot

            My question is how can I combine the resulting plots in a single plot? That is, to have both surv.plot and km.plot$plot overlayed over each other.

            Following another user's suggestion of doing the following results in an error:

            ...

            ANSWER

            Answered 2018-Jul-23 at 11:34

            This happens because the surv.plot layer contains mappings for a variable called label which is not included in the data for km.plot. You should be able to get around this by adding your surv.plot data as an argument to the geom rather than ggplot() when you create surv.plot. This way the data needed to draw the layer will "travel with" it.

            We can illustrate this with simpler data. Let's first create a plot from data with only a few columns:

            Source https://stackoverflow.com/questions/51477338

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Survival-analysis

            You can download it from GitHub.
            You can use Survival-analysis like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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