Anna | fetch images of magic cards | Chat library

by Oliv95 Python Version: Current License: GPL-2.0

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | Anna Summary

Anna is a Python library typically used in Messaging, Chat applications. Anna has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. However Anna build file is not available. You can download it from GitHub.

Bot for Discord that can fetch images of magic cards, among other things.

Support

Quality

Security

License

Reuse

Support

Anna has a low active ecosystem.

It has 1 star(s) with 1 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

There are 3 open issues and 3 have been closed. On average issues are closed in 22 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of Anna is current.

Quality

Anna has 0 bugs and 0 code smells.

Security

Anna has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

Anna code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

Anna is licensed under the GPL-2.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

Anna releases are not available. You will need to build from source code and install.

Anna has no build file. You will be need to create the build yourself to build the component from source.

It has 320 lines of code, 29 functions and 4 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed Anna and discovered the below as its top functions. This is intended to give you an instant insight into Anna implemented functionality, and help decide if they suit your requirements.

The main function .
Remove all admins
remove nick
Get a list of image urls .
Fetch card .
Return the other side of a card .
Format a card string .
Remove double quotes from a message .
Check if a card URL is a double face .

Get all kandi verified functions for this library.

Anna Key Features

No Key Features are available at this moment for Anna.

Anna Examples and Code Snippets

No Code Snippets are available at this moment for Anna.

Community Discussions

Trending Discussions on Anna

Connecting data from an array to an object to transform its value with a middleman

Connecting data from an array to an object by using a middleman object

How to strip down comma-separated strings to unique substrings

sed remove string until next occurence

SWRL rules in OWL 2

How Do I Sort A Stack Alphabetically in C++?

Is there an option to left_join a list-column?

How can I use grouping and page breaks to create a 2-sided SSRS badge report? (Microsoft SQL Server 2012 Report Builder)

Trying to print info from dictionaries in specific order and format

Firebase search by multiple queries and add to RecyclerView Android Studio

QUESTION

Connecting data from an array to an object to transform its value with a middleman

Asked 2022-Jan-19 at 03:58

What would be the best way to use queued_Dr to alter its values like upcoming_appointments.PCD by using all_appointments?

What would be the best approach to this problem?

...

ANSWER

Answered 2022-Jan-19 at 03:58

The first solution is to find the name in all_appointments and return the corresponding abbreviation.

The second solution is to just compose the abbreviation without other arrays.

Source https://stackoverflow.com/questions/70764604

QUESTION

Connecting data from an array to an object by using a middleman object

Asked 2022-Jan-18 at 09:27

Is there a way to connect queued_Dr to upcoming_appointments by using all_appointments

What would be the best approach to this problem?

...

ANSWER

Answered 2022-Jan-18 at 09:27

From the information you have given to us you don't need upcoming_appointments at all. The code below will return to you the desired result.

Source https://stackoverflow.com/questions/70752744

QUESTION

How to strip down comma-separated strings to unique substrings

Asked 2021-Nov-17 at 19:26

I'm struggling to strip down comma-separated strings to unique substrings in a cleanly fashion:

...

ANSWER

Answered 2021-Nov-17 at 19:26

You can use str_split to get the individual substrings, followed by unique to remove repeated strings. For example:

Source https://stackoverflow.com/questions/69995001

QUESTION

sed remove string until next occurence

Asked 2021-Nov-12 at 14:16

imagine, that i've some chatlog protocol. It could look like this:

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ANSWER

Answered 2021-Nov-10 at 14:15

The following script:

Source https://stackoverflow.com/questions/69912325

QUESTION

SWRL rules in OWL 2

Asked 2021-Oct-03 at 17:27

I'm currently discovering all the possibilities of the Owlready library. Right now I'm trying to process some SWRL rules and so far it's been going very good, but I'm stuck at one point.

I've defined some rules in my ontology and now I want to see all the results (so, everything inferred from a rule).

For example, if I had a rule

has_brother(David, ?b) ^ has_child(?b, ?s) -> has_uncle(?s, David)

and David has two brothers, John and Pete, and John's kid is Anna, Pete's kid is Simon, I would like too see something like:

has_brother(David, John) ^ has_child(John, Anna) -> has_uncle(Anna, David)

has_brother(David, Pete) ^ has_child(Pete, Simon) -> has_uncle(Simon, David)

Is this possible in any way? I thought that maybe if I run the reasoner, I could see it in its output, but I can't find this anywhere.

I appreciate any help possible!

...

ANSWER

Answered 2021-Oct-03 at 17:27

This is my solution:

Source https://stackoverflow.com/questions/69224096

QUESTION

How Do I Sort A Stack Alphabetically in C++?

Asked 2021-Sep-16 at 15:42

I'm new to C++, and I do not understand stacks that well. I tried following some tutorials to sort Stack1 using recursion, but nothing has been working or it is solely focused on arrays containing integers. I also tried sorting the Names array directly, but it does not work. How do I go about sorting my Names array for my Stack1 so in a non-complex manner (since I am new and do not understand it that well)?

Here's my code:

...

ANSWER

Answered 2021-Sep-16 at 10:06

To efficiently sort a stack, one would need to peek at random positions on the stack, preferably swapping the bottom of the stack with the largest element in the stack.

But this already violates the idea of the stack, thus we need something more, such as 2 or 3 more stacks.

One can start with one unsorted stack and two empty stacks, removing one item from the unsorted stack at a time and comparing if the element is smaller or larger than the top element of temporary stack A. If it's larger, place it on stack A, otherwise place it on stack B. In the end the largest element is at the top of stack A, and the original stack of random elements is empty. We can now move the top element from stack A to the top of the original stack, which starts to collect all the elements in descending order.

Then move all the elements from stacks A and B to the original stack and follow the previous step, except for last element, which is sorted.

If we are not allowed to know the size of the stacks (i.e. the number of iteration counts), then we need four stacks: unsorted, max so far, not max so far and sorted.

This algorithm would simulate bubble sort, however, since we know that the temporary stack A is partially sorted, we could probably utilise this fact to implement e.g. merge sort.

Source https://stackoverflow.com/questions/69205878

QUESTION

Is there an option to left_join a list-column?

Asked 2021-Sep-16 at 04:18

Suppose I have a data set with sales:

...

ANSWER

Answered 2021-Sep-16 at 00:12

I think separating the rows, extracting the project_ids, attaching the details, nesting, and then joining back would be simpler and faster than trying to map:

Source https://stackoverflow.com/questions/69200260

QUESTION

How can I use grouping and page breaks to create a 2-sided SSRS badge report? (Microsoft SQL Server 2012 Report Builder)

Asked 2021-Sep-14 at 21:03

I'm designing an SSRS badge report for Avery 5392 badge stock (6 per page) that will also print each wearer's record ID on the back of their badge.

I've set up RowNumber & RowMod columns in my SELECT statement so that I can filter into my design elements only 3 rows of data per column and control which rows go on the left or right-side report elements, respectively. I've also set up PageNumber as a possible grouping option for page breaks.

Please consider this dummy table as a proxy for the data I'm actually using:

...

ANSWER

Answered 2021-Sep-14 at 21:03

I've taken your sample data and reworked the query to give the data I would use if I need to do this. It may not suit your setup exactly but it should be close enough to revise.

I basically output page numbers and row and column numbers from the dataset query that we can then use in a Matrix control.

Here's the modified query..

Source https://stackoverflow.com/questions/68864879

QUESTION

Trying to print info from dictionaries in specific order and format

Asked 2021-Aug-26 at 09:58

I am writing a program that functions like a bus ticket booking system. One of the features is that you can check the order history for customers. I am trying to figure out how to code so that the order history can be displayed like:

...

ANSWER

Answered 2021-Aug-26 at 07:13

zip the values together

Source https://stackoverflow.com/questions/68933967

QUESTION

Firebase search by multiple queries and add to RecyclerView Android Studio

Asked 2021-Jul-30 at 08:23

I'm attempting to replicate a search function in a messaging app with Firebase and display the results in a RecyclerView.

I would like to return users whose firstname, username, or lastname start with the search input text in the same recyclerview, in that order.

I am able to successfully search by one of the children, in this case I'm searching for a user's first name, but I'm really stuck as to how to add the results from the username and lastname, and in such a way that there is no duplication (e.g. if I search "A", a user with firstname "Anna" and lastname "Albury" doesn't appear twice.

Any and all help appreciated, thanks.

Activity searchUsers method:

...

ANSWER

Answered 2021-Jul-30 at 08:23

According to your last comment:

What I'm looking for is a way to get around this by effectively search three times, once for first names, once for last names, and once for usernames, and collate the resulting users in a single RecyclerView.

In this case, you should perform three different queries and collect all the results using Tasks.whenAllSuccess() method:

Source https://stackoverflow.com/questions/68586744

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install Anna

You can download it from GitHub.
You can use Anna like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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