DGI | Deep Graph Infomax | Machine Learning library

 by   PetarV- Python Version: Current License: MIT

kandi X-RAY | DGI Summary

kandi X-RAY | DGI Summary

DGI is a Python library typically used in Artificial Intelligence, Machine Learning, Deep Learning, Pytorch, Tensorflow applications. DGI has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However DGI build file is not available. You can download it from GitHub.

Here we provide an implementation of Deep Graph Infomax (DGI) in PyTorch, along with a minimal execution example (on the Cora dataset). The repository is organised as follows:. Finally, execute.py puts all of the above together and may be used to execute a full training run on Cora.
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            kandi-support Support

              DGI has a low active ecosystem.
              It has 507 star(s) with 124 fork(s). There are 10 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 8 open issues and 10 have been closed. On average issues are closed in 8 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of DGI is current.

            kandi-Quality Quality

              DGI has 0 bugs and 3 code smells.

            kandi-Security Security

              DGI has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              DGI code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              DGI is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              DGI releases are not available. You will need to build from source code and install.
              DGI has no build file. You will be need to create the build yourself to build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              DGI saves you 153 person hours of effort in developing the same functionality from scratch.
              It has 381 lines of code, 28 functions and 10 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed DGI and discovered the below as its top functions. This is intended to give you an instant insight into DGI implemented functionality, and help decide if they suit your requirements.
            • Load data from a given dataset
            • Parse an index file
            • Preprocess features
            • Convert a sparse matrix to a tuple
            • Preprocess the adjacency matrix
            • Normalize adjacency matrix
            • Embed embedding
            Get all kandi verified functions for this library.

            DGI Key Features

            No Key Features are available at this moment for DGI.

            DGI Examples and Code Snippets

            No Code Snippets are available at this moment for DGI.

            Community Discussions

            QUESTION

            Artifact margin between sections
            Asked 2020-Dec-13 at 23:49

            can someone explain to me why I have a space between two sections, but in inspector I don't see any padding or margins or etc.

            Here is jsfiddle - https://jsfiddle.net/1frk5w8s/7/

            /////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

            ...

            ANSWER

            Answered 2020-Dec-13 at 23:49

            Add this rule with your css:

            Source https://stackoverflow.com/questions/65281220

            QUESTION

            Remove codes from city names using regex
            Asked 2020-Sep-03 at 18:35

            I need to find a regex that is able to sanitize the input by removing city codes and keeping the name of the cities.

            ...

            ANSWER

            Answered 2020-Sep-03 at 06:22

            The difficulty here is that you want to match a sequence of upper case letters, digits or spaces, but you don't want to match only a space, and probably you don't want to match anything that does not contain any digits.

            Although there may be a simpler form, one thing that would work would be to insist on there being a digit, with any number of the other characters both before and after it.

            The pattern should also start and finish on a word boundary, so that e.g. it does not strip off the capital letter at the start of the following word.

            Source https://stackoverflow.com/questions/63716996

            QUESTION

            Define Subgroup in Brian2 (library in python)
            Asked 2019-Dec-02 at 15:47

            I tried to test a spiking neural network in Python using Brian2. I received this error:

            ...

            ANSWER

            Answered 2019-Dec-02 at 15:47

            Defining subgroup in Brian2 according to following:

            For example we have p(neuron group) and we want to have two subgroup of it.

            Source https://stackoverflow.com/questions/53692787

            QUESTION

            How to copy a file from one directory to another with VBA
            Asked 2019-Nov-06 at 18:07

            I want to be able to copy an excel file from one folder to another one. But, everytime it copies it, I want to change the name to TABLEAUPCQ1, TABLEAUPCQ2, TABLEAUPCQ3, and so on..

            the reason is, I cant overwrite the excel file if someone is already using it in that other path..

            ...

            ANSWER

            Answered 2019-Nov-06 at 18:07

            Increase the counter by 1 after each sub execution within a cell value. That way you have the current count stored outside your function.

            Grab it, use it, increase it.

            Source https://stackoverflow.com/questions/58734242

            QUESTION

            Brute Force Approach for LCS and its Time Complexity [O(m*n)!?]
            Asked 2019-Mar-17 at 14:08

            I have read several Algorithm books where it is been told brute force approach of Longest Common Subsequence takes 2^n which is exponential in time complexity. Whereas, I've noticed that while I am applying my brute force technique it's taking O(mn) (from my personal observation). I would like to request you please read my approach clearly and visualize in mind and ask question for further clarification if needed. My Approach is following:- Say we have two strings s1 = "ECDGI" , s2 = "ABCDEFGHIJ". Now what I am doing is I chose either one of the given strings. For say, s1. for i = 1 to n (n is the last index of s1), I am taking each value and comparing with the s2 in such a way that for a single character of s1 I am checking with all the characters of s2. Mathematically, ith value is checking through all jth value up to m (m is the last index of s2). Here, if I find any common character I just move to next character from both strings. Then just compute subsequence. I compute all the possible subsequence for each characters from s1 by running n loops. Finally, I compute the largest value. From my understanding it's taking O(mn) time complexity overall. So My Question is, " Is my Time Complexity Calculation right ? "

            Trace :

            i = 1, value = E, lcs = 3 [EGI]

            i = 2, value = C, lcs = 4 [CDGI]

            i = 3, value = D, lcs = 3 [DGI]

            i = 4, value = G, lcs = 2 [GI]

            i = 5, value = I, lcs = 1 [I]

            Answer is = 4 (maximum lcs)

            My code is given below !

            ...

            ANSWER

            Answered 2019-Mar-17 at 14:08
            1. Your algorithm is wrong. Consider the case when s1 = "AABAA" and s2 = "AAAAB", your code gives 3, but LCS is 4.

            2. Time complexity is O(n * m * (n+m))

              • Why?

              • Well let`s consider worst case where we have s1 is n/2 'A' characters and n/2 'B' characters, and s2 is m/2 'A' characters and m/2 'C' characters

              • Now if we ignore doIt() function loops themselves give O(n * m)
              • So how many times doIt() is called? well for all pairs of n/2 first characters of s1 and m/2 of s2 so n/2 * m/2 times, or if we drop constants O(n * m ) times
              • Now lets analyze complexity of doIt()
              • It Uses something like 2 pointers to pass both strings so its complexity is O(n+m)
              • So total complexity is O(n * m * (n+m)) or O(n^2 * m + m^2 * n)

            Source https://stackoverflow.com/questions/55207687

            QUESTION

            Create a dodged barplot with ggplot2
            Asked 2018-Dec-04 at 15:34

            I have the dataset below:

            ...

            ANSWER

            Answered 2018-Dec-04 at 15:34

            Here's one way to achieve what you want:

            Source https://stackoverflow.com/questions/53615656

            QUESTION

            Downloadhandler() downloads a file with only the column names of the actual dataframe inRShiny
            Asked 2018-Nov-28 at 21:14

            I use the data below:

            ...

            ANSWER

            Answered 2018-Nov-28 at 21:14

            Im not sure why but I had to remove [input[["table_rows_all"]],]

            Source https://stackoverflow.com/questions/53522048

            QUESTION

            Subseting a dataframe by column names does not respond when applied in a shiny app
            Asked 2018-Nov-27 at 22:30

            I have a simple shiny app in which I subset a dataframe by row selection and by column names selection. After subseting by rows I tried 3 different methods to subset it by columns as well but the dataframe remains the same. More specifically I have used :

            ...

            ANSWER

            Answered 2018-Nov-27 at 21:56

            You were quite close. The first problem is that in your definition of df_subset, you use a which is not defined anywhere else in the script. I guess you meant to use db there instead of a. The second problem is that when you subset a, you do not assign it again to a, and so when you return a it will not be the subsetted version. Below is the fixed version of df_subset.

            Source https://stackoverflow.com/questions/53505887

            QUESTION

            Subseting a dataframe with shiny ignores specific rows
            Asked 2018-Nov-27 at 17:08

            I have a shiny app in which I want to subset the datatable displayed based on the user Input in the sidebar. The issue is that as you will see the 3 last rows of my dataframe are not displayed at all while all rows are selected. I suspect that this happens because the "DCH" exists 3 times instead of one but I do not know what happens with "LDP".

            DATA ...

            ANSWER

            Answered 2018-Nov-27 at 17:08

            When running your code, you will see the following errors in your console:

            Source https://stackoverflow.com/questions/53503657

            QUESTION

            The ggplotly() ignores legend labels editing despite using scale_fill_manual()
            Asked 2018-Oct-29 at 18:00

            I use the data frame below:

            ...

            ANSWER

            Answered 2018-Oct-29 at 18:00

            I don't know what plotly looks for exactly, but it looks like it doesn't care what your scale_fill_manual labels are and just pulls your fill factor groups as names. So one way would be to just create a label group in your data.

            A hacky way is to manually edit the plotly_build() of the plot.

            Source https://stackoverflow.com/questions/53046437

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install DGI

            You can download it from GitHub.
            You can use DGI like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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