Truck | : truck : A dynamic object oriented programming language | Interpreter library
kandi X-RAY | Truck Summary
kandi X-RAY | Truck Summary
Truck is a dynamic programming language with a focus on simplicity.
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QUESTION
I am in need of help proving that an algorithm has greedy choice property and optimal substructure.
Context of the problem:
Consider a problem where a company owns n gas stations that are connected by a highway.
Each gas station has a limited supply g_i of gas-cans. Since the company don't know which gas station is most visited they want all of them to have the same amount of gas.
So they hire a fueling-truck to haul gas between the stations in their truck. However, truck also consumes 1 gas-can per kilometer driven.
Your task will be to help the chain calculate the largest amount of gas-cans g_bar
they can have at all Stations.
Consider the example: Here we have g = (20, 40, 80, 10, 20) and
p = (0, 5, 13, 33, 36) (in kilometers). In order to send one gas-can from station 3 to
station 4 we need to put 41 gas-cans in the truck, as the fueling-truck will consume 40 before reaching their destination (to send two gas-cans we need to put 42 in the truck).
The optimal g_bar for the example is 21 and can be achieved as follows:
Station 2 sends 11 gas-cans towards Station 1. One gas-can arrives while ten are consumed on the way.
Station 3 sends 59 gas-cans towards Station 4. 19 arrive while 40 are consumed on the way.
Station 4 now has 29 gas-cans and send eight towards Station 5. Two of these arrive and six are consumed on the way.
The final distribution of gas-cans is: (21, 29, 21, 21, 22).
Given an integer g_bar. Determine whether it is possible to get at least g_bar gas-cans in every Gas Station.
in order for the greedy choice property and optimal substructure to make sense for a decision problem, you can define an optimal solution to be a solution with at least g_bar gas-cans in every gas station if such a solution exists; otherwise, any solution is an optimal solution.
Input: The position p_i and gas-can supply g_i of each bar. Here g_i is the supply for the bar at position p_i. You may assume that the positions are in sorted order – i.e. p_1 < p_2 < . . . < p_n.
Output: The largest amount g_bar, such that each gas-station can have a gas-can supply of at least g_bar after the truck have transferred gas-cans between the stations.
How can i prove Greedy Choice and Optimal Substructure for this?
...ANSWER
Answered 2022-Mar-20 at 06:03Let's define an optimal solution: Each station has at least X gas cans in each station (X = g_bar).
Proving greedy property
Let us assume our solution is sub-optimal. There must exist a station i such that gas[i] < X. Based on our algorithm, we borrow X - gas[i] from station i+1 (which is a valid move, since we had already found a solution). Now station i has gas = X. This contradicts the original assumption that there must exist a station i such that gas[i] < X, which means our solution isn't suboptimal. Hence, we prove the optimality.
Proving optimal substructure
Assume we have a subset of the stations of size N', and our solution is suboptimal. Again, if the solution is suboptimal, there must exist a station i such that gas[i] < X. You can use the greedy proof again to prove that our solution isn't suboptimal. Since we have optimal solution for each arbitrary subset, we prove that we have optimal substructure.
QUESTION
I have a list 'labels' and a dictionary with key, value pairs 'class_dict'.
I want to loop over my labels list, and print the dictionary key (e.g. 'airplane'), if the class_dict.value() is equal to the label[i].
...ANSWER
Answered 2022-Mar-09 at 15:41You could for example swap key and value of the dict and then simply access it with the list elements:
QUESTION
I have the following queries:
...ANSWER
Answered 2022-Feb-18 at 15:34Not with linq, no. Why? Because of two reasons:
- Query syntax has no way to get count and use union to get from one query
- Method count, is immediate execution and not deferred, so you can't chain into one query
To be honest, that would be difficult to achieve even with a sql query as the data has different data types and columns.
QUESTION
I have a list of dictionaries which is as follow-
...ANSWER
Answered 2021-Dec-22 at 08:28I think you can acheive what you want using the groupby function from itertools.
QUESTION
I would like to use transporters in my model in various places (tugboats, forklifts, reach stackers, trucks, etc.). However, my model paths and animation can't be drawn to scale, detailed explanation in brackets below. Is there a way I can move the transporter from one node to another based on travel time (similar to what a movable resource can do), rather than speed and distance? The "Move By Transporter" block does not seem to allow this and I have not been able to find a solution online. Thank you for your help.
(Explanation on why I can't draw to scale: firstly, some destination locations (storage areas, etc.) are not known yet and will just be represented by a travel delay to get there, secondly, different areas of the model will be drawn to different scales, i.e. some network paths will represent a multiple kilometers and some network paths will only represent a few hundred meters, etc.)
...ANSWER
Answered 2022-Jan-31 at 05:24You can draw the paths to suit your animation and then simply set the speed of the transporter that gets seized to a speed so that the duration of the movement matches what you need it to be, and when the transporter gets released set the speed back to normal
QUESTION
In my Anylogic model I have 200 zones and I have these populations of agents:
- Customers (parameters: name, GIS latitude, GIS longitude), one in every zone (except terminal zones)
- Terminals (parameters: name, GIS latitude, GIS longitude), one in evert terminal zone (5)
- Orders (parameters: customer (type: Customer), terminal (type: Terminal))
- Trucks (receive an order (that is created by a customer) and then travel to that terminal and customer)
Now, since there are large waiting times at terminals during the day time, I want to add a hub that is open at night in between the terminals and customers and let the trucks decide if:
- They want to travel at day time directly from the terminal to the customer, or
- They want to travel at night time from the terminal to a hub, and then at day time from the hub to the customer
They should make this choice based on driving+waiting costs that differ per route(origin,destination) and per time of day (day/night). I have these costs in a database and I linked them to the routes by first adding a new Java class:
And then I added this function to assign the costs from my database:
Now my question is, how can I let the trucks, per order they receive, choose their departure times (day/night) and route (from terminal -> customer / from terminal -> hub -> customer) based on these costs?
I want to add something like this below (where Region102 is the hub) to choose the cheapest option per order (which was just to try but of course does not work like this..) and to let the trucks then choose their departure time and route?
Thank you for all the help!
...ANSWER
Answered 2021-Dec-28 at 05:06You can create a function that has the customer and terminal as arguments and then find you the least costly option and return it. Here is a quick example where 'allPossibleRoutes' is just a collection where all the possible route combinations are stored as a list.
QUESTION
i'm trying to get media fields from the instagram api and i'm getting this error
...ANSWER
Answered 2022-Feb-01 at 18:30According to the documentation : https://developers.facebook.com/docs/instagram-basic-display-api/reference/media ,every field is a String
QUESTION
I have this type of wide dataset which I want to convert to long format. The column choice shows the order of the chosen alternative. So, if it is choice2 it means the second option was chosen and that column should have 1 for the second option and 0 for the others. The columns college, hsg2 coml5 should repeat.
Data:
...ANSWER
Answered 2022-Feb-03 at 10:51Use wide_to_long first, then get number from choice column and compare by counter per groups for final column:
QUESTION
I have Object:
...ANSWER
Answered 2022-Jan-30 at 15:30Collections.copy requires that the size of the destination list is at least the size of the source list. Your this.route has a size of 0 when you try to do the copy so you get an exception.
Instead use addAll:
QUESTION
I try to connect to firebase by react native.
Here is code
ANSWER
Answered 2021-Nov-04 at 07:53You importing import * as firebase from 'firebase' in the top of your file..Try to import this line and tell me if it works.
import firebase from "firebase/compat/app";
Some paths of the firebase have changed a long time ago so if you are watching legacy code snipets maybe you will have errors.
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Install Truck
You can use Truck like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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