BlogSpider | A crawler for auto-updating blogs

by TesterlifeRaymond Python Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | BlogSpider Summary

BlogSpider is a Python library. BlogSpider has no bugs, it has no vulnerabilities and it has low support. However BlogSpider build file is not available. You can download it from GitHub.

A crawler for auto-updating blogs

Support

Quality

Security

License

Reuse

Support

BlogSpider has a low active ecosystem.

It has 9 star(s) with 2 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

BlogSpider has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of BlogSpider is current.

Quality

BlogSpider has no bugs reported.

Security

BlogSpider has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

BlogSpider does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

BlogSpider releases are not available. You will need to build from source code and install.

BlogSpider has no build file. You will be need to create the build yourself to build the component from source.

Top functions reviewed by kandi - BETA

kandi has reviewed BlogSpider and discovered the below as its top functions. This is intended to give you an instant insight into BlogSpider implemented functionality, and help decide if they suit your requirements.

Download files from url
Write msg to file
Process an item
Process a runoob
Process a snippet
Read file contents

Get all kandi verified functions for this library.

BlogSpider Key Features

No Key Features are available at this moment for BlogSpider.

BlogSpider Examples and Code Snippets

No Code Snippets are available at this moment for BlogSpider.

Community Discussions

Trending Discussions on BlogSpider

python and json UTF-8 encoding

How to scrap only text?

Logging to a file using Scrapy and Crochet libraries

Scrapy: Simple Project

How to use Scrapy for URL crawling

Can we run scrapy code outside of scrapy shell?

Scrapy not yielding result (crawled 0 pages)

Python Scrapy Function Call

scrapy extrat from newspapers to txt

Using Scrapy to scrape data

QUESTION

python and json UTF-8 encoding

Asked 2020-Dec-27 at 01:57

I am currently facing some issues about encoding. As I am French, I frequently use characters like é or è.

I am trying to figure out why they are not displayed in a JSON file I created automatically with scrapy...

Here is my python code :

...

ANSWER

Answered 2020-Dec-27 at 01:57

Use FEED_EXPORT_ENCODING option: here in custom_settings.

Source https://stackoverflow.com/questions/65461945

QUESTION

How to scrap only text?

Asked 2020-Sep-06 at 08:32

Code :

...

ANSWER

Answered 2020-Sep-06 at 08:32

Just add (::text) at the end of your css selector like

Source https://stackoverflow.com/questions/63757338

QUESTION

Logging to a file using Scrapy and Crochet libraries

Asked 2020-Mar-03 at 16:06

I'm running Scrapy from scripts, using Crochet library in order to block codes. Now I'm trying to dump logs into a file, but it starts to redirect logs to STDOUT for some reason. I doubt the Crochet library in my mind, but I don't have any clues so far.

How can I debug this kind of problems? Please share your debugging know-hows with me.
How can I fix it so that I dump logs into a file?

...

ANSWER

Answered 2019-Dec-15 at 08:35

I see you are settings log settings for scrapy while you log using logging.info that would send the log message to python's root logger rather than scrapy's root logger**. Try using self.logger.info("whatever") inside a spyder instance as scrapy initializes a logger instance in each object. or set logging handler for the root logger using

Source https://stackoverflow.com/questions/59337728

QUESTION

Scrapy: Simple Project

Asked 2018-Sep-22 at 11:22

I want to start a simply scrapy project. It is a python project from visual studio. The VS is running in administration mode. Unfortunately, parse(...) is never called, but should..

...

ANSWER

Answered 2018-Sep-22 at 06:10

this looks entire problem of indentations once i fixed it it started working output

Source https://stackoverflow.com/questions/52453777

QUESTION

How to use Scrapy for URL crawling

Asked 2018-Jul-03 at 07:33

I want to crawl the link https://www.aparat.com/.

I crawl it correctly and get all the video links with header tag;like this :

...

ANSWER

Answered 2018-Jul-03 at 07:33

I did this with the following code :

Source https://stackoverflow.com/questions/50602900

QUESTION

Can we run scrapy code outside of scrapy shell?

Asked 2018-Mar-12 at 06:14

I am trying to build a crawler using Scrapy. Every tutorial in the Scrapy' sofficial documentation or in the blog, I See people making a class in the .py code and executing it through scrapy shell.

On their main page, the following example is given

...

ANSWER

Answered 2018-Mar-09 at 13:00

You can use a CrawlerProcess to run your spider in Python main script, and run with python myspider.py

For example:

Source https://stackoverflow.com/questions/49193757

QUESTION

Scrapy not yielding result (crawled 0 pages)

Asked 2017-Oct-07 at 15:18

Trying to figure out how scrapy works and using it to find information on forums.

items.py

...

ANSWER

Answered 2017-Oct-07 at 15:11

You should use response.css('li.past.line.event-item') and there is no need for responseSelector = Selector(response).

Also the CSS you are using li.past.line.event-item, is no more valid, so you need update those first based on the latest web page

To get the next page URL you can use

Source https://stackoverflow.com/questions/46614958

QUESTION

Python Scrapy Function Call

Asked 2017-Jun-19 at 19:38

I try to call the getNext() function from the main parse function that scrappy calls but it never gets called.

...

ANSWER

Answered 2017-Jun-19 at 19:38

You are trying to yield a generator, but meant to yield from a generator.

If you are on Python 3.3+, you can use yield from:

Source https://stackoverflow.com/questions/44638287

QUESTION

scrapy extrat from newspapers to txt

Asked 2017-May-04 at 13:26

I'm a little bit new to scrapy, and i need to extract some newspapers information for a work, i've tried some tutorial but none of them worked as i expected, the objective is to a given url, extract the informations about the first 4 ou 5 topics (the inside information when we click the link). I've tried to navigate through the links first of all, bit i fail, the output is empty and says 0 crawled pages.

...

ANSWER

Answered 2017-May-04 at 12:29

I had a quick look at http://www.dn.pt/pesquisa.html?q=economia%20empresas and it seems the content doesn't come with the initial HTML that is captured by scrapy.

Instead the content is downloaded and rendered by subsequent Javascript / AJAX requests which Scrapy doesn't capture out of the box.

Possible solutions:

Either you use Firebug or Chrome Developer Tools to understand how those background requests work and you try to emulate and scrape these background requests directly. (Means more work but the resulting scraper is much faster).

Or you add Splash or a Selenium instance to make them render the Javascript and then scrape the rendered pages directly.

Source https://stackoverflow.com/questions/43757803

QUESTION

Using Scrapy to scrape data

Asked 2017-Jan-30 at 14:46

I am trying to scrape data using scrapy. But having trouble in editing the code. Here is what I have done as an experiment:

...

ANSWER

Answered 2017-Jan-30 at 14:46

import scrapy

class BlogSpider(scrapy.Spider):
    name = 'blogspider'
    start_urls = ['http://anon.example.com']


    # get 502 url of name
    def parse(self, response):
        info_urls = response.xpath('//div[@class="text"]//a/@href').extract()
        for info_url in info_urls:
            yield scrapy.Request(url=info_url, callback=self.parse_inof)
    # visit each url and get info
    def parse_inof(self, response):
        info = {}
        info['name'] = response.xpath('//h2/text()').extract_first()
        info['phone'] = response.xpath('//text()[contains(.,"Phone:")]').extract_first()
        info['email'] = response.xpath('//*[@class="cs-user-info"]/li[1]/text()').extract_first()
        info['website'] = response.xpath('//*[@class="cs-user-info"]/li[2]/a/text()').extract_first()
        print(info)

Source https://stackoverflow.com/questions/41936887

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install BlogSpider

You can download it from GitHub.
You can use BlogSpider like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: