checkio | My solutions to the tasks at checkio.org
kandi X-RAY | checkio Summary
kandi X-RAY | checkio Summary
My solutions to the tasks at checkio.org
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Top functions reviewed by kandi - BETA
- Checks if the given string is valid .
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QUESTION
This issue occurs on MacOS using VSCode to debug an individual test (instead of the entire suite). When I try to debug this test with vscode, I get the following output:
...ANSWER
Answered 2022-Mar-12 at 06:31I've run into this as well. Found a workaround by adding this to my project file:
QUESTION
data = [1, 2, 3, 4, 5]
for x in data:
print(x)
if data.count(x) < 2:
data.remove(x)
...ANSWER
Answered 2021-Oct-28 at 13:20While the from @Stef and @0x5453 are both relevant to your problem. The comment from @ConnorTJ is patently wrong. The remove function does not remove the item at the index but the first occurrence of the item.
To answer your question, about what's going on here, let[s examine your code: The first pass through the value of x is 1 You print the value of x You then test to see if the number of occurrences of x is less than 2 Since the answer is yes, you proceed to remove the item from the list.
The second pass through the list the For loop picks up the next value in the list (at index 1) which is now the value 3 You print the value 3 You check to see if the count of 3 is less than 2 Since the count is less you remove that item from the list.
This process than continues
QUESTION
def checkio(array: list) -> int:
"""
Sums even-indexes elements and multiply at the last
"""
a = []
if array:
for i in array:
if array.index(i) == 0 or array.index(i) % 2 == 0:
a.append(i)
print(a)
return sum(a) * array[-1]
else:
return 0
checkio([-37, -36, -19, -99, 29, 20, 3, -7, -64, 84, 36, 62, 26, -76, 55, -24, 84, 49, -65, 41])
...ANSWER
Answered 2021-Oct-08 at 17:12Because the index(x) method returns the position of the first value that is equal to x as written in Python documentation, you can find here:
https://docs.python.org/3/tutorial/datastructures.html
so the array.index(84) will return 9 and so it will not be appended to "a".
QUESTION
Can someone let me why the regular expression
...ANSWER
Answered 2021-Jul-15 at 21:31Use the ignore case regex;
(?i)
-ignore or case-insensitive mode ON
Data
data=[
QUESTION
I need your help since i'm stuck at the challenge from checkio. What am i missing? I get back:
Your result:"one,two,three" Right result:"one,three,two"
The Challenge: You are given two string with words separated by commas. Try to find what is common between these strings. The words are not repeated in the same string. Your function should find all of the words that appear in both strings. The result must be represented as a string of words separated by commas in alphabetic order.
UPDATE
this is my code:
...ANSWER
Answered 2020-Mar-24 at 19:50match.toString()
doesn't change the value of match
variable. You need to return it from the function.
QUESTION
I'm trying to solve this task.
I wrote function
for this purpose which uses itertools.product() for Cartesian product of input iterables:
ANSWER
Answered 2020-Jan-16 at 01:59I guess the problem is to find the distribution of the sum of dice. An efficient way to do that is via discrete convolution. The distribution of the sum of variables is the convolution of their probability mass functions (or densities, in the continuous case). Convolution is an n-ary operator, so you can compute it conveniently just two pmf's at a time (the current distribution of the total so far, and the next one in the list). Then from the final result, you can read off the probabilities for each possible total. The first element in the result is the probability of the smallest possible total, and the last element is the probability of the largest possible total. In between you can figure out which one corresponds to the particular sum you're looking for.
The hard part of this is the convolution, so work on that first. It's just a simple summation, but it's just a little tricky to get the limits of the summation correct. My advice is to work with integers or rationals so you can do exact arithmetic.
After that you just need to construct an appropriate pmf for each input die. The input is just [1, 1, 1, ... 1] if you're using integers (you'll have to normalize eventually) or [1/n, 1/n, 1/n, ..., 1/n] if rationals, where n = number of faces. Also you'll need to label the indices of the output correctly -- again this is just a little tricky to get it right.
Convolution is a very general approach for summations of variables. It can be made even more efficient by implementing convolution via the fast Fourier transform, since FFT(conv(A, B)) = FFT(A) FFT(B). But at this point I don't think you need to worry about that.
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