checkio | My solutions to the tasks at checkio.org

 by   abeaumont Python Version: Current License: WTFPL

kandi X-RAY | checkio Summary

kandi X-RAY | checkio Summary

checkio is a Python library. checkio has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However checkio build file is not available. You can download it from GitHub.

My solutions to the tasks at checkio.org
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            kandi-support Support

              checkio has a low active ecosystem.
              It has 5 star(s) with 0 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              checkio has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of checkio is current.

            kandi-Quality Quality

              checkio has 0 bugs and 0 code smells.

            kandi-Security Security

              checkio has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              checkio code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              checkio is licensed under the WTFPL License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              checkio releases are not available. You will need to build from source code and install.
              checkio has no build file. You will be need to create the build yourself to build the component from source.
              It has 72 lines of code, 7 functions and 8 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed checkio and discovered the below as its top functions. This is intended to give you an instant insight into checkio implemented functionality, and help decide if they suit your requirements.
            • Checks if the given string is valid .
            Get all kandi verified functions for this library.

            checkio Key Features

            No Key Features are available at this moment for checkio.

            checkio Examples and Code Snippets

            No Code Snippets are available at this moment for checkio.

            Community Discussions

            QUESTION

            Error while running test with vscode: some sort of issue with the project file
            Asked 2022-Mar-12 at 06:31

            This issue occurs on MacOS using VSCode to debug an individual test (instead of the entire suite). When I try to debug this test with vscode, I get the following output:

            ...

            ANSWER

            Answered 2022-Mar-12 at 06:31

            I've run into this as well. Found a workaround by adding this to my project file:

            Source https://stackoverflow.com/questions/71446767

            QUESTION

            for loop doesn't itterate through all the data?
            Asked 2021-Oct-28 at 13:54
            data = [1, 2, 3, 4, 5]
            for x in data:
                    print(x)
                    if data.count(x) < 2:
                            data.remove(x)
            
            ...

            ANSWER

            Answered 2021-Oct-28 at 13:20

            While the from @Stef and @0x5453 are both relevant to your problem. The comment from @ConnorTJ is patently wrong. The remove function does not remove the item at the index but the first occurrence of the item.

            To answer your question, about what's going on here, let[s examine your code: The first pass through the value of x is 1 You print the value of x You then test to see if the number of occurrences of x is less than 2 Since the answer is yes, you proceed to remove the item from the list.

            The second pass through the list the For loop picks up the next value in the list (at index 1) which is now the value 3 You print the value 3 You check to see if the count of 3 is less than 2 Since the count is less you remove that item from the list.

            This process than continues

            Source https://stackoverflow.com/questions/69754569

            QUESTION

            When processing a list a specific value is skipped
            Asked 2021-Oct-08 at 17:43
            def checkio(array: list) -> int:
                """
                Sums even-indexes elements and multiply at the last
                """
                a = []
                if array:
                    for i in array:
                        if array.index(i) == 0 or array.index(i) % 2 == 0:
                            a.append(i)
                    print(a)
                    return sum(a) * array[-1]
                else:
                    return 0
            
            
            checkio([-37, -36, -19, -99, 29, 20, 3, -7, -64, 84, 36, 62, 26, -76, 55, -24, 84, 49, -65, 41])
            
            ...

            ANSWER

            Answered 2021-Oct-08 at 17:12

            Because the index(x) method returns the position of the first value that is equal to x as written in Python documentation, you can find here:

            https://docs.python.org/3/tutorial/datastructures.html

            so the array.index(84) will return 9 and so it will not be appended to "a".

            Source https://stackoverflow.com/questions/69499423

            QUESTION

            Python regular expression unable to find pattern - using pyspark on Apache Spark
            Asked 2021-Jul-15 at 21:31

            Can someone let me why the regular expression

            ...

            ANSWER

            Answered 2021-Jul-15 at 21:31

            Use the ignore case regex;

            (?i)-ignore or case-insensitive mode ON

            Data

            data=[

            Source https://stackoverflow.com/questions/68400780

            QUESTION

            Checkio Common Words Challenge: How do i continue?
            Asked 2020-Mar-24 at 19:50

            I need your help since i'm stuck at the challenge from checkio. What am i missing? I get back:

            Your result:"one,two,three" Right result:"one,three,two"

            The Challenge: You are given two string with words separated by commas. Try to find what is common between these strings. The words are not repeated in the same string. Your function should find all of the words that appear in both strings. The result must be represented as a string of words separated by commas in alphabetic order.

            UPDATE

            this is my code:

            ...

            ANSWER

            Answered 2020-Mar-24 at 19:50

            match.toString() doesn't change the value of match variable. You need to return it from the function.

            Source https://stackoverflow.com/questions/60838125

            QUESTION

            How to iterate through the Cartesian product of ten lists (ten elements each) faster? (Probability and Dice)
            Asked 2020-Jan-18 at 07:17

            I'm trying to solve this task. I wrote function for this purpose which uses itertools.product() for Cartesian product of input iterables:

            ...

            ANSWER

            Answered 2020-Jan-16 at 01:59

            I guess the problem is to find the distribution of the sum of dice. An efficient way to do that is via discrete convolution. The distribution of the sum of variables is the convolution of their probability mass functions (or densities, in the continuous case). Convolution is an n-ary operator, so you can compute it conveniently just two pmf's at a time (the current distribution of the total so far, and the next one in the list). Then from the final result, you can read off the probabilities for each possible total. The first element in the result is the probability of the smallest possible total, and the last element is the probability of the largest possible total. In between you can figure out which one corresponds to the particular sum you're looking for.

            The hard part of this is the convolution, so work on that first. It's just a simple summation, but it's just a little tricky to get the limits of the summation correct. My advice is to work with integers or rationals so you can do exact arithmetic.

            After that you just need to construct an appropriate pmf for each input die. The input is just [1, 1, 1, ... 1] if you're using integers (you'll have to normalize eventually) or [1/n, 1/n, 1/n, ..., 1/n] if rationals, where n = number of faces. Also you'll need to label the indices of the output correctly -- again this is just a little tricky to get it right.

            Convolution is a very general approach for summations of variables. It can be made even more efficient by implementing convolution via the fast Fourier transform, since FFT(conv(A, B)) = FFT(A) FFT(B). But at this point I don't think you need to worry about that.

            Source https://stackoverflow.com/questions/59751892

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install checkio

            You can download it from GitHub.
            You can use checkio like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/abeaumont/checkio.git

          • CLI

            gh repo clone abeaumont/checkio

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            git@github.com:abeaumont/checkio.git

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