alexa-apis-for-python | Alexa APIs for Python consists | SDK library
kandi X-RAY | alexa-apis-for-python Summary
kandi X-RAY | alexa-apis-for-python Summary
The Alexa APIs for Python consists of python classes that represent the request and response JSON of Alexa services. These models act as core dependency for the Alexa Skills Kit Python SDK (https://github.com/alexa/alexa-skills-kit-sdk-for-python).
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Top functions reviewed by kandi - BETA
- Get skill metrics
- Invoke the API endpoint
- Build query string
- Build the url
- List capability evaluations
- Get skill validations
- List Nlu Evaluations
- Updates an impact for a product
- List Asr Evaluations
- Updates account linking information
- Updates a skill manifest
- Get annotations for an ASR annotation set
- Call profile Nlu
- Get in skill products transactions
- Get interaction model version
- Updates annotation set annotations
- Call get utterance data API
- Get the list of InSkillProducts for a given vendor
- Method to update an interaction model
- List interaction model versions
- Calling nlu evaluations_v1
- Get conflicts for an interaction model
- Get conflict detection job status
alexa-apis-for-python Key Features
alexa-apis-for-python Examples and Code Snippets
Community Discussions
Trending Discussions on alexa-apis-for-python
QUESTION
I'm newbie to Alexa custom skill and if my users trigger an intent which requires authentication, i want them to link their accounts to continue using my skill. Of course my skill needs to return an instructions for them to know how to link their account.
I found in the Officical docs but unfortunately there is no example code for python.
After hours researching on internet, i found LinkAccountClass on ask_sdk_model.ui
. So i started to add this class to my code like that:
from ask_sdk_model.ui import LinkAccountCard
if not handler_input.request_envelope.context.system.user.access_token:
speech = "You must open alexa app on your phone and link you account to continue"
handler_input.response_builder.speak(speech).set_card(LinkAccountCard(speech))
return handler_input.response_builder.set_should_end_session(False).response
But Alexa keeps saying to me that "Sorry, i can't help you with this". If i use .set_card(SimpleCard(speech))
instead of .set_card(LinkAccountCard(speech))
, Alexa display the message "You must open alexa app on your phone and link you account to continue" without any error.
So how can i return the linkAccountCard to user to help them go to the linking accout in setting?
Thank a lot!
...ANSWER
Answered 2020-May-08 at 13:05LinkAccountCard
doesn't accept any parameters; change it to .set_card(LinkAccountCard())
and you should be good. Alexa provides the copy for that card.
Alternatively, you could use…
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Install alexa-apis-for-python
You can use alexa-apis-for-python like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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