continuation | A module for handling continuations in Python | Functional Programming library

 by   baruchel Python Version: 0.1 License: MIT

kandi X-RAY | continuation Summary

kandi X-RAY | continuation Summary

continuation is a Python library typically used in Programming Style, Functional Programming applications. continuation has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has high support. You can install using 'pip install continuation' or download it from GitHub, PyPI.

The continuation module is another attempt for providing a clean way of embedding continuation-passing-style (CPS) expressions in a Python script. While not the single purpose of this module, tail-recursion can easely be acheived with it. The module internally uses standard and pythonic features (mostly lambda calculus and exceptions) and doesn't attempt to "inspect" the stack or the functions for modifying them. For this reason, it should integrate smoothly with any version of Python. Furthermore, nested systems of continuations are correctly handled.
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            kandi-support Support

              continuation has a highly active ecosystem.
              It has 28 star(s) with 1 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 1 open issues and 0 have been closed. On average issues are closed in 143 days. There are no pull requests.
              OutlinedDot
              It has a negative sentiment in the developer community.
              The latest version of continuation is 0.1

            kandi-Quality Quality

              continuation has 0 bugs and 0 code smells.

            kandi-Security Security

              continuation has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              continuation code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              continuation is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              continuation releases are not available. You will need to build from source code and install.
              Deployable package is available in PyPI.
              Build file is available. You can build the component from source.
              Installation instructions, examples and code snippets are available.
              continuation saves you 19 person hours of effort in developing the same functionality from scratch.
              It has 54 lines of code, 8 functions and 2 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed continuation and discovered the below as its top functions. This is intended to give you an instant insight into continuation implemented functionality, and help decide if they suit your requirements.
            • Call a function in a loop .
            • Calls the wrapped function f .
            • Decorator to specify a continuation signature .
            • Initialize function .
            Get all kandi verified functions for this library.

            continuation Key Features

            No Key Features are available at this moment for continuation.

            continuation Examples and Code Snippets

            No Code Snippets are available at this moment for continuation.

            Community Discussions

            QUESTION

            copy a string form a line and paste at the end in another line for a huge file based on pattern
            Asked 2021-Jun-15 at 20:47

            I have the below requirement . i am trying to run the condition in loop and its taking more time. is there a one time command anything which will not take more time to process a 70 MB file.

            Requirement: if @pRECTYPE="SBSB" line contains @pSBEL_MCTR_RSN="XXX" tag then we need to copy and append that to next @pRECTYPE="SBEL record at the end of the line

            File :note : in file there will be no blank lines. I have given enter to avoid line continuation

            @pRUKE=dfgt@pRECTYPE="SMDR", @pCONFIG="Y" XXXXXXX

            @pRUKE=dfgt@pRECTYPE="SBSB", @pGWID="1234", @pSBEL_MCTR_RSN="KX28", @pSBSB_9000_COLL=""

            @pRUKE=dfgt@pRECTYPE="KBSG", @pKBSG_UPDATE_CD="IN", XXXXXXXXXXX

            @pRUKE=dfgt@pRECTYPE="SBEL", @pSBEL_EFF_DT="01/01/2017", @pCSPI_ID="JKOX0001", @pSBEL_FI="A"

            @pRUKE=dfgt@pRECTYPE="SBEK", @pSBEK_UPDATE_CD="IN",XXXXXXXXXXXXXXXXXXX

            @pRUKE=dfgt@pRECTYPE="DBCS", @pDBCS_UPDATE_CD="IN",XXXXXXXXXXXXXXXXXXXXXXXXXX

            @pRUKE=dfgt@pRECTYPE="MEME", @pMEME_REL="18", @pMEEL_MCTR_RSN="KX28"

            @pRUKE=dfgt@pRECTYPE="ATT0", @pATT0_UPDATE_CD="AP",XXXXXXXXX

            @pRUKE=dfgt@pRECTYPE="SBSB", @pGWID="1234", @pSBEL_MCTR_RSN="KX28", @pSBSB_9000_COLL=""

            @pRUKE=dfgt@pRECTYPE="KBSG", @pKBSG_UPDATE_CD="IN", XXXXXXXXXXX

            example :

            Before : @pRUKE=dfgt@pRECTYPE="SMDR", @pCONFIG="Y" XXXXXXX

            @pRUKE=dfgt@pRECTYPE="SBSB", @pGWID="1234", @pSBEL_MCTR_RSN="KX28", @pSBSB_9000_COLL=""

            @pRUKE=dfgt@pRECTYPE="KBSG", @pKBSG_UPDATE_CD="IN", XXXXXXXXXXX

            @pRUKE=dfgt@pRECTYPE="SBEL", @pSBEL_EFF_DT="01/01/2017", @pCSPI_ID="JKOX0001", @pSBEL_FI="A"

            After:

            @pRUKE=dfgt@pRECTYPE="SMDR", @pCONFIG="Y" XXXXXXX

            @pRUKE=dfgt@pRECTYPE="SBSB", @pGWID="1234", @pSBEL_MCTR_RSN="KX28", @pSBSB_9000_COLL=""

            @pRUKE=dfgt@pRECTYPE="KBSG", @pKBSG_UPDATE_CD="IN", XXXXXXXXXXX

            @pRUKE=dfgt@pRECTYPE="SBEL", @pSBEL_EFF_DT="01/01/2017", @pCSPI_ID="JKOX0001", @pSBEL_FI="A", @pSBEL_MCTR_RSN="KX28"

            if after SBSB, if there is no SBEL, then that SBSB can be ignored.

            what i did is egrep -n "pRECTYPE="SBSB"|pRECTYPE="SBEL"" filename | sed '$!N;/pRECTYPE="SBEL"/P;D' | awk -F: '{print $1}' | awk 'NR%2{printf "%s,",$0;next;}1' > 4.txt;

            by this i will get the line number eg: 2,4 17,19

            line 9 12 14 will be ignored

            while read line do

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:47

            For performance, you need to really limit how many external tools you invoke inside a loop in a shell script.

            This requires GNU awk:

            Source https://stackoverflow.com/questions/67992675

            QUESTION

            How to force pull / checkout branch that was recreated on origin?
            Asked 2021-Jun-11 at 11:51

            I have a release branch I call latest and I can easily recreate it from a tagged release e.g.

            ...

            ANSWER

            Answered 2021-Jun-11 at 11:51
            TL;DR

            If you must do this, use detached-HEAD mode. Have users check out origin/latest rather than creating a branch.

            (It's probably wiser to just make a new release-candidate tag. See fredrik's comment.)

            Long

            Git "dislikes it" when branch names "move backwards".1

            What I mean by this is that a branch name is expected to "move forwards", and what I mean by that is ... well, consider how Git branch names work. The purpose of a branch name is to locate the last commit that we call "part of the branch". It is the commits themselves that actually matter; the branch name just finds the last one.

            That is, we might start with a series of, say, eight total commits, which we label with the name master or main:

            Source https://stackoverflow.com/questions/67934394

            QUESTION

            Scheme equal-tree procedure
            Asked 2021-Jun-10 at 08:33

            Given a new implementation of tree in Scheme using list:

            ...

            ANSWER

            Answered 2021-Jun-09 at 23:06

            You have a reasonable-looking sequence of if tests (though using cond instead would be more idiomatic Scheme). But the values you return do not generally look correct.

            The first problem I see is in your first if clause. If both trees are empty, you return '(). But according to the spec, you should be calling the succ function with that result. This may look unimportant if you use id as your continuation, but note that each recursive step builds up a more detailed succ continuation, so in general succ may be a quite impactful function.

            The second if is also a problem. Again you return '(), when you are supposed to return the first conflicting subtrees. It's not clear to me what that means, but it would be reasonable to pass a pair of tree1 and tree2 to fail.

            The third and fourth clause look fine. You call succ with a pair of the two leaves, as expected.

            The recursive call is clearly wrong: you have mis-parenthesized calls to cons, and your lambda variable is named X but you refer to it as x. The series of cons calls doesn't really look right either, but you can experiment with that once your more pressing syntactic issues are resolved and your base cases work properly.

            Lastly, you are doing a lot of low-level work with cons, car, '(), and so on. You should be using the abstract functions provided to you, such as add-subtree and (make-tree), instead of using the low-level primitives they are built on.

            Source https://stackoverflow.com/questions/67905688

            QUESTION

            Why can't comments appear after a line continuation character?
            Asked 2021-Jun-09 at 23:06

            Why does Python not allow a comment after a line continuation "\" character, is it a technical or stylistic requirement?

            According to the docs (2.1.5):

            A line ending in a backslash cannot carry a comment.

            and (2.1.3):

            A comment signifies the end of the logical line unless the implicit line joining rules are invoked. Comments are ignored by the syntax.

            PEP 8 does discourage inline comments so I can see how this may stylistically be "unpythonic." I could also see how the "\" could be ambiguous if it allowed comments (should the interpreter ignore all subsequent tokens or just comments?) but I think a distinction could easily be made.

            Coming from Javascript and accustomed to the fluid interface style, I prefer writing chains like the following instead of reassignment:

            ...

            ANSWER

            Answered 2021-Jun-09 at 21:48

            For the same reason you can't have whitespace after the backslash. It simplifies the parsing, as it can simply remove any backslash-newline pairs before doing any more parsing. If there were spaces or comments after the backslash, there's no backslash-newline sequence to remove.

            Source https://stackoverflow.com/questions/67912068

            QUESTION

            Borrowed value does not live enough?
            Asked 2021-Jun-07 at 23:05

            This is the continuation of `RefCell` cannot be shared between threads safely?, made a new Q for better presentation.

            I made a minimal main with a Mutex, but now test_for_closure does not live long enough and is dropped here while still borrowed. What a ride! :)

            Rust playground link: https://play.rust-lang.org/?version=nightly&mode=debug&edition=2018&gist=7bf56545350624e75aafa10524ea59ff

            ...

            ANSWER

            Answered 2021-Jun-07 at 23:05

            There are two issues, first of all, Body only implements From<&'static str> but the given &str is bound to the lifetime on the MutexGuard, therefore the Body::from call fails with a lifetime error. You can work around this via foo.clone().

            The second issue is about the multiple nested scopes which would require additional clone()s on the Arc> and move on the service_fn closure. The following compiles:

            Source https://stackoverflow.com/questions/67879442

            QUESTION

            `RefCell` cannot be shared between threads safely?
            Asked 2021-Jun-07 at 19:21

            This is a continuation of How to re-use a value from the outer scope inside a closure in Rust? , opened new Q for better presentation.

            ...

            ANSWER

            Answered 2021-Jun-07 at 19:19

            The first error in your error message is that Sync is not implemented for RefCell. This is by design, as stated by Sync's rustdoc:

            Types that are not Sync are those that have “interior mutability” in a non-thread-safe form, such as Cell and RefCell. These types allow for mutation of their contents even through an immutable, shared reference. For example the set method on Cell takes &self, so it requires only a shared reference &Cell. The method performs no synchronization, thus Cell cannot be Sync.

            Thus it's not safe to share RefCells between threads, because you can cause a data race through a regular, shared reference.

            But what if you wrap it in Arc ? Well, the rustdoc is quite clear again:

            Arc will implement Send and Sync as long as the T implements Send and Sync. Why can’t you put a non-thread-safe type T in an Arc to make it thread-safe? This may be a bit counter-intuitive at first: after all, isn’t the point of Arc thread safety? The key is this: Arc makes it thread safe to have multiple ownership of the same data, but it doesn’t add thread safety to its data. Consider Arc. RefCell isn’t Sync, and if Arc was always Send, Arc would be as well. But then we’d have a problem: RefCell is not thread safe; it keeps track of the borrowing count using non-atomic operations.

            In the end, this means that you may need to pair Arc with some sort of std::sync type, usually Mutex.

            Arc will not be Sync unless T is Sync because of the same reason. Given that, probably you should use std/tokio Mutex instead of RefCell

            Source https://stackoverflow.com/questions/67877287

            QUESTION

            Flutter web tabbar scroll issue with non primary scrollcontroller
            Asked 2021-Jun-07 at 09:51

            In continuation with question

            The solution provided above is good. But hard for me to implement in my project.

            Expected results:

            • I've created two tabs.
            • In each tab I have SingleChildScrollView wrapped with Scrollbar.
            • I can not have the primary scrollcontroller in both the tabs, because that throws me exception: "ScrollController attached to multiple scroll views."
            • For Tab ONE I use primary scrollcontroller, for Tab TWO I created Scrollcontroller and attached it.
            • Widgets in both the tabs should be scrollabale using keyboard and mouse.

            Actual results:

            • For Tab ONE with primary scrollcontroller I can scroll both by keyboard and dragging scrollbar.
            • But for Tab TWO with non primary scrollcontroller, I have to scroll only by dragging scrollbar. This tab doesn't respond to keyboard page up /down keys.
            • When keyboard keys are used in Tab TWO actually contents of tab ONE are getting scrolled.

            Check code:

            ...

            ANSWER

            Answered 2021-Jun-07 at 09:51

            This has been accepted as a bug in flutter. Pl follow for progress here: https://github.com/flutter/flutter/issues/83711

            Note for other developers facing same issue. To overcome the mentioned problem, I changed my design layout. Instead of tabbar view I used Navigationrail widget. This solved my problem. NavigationRail widget allowed me to attach primary scroll controller to multiple widgets without giving me exception: "ScrollController attached to multiple scroll views." Sample code.

            Source https://stackoverflow.com/questions/67789737

            QUESTION

            Oracle SQL - Find origin ID of autoincrement column
            Asked 2021-Jun-04 at 13:46

            There's a table on my ERP database that has data about certain events. It has the start date, end date and a column shows if the event is a continuation of a previous one (sequential_id references unique_id). Here's an example:

            unique_id start_date end_date sequential_id 001 2021-01-01 2021-01-15 002 2021-02-01 2021-02-16 001 003 2021-03-01 2021-03-17 002 004 2021-03-10 2021-03-11 005 2021-03-19

            In the example above, rows 001, 002 and 003 are all part of the same event, and 004/005 are unique events, with no sequences. How can I group the data in a way that the output is like this:

            origin_id start_date end_date 001 2021-01-01 2021-03-17 004 2021-03-10 2021-03-11 005 2021-03-19

            I've tried using group by, but due to sequential_id being auto incremental, it didn't work.

            Thanks in advance.

            ...

            ANSWER

            Answered 2021-Jun-04 at 13:45

            You can use hierarchical query for this:

            Source https://stackoverflow.com/questions/67837833

            QUESTION

            Using the result of a query to display images inside a php while loop one after the other
            Asked 2021-Jun-02 at 10:36

            This is a continuation of a post which I could not get an answer that works so I here I go again.

            I am trying to display images using data returned by a mySQL query. The query returns the names of an image files and a timelapse which is a number (seconds). I need to display each image for the number of seconds returned in TimeLapse.

            With help from my first post I am able to display images that are static but not from the result of the query.

            The static method works and displays all the images one after the other

            ...

            ANSWER

            Answered 2021-Jun-02 at 10:36

            The problem is because the PHP loop which creates the div elements is in the wrong place. You repeat the entire .outer structure multiple times with each containing a single .banner-container.

            You should instead loop inside the single .outer and create multiple .banner-container elements within it, like this:

            Source https://stackoverflow.com/questions/67803363

            QUESTION

            Unable to click on an ahref link using Python Selenium
            Asked 2021-Jun-01 at 08:08

            This is the html code:

            ...

            ANSWER

            Answered 2021-Jun-01 at 07:40

            You need to switch to new tab first then you can click on Print using that Id that you have been trying.

            Switch to new windows like this :

            Source https://stackoverflow.com/questions/67784552

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install continuation

            or (for a system-wide installation):. Since the module is rather small, the single file __init__.py can also be quickly renamed as continuation.py and directly put in the directory of a given project for ad hoc purposes.

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            pip install continuation

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            gh repo clone baruchel/continuation

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