koko | Extracting Entities with Limited Evidence
kandi X-RAY | koko Summary
kandi X-RAY | koko Summary
Extracting Entities with Limited Evidence
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Top functions reviewed by kandi - BETA
- Run a KOKO query
- Get all spans of the given type
- Return a list of topEntities for the given query
- Returns the top Entities from a parsed parser
- Returns a list of Mention objects
- Parse a query string
- Searches the query
- Parse condition
- Parse a literal
- Populates self _ents_entities
- Runs analysis on the given chunk
- Cache response
- Get a language service
- Render a query
- Render root page
- Populate the tokens
- Analyze the syntax of a document
- Creates a list of Segments objects
- Populates the list of sentences
- Build Mention objects from spans
- Retrieves the sentence number given a span
- Return the top entities of the query
- Find the correct entity matching the given entity
koko Key Features
koko Examples and Code Snippets
Community Discussions
Trending Discussions on koko
QUESTION
I recently started learning c++ and I have a problem with implementing my own string class with string concatenation. When the strings are added together, an error appears in debugging : I checked on many lines and noticed that the program works fine when the line is short , but stops working at all with long lines I think I messed up my memory somewhere , but I can't find where I will be very glad of any help
...ANSWER
Answered 2021-Apr-22 at 16:10There are a lot of things wrong with your code.
- Where is your
operator=? You appear to have violated the Rule of Three. This is a massive memory bug. for (int i = 1; i <= length; i++) if (i % 2 == 0)seems like a weird way to writefor (int i = 2; i <= length; i+=2). This works fine, it's just weird.operator+does not allocate enough bytes for a null terminator, so all operations after that will read past the end of the buffer. This is a massive memory bug.String(char* str)doesn't make a copy of the data, it assumes ownership of the pointer passed in. Which might work, except thatoperator+constructs aStringfromtmp, and then deletestmp, so now theString's data is gone. This is a massive memory bug.
QUESTION
i was searching for answer and trying so many options. Finally i found way to pass my own javaxf object to GridPane. But I still think there is a better way to this than I am doing. So here is my code: Main:
...ANSWER
Answered 2021-Apr-17 at 14:54As @JimD already commented, embedding a reference to the parent of a Node into a node is bad practice. There's nothing special about the Rectangles other than the event handler which toggles the colour. Assuming that you don't want to access the "selected" state of the Rectangles, you can ditch the custom class altogether.
The following code does everything that your sample does, except the call to the [not included] "ShelfShowUp.display("KOKOS", 7)" :
QUESTION
This is my first time when I need to do something with dictionaries. I can't overwrite the item.Value and i don't know how should I do that.
Write a program that reads the name of one monkey per line from the lines of standard input to the end of file (EOF) and the number of bananas it collects in the following format:
monkey_name; number of bananas
The program writes the names of the monkeys and the number of bananas they have collected to the standard output in the form given in the example output, in lexicographically ascending order based on the names of the monkeys!
Input:
...ANSWER
Answered 2021-Apr-03 at 14:44class Program
{
static void Main()
{
string input;
string[] row;
IDictionary majom = new SortedDictionary();
//int i;
//bool duplicate = false;
while ((input = Console.ReadLine()) != null && input != "")
{
//duplicate = false;
row = input.Split(';');
// Usually dictionaries have key and value
// hier are they extracted from the input
string key = row[0];
int value = int.Parse(row[1]);
// if the key dose not exists as next will be created/addded
if (!majom.ContainsKey(key))
{
majom[key] = 0;
}
// the value coresponding to the already existing key will be increased
majom[key] += value;
//foreach (var item in majom)
//{
// if (item.Key == row[0])
// {
// duplicate = true;
// i = int.Parse(row[1]);
// item.Value += i; I'm stuck at here. I dont know how am i able to modify the Value
// }
//}
//if (!duplicate)
//{
// i = int.Parse(row[1]);
// majom.Add(row[0], i);
//}
}
foreach (var item in majom)
{
Console.WriteLine(item.Key + ": " + item.Value);
}
}
}
QUESTION
I have table with json string
...ANSWER
Answered 2021-Mar-14 at 18:54Below will work for you
QUESTION
im using laravel 7 and trying to get datas from api use http.
when i use dd('$datas'),i got this
...ANSWER
Answered 2021-Jan-29 at 04:35If you look at the data you are getting back from the API, your data is actually nested inside objects that live under a manajemen_sdm property.
Your loop should work correctly if you update it to loop over the manajemen_sdm key:
QUESTION
so i made a list and i used tkinter for choosing a random data in list and showing that in a showinfo box. now i was just wondering if its possible to make a random image for random data. for eg i am making a app that generates a random anime name from the list but i want to add the anime picture also is there any way i can do that ? i haven't tried building it but here is what i have made so far.
i have no error i just want to have different picture for different names from the list chose randomly
...ANSWER
Answered 2021-Jan-14 at 09:26Since you want the image to be corresponding to the anime titles I suggest you use a dictionary instead of a list. Also, use Toplevel widget to display the output.
So here is an example code:
QUESTION
My original problem:
"I have created web scraping tool for picking data from listed houses.
I have problem when it comes to changing page. I did make for loop to go from 1 to some number.
Problem is this: In this web pages last "page" can be different all the time. Now it is 70, but tomorrow it can be 68 or 72. And if I but range for example to (1-74) it will print last page many times, because if you go over the maximum the page always loads the last."
Then I got help from Ricco D who wrote code that it will know when to stop:
...ANSWER
Answered 2020-Dec-21 at 18:44Finding your element with class name doesn't seem to be the best idea..because of this. Same class name for all the next elements.
I don't know what you are looking for exactly because of the language. I suggest..you go to the website>press f12>press ctrl+f>type the xpath..See what elements you get.If you don't know about xpaths read this. https://blog.scrapinghub.com/2016/10/27/an-introduction-to-xpath-with-examples
QUESTION
I'm a newbie in perl, how I can make this better and faster? (SPOJ task)
...ANSWER
Answered 2020-Sep-20 at 20:16Something which is divisible by 5 and 3 is divisible by 15, so your logic is more straight forward as...
- Divisible by 15
- Divisible by 5
- Divisible by 3
- Not divisible by 5 nor 3
I'd also take advantage of say.
I'd also replace the awkward until with a for and not bother with $i.
Avoid using $a and $b because these are special variables used by sort.
Turn on strict and warnings.
Strip the newline off $a. Technically not necessary if you're going to use it as a number, but if you don't printing it will have an extra newline.
A non-number % anything is 0. Unless we validate the input, if you input nothing or "bananas" you'll get SPOKOKOKO. We can check if the input looks like something Perl considers a number with Scalar::Util::looks_like_number. If it isn't a number, throw an exception; it isn't the function's job to figure out what to do with a non-number. Perl doesn't really have exceptions, but we can get close with a die and eval.
And put the logic inside a subroutine. This separates the details of the input and output from the logic. The logic can now be named, documented, tested, and reused. This also avoids the redundant say.
QUESTION
I'm having issues aligning my footer text in a straight line. I'm a beginner here so I apologize if this question is redundant! See below:
I need all three of those lines, to be in a straight line.
My professor teaches a grid method, but that's not working for me at the moment. Any suggestions?
Here is my code:
...ANSWER
Answered 2020-Aug-06 at 22:16QUESTION
public class TulosteluaLikeABoss {
public static void tulostaTahtia(int maara) {
// part 1
int i = 0;
while (maara >i) {
System.out.print("*");
i++;
}
System.out.println("");
}
public static void tulostaTyhjaa(int maara) {
// part 1.1
int i = 0;
while (maara > i) {
System.out.print(" ");
i++;
}
}
//something is wrong below
public static void tulostaKolmio(int koko) {
// part 2
int j = koko;
int k = 0;
while (koko >= k) {
tulostaTahtia(k);
tulostaTyhjaa(j);
k++;
j = j-1;
}
}
// from here below is irrelevant
public static void jouluKuusi(int korkeus) {
// part 3
}
public static void main(String[] args) {
// Testit eivät katso main-metodia, voit muutella tätä vapaasti.
tulostaKolmio(5);
System.out.println("---");
jouluKuusi(4);
System.out.println("---");
jouluKuusi(10);
}
}
ANSWER
Answered 2020-Jul-12 at 15:25tulostaKolmio(1) assigns koko the value of 1. The while loop in the method will run (koko + 1) number of times. During the first run in the loop tulostaTahita(0) gets called (since k=0 right now), altough it will not print any starts at this call it will print a new line because you have that outside the while loop in the tulostaTahita method.
During the second run in the loop, k=1 and thus tulostaTahita(1) is called. This will print another line so in the end you are left with 2 lines (where the first one is empty).
To solve this you want to add an if statement to make sure tulostaTahita only prints a new line when maara is greater than 0.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install koko
You can use koko like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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