anytree | Python tree data library

 by   c0fec0de Python Version: 2.9.0 License: Apache-2.0

kandi X-RAY | anytree Summary

kandi X-RAY | anytree Summary

anytree is a Python library typically used in Data Science applications. anytree has no bugs, it has no vulnerabilities, it has a Permissive License and it has high support. However anytree build file is not available. You can install using 'pip install anytree' or download it from GitHub, PyPI.

Python tree data library
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            kandi-support Support

              anytree has a highly active ecosystem.
              It has 807 star(s) with 120 fork(s). There are 22 watchers for this library.
              There were 1 major release(s) in the last 12 months.
              There are 40 open issues and 123 have been closed. On average issues are closed in 148 days. There are 13 open pull requests and 0 closed requests.
              It has a positive sentiment in the developer community.
              The latest version of anytree is 2.9.0

            kandi-Quality Quality

              anytree has 0 bugs and 0 code smells.

            kandi-Security Security

              anytree has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              anytree code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              anytree is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              anytree releases are available to install and integrate.
              Deployable package is available in PyPI.
              anytree has no build file. You will be need to create the build yourself to build the component from source.
              anytree saves you 1346 person hours of effort in developing the same functionality from scratch.
              It has 3017 lines of code, 292 functions and 53 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed anytree and discovered the below as its top functions. This is intended to give you an instant insight into anytree implemented functionality, and help decide if they suit your requirements.
            • The children of this node
            • Check children of children
            • Post - attach children
            • Pre - attach children
            • Parent node
            • Attach this node to the parent
            • Post - attach hook
            • Pre - attach hook
            • Returns the depth of the path
            • Iterate through children
            • Return True if the given level is at the given level
            • Get children from children
            • Import data from the given data
            • Import data
            • Return an iterator for post order
            • Yields the next child of the children
            • Returns a tuple of the path
            Get all kandi verified functions for this library.

            anytree Key Features

            No Key Features are available at this moment for anytree.

            anytree Examples and Code Snippets

            Python - tkinter: Illustration of tree in treeview
            Pythondot img1Lines of Code : 41dot img1License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            from anytree import Node, RenderTree, AsciiStyle, PreOrderIter
            from tkinter import *
            from tkinter import ttk
            
            
            udo = Node("Udo")
            marc = Node("Marc", parent=udo)
            lian = Node("Lian", parent=marc)
            dan = Node("Dan", parent=udo)
            jet = Node("Jet
            How can I take comma separated inputs for python AnyTree module?
            Pythondot img2Lines of Code : 6dot img2License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            if io!='q':
                name, role, grp = io.upper(). split(',')
                lst_input.append([name,role, grp]) 
            
            lst.append(lst_input[0][i:i + 3])
            
            Visualizing a tree with nodes of different colors with anytree
            Pythondot img3Lines of Code : 8dot img3License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            def set_color_shape(node):
                attrs = []
                attrs += [f'color={node.color}'] if hasattr(node, 'color') else []
                attrs += [f'shape={node.shape}'] if hasattr(node, 'shape') else []
                return ', '.join(attrs)
            
            DotExporter(ceo, nodeattrf
            Build a tree from a list of objects
            Pythondot img4Lines of Code : 63dot img4License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            import itertools
            
            import anytree
            
            data = [
                ['100km/h', '20m', '10uSv'],
                ['100km/h', '40m', '10uSv'],
                ['100km/h', '60m', '20uSv'],
                ['120km/h', '40m', '20uSv'],
                ['120km/h', '40m', '30uSv'],
                ['120km/h', '60m', '20uSv']
            How to retrieve all attributes of an anytree Node?
            Pythondot img5Lines of Code : 4dot img5License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            s0.__dict__.items()
            
            [(k, v) for k, v in s0.__dict__.items() if k not in ('name', 'parent', 'children')]
            
            Get parent node name in anytree
            Pythondot img6Lines of Code : 23dot img6License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            from anytree import Node
            from anytree import find
            
            root = Node("f")
            b = Node("b", parent=root)
            d = Node("d", parent=b)
            c = Node("c", parent=d)
            
            name='c'
            result = find(root, lambda node: node.name == name)
            
            print('result Node:', result)
            
            if
            Untrackable object attribute
            Pythondot img7Lines of Code : 14dot img7License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            for level in levels:
                for node in level:
                    gate = node.name
                    if node.is_leaf:
                        # set `garblers_label` and `evaluators_label` from 
                        # the next two elements of the `labels` argument 
                    else:
                 
            Why is my PLY parser not grouping anytree nodes together properly?
            Pythondot img8Lines of Code : 30dot img8License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            p[0] = Node(p[2],children = [Node(p[1]),Node(p[3])])
            
            p[0] = Node(p[1], children = [Node(p[2])])
            
            p[0] = Node("GROUP", children = [Node(p[2])])
            
            #binary operators
            def 
            Generate tree from file with indents using anytree
            Pythondot img9Lines of Code : 36dot img9License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            treestring = '''
            ROOT
               Node1
                  Node2
                     Node3
                        Node4
               Node5
               Node6'''.strip()
            
            leaves = treestring.splitlines()
            
            # initialize stack with the root node
            stack = {0: Node(leaves.pop(0))}
            
            for leaf in leaves:
                
              
            Convert a nested list into rows using python
            Pythondot img10Lines of Code : 27dot img10License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            import itertools as it
            def flatten(d, s = False):
               if not s:
                  l = [[i] if not isinstance(i, list) else flatten(i, True) for i in d]
                  yield from it.product(*l)
               else:
                  for i in d:
                     if not isinstance(i, list):
                

            Community Discussions

            QUESTION

            Python - tkinter: Illustration of tree in treeview
            Asked 2022-Mar-25 at 17:38

            Is their a way to illustrate some tree like:

            ...

            ANSWER

            Answered 2022-Mar-25 at 17:38

            Found some way, but dont't know if their is some better method to solve the problem.

            Code:

            Source https://stackoverflow.com/questions/71614181

            QUESTION

            How can I take comma separated inputs for python AnyTree module?
            Asked 2022-Feb-20 at 08:43

            Community. I need to accept multiple comma-separated inputs to produce a summary of information ( specifically, how many different employees participated in each group/project)? The program takes employees, managers and groups in the form of strings.

            I'm using anytree python library to be able to search/count the occurrence of each employee per group. However, this program is only accepting one value/cell at a time instead of multiple values.

            Here is the tree structure and how I accept input values?

            ...

            ANSWER

            Answered 2022-Feb-13 at 12:47

            I believe one way to go about it is:

            Source https://stackoverflow.com/questions/71079342

            QUESTION

            Visualizing a tree with nodes of different colors with anytree
            Asked 2022-Feb-14 at 22:59

            I am looking for a simple way to construct and draw a tree (on google colab).

            Importantly, I would like to have nodes of different colors and shapes. Ideally, I would like something as follows.

            ...

            ANSWER

            Answered 2022-Feb-14 at 22:59

            Anytree's DotExporter has a nodeattrfunc argument, where you can pass a function that accepts a Node and returns the attributes it should be given in a DOT language string. Thus, if you have stored your color and shape information as node attributes, you can use a custom nodeattrfunc like the following to translate those into DOT attributes:

            Source https://stackoverflow.com/questions/70746580

            QUESTION

            Build a tree from a list of objects
            Asked 2022-Jan-24 at 22:58

            I am trying to build a tree from a list of objects, which are characterised by several properties. Each object can have 3 properties that play a role in building a tree, that is velocity altitude exposure.

            ...

            ANSWER

            Answered 2022-Jan-24 at 22:58

            You dont provide original data, so I tried to guess them.

            I started with constructing nested dicts and then converting them to anytree format with recursive function.

            Here is the code:

            Source https://stackoverflow.com/questions/70828307

            QUESTION

            How to retrieve all attributes of an anytree Node?
            Asked 2022-Jan-03 at 13:01

            For an anytree Node, how can I get all the attributes and their values?

            For example, if I do:

            ...

            ANSWER

            Answered 2022-Jan-03 at 13:01

            This is working in your case:

            Source https://stackoverflow.com/questions/70565977

            QUESTION

            Get parent node name in anytree
            Asked 2021-Nov-23 at 09:17

            I have created a tree using anytree for my custom taxonomy and I am able to search the tree using:

            ...

            ANSWER

            Answered 2021-Nov-23 at 00:30

            Three things to note:

            1. you can cast anytree.Node to a string
            2. the first 6 characters of the stringified Node class is always Node(' and the last 2 characters are always ')
            3. the anytree.Node class has a separator attribute which you can use to split the stringified Node on

            Combining these facts:

            Source https://stackoverflow.com/questions/70072804

            QUESTION

            Untrackable object attribute
            Asked 2021-Aug-18 at 16:13

            I am trying to adapt this code here: https://github.com/nachonavarro/gabes/blob/master/gabes/circuit.py (line 136) but am coming across an issue because several times the attribute .chosen_label is used but I can find no mention of it anywhere in the code. The objects left_gate, right_gate and gate are Gate objects (https://github.com/nachonavarro/gabes/blob/master/gabes/gate.py)

            ...

            ANSWER

            Answered 2021-Aug-18 at 16:13

            The attribute is set in the same method:

            Source https://stackoverflow.com/questions/68835311

            QUESTION

            Why is my PLY parser not grouping anytree nodes together properly?
            Asked 2021-Aug-05 at 01:04

            I am trying to build a CAS in Python and am currently stuck on implementing the parser I will use to go from expression string to an Anytree tree I can eventually manipulate and simplify. The issue seems to be that, when parsing, yacc doesn't implement my GROUP node with it's proper children nodes as defined in my parser grammar spec. I've tried messing with precedences and associativities, switching up the order of the grammar rules but nothing seems to make it parent the nodes properly. What's even stranger is that in debug/verbose mode, it makes a node for the expression when it pattern-matches to it, but it (for some reason) fails to parent it to the GROUP node when it recognises an LPAREN expression RPAREN token

            Here's my code:

            ...

            ANSWER

            Answered 2021-Aug-05 at 01:04

            The first argument to Node is expected to be a string. (In fact, it's expected to be a string which labels the node, but I'll get back to that in a minute.) If it's not a string, it's converted to one.

            So consider your action:

            Source https://stackoverflow.com/questions/68655461

            QUESTION

            Generate tree from file with indents using anytree
            Asked 2021-Jul-10 at 21:25

            I'm using anytree to generate a tree from a file, Tree.txt. Each indent is 3 spaces ( ). Here's what my file looks like:

            ...

            ANSWER

            Answered 2021-Jul-10 at 21:25

            You'll need a kind of stack to keep track of the depth of the nodes, then you can use the number of initial spaces to determine which parent node to append each leaf to. E.g., three spaces means one level down, so you need to append to the root node at index 0 in the stack. (You could also say that by using a stack we are taking the absolute depth of the leaves, while you tried to solve it relatively if I'm making any sense). I suspect if you use find_by_attr, that might not work in case there are leaves with the same name.

            Source https://stackoverflow.com/questions/68329540

            QUESTION

            Convert a nested list into rows using python
            Asked 2021-May-02 at 04:03

            I am experiencing a scenario where my indigenous recursive implementation program output's a nested list, very similar to a tree. The nested list designed is an abstraction of a complicated structure. What I would require, is to resolve the nested list into many different rows as much as combinations available (optionally implementing recursion).

            Previously I tried anytree but my needs are complicated and though good, it was not yielding to my tailored demand. Please do take into account that the nested list is multi-dimensional

            input 1

            ...

            ANSWER

            Answered 2021-May-02 at 04:03

            You can use recursion with itertools.product:

            Source https://stackoverflow.com/questions/67352577

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install anytree

            You can install using 'pip install anytree' or download it from GitHub, PyPI.
            You can use anytree like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            Install
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            pip install anytree

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            https://github.com/c0fec0de/anytree.git

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            gh repo clone c0fec0de/anytree

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            git@github.com:c0fec0de/anytree.git

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