ad-password-self-service | password self-service platform | Regex library
kandi X-RAY | ad-password-self-service Summary
kandi X-RAY | ad-password-self-service Summary
Based on the password self-service platform of Python 3.8 + Django 3.2, AD users can change their passwords by themselves. Combined with <DingTalk>/<Enterprise WeChat> application password-free authorization, they can reset their passwords and unlock their own accounts.
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Top functions reviewed by kandi - BETA
- Handle a callback
- Determine the event type
- Decrypts a string
- Set app ticket
- Delete a user
- Make a POST request
- Generate request url
- Base request
- Create a new chat
- Update the spreadsheet s properties
- Create a calendar event
- Create an approval
- Update app visibility
- Update a department
- Get a list of visible applications
- Update chat info
- Create a new department
- Batch send message
- Gets a list of department details
- Batch update a spreadsheet
- Get a list of rooms
- Update calendar event
- Reset password by callback
- The index view
- Open a mini program
- Updates the Drive file public permission
ad-password-self-service Key Features
ad-password-self-service Examples and Code Snippets
# ########## AD配置,修改为自己的
# AD主机,可以是IP或主机域名,例如可以是: abc.com或172.16.122.1
AD_HOST = r'修改成自己的'
# AD域控的DOMAIN名,例如:abc
AD_DOMAIN = r'修改成自己的'
# 用于登录AD做用户信息处理的账号,需要有修改用户账号密码或信息的权限。
# AD账号,例如:pwdadmin
AD_LOGIN_USER = r'修改成自己的'
# 密码
AD_LOGIN_USER_PWD = r'修改为
# ########## AD配置,修改为自己的
# AD主机,可以是IP或主机域名,例如可以是: abc.com或172.16.122.1
AD_HOST = r'修改成自己的'
# AD域控的DOMAIN名,例如:abc
AD_DOMAIN = r'修改成自己的'
# 用于登录AD做用户信息处理的账号,需要有修改用户账号密码或信息的权限。
# AD账号,例如:pwdadmin
AD_LOGIN_USER = r'修改成自己的'
# 密码
AD_LOGIN_USER_PWD = r'修改为
#!/bin/sh
INI="PWD_SELF_SERVICE_HOME/uwsgi.ini"
UWSGI="/usr/share/python-3.6.9/bin/uwsgi"
PSID=`ps aux | grep "uwsgi"| grep -v "grep" | wc -l`
if [ ! -n "$1" ]
then
content="Usages: sh uwsgiserver [start|stop|restart]"
echo -e "\033[31m $co
Community Discussions
Trending Discussions on Regex
QUESTION
I have the following regex: /\.([s]?[ac]ss)$/
. The problem is, it matches .scss
, .sass
, .css
, .ass
. How would I make it not match .ass
?
ANSWER
Answered 2022-Mar-02 at 08:35You can use
QUESTION
I have an array of 5 numbers, I'd like to match as long as there are three of the same number and two of the same different number in the array, placement does not matter. Number sequences can be any random string of 5 numbers between 1 - 5.
Examples of matches would be:
33322
24422
52225
44111
54545
*basically any grouping of 2 and 3 of the same numbers needs to match.
Best I've come up with so far:
^([0-9])\1{2}|([0-9])\1{1}$
I am not so good with regex, any help would be greatly appreciated.
...ANSWER
Answered 2022-Jan-16 at 23:38You can use
QUESTION
Currently, this is my code.
...ANSWER
Answered 2022-Jan-06 at 04:57A simple solution would be to convert all characters to lowercase, replace any character that isn't a-z, 0-9, or a space with a space character, and then replace multiple space characters with a single space character.
QUESTION
I am generating some meaningful name with the following rule in a JavaScript/Node JS program:
Input: "tenancy_account__accountPublicId__workspace__workspacePublicId__remove-user__userPublicId"
Expected output: "TenancyAccountAccountPublicIdWorkspaceWorkspacePublicIdRemove-userUserPublicId"
Rules:
- replace any character with zero or more underscore to the non-underscored uppercase
Example:
x | __*x => X
- If exists remove last _
This is what is tried so far, looking for better alternatives, if any:
...ANSWER
Answered 2021-Dec-17 at 14:21Split and slice
QUESTION
Java 11 added some new methods to the Pattern
class (a compiled version of a regular expression), including:
I am trying to understand the difference between the two and when I would want to use one over the other?
...ANSWER
Answered 2021-Nov-16 at 14:57Pattern.asPredicate
will return true if any part of the input string matches the Regular expression. You should use this method if you're testing some larger body of text for a certain pattern. For example, to test whether a comment from a user contains a hyperlink.Pattern.asMatchPredicate
will return true if the entire input string matches the Regular expression. You should use this method if you're testing the entire input for a certain pattern. For example, to validate the phone number of a user in their profile.
Pattern.asPredicate
internally uses Matcher.find()
, while Pattern.asMatchPrediate
internally uses Matcher.matches()
. So the difference between the two boils down to the difference between these two methods from the Matcher
class.
Below are some examples to showcase the difference. You can copy & paste below code in an online Java sandbox like https://www.compilejava.net/ to play around with it yourself.
QUESTION
I am trying to replace a single occurrence of a character '1' in a String with a different character.
This same character can occur multiple times in the String which I am not interested in.
For example, in the below string I want to replace the single occurrence of 1 with 2.
...ANSWER
Answered 2021-Nov-13 at 09:22Use a negative lookahead in the regexp to match a 1
that isn't followed by another 1
:
QUESTION
I'm attempting to solve a very simple problem - find strings in an array which only contain certain letters. However, I've run up against something in the behavior of regular expressions and/or grep
that I don't get.
ANSWER
Answered 2021-Nov-02 at 13:15Both fails
are fixed with the addition of anchors ^
and $
and quantifier +
These both work:
QUESTION
I'm looking for a regexp that matches any line that contains 'B', 'R', 'A' and 'S' (in any order) at the start. It would match all the following lines, except the last two.
...ANSWER
Answered 2021-Oct-30 at 21:05There are only 24 permutations :)
QUESTION
I have a Json file having multiple comments and I want to replace a value in it.
I tried the below and it gives me a json file without comments. But I don't understand how to change the value and save it back with comments. Is this even possible because we are replacing all the comments with empty lines?
...ANSWER
Answered 2021-Oct-22 at 22:32Use
QUESTION
The header question may not be easy to understand. Hope you can understand my detailed info below.
I have sentence data below, that has some tags, represented by [tn]tag[/tn]
:
ANSWER
Answered 2021-Oct-04 at 08:47Here is a solution that assumes that there are no nested tags, that all tags open and close in the part. Also, this assumes that all characters from the sentence are in parts
. For this last assumption, I had to add the .
after it has to be in the second expected part. I also had to remove newline characters from the sentence but I think it was because of the copy/paste.
This solution will loop through all characters and store two parallel buffers : one with the tags, one without. We will use the second one to compare with the parts, and use the first one to generate the output.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install ad-password-self-service
You can use ad-password-self-service like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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