bunny1 | write smart bookmarks in python and then share
kandi X-RAY | bunny1 Summary
kandi X-RAY | bunny1 Summary
bunny1 is a tool that lets you write smart bookmarks in python and then share them across all your browsers and with a group of people or the whole world. It was developed at Facebook and is widely used there.
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Top functions reviewed by kandi - BETA
- Run a command .
- Generate the help text .
- Main entry point .
- Lists all available commands .
- Main function .
- Set the password .
- Rewrite a URL .
- Add basic options .
- Check if x is an integer .
- Decorate a function as a preprocessor .
bunny1 Key Features
bunny1 Examples and Code Snippets
Community Discussions
Trending Discussions on bunny1
QUESTION
I was trying to build a program and got a problem of storing data into an array after each click of a button. After each click, I am sending some data through ajax to a php page and i want to store all sent data in an array and display them in an tabular format later.
I have checked in the console by inspect element and the problem arising is its always overwrites the old value in an array to a new value. I dont find where i am wrong. if someone please help me will be of great help.
...ANSWER
Answered 2018-Nov-15 at 16:42This does not work, because each time you make the AJAX call you start a new instance of the PHP script, that does not know about the other calls.
You have a couple of options:
- Store the previous array entries in a server session
- Store the previous array entries in a DB
- Collect all data about buttons on client side (in Java Script) and send the whole array to your PHP script
For your case I would recommend a server session.
Here is an example code (untested) with rudimentary session handling:
QUESTION
CREATED A FIDDLE HERE: https://jsfiddle.net/jqqn2gg7/
I posted a fiddle above about my issue. If you go to "Bunny1" you can hover on the bunnies and you'll see that you can open the first one, but the second one won't even budge. I tried everything, even the first bunny stopped working. Went back to working thou.
What is missing here?
I also tried to use "Escape" button to close instead of only the "X" button.
I'll post my issue code here:
...ANSWER
Answered 2017-Aug-23 at 09:02You can use getElementsByClassName
instead of getElementById
.
Check this fiddle: fiddle
QUESTION
I'm testing movement for a practice game I'm working on, what I'm trying to get going with is a loop that will run twice (because the object is a rabbit) inside of an interval so that the object won't move in a continuous circle and it'll have uniqueness to it. How I'm executing it is the interval will run every 1500 miliseconds and the timeout (inside the interval) will run in half of that time to create the rabbit moving in one direction twice instead of once. The problem is after some time the bunny will take larger steps forword and do so faster. I'm not completely sure what the problem is, thank you for looking at this. Heres my code
...ANSWER
Answered 2017-Jun-17 at 21:57You immediately invoke mv after creating it in bunny1move, but after each call to mv it sets a timeout to call itself again one second later. After it gets called again it sets a new timeout to call itself after the next second, and so on. This chain of calls extends ad infinitum.
This by itself wouldn't be too bad, actually it seems like it would be what you want, to have mv called every second. The problem happens when you call bunny1move every two seconds, each of these repeating calls to bunny1move creates a new chain of mv's and they all stack on top of the previous chains.
So it's not so much that the bunny is moving farther on each iteration, it's that more and more mv chains are being created, and they are all being called in sync, making it look like a longer jump when really it's just many more little jumps.
If you put a console.log statement at the end of mv you can see this increase in mv calls over time.
You should just be able to get rid of mv altogether, then call setInterval on bunny1move for every second:
QUESTION
I'm trying to place an image on a certain spot on a div. Here is what it looks like so far. The boxed area is where I wish to display the image (which is circled).
I tired mutliple ways yet the image only seems to
- Remain on the left
- Move to the right but goes under the text
What I'm trying to achieve is to place the image on top of the listed text so it can fill in the empty area. Also, I am trying to make sure that the scrollbar doesn't appear.
Any help is much appreciated!
css
...ANSWER
Answered 2017-May-28 at 14:24You need the img
to be above the elements you want floated beside of it. So just move the img
before the list. And if you want to move it down on the page, use margin
or transform: translateY()
.
But your li
' also need to be in a ul
, and the center
tag is deprecated - you need to use CSS for that instead.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install bunny1
You can use bunny1 like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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