zodiac | A monkeypatching library for python | Download Utils library

by colinmarc Python Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | zodiac Summary

zodiac is a Python library typically used in Utilities, Download Utils applications. zodiac has no bugs, it has no vulnerabilities, it has build file available and it has low support. You can download it from GitHub.

zodiac - unite monkey and snake.

Support

Quality

Security

License

Reuse

Support

zodiac has a low active ecosystem.

It has 52 star(s) with 0 fork(s). There are 4 watchers for this library.

It had no major release in the last 6 months.

zodiac has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of zodiac is current.

Quality

zodiac has 0 bugs and 0 code smells.

Security

zodiac has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

zodiac code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

zodiac does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

zodiac releases are not available. You will need to build from source code and install.

Build file is available. You can build the component from source.

Installation instructions are not available. Examples and code snippets are available.

zodiac saves you 68 person hours of effort in developing the same functionality from scratch.

It has 178 lines of code, 28 functions and 5 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed zodiac and discovered the below as its top functions. This is intended to give you an instant insight into zodiac implemented functionality, and help decide if they suit your requirements.

Patch source to dest
Rebase a function
Rebase a class
Builds a patched patch
Get a value from an object
Rebase an object
Replace a module
Internal helper to set attributes
Create a closure cell from obj

Get all kandi verified functions for this library.

zodiac Key Features

No Key Features are available at this moment for zodiac.

zodiac Examples and Code Snippets

No Code Snippets are available at this moment for zodiac.

Community Discussions

Trending Discussions on zodiac

Why does flexWrap: 'wrap' doesn't work in my React Native application?

Spring application can't get access to the Controller

Pyspark: How to filter dataframe based on string and absence of prefix?

for statement from dictionary, python

Is there other way of getting an input like date format?

How can I loop through all categories to display each category post separately?

Combining environment variables in Cypress?

IF condition is evaluated wrong for string comparison

Pyspark: create new column by splitting text

Convert datetime into a zodiac name

QUESTION

Why does flexWrap: 'wrap' doesn't work in my React Native application?

Asked 2021-Mar-05 at 15:40


  
    
  

  {/* 11 more similarly sized images in View containers */}

...

ANSWER

Answered 2021-Mar-05 at 12:30

When the height of the content is greater than the height of the Screen, always think to use ScrollVIew instead You for a better UI it's also better to use Dimension package like

Source https://stackoverflow.com/questions/66492540

QUESTION

Spring application can't get access to the Controller

Asked 2021-Mar-04 at 06:01

http://localhost:8080 working correctly and showing index.jsp

When I write http://localhost:8080/hello it shows:

HTTP Status 404

Type Status Report

Description The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.

Doesn't outputting Test in console because it just doesn't get into the method

Tried everything. Don't know why it doesn't work.

Really need your help!

pom.xml:

...

ANSWER

Answered 2021-Mar-04 at 06:01

I copied all your files without any changes and my /hello mapping is working. Try to launch this code: https://drive.google.com/file/d/1c2BEFgD2c4uQAGA1kE6KD7w4aX98c5ZF/view?usp=sharing. If it's not working for you, try correctly configure your tomcat server in IDE settings, maybe problem in it.

Source https://stackoverflow.com/questions/66465295

QUESTION

Pyspark: How to filter dataframe based on string and absence of prefix?

Asked 2021-Feb-03 at 17:45

I have a pyspark dataframe like so with rows that have 'zodiac' and rows that have 'nonzodiac'

...

ANSWER

Answered 2021-Feb-03 at 09:12

It is because nonzodiac contains zodiac substring. You need to write more strict regexp For example add one more character:

Source https://stackoverflow.com/questions/66018007

QUESTION

for statement from dictionary, python

Asked 2021-Jan-22 at 02:06

Basically, I am new to programming and I sign up for a python course. I receive an exercise asking as follow:

Build a function that returns, given an arbitrary birth year, the Chinese zodiac sign corresponding to that calendar year. You start from a dictionary of Chinese zodiac signs from 2001-2012 (covering the whole 12-sign cycle)

So my idea is to create a dictionary,

...

ANSWER

Answered 2021-Jan-22 at 01:52

You are on the right track. You can create a dictionary to store the Chinese Zodiac Signs. Since there are 12 of them and to make the math easier, let's get the modulus value of 12 for each year. That makes mod 0 = Monkey,... mod 11 = Goat.

With that, you can do year % 12 will result with a number that we can use to extract the value from the dictionary d. The way to extract the value from the dictionary is dict[key]. In our case it will be d[0] will give Monkey.

With that, we can write the program as follows:

Source https://stackoverflow.com/questions/65838141

QUESTION

Is there other way of getting an input like date format?

Asked 2021-Jan-21 at 17:11

I was hoping and looking for some other ideas or ways to do this. As you can see, I asked the user for the input which is mmddyyyy (05022001 = May 2, 2001) and used substring in order for me to to take the certain input in the index then parse it. Now, What I want to accomplish is to find another way to do this for example is using the formal date formatter which in my case I didn't use. I think date formatter is alot better than this, but I don't get the idea out of it.

Here's what I've got so far. Thanks in advance.

...

ANSWER

Answered 2021-Jan-21 at 17:11

You should inform the user of what format you expect.

Take the input string and make a parse attempt. Trap for exception in case of faulty input. No need for you to check the ranges of month and day. LocalDate.parse makes those data entry validation checks for you.

Source https://stackoverflow.com/questions/65831738

QUESTION

How can I loop through all categories to display each category post separately?

Asked 2021-Jan-10 at 17:05

I'm developing a simple wordpress site. I've created a home page named home.php and trying to dynamically display posts separately according to category. the code is the following:

...

ANSWER

Answered 2021-Jan-10 at 17:05

Have you tried using category_id as the argument for category instead of category_name in your $query_args?

Also, you should get your categories dynamically instead of creating the array for categories manually. Otherwise, you'll have a problem if you add or remove categories in the future. Have a look at https://developer.wordpress.org/reference/functions/get_categories/.

Source https://stackoverflow.com/questions/65645487

QUESTION

Combining environment variables in Cypress?

Asked 2020-Dec-10 at 01:09

This is a follow up to my How to refer to environment variables in Cypress config files? post. Steve Zodiac's answer is the correct one indeed.

So I have a config file with environment block like this

...

ANSWER

Answered 2020-Dec-10 at 01:09

--env '{"db":{"user":"db_user","password":"pw1234"}}'cyress are you sure its working ?

Source https://stackoverflow.com/questions/65192264

QUESTION

IF condition is evaluated wrong for string comparison

Asked 2020-Nov-09 at 07:52

When you type the zodiac sign in the parameter, an example is "Leo" or "LEO", the output should appear as "This user is a LEO" but when I do it only shows me the word "INVALID".

Can someone help me so that when I try to type a specific word it will appear as what the conditions states?

This is my code:

...

ANSWER

Answered 2020-Nov-08 at 17:25

Instead: if zodiac = 'Capricorn''CAPRICORN' You should have: if zodiac = 'Capricorn' or zodiac = 'CAPRICORN'

Source https://stackoverflow.com/questions/64739555

QUESTION

Pyspark: create new column by splitting text

Asked 2020-Nov-02 at 19:49

I have a pyspark dataframe like this:

...

ANSWER

Answered 2020-Nov-02 at 19:49

I would use from pyspark.sql.functions import regexp_extract:

Source https://stackoverflow.com/questions/64652253

QUESTION

Convert datetime into a zodiac name

Asked 2020-Oct-11 at 21:32

I have a date of someone's birth as "12/02/1980 00:00:00" but I want to convert it into a zodiac name. So I want 12/02/1980 to be displayed as Sagittarius. Is that possible to do?

...

ANSWER

Answered 2020-Oct-10 at 12:34

Can do something like this

Source https://stackoverflow.com/questions/64292953

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install zodiac

You can download it from GitHub.
You can use zodiac like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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