bandicoot | source python toolbox to analyze mobile phone metadata

 by   computationalprivacy Python Version: 0.6.0 License: MIT

kandi X-RAY | bandicoot Summary

kandi X-RAY | bandicoot Summary

bandicoot is a Python library typically used in Utilities applications. bandicoot has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. However bandicoot has 2 bugs. You can install using 'pip install bandicoot' or download it from GitHub, PyPI.

an open-source python toolbox to analyze mobile phone metadata
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            kandi-support Support

              bandicoot has a low active ecosystem.
              It has 217 star(s) with 59 fork(s). There are 30 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 2 open issues and 21 have been closed. On average issues are closed in 144 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of bandicoot is 0.6.0

            kandi-Quality Quality

              bandicoot has 2 bugs (0 blocker, 0 critical, 2 major, 0 minor) and 38 code smells.

            kandi-Security Security

              bandicoot has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              bandicoot code analysis shows 0 unresolved vulnerabilities.
              There are 10 security hotspots that need review.

            kandi-License License

              bandicoot is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              bandicoot releases are available to install and integrate.
              Deployable package is available in PyPI.
              Build file is available. You can build the component from source.
              bandicoot saves you 1810 person hours of effort in developing the same functionality from scratch.
              It has 3999 lines of code, 299 functions and 52 files.
              It has high code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed bandicoot and discovered the below as its top functions. This is intended to give you an instant insight into bandicoot implemented functionality, and help decide if they suit your requirements.
            • Read a csv file
            • Compute missing neighbors
            • Load the attributes from a CSV file
            • Prints a summary of the individual records
            • Decorator for grouping functions
            • Cache a grouping query
            • Generate a grouping query
            • Wraps a function that performs aggregation
            • Export a list of objects to a JSON file
            • Calculate the radius of the gyration
            • Computes the clustering coefficient
            • Start visualization
            • Calculate the balance of a list of contacts
            • Calculate the assortativity of attributes
            • Decorator to group recharges
            • Compute the clustering coefficient of an undirected user
            • Decorator for spatial spatial grouping
            • Resolve the list of records
            • Performs the DBSCAN clustering
            • Read Orange calls
            • Read the cellic elevation table
            • Compute the response rate for a list of records
            • Count the assortativity of a user
            • Export a list of objects to a csv file
            • Calculate the response delay for each conversation
            • Compute the churn rate for a given user
            Get all kandi verified functions for this library.

            bandicoot Key Features

            No Key Features are available at this moment for bandicoot.

            bandicoot Examples and Code Snippets

            Pygame Hangman Easier Way To Generate New Words? Instead Of Making Another Main Loop
            Pythondot img1Lines of Code : 136dot img1License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            def hangmanGuess( secret_word, guess_letter, used_letters ):
                """ Given a guess, return "correct" if the letter is in the secret, but
                    already used.  Return "fail" if the letter is not in the secret, and
                    "duplicate" for a
            Web Scraping Ebay Using Python and BeautifulSoup
            Pythondot img2Lines of Code : 14dot img2License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            title=".*?"
            
            import re
            
            pattern =r'title=".*?"'
            text ='''
            
            How to sort a list to be in descending order by numbers after :
            Pythondot img3Lines of Code : 6dot img3License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            x = ['A: 10', 'B: 2', 'C: 12']
            x.sort(key=lambda y:int(y.split(":")[-1]), reverse=True)
            print(x)
            
            ['C: 12', 'A: 10', 'B: 2']
            
            Print() does not work in 'for' loop with zip()
            Pythondot img4Lines of Code : 20dot img4License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            for info in zip(titles,prices, tags, total_platforms):
                print(info)
            
            ('Dungeon Warfare 2', 'COL$ 22.500', ['Indie', 'Strategy', 'Tower Defense'], ['win', 'mac'])
            ('Kingdom Come: Deliverance – From the Ashes', 'CO
            Pythonanywhere - Return multiple lines of text
            Pythondot img5Lines of Code : 9dot img5License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            
            This game(s) belongs to you:
                
              {% for title in titles %}
            • {{title}}
            • {% endfor %}
            Find if string is in variable
            Pythondot img6Lines of Code : 20dot img6License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            d = {'g_dirt4': g_dirt4, 'g_destiny2': g_destiny2, ... }
            
            max_value = max(d.values())
            maximal_keys = { k for k,v in d.items() if v==max_value }
            
            if 'g_dirt4' in maximal_keys:
               etc.
            
            d = {'Dirt 4': g_dirt4, 'Destin

            Community Discussions

            QUESTION

            Problem on getting JSON values in C# with an unrecognizable format
            Asked 2020-Mar-03 at 18:39

            I'm trying to get the nodes inside a JSON request, this: https://store.steampowered.com/api/appdetails?appids=731490

            But it's returning a format that a online json convert doesn't recognize and i can't get the values of nodes with C#.

            Currently, i'm trying:

            ...

            ANSWER

            Answered 2020-Mar-02 at 20:57

            JObject.SelectToken expects a path to a particular token. It doesn't traverse the object to find anything with a matching name.

            Looking at the object, the root object seems to have a single property with the key being the app id. That in turn has two properties, success and data, with data containing the actual info you seek.

            The following works for me:

            Source https://stackoverflow.com/questions/60496293

            QUESTION

            How to perform a search based on aggregation?
            Asked 2019-Aug-19 at 01:33

            I have an elasticsearch index whose documents are setup similar to that of the following: each document holds a survey participant and their answers to questions involving their favorite video game console and video games. Here is an example document (all of the mappings are keywords):

            ...

            ANSWER

            Answered 2019-Aug-18 at 18:37

            You were not far from the solution. You have to perform the first aggregation and then an aggregation inside of it. Like this:

            Source https://stackoverflow.com/questions/57546993

            QUESTION

            Summarise numeric columns, return last value of non-numeric
            Asked 2018-Aug-23 at 08:03

            It's not uncommon to want to summarise numeric columns of a dataframe or tibble, while doing something else to non-numeric columns.

            There is a nice trick for this here, but it seems to fail for character columns.

            First, here it is working, returning the mean of the numeric columns and the value of the first row of the other columns

            ...

            ANSWER

            Answered 2018-Aug-23 at 08:03

            ifelse seems to be the problem so i have created a function. I have updated my answer. i have tested it on the dates attributes and it seems to work on the list as well. I hope it'll solve your problem:

            Source https://stackoverflow.com/questions/51978519

            QUESTION

            Escaping Special Characters in JS RegExp (Used within jQuery .each())
            Asked 2018-Jul-02 at 13:25

            Firstly, I must apologize if the title is poorly constructed. I'm struggling to try to consolidate all the valid points into a brief enough title. If you can think of a better alternative, please feel free to edit.

            The Problem

            I've created a JavaScript/jQuery alternative to the poorly supported HTML5 element and for the most part I'm happy with how it has turned out.

            It all works, but one problem I have with special RegExp characters, is that I'm not too sure how I can escape them so that I'm not being given errors in the console.

            Characters in particular that I want to escape are (, ) and /. I know that in JavaScript regular expressions, you should use a backslash to escape these characters, but of the attempts I've tried thus far, the code stops working completely so clearly I'm not doing something right.

            I am just wondering how I could implement the escaping into my current code? You can see from the commented-out lines some other methods I've tried.

            The Error

            The input works and displays the games correctly. However, if you select one of the Grand Theft Auto V options from the jsFiddle and then go to backspace on the parentheses, the console will throw this error:

            Uncaught SyntaxError: Invalid regular expression: /Grand Theft Auto V (PC/: Unterminated group

            The Code

            Live preview: jsFiddle

            JavaScript/jQuery:

            ...

            ANSWER

            Answered 2018-Jul-02 at 06:39

            You are correct you need to escape the characters for the regex.

            Try to escape the game_name in the regex with two backslashes like this:

            Source https://stackoverflow.com/questions/51129886

            QUESTION

            Does RcppArmadillo enable bandicoot?
            Asked 2018-Mar-21 at 16:10

            I just would like to know if RcppArmadillo enables bandicoot, or is there any other way to enable gpu calculation with RcppArmadillo?

            Thank you, maybe it is too generalized but i did not find much info on the web about that.

            ...

            ANSWER

            Answered 2018-Mar-21 at 16:10

            The entire Armadillo repo is completely free of any reference to bandicoot so how could RcppArmadillo possibly support it?

            Source https://stackoverflow.com/questions/49410927

            QUESTION

            keep carousel on same slide after refresh
            Asked 2017-Aug-15 at 04:19

            so i have a bootstrap carousel on my page and i'm trying to change the content of the page depending on which slide in currently showed. i have the current slide index in a javascript variable but can't transfer the value to php. so i am now getting the value with GET but the php variable's value don't change unless i refresh the page, but when i do refresh the page the slides reset to the first one. how can i let the carousel stay on the same slide even after the page is refreshed? thank you

            this is my carousel:

            ...

            ANSWER

            Answered 2017-Aug-05 at 04:01

            You could store the current slide number as a local variable.

            localStorage.setItem('slide', activeSlideNumber)

            Then when the document loads, check to see if the slide variable exists in storage as follows.

            Source https://stackoverflow.com/questions/45517863

            QUESTION

            Python @app.route("/custom"), return page doesn't work
            Asked 2017-Jun-18 at 14:58

            I am using Pythonanywhere.com with Flask. I am using this code for the html:

            ...

            ANSWER

            Answered 2017-Jun-18 at 14:58

            Change action="." to action="#".

            action="." causes the request to be sent to one level above the current url which is why /quiz disappear.

            Source https://stackoverflow.com/questions/44616183

            QUESTION

            Find if string is in variable
            Asked 2017-Jun-13 at 13:56

            I have this script to get the variable with the highest value + it's name. If there are more variables with the same highest variable then it will return all of them. If you don't understand what I am saying, this is what I mean: Check if something in a dictionary is the same as the max value in that dictionary?

            Script

            ...

            ANSWER

            Answered 2017-Jun-13 at 13:56

            Here is how you might find the set of keys that map to the maximum value in your dictionary.

            Source https://stackoverflow.com/questions/44498538

            QUESTION

            Prevent parent category radio button from being clicked
            Asked 2017-Jan-16 at 00:28

            I've got this function/script that converts the checkboxes into radio buttons (in the Categories metabox), but I need to extend the functionality a little but I'm unsure how to go about it.

            The script:

            ...

            ANSWER

            Answered 2017-Jan-16 at 00:27

            Please check the comment in the script code.

            Source https://stackoverflow.com/questions/41667321

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install bandicoot

            You can install using 'pip install bandicoot' or download it from GitHub, PyPI.
            You can use bandicoot like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

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            Install
          • PyPI

            pip install bandicoot

          • CLONE
          • HTTPS

            https://github.com/computationalprivacy/bandicoot.git

          • CLI

            gh repo clone computationalprivacy/bandicoot

          • sshUrl

            git@github.com:computationalprivacy/bandicoot.git

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