morpholog | Morphological Parser for Russian is able to split words
kandi X-RAY | morpholog Summary
kandi X-RAY | morpholog Summary
Many neologisms are not presented in the dictionary, so, Morpholog 'makes guess' about it:.
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Trending Discussions on morpholog
QUESTION
I would like to find minimum distance of each voxel to a boundary element in a binary image in which the z voxel size is different from the xy voxel size. This is to say that a single voxel represents a 225x110x110 (zyx) nm volume.
Normally, I would do something with scipy.ndimage.morphology.distance_transform_edt (https://docs.scipy.org/doc/scipy-0.14.0/reference/generated/scipy.ndimage.morphology.distance_transform_edt.html) but this gives the assume that isotropic sizes of the voxel:
...ANSWER
Answered 2021-Jun-15 at 02:32Normally, I would do something with scipy.ndimage.morphology.distance_transform_edt but this gives the assume that isotropic sizes of the voxel:
It does no such thing! You are looking for the sampling=
parameter. From the latest version of the docs:
Spacing of elements along each dimension. If a sequence, must be of length equal to the input rank; if a single number, this is used for all axes. If not specified, a grid spacing of unity is implied.
The wording "sampling" or "spacing" is probably a bit mysterious if you think of pixels as little squares/cubes, and that is probably why you missed it. In most situations, it is better to think of pixels as point samples on a grid, with fixed spacing between samples. I recommend Alvy Ray's a pixel is not a little square for a better understanding of this terminology.
QUESTION
Like the Title says, I am trying to read an online data file that is in .tbl format. Here is the link to the data: https://irsa.ipac.caltech.edu/data/COSMOS/tables/morphology/cosmos_morph_cassata_1.1.tbl
I tried the following code
...ANSWER
Answered 2021-Jun-11 at 06:50Your file has four header rows and different delimiters in header (|
) and data (whitespace). You can read the data by using skiprows
argument of read_table
.
QUESTION
I am trying to blur of highest variance point from the image. I wrote code below. 1st part finds the variance of the image. I checked the resultant variance of an image and it is correct. (I used Lena's image) In 2nd part, I find the highest variance coordinates and send to this Function which finds gaussian blur. When I execute this code, it throws "C:\Tmp\blur_highest_variance.py", line 66, in sigma=15) numpy.core._exceptions.UFuncTypeError: Cannot cast ufunc 'subtract' output from dtype('float64') to dtype('uint8') with casting rule 'same_kind'
I tried a few conversions between types but no avail. Can you show me some direction?
ANSWER
Answered 2021-Jun-10 at 18:48The error message tells us the line and the reason for the error:
Traceback (most recent call last):
File "C:\Tmp\blur_highest_variance.py", line 66, in sigma=15)
numpy.core._exceptions.UFuncTypeError: Cannot cast ufunc 'subtract' output from dtype('float64') to dtype('uint8') with casting rule 'same_kind'
It is more simple to debug the code using intermediate variables:
For example, use an intermediate named gmask
:
QUESTION
I used the following code to generate images and then add white noise to finally apply morphological operation (opening) to the final image.
**Question ** - why do I get a different result (Result-1) when I add UINT8 image with UINT8 noise
...ANSWER
Answered 2021-Jun-04 at 03:59Uint8 dtypes are inherently limited to values between 0 and 255. So, when you add to a value with a value of 255 (in your case, the white text) with another uint8 value, it can't go any higher and will be capped to 255 (ignoring under/overflow).
Now, when you add a uint8 to a higher-bitsized value (float, int, double, whatever), python inherently translates the result to the larger bit number. So, if you have a uint8 image and add int32 noise to it, the result will be able to have values higher than 255 (Which you set your text to). To remove this, you need to either cast the result to uint8:
QUESTION
I tried implementing morphological erosion on digital images with Python. I uploaded a binary image and defined a structural element - ones(3,3). But when I run the code, the following error occurs:
RuntimeError: sequence argument must have length equal to input rank
Please assit. Below are my codes:
...ANSWER
Answered 2021-May-30 at 12:14Posting what I mentioned as a comment - You are trying to perform the erosion operation on a RGB image. You need to convert the RGB image to a binary image and then perform erosion with the structuring element.
QUESTION
In the following microscopy image, I extracted the horizontal white line grid using morphological operators in OpenCV. I couldn't completely get rid of the noise which is why there are some white lines in-between. The grid lines need to be parallel to the x-axis. During the microscopic reading process, perfect parallelism cannot be ensured. In this case, the lines are moving slightly upwards from left to right. How can I realign the lines to the x-axis so that they are parallel to the lower and upper edges of the image using OpenCV or any other Python package?
I'm relatively new to OpenCV so if anyone could give me a hint what operations or functions would be helpful to tackle this problem, I'd be grateful.
Thanks!
...ANSWER
Answered 2021-May-25 at 09:50You may fit lines, get the mean angle and rotate the image.
The suggested solution uses the following stages:
- Threshold (binarize) the image.
- Apply closing morphological operation for connecting the lines.
- Find contours.
- Iterate the contours and fit a line for each contour.
Compute the angle of each line, and build a list of angles. - Compute the mean angle of the angles that are "close to the median angle".
- Rotate the image by the mean angle.
Here is the code:
QUESTION
I used this function to count objects in segmendted images (I loaded my pretrained weights for prediction)
...ANSWER
Answered 2021-May-18 at 12:33remove_small_objects expected a labeled image, putting: imgl=skimage.morphology.remove_small_objects(imgl, min_size=12) under imgl=measure.label(predd, background=0,connectivity=2) solved the problem.
QUESTION
I am working on a project that aims to extract the "interesting" sequences from an mp4 video using different concepts.
One of them is supposed to be the image entropy and right now, I am a bit stuck.
I have followed this tutorial to get the entropy for a few selected screenshots from the video: https://scikit-image.org/docs/dev/auto_examples/filters/plot_entropy.html
For that, I got results like this one which is what I wanted.
To apply it to my test video, I did the following:
...ANSWER
Answered 2021-May-13 at 15:55You are getting strange results because the range of entropy_frame
is about [0, 6.0].
You need to convert the range to [0, 255] and cast the result from float
to uint8
.
A simple way to do the range conversion is multiply by (255/max(entropy_mat)
):
QUESTION
I have been asking several questions for locating and extracting maze from photos on SOF, but none of the answers I get work across different photos, not even across 4 testing photos. Every time when I tweaked the code to make it work for 1 photo, it will fail on the rest of photos due to warped corners/parts or light etc. I feel that I need to find a way which is insensitive to warped image and different intensity of light or the different colors of maze walls(the lines inside a maze).
I have been trying to make it work for 3 weeks without a luck. Before I drop the idea, I would like to ask is it possible to just use Image Processing without AI to locate and extract a maze from a photo? If yes, could you please show me how to do it?
Here are the code and photos:
...ANSWER
Answered 2021-May-12 at 13:17You really want to get these $ 6.9 dishes, he?
For the four given images, I could get quite good results using the following workflow:
- White balance the input image to enforce nearly white paper. I took this approach using a small patch from the center of the image, and from that patch, I took the pixel with the highest
R + G + B
value – assuming the maze is always centered in the image, and there are some pixels from the white paper within the small patch. - Use the saturation channel from the HSV color space to mask the white paper, and (roughly) crop that portion from the image.
- On that crop, perform the existing
reconstruction
approach.
Here are the results:
maze.jpg
simple.jpg
middle.jpg
hard.jpg
That's the full code:
QUESTION
I am trying to improve this image with the help of morphological operations. The result I get is good but it takes almost 40 seconds to get the resulting image and I was wondering if there is any other method to get a similar or even better result without taking too long.
Below I attach the images and the code that i used to enhance the original image. Thanks
...ANSWER
Answered 2021-May-10 at 14:28Almost all of your time is being taken up by the closing function. This is mostly because that function's runtime scales terribly with kernel size and disk(40) is probably an 80x80 kernel under the hood. We can approximate the same thing by downscaling the image and running an equivalent-sized kernel on the smaller image.
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Install morpholog
You can use morpholog like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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