morpholog | Morphological Parser for Russian is able to split words

 by   constantin50 Python Version: 1.6 License: MIT

kandi X-RAY | morpholog Summary

kandi X-RAY | morpholog Summary

morpholog is a Python library. morpholog has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However morpholog build file is not available. You can install using 'pip install morpholog' or download it from GitHub, PyPI.

Many neologisms are not presented in the dictionary, so, Morpholog 'makes guess' about it:.
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              morpholog has a low active ecosystem.
              It has 7 star(s) with 0 fork(s). There are no watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              morpholog has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of morpholog is 1.6

            kandi-Quality Quality

              morpholog has no bugs reported.

            kandi-Security Security

              morpholog has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              morpholog is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              morpholog releases are not available. You will need to build from source code and install.
              Deployable package is available in PyPI.
              morpholog has no build file. You will be need to create the build yourself to build the component from source.
              Installation instructions, examples and code snippets are available.

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            morpholog Key Features

            No Key Features are available at this moment for morpholog.

            morpholog Examples and Code Snippets

            No Code Snippets are available at this moment for morpholog.

            Community Discussions

            QUESTION

            image distance transform different xyz voxel sizes
            Asked 2021-Jun-15 at 02:32

            I would like to find minimum distance of each voxel to a boundary element in a binary image in which the z voxel size is different from the xy voxel size. This is to say that a single voxel represents a 225x110x110 (zyx) nm volume.

            Normally, I would do something with scipy.ndimage.morphology.distance_transform_edt (https://docs.scipy.org/doc/scipy-0.14.0/reference/generated/scipy.ndimage.morphology.distance_transform_edt.html) but this gives the assume that isotropic sizes of the voxel:

            ...

            ANSWER

            Answered 2021-Jun-15 at 02:32

            Normally, I would do something with scipy.ndimage.morphology.distance_transform_edt but this gives the assume that isotropic sizes of the voxel:

            It does no such thing! You are looking for the sampling= parameter. From the latest version of the docs:

            Spacing of elements along each dimension. If a sequence, must be of length equal to the input rank; if a single number, this is used for all axes. If not specified, a grid spacing of unity is implied.

            The wording "sampling" or "spacing" is probably a bit mysterious if you think of pixels as little squares/cubes, and that is probably why you missed it. In most situations, it is better to think of pixels as point samples on a grid, with fixed spacing between samples. I recommend Alvy Ray's a pixel is not a little square for a better understanding of this terminology.

            Source https://stackoverflow.com/questions/67961571

            QUESTION

            Reading an online .tbl data file in python
            Asked 2021-Jun-11 at 06:50

            Like the Title says, I am trying to read an online data file that is in .tbl format. Here is the link to the data: https://irsa.ipac.caltech.edu/data/COSMOS/tables/morphology/cosmos_morph_cassata_1.1.tbl

            I tried the following code

            ...

            ANSWER

            Answered 2021-Jun-11 at 06:50

            Your file has four header rows and different delimiters in header (|) and data (whitespace). You can read the data by using skiprows argument of read_table.

            Source https://stackoverflow.com/questions/67927318

            QUESTION

            Trying to blur highest variance point of an image but some conversion problem exist in code
            Asked 2021-Jun-10 at 20:29

            I am trying to blur of highest variance point from the image. I wrote code below. 1st part finds the variance of the image. I checked the resultant variance of an image and it is correct. (I used Lena's image) In 2nd part, I find the highest variance coordinates and send to this Function which finds gaussian blur. When I execute this code, it throws "C:\Tmp\blur_highest_variance.py", line 66, in sigma=15) numpy.core._exceptions.UFuncTypeError: Cannot cast ufunc 'subtract' output from dtype('float64') to dtype('uint8') with casting rule 'same_kind' I tried a few conversions between types but no avail. Can you show me some direction?

            ...

            ANSWER

            Answered 2021-Jun-10 at 18:48

            The error message tells us the line and the reason for the error:

            Traceback (most recent call last):
            File "C:\Tmp\blur_highest_variance.py", line 66, in sigma=15)
            numpy.core._exceptions.UFuncTypeError: Cannot cast ufunc 'subtract' output from dtype('float64') to dtype('uint8') with casting rule 'same_kind'

            It is more simple to debug the code using intermediate variables:
            For example, use an intermediate named gmask:

            Source https://stackoverflow.com/questions/67924044

            QUESTION

            Why do I get different results while adding noise to a binary images which have different dtypes
            Asked 2021-Jun-04 at 03:59

            I used the following code to generate images and then add white noise to finally apply morphological operation (opening) to the final image.

            **Question ** - why do I get a different result (Result-1) when I add UINT8 image with UINT8 noise

            ...

            ANSWER

            Answered 2021-Jun-04 at 03:59

            Uint8 dtypes are inherently limited to values between 0 and 255. So, when you add to a value with a value of 255 (in your case, the white text) with another uint8 value, it can't go any higher and will be capped to 255 (ignoring under/overflow).

            Now, when you add a uint8 to a higher-bitsized value (float, int, double, whatever), python inherently translates the result to the larger bit number. So, if you have a uint8 image and add int32 noise to it, the result will be able to have values higher than 255 (Which you set your text to). To remove this, you need to either cast the result to uint8:

            Source https://stackoverflow.com/questions/67831201

            QUESTION

            Morphological erosion on digital images with Python - error
            Asked 2021-May-30 at 12:14

            I tried implementing morphological erosion on digital images with Python. I uploaded a binary image and defined a structural element - ones(3,3). But when I run the code, the following error occurs:

            RuntimeError: sequence argument must have length equal to input rank

            Please assit. Below are my codes:

            ...

            ANSWER

            Answered 2021-May-30 at 12:14

            Posting what I mentioned as a comment - You are trying to perform the erosion operation on a RGB image. You need to convert the RGB image to a binary image and then perform erosion with the structuring element.

            Source https://stackoverflow.com/questions/67758203

            QUESTION

            Rotate Image to align features with X-axis in OpenCV Python
            Asked 2021-May-25 at 09:50

            In the following microscopy image, I extracted the horizontal white line grid using morphological operators in OpenCV. I couldn't completely get rid of the noise which is why there are some white lines in-between. The grid lines need to be parallel to the x-axis. During the microscopic reading process, perfect parallelism cannot be ensured. In this case, the lines are moving slightly upwards from left to right. How can I realign the lines to the x-axis so that they are parallel to the lower and upper edges of the image using OpenCV or any other Python package?

            I'm relatively new to OpenCV so if anyone could give me a hint what operations or functions would be helpful to tackle this problem, I'd be grateful.

            Thanks!

            ...

            ANSWER

            Answered 2021-May-25 at 09:50

            You may fit lines, get the mean angle and rotate the image.

            The suggested solution uses the following stages:

            • Threshold (binarize) the image.
            • Apply closing morphological operation for connecting the lines.
            • Find contours.
            • Iterate the contours and fit a line for each contour.
              Compute the angle of each line, and build a list of angles.
            • Compute the mean angle of the angles that are "close to the median angle".
            • Rotate the image by the mean angle.

            Here is the code:

            Source https://stackoverflow.com/questions/67684060

            QUESTION

            why len(measure.regionprops(imgl)) gives me a wrong number of objects?
            Asked 2021-May-18 at 12:33

            I used this function to count objects in segmendted images (I loaded my pretrained weights for prediction)

            ...

            ANSWER

            Answered 2021-May-18 at 12:33

            remove_small_objects expected a labeled image, putting: imgl=skimage.morphology.remove_small_objects(imgl, min_size=12) under imgl=measure.label(predd, background=0,connectivity=2) solved the problem.

            Source https://stackoverflow.com/questions/67557518

            QUESTION

            Python OpenCV Strange result for image entropy on video
            Asked 2021-May-13 at 15:55

            I am working on a project that aims to extract the "interesting" sequences from an mp4 video using different concepts.

            One of them is supposed to be the image entropy and right now, I am a bit stuck.

            I have followed this tutorial to get the entropy for a few selected screenshots from the video: https://scikit-image.org/docs/dev/auto_examples/filters/plot_entropy.html

            For that, I got results like this one which is what I wanted.

            To apply it to my test video, I did the following:

            ...

            ANSWER

            Answered 2021-May-13 at 15:55

            You are getting strange results because the range of entropy_frame is about [0, 6.0].
            You need to convert the range to [0, 255] and cast the result from float to uint8.

            A simple way to do the range conversion is multiply by (255/max(entropy_mat)):

            Source https://stackoverflow.com/questions/67495553

            QUESTION

            How to locate and extract a maze from a photo without being sensitive to warp or light
            Asked 2021-May-13 at 13:27

            I have been asking several questions for locating and extracting maze from photos on SOF, but none of the answers I get work across different photos, not even across 4 testing photos. Every time when I tweaked the code to make it work for 1 photo, it will fail on the rest of photos due to warped corners/parts or light etc. I feel that I need to find a way which is insensitive to warped image and different intensity of light or the different colors of maze walls(the lines inside a maze).

            I have been trying to make it work for 3 weeks without a luck. Before I drop the idea, I would like to ask is it possible to just use Image Processing without AI to locate and extract a maze from a photo? If yes, could you please show me how to do it?

            Here are the code and photos:

            ...

            ANSWER

            Answered 2021-May-12 at 13:17

            You really want to get these $ 6.9 dishes, he?

            For the four given images, I could get quite good results using the following workflow:

            • White balance the input image to enforce nearly white paper. I took this approach using a small patch from the center of the image, and from that patch, I took the pixel with the highest R + G + B value – assuming the maze is always centered in the image, and there are some pixels from the white paper within the small patch.
            • Use the saturation channel from the HSV color space to mask the white paper, and (roughly) crop that portion from the image.
            • On that crop, perform the existing reconstruction approach.

            Here are the results:

            maze.jpg

            simple.jpg

            middle.jpg

            hard.jpg

            That's the full code:

            Source https://stackoverflow.com/questions/67487439

            QUESTION

            Is there a more efficient way to find the contour of this object and fill the blank spaces in python?
            Asked 2021-May-10 at 14:28

            I am trying to improve this image with the help of morphological operations. The result I get is good but it takes almost 40 seconds to get the resulting image and I was wondering if there is any other method to get a similar or even better result without taking too long.

            Below I attach the images and the code that i used to enhance the original image. Thanks

            Original spine image Final spine image

            ...

            ANSWER

            Answered 2021-May-10 at 14:28

            Almost all of your time is being taken up by the closing function. This is mostly because that function's runtime scales terribly with kernel size and disk(40) is probably an 80x80 kernel under the hood. We can approximate the same thing by downscaling the image and running an equivalent-sized kernel on the smaller image.

            Source https://stackoverflow.com/questions/67461447

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install morpholog

            You can install using 'pip install morpholog' or download it from GitHub, PyPI.
            You can use morpholog like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

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            pip install morpholog

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            gh repo clone constantin50/morpholog

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