scorpio | serious constellations | Pub Sub library

by cov-lineages Python Version: v0.3.16 License: GPL-3.0

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | scorpio Summary

scorpio is a Python library typically used in Messaging, Pub Sub, Nodejs, Symfony applications. scorpio has no bugs, it has no vulnerabilities, it has build file available, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

serious constellations of reoccurring phylogenetically-independent origin.

Support

Quality

Security

License

Reuse

Support

scorpio has a low active ecosystem.

It has 25 star(s) with 1 fork(s). There are 11 watchers for this library.

It had no major release in the last 12 months.

There are 6 open issues and 22 have been closed. On average issues are closed in 15 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of scorpio is v0.3.16

Quality

scorpio has no bugs reported.

Security

scorpio has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

scorpio is licensed under the GPL-3.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

scorpio releases are available to install and integrate.

Build file is available. You can build the component from source.

Installation instructions are not available. Examples and code snippets are available.

Top functions reviewed by kandi - BETA

kandi has reviewed scorpio and discovered the below as its top functions. This is intended to give you an instant insight into scorpio implemented functionality, and help decide if they suit your requirements.

Type constellations
Combine two calls
Count the number of variants in a record
Creates a new constellation
Classify constellations
Create a constellation
Combine two constellation objects
Combine the constellation by a name
Generate the barcode for the variant sequence
Define mutations in a list
Translate a reference sequence into a query string
Translate CDS to protein
Convert a yaml file into a dictionary
Parse rules from old rules
Parse a dictionary of variables
Parse command line arguments
Update feature dictionary

Get all kandi verified functions for this library.

scorpio Key Features

No Key Features are available at this moment for scorpio.

scorpio Examples and Code Snippets

No Code Snippets are available at this moment for scorpio.

Community Discussions

Trending Discussions on scorpio

I am getting error in this simple piece of code while using super function

How can I run my python code on google and give access to public or other users without using any money

How can I display data from object in angular app?

Scorpio broker - environment variables set in docker-compose-aaio.yml not getting picked up at runtime

Is there other way of getting an input like date format?

Difference between Fiware Scorpio Broker and Orion Broker

How to print a quote based on the inputed Zodiac Sign with Python?

How to rename existing xticklabels using dictionary in histagram

How can I search any item in many list very efficiently?

unfortunately,project has stopped in android studio

QUESTION

I am getting error in this simple piece of code while using super function

Asked 2021-Apr-21 at 13:48

I have tried changing the code a little but it didn't work. Here's the code anyway.

...

ANSWER

Answered 2021-Apr-21 at 13:48

class Electric_car:
    def __init__(self,model,name,year):
        super(Car()).__init__(model,name,year)

Source https://stackoverflow.com/questions/67193733

QUESTION

How can I run my python code on google and give access to public or other users without using any money

Asked 2021-Mar-18 at 05:45

I have made a program using python language which tells your Horoscope. I made that on Jupyter-notebook, Anaconda. I opened it on word its code is: {

...

ANSWER

Answered 2021-Mar-18 at 05:38

Colab is quite similar to jupyter notebook and is free to use. Just send the link to other once you add your code. https://colab.research.google.com/ is the link. A quick guide is: https://colab.research.google.com/github/jckantor/CBE30338/blob/master/docs/01.01-Getting-Started-with-Python-and-Jupyter-Notebooks.ipynb

Source https://stackoverflow.com/questions/66685325

QUESTION

How can I display data from object in angular app?

Asked 2021-Mar-13 at 13:25

I have an issue with displaying data from API response. The data that I receive are objects in the object. I tried to display data by JSON.striginfy but the data isn't clear.

This data I receive from api:

JSON:

...

ANSWER

Answered 2021-Mar-12 at 18:01

You may do so using the following code on the template by using the keyvalue pipe:

Source https://stackoverflow.com/questions/66604421

QUESTION

Scorpio broker - environment variables set in docker-compose-aaio.yml not getting picked up at runtime

Asked 2021-Jan-22 at 10:23

I am running Scorpio using the docker-compose file: docker-compose-aaio.yml but I want to use an RDS postgres instance rather than a container instance. I have updated the docker-compose-aaio.yml file as follows:

...

ANSWER

Answered 2021-Jan-22 at 10:23

there is another config parameter in spring for postgres. spring.datasource.hikari.url This is missing in documentation. I'll update it for the next release. For the full set of changeable options you can have a look in the application.yml https://github.com/ScorpioBroker/ScorpioBroker/blob/development/AllInOneRunner/src/main/resources/application.yml

Good Luck Benjamin

Source https://stackoverflow.com/questions/65814811

QUESTION

Is there other way of getting an input like date format?

Asked 2021-Jan-21 at 17:11

I was hoping and looking for some other ideas or ways to do this. As you can see, I asked the user for the input which is mmddyyyy (05022001 = May 2, 2001) and used substring in order for me to to take the certain input in the index then parse it. Now, What I want to accomplish is to find another way to do this for example is using the formal date formatter which in my case I didn't use. I think date formatter is alot better than this, but I don't get the idea out of it.

Here's what I've got so far. Thanks in advance.

...

ANSWER

Answered 2021-Jan-21 at 17:11

You should inform the user of what format you expect.

Take the input string and make a parse attempt. Trap for exception in case of faulty input. No need for you to check the ranges of month and day. LocalDate.parse makes those data entry validation checks for you.

Source https://stackoverflow.com/questions/65831738

QUESTION

Difference between Fiware Scorpio Broker and Orion Broker

Asked 2020-Dec-09 at 10:59

Multiple brokers are available over Fiware,

Which have better performance Fiware Scorpio Broker and Orion Broker?
Does Orion Broker is NGSI-LD compliance and what is its roadmap to achieve the NGSI-LD specification?

...

ANSWER

Answered 2020-Dec-09 at 10:59

The FIWARE Catalogue currently contains four context brokers:

Orion - NGSI-v2 only
Orion-LD - mixed NGSI-LD and NGSI-v2 support
Scorpio - NGSI-LD only
Stellio - NGSI-LD only

Orion-LD is a fork from the original Orion repository and aims to be merged back at some point. It is the only context broker which can service both NGSI-v2 and NGSI-LD.

Scorpio and Stellio are pure NGSI-LD brokers which don't require the compromises of having to serve both syntaxes. Scorpio positions itself as the heavyweight broker, with a strong interest in federations. Stellio is somewhere in the middle between Scorpio and Orion.

All NGSI-LD brokers are trying to align to the ETSI standard, however new features are still being added (the latest ESTI update, the 1.3.1 specification was a couple of months ago). My understanding is that Orion complies with 95% of the 1.2.1 specification (excluding the temporal API). Scorpio is probably higher but some minor differences can be found within payloads

Running an ACID test NGSI-LD Test-Suite returns the following for Scorpio:

Source https://stackoverflow.com/questions/65178803

QUESTION

How to print a quote based on the inputed Zodiac Sign with Python?

Asked 2020-Aug-27 at 16:40

I'm making a console personality test and I want to print a quote for the inputed zodiac sign of the player. I don't want to use tons of if statements, can I do this with dictionaries and loops?

Where the keys are the zodiac signs and the values are the specific quotes, then using a loop and a short if statement to loop the keys with the given input and print the corresponding value which is the quote.

Here's my code:

...

ANSWER

Answered 2020-Aug-27 at 16:35

You could just get the zodiac sign from the dictionary with

Source https://stackoverflow.com/questions/63620158

QUESTION

How to rename existing xticklabels using dictionary in histagram

Asked 2020-Jul-22 at 09:37

Encounter a problem, how to rename existing xticklabels in lineplot using dictionary ? Part of code:

...

ANSWER

Answered 2020-Jul-22 at 09:24

I assume your data are in a dataframe like this df:

Source https://stackoverflow.com/questions/63028733

QUESTION

How can I search any item in many list very efficiently?

Asked 2020-May-17 at 22:38

I have a problem to find very efficient way to search birthday in many list.

Here is my horoscope_dates function

...

ANSWER

Answered 2020-May-17 at 22:38

from datetime import date

horoscope_dates = {"aries": (date(2020, 3, 21), date(2020, 4, 20)),
                   "taurus": (date(2020, 4, 20), date(2020, 5, 21)),
                   "gemini": (date(2020, 5, 21), date(2020, 6, 22)),
                   }

month = int(input("Enter your month of birth: "))
day = int(input("Enter your day of birth: "))
year = 2020
birthday = date(year, month, day)

for horoscope, (start, end) in horoscope_dates.items():
    if start <= birthday < end:
        print(horoscope)
        break

Source https://stackoverflow.com/questions/61859211

QUESTION

unfortunately,project has stopped in android studio

Asked 2020-Apr-24 at 17:04

The code is all about taking the zodiac sign as the input in the 1st activity and when clicked OK navigates to the next activity where it displays the details as the web view of that particular zodiac sign. When ever I try to run the code in the emulator or in my mobile I get a warning project is continuously stopping and the application closes.

...

ANSWER

Answered 2020-Apr-24 at 17:04

You are calling startActivity twice, also .setClass is not needed:

Source https://stackoverflow.com/questions/61362952

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install scorpio

You can download it from GitHub.
You can use scorpio like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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