fmt | Using f-strings ( PEP
kandi X-RAY | fmt Summary
kandi X-RAY | fmt Summary
Using f-strings(PEP 498) style literal string interpolation without Python 3.6.
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QUESTION
i want to preload M2M
relation with gorm and it is not populating the slice with Preload
function.
ANSWER
Answered 2021-Jun-15 at 14:41There are a couple of things to try out and fix:
You probably don't need the many2many
attribute to load the DonationDetail
slice, since they can be loaded only with DonationID
. If you have a foreign key, you can add it like this:
QUESTION
I am trying to convert the io.ReadCloser
(interface) that I am getting after running the Docker image via Go docker-sdk
to []byte
for further use.
When I read from the io.ReadCloser
using stdcopy.StdCopy
to stdout
, it prints the data perfectly.
The code stdcopy.StdCopy(os.Stderr, os.Stdout, out)
prints:
ANSWER
Answered 2021-Jun-15 at 11:30Those are stray bytes like *
, %
, etc. prefixed with some of the lines.
The stray bytes appear to be a custom stream multiplexing protocol, allowing STDOUT
and STDERR
to be sent down the same connection.
Using stdcopy.StdCopy()
interprets these custom headers and those stray characters are avoided by removing the protocol header for each piece of data.
Refer: https://github.com/moby/moby/blob/master/pkg/stdcopy/stdcopy.go#L42
QUESTION
I am trying to understand the example with incorrect sync code from The Go Memory Model.
...Double-checked locking is an attempt to avoid the overhead of synchronization. For example, the twoprint program might be incorrectly written as:
ANSWER
Answered 2021-Jun-14 at 19:18According to the Go memory model:
There are no guarantees that one goroutine will see the operations performed by another goroutine unless there is an explicit synchronization between the two using channels, mutex. etc.
In your example: the fact that a goroutines sees done=true
does not imply it will see a
set. This is only guaranteed if there is explicit synchronization between the goroutines.
The sync.Once
probably offers such synchronization, so that's why you have not observed this behavior. There is still a memory race, and on a different platform with a different implementation of sync.Once
, things may change.
QUESTION
I want to create a .wasm
file which still has the function names exported when compiled.
ANSWER
Answered 2021-Jun-15 at 09:04If you plan to write a lot of WASM in Go, you might want to consider compiling with TinyGo, which is a Go compiler for embedded and WASM.
TinyGo supports a //export
or alias //go:export
comment directive that does what you're looking for.
I'm copy-pasting the very first example from TinyGo WASM docs:
QUESTION
Problem Ticking Timer
You are building a Timer app that should count up to a given number. Your program needs to take a number as input and make the Timer tick that number of times.
The code in main initializes a Timer and takes a number as input. Then it calls the tick() method for the Timer the given number of times.
Define the Timer struct with two fields: id and value, and define the tick() method, which should increment the value by one and output its current value. Use a struct pointer as the method's receiver to be able to change the value of the Timer.
...ANSWER
Answered 2021-Jun-13 at 19:56From your question I understand that you want to build a time ticker
program ,which would take number
as input and invoke tick()
method for those number of times .I have created a simple program for your scenario as follows:
QUESTION
super newbie developer here. So say I have a variable (key) (i.e. type string) in golang that I want to send client-side (Vue js). I've tried sending it locally but Vue js isn't able to read it. So I'm 100% sure I'm doing it wrong within golang.
Would I need to POST it to a local server (ex: localhost:3001) and GET it from vue js? How should I send this POST request in go? Are there better options?
Snippet of current vue code :
...ANSWER
Answered 2021-Jun-13 at 12:31Without seeing exactly how your Go code is written it's difficult to fully understand what you're doing on that side, especially since you stated:
So I'm 100% sure I'm doing it wrong within golang
However, as an example to fill in the blank, I'm going to make the assumption you're doing something like so:
QUESTION
I am developing a rest api using golang based on /v1/public/characters
of Marvel API. I need to return all the character ids in the format of
ANSWER
Answered 2021-Jun-12 at 18:47Create int array
with your IDs and marshal it and write it to your response.
Replace your last tree lines with following code and test.
QUESTION
I read the book "Concurrency in Go" written by Katherine Cox-Buday and I don't understand comments for examples of buffered channels.
The author says:
...ANSWER
Answered 2021-Jun-12 at 18:10Yes, it sounds like this book needs a better editor!
the channel capacity is indeed indicated as the 2nd argument to make
:
QUESTION
I've begun learning Go, and I ran into a strange bug, and an even stranger fix for it working on a HackerRack problem:
...ANSWER
Answered 2021-Jun-12 at 06:41So we have an actually correct answer here, the issue is that you're writing to the boolean but never reading from it. Without the Println()
, it's not used in a conditional or any other expression anywhere that depends on its value, so the assignments to it don't affect the program flow. You could remove all of the lines assigning values to insideValley
and the program would act no differently than it does right now (excepting the Println(), of course, which is why adding that "fixed" the issue).
Go is specifically designed to flag "junk" code like that, that adds nothing to the program flow, as a compiler error (well, in most cases. Unused globals and unused functions are some exceptions to that). Simply add in whatever is supposed to be using that boolean's value (such as a conditional based on its value), and you'll stop getting the "variable unused" error.
And as noted in the comments of Vishwa Ratna's answer, vars do not have to be used in every logical pathway. They only need to be used (ie. read from) in at least one logical pathway.
QUESTION
In the below code the first printAll
has a compile error ./main.go:10:7: cannot use info (type []fs.FileInfo) as type fileInfoList in argument to print
. How come this is the case? Shouldn't the fileInfo
interface be met since each fs.FileInfo
type has a Name
method?
ANSWER
Answered 2021-Jun-12 at 06:12You're correct, fs.FileInfo
implement the interface fileInfo
!
However, that does not mean that you can assign a value of type []fs.FileInfo
to a variable typed []fileInfo
- these are completely different types.
In fact - the types cannot even be converted to each other, they are laid out completely differently in memory: interface values are a pair of {concrete type,data struct pointer}, and struct values are just what you see in the struct!
So, the short answer is that you have to do something like your loop which assigns values and appends them to the slice of interface values... behind the scenes what is happening is Go is creating an interface value for each of the struct slice elements for you, automatically.
A succinct way to say this all is: "Go interfaces types are covariant with the struct types that implement them, but slices of interface values are not type-covariant with slices of structs that implement those values."
For more info on slices of structs vs. interface types, see https://www.timr.co/go-interfaces-the-tricky-parts/
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