smear | spatial interpolation | Machine Learning library
kandi X-RAY | smear Summary
kandi X-RAY | smear Summary
spatial interpolation of large irregular two-dimensional scatter datasets.
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Top functions reviewed by kandi - BETA
- Plot theth point on a triangle
- Return a list of triangles that are connected to a vertex
- Returns a triangle of a Delaunay triangle
- Return the CircumCenter of the vertices
- Check if two points are right
- Return the triangles of a triangle
- Return True if all elements equal to n
- Transform spherical coordinates to xy coordinates
- Return the norm of x
- Create a projection object
- Retrieve projection details
smear Key Features
smear Examples and Code Snippets
Community Discussions
Trending Discussions on smear
QUESTION
Reported to Qt as a bug: https://bugreports.qt.io/browse/QTBUG-93475
I am re-drawing a QPixmap
multiple times in different locations, with differnt rotations by transforming the QPainter. In certain situations the QPixmap
is not drawing correctly. The GIF below shows my initial discovery of this issue with a QPixmap
containing a green cylinder, notice how the rendering behaves as expected to the left of the GIF, but there is a boundary beyond which the rendering is incorrect. The QPixmap
content appears to stick in place, and the pixels at the edge appear to smear out accross the rest of the pixmap. In the GIF there is a magenta background to the QPixmap
, this because the targetRect
used by QPainter::drawPixmap()
is also beuing used to seperately fill a rectangle underneath the pixmap, this was because I wanted to check that the target rect was being computed correctly.
To keep things simple I am simply filling the QPixmap
with magenta pixels, with a 1 pixel wide transparent edge so that the smearing causes the pixmaps to dissapear completely. It doesn't show the image "sticking" in place but it clearly shows the boundary as beyond it the pixmaps seem to dissapear.
I have been experimenting with this myself and I believe this to be entirely caused by the rotating of the QPainter
.
The angle of rotation seems to have an effect, if all of the pixmaps are rotated to the same angle then the boundary changes from a fuzzy diagonal line (where fuzzy means the boundary for dissapearing is different for each pixmap) to a sharp 90 degree corner (where sharp means that the boundary for dissapearing is the same for all pixmaps).
The range of different angles also seems to play a part, if the randomly generated angles are in a small 10 degree range, then the boundary is just a slightly fuzzier right angle, with a bevelled corner. There seems to be a progression from sharp right angle to fuzzy diagonal line as the number of different rotations is applied.
CodeQtTestBed/pro:
...ANSWER
Answered 2021-May-06 at 14:43This issue is very interesting. As far as I could test, your code looks good, I feel like this is a Qt bug, and I think you need to report it to Qt: https://bugreports.qt.io/. You should post a single piece of code to illustrate the issue, your second one from your "Update" edit is good: it makes it easy to reproduce the issu. Maybe you should also post a small video to illustrate how things are getting wrong when you zoom in/out or move the area with the mouse.
I tried some alternatives to hopefully find a workaround, but I found none:
- Tried to use a
QImage
rather than aQPixmap
, same issue - Tried to load the pixmap from a frozen png/qrc file, same issue
- Tried to use
QTransform
to play with scale/translation/rotation, same issue - Tried Linux and Windows 10: same issue observed
Note that:
- If you don't rotate (comment
paint.rotate(entity.rotation_);
), the issue is not visible - If your pixmap is a simple mono-colored square (simply fill your pixmap with a single color using
pixmap_.fill(QColor::fromRgba(0x12345600));
), the issue is not visible anymore. That's the most surprising, looks like a pixel from the image is being reused as background and messes things up but if all the image pixels are the same it does not lead to any display issue.
Workaround proposed by the Qt team
"The issue can easily be worked around by enabling the SmoothPixmapTransform render hint on the painter"
QUESTION
I bought a cheap chinese ip camera (GWIPC-26xxx/Yoosee). I want to record its stream with ffmpeg.
On FFMPEG I manage to make it work only using the RTSP/UDP transport protocol, like bellow. It also plays flawlessly on VLC.
...ANSWER
Answered 2021-Feb-22 at 11:07FFMPEG not very tolerant in RTSP setupIP cameras are of varying quality, some behaving erratically in my experience. Dealing with their RTSP streams requires a dose of fault-tolerance.
This appears to be a byproduct of the low-end of the CCTV industry playing fast and loose with standards, RTSP and ONVIF being the two most frequently abused. Fortunately, you can usually work around these problems. Unless your IP cameras and controller are all designed to play nicely together, only use ONVIF for once-only discovery and settings management.
After struggling I started comparing the RTSP/SETUP messages between openRTSP
and ffmpeg
. openRTSP
by default already outputs a lot of verbose diagnostic.
openRTSP
openRTSP
sends the commands OPTIONS
, DESCRIBE
and then SETUP
. The SETUP messages were:
QUESTION
Hi I created a program that will create deviations from a real trajectory, it is complicated and I do not have a simple example unfortunately.
It calculates a path with stochastic initial conditions from the real path and does this for x iterations, the goal is to show that the deviations become larger at greater times.
The real path and the deviations are showed below.
However I want to show that the deviations become greater the longer in time we are. Ofcourse I could just calculate the variance and plot mean+var and mean-var at each time step but I was wondering if I could plot something like this, using hist2d
You see that the blocks are not as smooth as a like and this is not that great to use.
Then I went and looked at python's kde and created the following.
This is also not preferable as I think it bins more points at the minima and maxima. Also it is 'too smeared out'. Especially in the beginning, all the points are the same so I want there just to be a straight line to really show that the deviations start later on.
I guess my question is; is what I want even possible and what package/command should I use. I haven't found what I am looking for on other questions. Or has anyone a suggestion to nicely show what I want in a any other way?
...ANSWER
Answered 2021-Mar-16 at 12:52You could use something like the matplotlib.pyplot.fill_between method. It fills everything between y1 (max) and y2 (min) for a given (common) x array. You would then be able to accentuate that the filled region keeps enlarging with increasing x value.
However, this would require you to find the minimal and maximal value of your deviations at each time point and save these to two separate arrays. The exact method of doing this will depend on how you are storing these individual runs.
In case they are separate lists / arrays, you can convert these to a numpy matrix / pandas dataframe and use the minimum / maximum methods along the relevant axis.
QUESTION
I have the following custom function that I am using to create a table of summary statistics in R.
...ANSWER
Answered 2021-Mar-07 at 22:33The line
QUESTION
I am trying to scrape some data from a website and the HTML code would look like as follows.
...ANSWER
Answered 2021-Jan-07 at 12:05There are different approaches to get the names.
#1 - Get all names
joined as a string
as you expected output:
QUESTION
I have a ListView control and I want to add a checkbox in upper left corner of ListView.
The solution for adding the CheckBox control that I'm using is this:
...ANSWER
Answered 2021-Jan-26 at 05:34Assuming you don't want the option that I used in the linked post, the other way that you can approach this is adding the CheckBox
to the header of the ListView
.
Using SendMessageYou can send LVM_GETHEADER message to the listview control and get the handle of the header, then SetParent will help you to set the header as parent of checkbox:
QUESTION
This is a weird smearing effect I've never seen before in rendered matplotlib figures that looks like a printer error. I'm not clear on what might be causing it. I'm processing a sizeable dataframe (4.5gb) to render two copies of the same figure generated from each row, filenames are derived from the data which is why they're not simply copied and renamed after the process.
Here's a simpler version with np.random
instead of the dataframe:
ANSWER
Answered 2020-Dec-11 at 13:29Clearing the figure at the end of the apply
loop and setting the colorbar ticks with vmin
and vmax
solves the problem. See also this answer.
QUESTION
In the example below:
...ANSWER
Answered 2020-Sep-30 at 08:35QUESTION
I am trying to rotate the major- and the minor axis within a multi-categorical plot in Bokeh (similar to what is done for major tick labels here and done within matplotlib here. When having several categories, their labels/text often get smeared together.
Taking some inspiration from the Bokeh documentation on Categorical Data the result, using Bokehs vbar
functionality, would look something like
The major axis can be set using
...ANSWER
Answered 2020-Mar-31 at 20:06UPDATE
This capability was added in Bokeh 0.12.16
, you can now do:
QUESTION
I have the following image (please note the transparent background):
I also have a black/white mask of the same size:
I would like to "crop" the dress and get just the portion of the first image contained in the black circle. I tried many different methods but they didn't work or are too slow:
1) ImageMagick (command line) <== which command can I use to achieve this? I tried multiply and copyopacity but they didn't work
2) WideImage is working: $maskedImage = $source->applyMask($mask);
but it takes more than 12 seconds.
I am interested in a ImageMagick solution if possible.
EDIT
The provided solutions work fine if the mask is smaller than the original image and if the original image is simple. With these source image and mask the result is "smeared":
Source:
Mask:
Command:
convert source.png \( mask.png -negate \) -alpha off -compose copy_opacity -composite result.png
Result (I added a grey background instead of the transparent one in order to show the wrong white):
...ANSWER
Answered 2020-Mar-04 at 08:43At the end of the day I kept using WideImage which is quite slow but works well. This is the class I use to mask images:
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Install smear
You can use smear like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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