aoc-2020 | Development environment for adventofcode.com - 2020 edition | Chat library
kandi X-RAY | aoc-2020 Summary
kandi X-RAY | aoc-2020 Summary
Spoiler Alert! If you want to solve the aoc problems on your own, do not read any further. This repository contains solutions for the problems in several languages. Result can be found on aoc-2020.netlify.com powered by netlify. In this repository, we will collect the code for the solutions of adventofcode for the 2020 event. If you want to join the discussions, here is the invitation for our slack channel. The slack channel itself is aoc-2020. The id of the shared leaderboard is 117454-7d5aa225 .
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Top functions reviewed by kandi - BETA
- Generate automat
- Finds the neighbors of a dictionary
- Update the board
- Check that the passport extended field is supported
- Print debug information
- Searches for matching tickets
- Add a number
- Check if a star is valid
- Validates a number
- Solve the formula
- Find the right closing bracket
- Find the neighbors of a given dictionary
- Play a game
- Load data from input txt file
- Create an image from a neighborhood
- Solve a formula
- Particular part 2
- Navigate a list of instructions
- Loop through the instructions
- Get seat id from data
- Try to find a solution
- Get answers from answers_list
- Checks if the password is valid
- This function moves a ship star
- Takes a list of valid_tickets and returns a mapping of field values to matching rules
- Play two patterns
- Splits data into a list of possible adapters
aoc-2020 Key Features
aoc-2020 Examples and Code Snippets
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Trending Discussions on aoc-2020
QUESTION
Is there any way to process a changing list using higher-order functions in Clojure and not using explicit recursion? For example, consider the following problem (that I made up to illustrate what I have in mind):
Problem: Given a list of unique integers of unknown order. Write a that produces an output list as follows:
- For any even integer, keep the same relative position in the output list.
- For any odd integer, multiply by ten, and put the new number at a new place: at the back of the original list.
So for example, from original vector [1 2 3 4 5], we get: [2 4 10 30 50]
I know how to solve this using explicit recursion. For example:
...ANSWER
Answered 2020-Dec-27 at 02:23This is much easier to do without recursion than with it! Since you only care about the order of evens relative to other evens, and likewise for odds, you can start by splitting the list in two. Then, map the right function over each, and simply concatenate the results.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install aoc-2020
You can use aoc-2020 like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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