eva | Open source voice-enabled personal assistant
kandi X-RAY | eva Summary
kandi X-RAY | eva Summary
Eva is an open source alternative to Amazon Echo or Google Home. The core of Eva is a simple service that provides hooks for plugins during interactions with users. On it's own, Eva does very little. It's potential comes from the plugins the user chooses to enable (or create).
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Start audio detection
- Log a debug message
- Log a message
- Log a warning message
- Save the current configuration
- Create a ConfigObj from a config file
- Get a ConfigObj object from the env
- Returns the absolute path to the current environment
- Return a ConfigObj object
- Set the output text
- Return a Scheduler instance
- Set the audio
- Listen for keyboard events
- Start detection
- Consume messages from a queue
- Consume messages from MongoDB
- Set the output audio
- Play an audio file
- Interactively interact with the CLI
- Start listening for events
- Set input text
- Start a consumer process
- Get results of a given command
- Start consuming messages from a queue
- Remove all available plugins
- Called when an icon is clicked
- Return the value of the attribute of this object
eva Key Features
eva Examples and Code Snippets
Community Discussions
Trending Discussions on eva
QUESTION
I have a dataset with the name of Danish ministers and their position from 1990 to 2020 (data comes from dataset called WhoGovern; https://politicscentre.nuffield.ox.ac.uk/whogov-dataset/). The dataset consists of the ministers name
, the ministers position
, the prestige
of that position, and the year
in which the minister had that given position.
My problem is that some ministers are counted twice in the same year (i.e., the rows aren't unique in terms of name
and year
). See the example in the picture below, where "Bertel Haarder" was both Minister of Health and Minister of Interior Affairs in 2010 and 2021.
I want to create a dataset, where all the rows are unique combinations of name
and year
. However, I do not want to remove any information from the dataset. Instead, I want to use the information in the prestige
column to combine the duplicated rows into one. The observations with the highest prestige should be the main observations, where the other information should be added in a new column, e.g., position2
and prestige2
. In the example with Bertel Haarder the data should look like this:
(PS: Sorry for bad presenting of the tables, but didn't know how to create a nice looking table...)
Here's the dataset for creating a reproducible example with observations from 2010-2020:
...ANSWER
Answered 2021-Jun-08 at 14:04Reshape the data to wide format twice, once for position
and the other for prestige_1
, and join the two results.
QUESTION
ANSWER
Answered 2021-Jun-03 at 08:17One thing you could do would be to add a separate scaled y-axis for the geom_line
like this
QUESTION
Example :[{
inst:"EVA",
std:"12th"
},
{
inst:"KSF",
std:"12th"
}]
...ANSWER
Answered 2021-May-25 at 05:33There is no "upsert" operation for objects in arrays. If you need to make changes to that array, you will have to read the document, modify the contents of the array in memory, then update the document with the new contents of the array.
Arrays of objects usually do not work the way that people want, given their limitations on querying and updating. It's usually better to store data as documents in a nested subcollection, so they can be more easily queried and updated by the contents of their fields.
QUESTION
- I have a list of tuples that I wish to use as values for my new dictionary.
- I have a list of strings that I wish to use as keys for my new dictionary.
- However I want to use the capital city as a key for the nested dictionary.
ANSWER
Answered 2021-May-12 at 09:11Is this what You want? just need to use indexes:
QUESTION
I have a table like the following:
...ANSWER
Answered 2021-May-05 at 20:03Use rank()
:
QUESTION
I have three tables
Person
employeeNumber name last_name EN12345 Joe Pilgrim EN98764 Eva SnowCashier
employeeNumber socialNumber insuranceNumber EN98764 SN98764 IN98764Manager
employeeNumber socialNumber insuranceNumber EN12345 SN12345 IN12345I need to join this tables into a new table Employee
employeeNumber name last_name socialNumber insuranceNumber EN12345 Joe Pilgrim SN12345 IN12345 EN98764 Eva Snow SN98764 IN98764I have no problem on the part of the name and last name, but I don't know how to do the rest. I have a vague idea, something like:
SELECT cashier.socialNumber, cashier.insuranceNumber OR manager.socialNumber, manager.insuranceNumber FROM person INNER JOIN cashier ON person.employeeNumber = cashier.employeeNumber OR INNER JOIN manager ON person.employeeNumber = manager.employeeNumber
I know this cannot be executed like this, but I don't what to use.
...ANSWER
Answered 2021-May-03 at 17:21You can use two left join
s:
QUESTION
following are my files for html, .ts and json . As json data was very extensive therefore i have just added a few states and their cities. my 1st dropdown is showing all states. Now I want to match my 1st dropdown's selected value of state with a key "state" in "cities" object in my json file so i can populate 2nd dropdown with cities relevant to that state. and I want to do this in function "getCitiesForSelectedState". please help me find solution for this.
//.ts file
...ANSWER
Answered 2021-Apr-27 at 16:44You can do it with the $event
parameter.
Make sure to compare your values safely.
If your value is not in the right type or has spaces or unwanted chars, this c.state == val
might not work.
You can use the trim
function to compare your value safely:
c.state.trim() == val.trim()
HTML
QUESTION
Question is simple. I need to find the tag of the main element in a xml using python.
...ANSWER
Answered 2021-Apr-24 at 09:21Finally found a solution. I recursively iterate every element and count children of each element. At the end of the loop, the element with the most children becomes the main element. Here's the code:
QUESTION
I have a little snippet of c that looks like this:
...ANSWER
Answered 2021-Apr-21 at 07:22If we consider file.c
:
QUESTION
I am using Nebular package to create a custom Web Site for a friend. I want that user I have to logged in with Twitch Account to use the site, but I have some problem with NbAuthModule
. This is what I have done
app.module.ts
...ANSWER
Answered 2021-Apr-15 at 21:19To solve this I add 2 parameters with the following syntax in app.module.ts
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install eva
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page