deduplicated | Check duplicated files
kandi X-RAY | deduplicated Summary
kandi X-RAY | deduplicated Summary
Check duplicated files
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- Render directory
- Return sha1 hash of a file
- Return a directory by hashid
- Return a list of files in the database
- Render directory update
- Update the duplicated metadata
- Update the file hash
- Generator that yields hashes for update
- Prints a listing of directories
- Format a file size
- Get the last updated timestamp
- Prints the duplicated files
- Get duplicated files
- Delete file
- Delete a file from the database
- Return a list of directory names
- Redirect to a directory
- Optimizes the database
- Delete all duplicated files in the directory
- Return a list of files in the cache
- List available directories
- Print out the hash of all files
deduplicated Key Features
deduplicated Examples and Code Snippets
Community Discussions
Trending Discussions on deduplicated
QUESTION
for example, I want to dedup an ID and it keep the maximum or minimum depending on variable that I want to specify. Can I do that using some function in pandas? Data is as dataframe. The drop_duplicate() don't help because It doesn't keep the value that I want, just by order.
...ANSWER
Answered 2022-Mar-31 at 02:18You can start by separately taking the min
of Acesso
grouped by ID
and the max
of Number
grouped by ID
.
You then just have to concatenate these into a single DataFrame. The code would look like this:
QUESTION
For every unique combination of the first two indexes, I want all of the rows (and the index name) of their third index transformed into a json string column.
For example
...ANSWER
Answered 2022-Jan-31 at 23:02You can groupby
"id" and "color" and then apply to_dict
with orient parameter set to "records" to each group:
QUESTION
I want my dataframe to return unique rows based on two logical conditions (OR not AND).
But when I ran this, df %>% group_by(sex) %>% distinct(state, education) %>% summarise(n=n())
I got deduplicated rows based on the two conditions joined by AND not OR.
Is there a way to get something like this df %>% group_by(sex) %>% distinct(state | education) %>% summarise(n=n())
so that the deduplicated rows will be joined by OR not AND?
Thank you.
...ANSWER
Answered 2022-Jan-28 at 10:59You can use tidyr::pivot_longer
and then distinct
afterwards:
QUESTION
I have a need to do some processing on many thousands of strings (each string being an element in a list, imported from records in a SQL table).
Each string comprises a number of phrases delimited by a consistent delimiter. I need to 1) eliminate duplicate phrases in the string; 2) sort the remaining phrases and return the deduplicated, sorted phrases as a delimited string.
This is what I've conjured:
...ANSWER
Answered 2022-Jan-03 at 19:25You can avoid splitting two times (just don't join in the first step), and there is no need to use an f-string when passing delimiter
to split()
.
QUESTION
When I upgrade IoTDB to version 0.12.3, I could not query for more than 1000 timeseries anymore. Even I modified the configuration max_deduplicated_path_num, I could still get the error: Too many paths in one query! Currently allowed max deduplicated path number is 1000. Please use slimit or adjust max_deduplicated_path_num in iotdb-engine.properties.
ANSWER
Answered 2021-Dec-19 at 05:02it is a bug in v0.12.3, and it would be fixed in v0.12.4, which will be released recently. Currently, you could uncomment this configuration: chunk_timeseriesmeta_free_memory_proportion=1: 100:200:300:400
. And then, the modification of max_deduplicated_path_num
would take effect.
QUESTION
I have X sources that contain info about assets (hostname, IPs, MACs, os, etc.) in our environment. The sources contain anywhere from 1500 to 150k entries (at least the ones I use now). My script is supposed to query each of them, gather that data, deduplicate it by merging info about the same assets from different sources, and return unified list of all entries. My current implementation does work, but it's slow for bigger datasets. I'm curious if there is better way to accomplish what I'm trying to do.
Universal problem
Deduplication of data by merging similar entries with the caveat that merging two assets might change whether the resulting asset will be similar to the third asset that was similar to the first two before merging.
Example:
~ similarity, + merging
(before) A ~ B ~ C
(after) (A+B) ~ C or (A+B) !~ C
I tried looking for people having the same issue, I only found What is an elegant way to remove duplicate mutable objects in a list in Python?, but it didn't include merging of data which is crucial in my case.
The classes usedSimplified for ease of reading and understanding with unneeded parts removed - general functionality is intact.
...ANSWER
Answered 2021-Oct-21 at 00:04Summary: we define two sketch functions f and g from entries to sets of “sketches” such that two entries e and e′ are similar if and only if f(e) ∩ g(e′) ≠ ∅. Then we can identify merges efficiently (see the algorithm at the end).
I’m actually going to define four sketch functions, fos, faddr, gos, and gaddr, from which we construct
- f(e) = {(x, y) | x ∈ fos(e), y ∈ faddr(e)}
- g(e) = {(x, y) | x ∈ gos(e), y ∈ gaddr(e)}.
fos and gos are the simpler of the four. fos(e) includes
- (1, e.
os
), if e.os
is known - (2,), if e.
os
is known - (3,), if e.
os
is unknown.
gos(e) includes
- (1, e.
os
), if e.os
is known - (2,), if e.
os
is unknown - (3,).
faddr and gaddr are more complicated because there are prioritized attributes, and they can have multiple values. Nevertheless, the same trick can be made to work. faddr(e) includes
- (1,
h
) for eachh
in e.hostname
- (2,
m
) for eachm
in e.mac
, if e.hostname
is nonempty - (3,
m
) for eachm
in e.mac
, if e.hostname
is empty - (4,
i
) for eachi
in e.ip
, if e.hostname
and e.mac
are nonempty - (5,
i
) for eachi
in e.ip
, if e.hostname
is empty and e.mac
is nonempty - (6,
i
) for eachi
in e.ip
, if e.hostname
is nonempty and e.mac
is empty - (7,
i
) for eachi
in e.ip
, if e.hostname
and e.mac
are empty.
gaddr(e) includes
- (1,
h
) for eachh
in e.hostname
- (2,
m
) for eachm
in e.mac
, if e.hostname
is empty - (3,
m
) for eachm
in e.mac
- (4,
i
) for eachi
in e.ip
, if e.hostname
is empty and e.mac
is empty - (5,
i
) for eachi
in e.ip
, if e.mac
is empty - (6,
i
) for eachi
in e.ip
, if e.hostname
is empty - (7,
i
) for eachi
in e.ip
.
The rest of the algorithm is as follows.
Initialize a
defaultdict(list)
mapping a sketch to a list of entry identifiers.For each entry, for each of the entry’s f-sketches, add the entry’s identifier to the appropriate list in the
defaultdict
.Initialize a
set
of edges.For each entry, for each of the entry’s g-sketches, look up the g-sketch in the
defaultdict
and add an edge from the entry’s identifiers to each of the other identifiers in the list.
Now that we have a set of edges, we run into the problem that @btilly noted. My first instinct as a computer scientist is to find connected components, but of course, merging two entries may cause some incident edges to disappear. Instead you can use the edges as candidates for merging, and repeat until the algorithm above returns no edges.
QUESTION
I've got a certain spider which inherits from SitemapSpider
. As expected, the first request on startup is to sitemap.xml
of my website. However, for it to work correctly I need to add a header to all the requests, including the initial ones which fetch the sitemap. I do so with DownloaderMiddleware, like this:
ANSWER
Answered 2021-Oct-19 at 12:48It won't do something with the first response and neither fetch a second response since you are returning a new request from your custom DownloaderMiddleware process_request
function which is being filtered out. From the docs:
If it returns a Request object, Scrapy will stop calling process_request methods and reschedule the returned request. Once the newly returned request is performed, the appropriate middleware chain will be called on the downloaded response.
It might work if you explicitly say to not filter your second request.
QUESTION
If using SeekToCurrentErrorHandler
with stateful retry, such that the message is polled from the broker for each retry, there is a risk that for a long retry period that a consumer group rebalance could cause the partition to be re-assigned to another consumer. Hence the stateful retry period/attempts would be reset, as the new consumer has no knowledge of the state of the retry.
Taking an example, if a retry max period was 24 hours, but consumer group re-balancing was happening on average every 12 hours, the retry could never complete, and the message (and those behind it) would eventually expire from the topic once they exceeded the retention period. (Assuming the cause of the retryable exception was not resolved in this time). The message would not end up on the DLT after 24 hours as expected, as retries would not be exhausted due to the reset.
I assume that even if a consumer is retrying by re-polling messages, there is no guarantee that following a re-balance that this consumer would retain assignment to this partition. Or is it the case that we can be confident that so long as this consumer instance is alive that it would typically retain assignment to the partition it is polling?
Are there best practises/guidelines on use of stateful retry to cater for this?
Stateless retry means any total retry time that exceeds the poll timeout would cause rebalancing and duplicate message delivery. To avoid that then the retry period must be very limited. Or is the guideline to allow this, ensure messages are deduplicated by the consumer, so that the duplicate messages are acceptable and long running stateless retries can be configured?
Is the only safe and stable option for enabling a retry period of something like several hours (e.g. to cater for a service being unavailable for this period) to use retry topics?
Thanks, Rob.
...ANSWER
Answered 2021-Oct-13 at 18:01The whole point of stateful retry was to avoid a rebalance; without it, the consumer would be delayed up to the aggregate of all retry attempt delays.
However, retry in the listener adapter (including stateful retry) has now been deprecated because the error handler can now do everything the RetryTemplate
can do (back off, exception classification, etc, etc).
With stateful retry (or backoffs in the error handler), the longest back off must be less than max.poll.interval.ms
.
A 24 hour backoff is, frankly, ridiculous - it would be better to just stop the container and restart it a day later.
QUESTION
I am working on outputting total deduplicated counts from a pre-aggregated frame as follows.
I currently have a data frame that displays like so. It's the initial structure and the point that I have gotten to by filtering out unneeded columns.
ID Source 101 Grape 101 Flower 102 Bee 103 Peach 105 FlowerWe can see from the example above that 101 is found in both Grape and Flower. I would like to arrange the format so that the distinct string values from the "Source" column become their own sources, as from there I can perform a groupBy for a specific arrangement of yes's and no's as so.
ID Grape Flower Bee Peach 101 Yes Yes No No 102 No No Yes No 103 No No No YesI agree that creating this manually via the above example is a good fit, but I am working with +100m rows and need something more susinct.
What I've extracted so far is a list of distinct Source values and arranged them into a list:
...ANSWER
Answered 2021-Oct-05 at 13:26That's just a pivot :
QUESTION
We have the NPE at the line of coe mentioned at the topic when calling for
...ANSWER
Answered 2021-Sep-30 at 07:50It was missing the key part of :
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Vulnerabilities
No vulnerabilities reported
Install deduplicated
You can use deduplicated like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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