deduplicated | Check duplicated files

 by   eduardoklosowski Python Version: 1.0b2 License: MIT

kandi X-RAY | deduplicated Summary

kandi X-RAY | deduplicated Summary

deduplicated is a Python library. deduplicated has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install deduplicated' or download it from GitHub, PyPI.

Check duplicated files
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            kandi-support Support

              deduplicated has a low active ecosystem.
              It has 26 star(s) with 6 fork(s). There are 6 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 0 open issues and 1 have been closed. On average issues are closed in 5 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of deduplicated is 1.0b2

            kandi-Quality Quality

              deduplicated has 0 bugs and 0 code smells.

            kandi-Security Security

              deduplicated has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              deduplicated code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              deduplicated is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              deduplicated releases are not available. You will need to build from source code and install.
              Deployable package is available in PyPI.
              Build file is available. You can build the component from source.
              deduplicated saves you 380 person hours of effort in developing the same functionality from scratch.
              It has 906 lines of code, 48 functions and 12 files.
              It has high code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed deduplicated and discovered the below as its top functions. This is intended to give you an instant insight into deduplicated implemented functionality, and help decide if they suit your requirements.
            • Render directory
            • Return sha1 hash of a file
            • Return a directory by hashid
            • Return a list of files in the database
            • Render directory update
            • Update the duplicated metadata
            • Update the file hash
            • Generator that yields hashes for update
            • Prints a listing of directories
            • Format a file size
            • Get the last updated timestamp
            • Prints the duplicated files
            • Get duplicated files
            • Delete file
            • Delete a file from the database
            • Return a list of directory names
            • Redirect to a directory
            • Optimizes the database
            • Delete all duplicated files in the directory
            • Return a list of files in the cache
            • List available directories
            • Print out the hash of all files
            Get all kandi verified functions for this library.

            deduplicated Key Features

            No Key Features are available at this moment for deduplicated.

            deduplicated Examples and Code Snippets

            No Code Snippets are available at this moment for deduplicated.

            Community Discussions

            QUESTION

            Dedup variable keeping max or min in specific variable on dataframe python
            Asked 2022-Mar-31 at 02:18

            for example, I want to dedup an ID and it keep the maximum or minimum depending on variable that I want to specify. Can I do that using some function in pandas? Data is as dataframe. The drop_duplicate() don't help because It doesn't keep the value that I want, just by order.

            ...

            ANSWER

            Answered 2022-Mar-31 at 02:18

            You can start by separately taking the min of Acesso grouped by ID and the max of Number grouped by ID.

            You then just have to concatenate these into a single DataFrame. The code would look like this:

            Source https://stackoverflow.com/questions/71685610

            QUESTION

            Pandas, transform inner most index into a json string column or a list of dictionaries
            Asked 2022-Jan-31 at 23:02

            For every unique combination of the first two indexes, I want all of the rows (and the index name) of their third index transformed into a json string column.

            For example

            ...

            ANSWER

            Answered 2022-Jan-31 at 23:02

            You can groupby "id" and "color" and then apply to_dict with orient parameter set to "records" to each group:

            Source https://stackoverflow.com/questions/70933743

            QUESTION

            Unique rows based on two logical conditions
            Asked 2022-Jan-28 at 11:01

            I want my dataframe to return unique rows based on two logical conditions (OR not AND).

            But when I ran this, df %>% group_by(sex) %>% distinct(state, education) %>% summarise(n=n()) I got deduplicated rows based on the two conditions joined by AND not OR.

            Is there a way to get something like this df %>% group_by(sex) %>% distinct(state | education) %>% summarise(n=n()) so that the deduplicated rows will be joined by OR not AND?

            Thank you.

            ...

            ANSWER

            Answered 2022-Jan-28 at 10:59

            You can use tidyr::pivot_longer and then distinct afterwards:

            Source https://stackoverflow.com/questions/70891868

            QUESTION

            Most Pythonic way to eliminate duplicate entries in a delimited string (not a list) and returning the sorted result
            Asked 2022-Jan-03 at 19:25

            I have a need to do some processing on many thousands of strings (each string being an element in a list, imported from records in a SQL table).

            Each string comprises a number of phrases delimited by a consistent delimiter. I need to 1) eliminate duplicate phrases in the string; 2) sort the remaining phrases and return the deduplicated, sorted phrases as a delimited string.

            This is what I've conjured:

            ...

            ANSWER

            Answered 2022-Jan-03 at 19:25

            You can avoid splitting two times (just don't join in the first step), and there is no need to use an f-string when passing delimiter to split().

            Source https://stackoverflow.com/questions/70570413

            QUESTION

            Cannot query for more than 1000 timeseries after upgrading to 0.12.3 in IoTDB database
            Asked 2021-Dec-19 at 05:02

            When I upgrade IoTDB to version 0.12.3, I could not query for more than 1000 timeseries anymore. Even I modified the configuration max_deduplicated_path_num, I could still get the error: Too many paths in one query! Currently allowed max deduplicated path number is 1000. Please use slimit or adjust max_deduplicated_path_num in iotdb-engine.properties.

            ...

            ANSWER

            Answered 2021-Dec-19 at 05:02

            it is a bug in v0.12.3, and it would be fixed in v0.12.4, which will be released recently. Currently, you could uncomment this configuration: chunk_timeseriesmeta_free_memory_proportion=1: 100:200:300:400. And then, the modification of max_deduplicated_path_num would take effect.

            Source https://stackoverflow.com/questions/70405301

            QUESTION

            Deduplication/merging of mutable data in Python
            Asked 2021-Oct-21 at 00:04
            High-level view of the problem

            I have X sources that contain info about assets (hostname, IPs, MACs, os, etc.) in our environment. The sources contain anywhere from 1500 to 150k entries (at least the ones I use now). My script is supposed to query each of them, gather that data, deduplicate it by merging info about the same assets from different sources, and return unified list of all entries. My current implementation does work, but it's slow for bigger datasets. I'm curious if there is better way to accomplish what I'm trying to do.

            Universal problem
            Deduplication of data by merging similar entries with the caveat that merging two assets might change whether the resulting asset will be similar to the third asset that was similar to the first two before merging.
            Example:
            ~ similarity, + merging
            (before) A ~ B ~ C
            (after) (A+B) ~ C or (A+B) !~ C

            I tried looking for people having the same issue, I only found What is an elegant way to remove duplicate mutable objects in a list in Python?, but it didn't include merging of data which is crucial in my case.

            The classes used

            Simplified for ease of reading and understanding with unneeded parts removed - general functionality is intact.

            ...

            ANSWER

            Answered 2021-Oct-21 at 00:04

            Summary: we define two sketch functions f and g from entries to sets of “sketches” such that two entries e and e′ are similar if and only if f(e) ∩ g(e′) ≠ ∅. Then we can identify merges efficiently (see the algorithm at the end).

            I’m actually going to define four sketch functions, fos, faddr, gos, and gaddr, from which we construct

            • f(e) = {(x, y) | x ∈ fos(e), y ∈ faddr(e)}
            • g(e) = {(x, y) | x ∈ gos(e), y ∈ gaddr(e)}.

            fos and gos are the simpler of the four. fos(e) includes

            • (1, e.os), if e.os is known
            • (2,), if e.os is known
            • (3,), if e.os is unknown.

            gos(e) includes

            • (1, e.os), if e.os is known
            • (2,), if e.os is unknown
            • (3,).

            faddr and gaddr are more complicated because there are prioritized attributes, and they can have multiple values. Nevertheless, the same trick can be made to work. faddr(e) includes

            • (1, h) for each h in e.hostname
            • (2, m) for each m in e.mac, if e.hostname is nonempty
            • (3, m) for each m in e.mac, if e.hostname is empty
            • (4, i) for each i in e.ip, if e.hostname and e.mac are nonempty
            • (5, i) for each i in e.ip, if e.hostname is empty and e.mac is nonempty
            • (6, i) for each i in e.ip, if e.hostname is nonempty and e.mac is empty
            • (7, i) for each i in e.ip, if e.hostname and e.mac are empty.

            gaddr(e) includes

            • (1, h) for each h in e.hostname
            • (2, m) for each m in e.mac, if e.hostname is empty
            • (3, m) for each m in e.mac
            • (4, i) for each i in e.ip, if e.hostname is empty and e.mac is empty
            • (5, i) for each i in e.ip, if e.mac is empty
            • (6, i) for each i in e.ip, if e.hostname is empty
            • (7, i) for each i in e.ip.

            The rest of the algorithm is as follows.

            • Initialize a defaultdict(list) mapping a sketch to a list of entry identifiers.

            • For each entry, for each of the entry’s f-sketches, add the entry’s identifier to the appropriate list in the defaultdict.

            • Initialize a set of edges.

            • For each entry, for each of the entry’s g-sketches, look up the g-sketch in the defaultdict and add an edge from the entry’s identifiers to each of the other identifiers in the list.

            Now that we have a set of edges, we run into the problem that @btilly noted. My first instinct as a computer scientist is to find connected components, but of course, merging two entries may cause some incident edges to disappear. Instead you can use the edges as candidates for merging, and repeat until the algorithm above returns no edges.

            Source https://stackoverflow.com/questions/69636389

            QUESTION

            Scrapy appears to be deduplicating the first request when it is processed with DownloaderMiddleware
            Asked 2021-Oct-19 at 16:21

            I've got a certain spider which inherits from SitemapSpider. As expected, the first request on startup is to sitemap.xml of my website. However, for it to work correctly I need to add a header to all the requests, including the initial ones which fetch the sitemap. I do so with DownloaderMiddleware, like this:

            ...

            ANSWER

            Answered 2021-Oct-19 at 12:48

            It won't do something with the first response and neither fetch a second response since you are returning a new request from your custom DownloaderMiddleware process_request function which is being filtered out. From the docs:

            If it returns a Request object, Scrapy will stop calling process_request methods and reschedule the returned request. Once the newly returned request is performed, the appropriate middleware chain will be called on the downloaded response.

            It might work if you explicitly say to not filter your second request.

            Source https://stackoverflow.com/questions/69598501

            QUESTION

            Spring-Kafka: Impact of Consumer Group Rebalancing on Stateful Retry
            Asked 2021-Oct-13 at 18:01

            If using SeekToCurrentErrorHandler with stateful retry, such that the message is polled from the broker for each retry, there is a risk that for a long retry period that a consumer group rebalance could cause the partition to be re-assigned to another consumer. Hence the stateful retry period/attempts would be reset, as the new consumer has no knowledge of the state of the retry.

            Taking an example, if a retry max period was 24 hours, but consumer group re-balancing was happening on average every 12 hours, the retry could never complete, and the message (and those behind it) would eventually expire from the topic once they exceeded the retention period. (Assuming the cause of the retryable exception was not resolved in this time). The message would not end up on the DLT after 24 hours as expected, as retries would not be exhausted due to the reset.

            I assume that even if a consumer is retrying by re-polling messages, there is no guarantee that following a re-balance that this consumer would retain assignment to this partition. Or is it the case that we can be confident that so long as this consumer instance is alive that it would typically retain assignment to the partition it is polling?

            Are there best practises/guidelines on use of stateful retry to cater for this?

            Stateless retry means any total retry time that exceeds the poll timeout would cause rebalancing and duplicate message delivery. To avoid that then the retry period must be very limited. Or is the guideline to allow this, ensure messages are deduplicated by the consumer, so that the duplicate messages are acceptable and long running stateless retries can be configured?

            Is the only safe and stable option for enabling a retry period of something like several hours (e.g. to cater for a service being unavailable for this period) to use retry topics?

            Thanks, Rob.

            ...

            ANSWER

            Answered 2021-Oct-13 at 18:01

            The whole point of stateful retry was to avoid a rebalance; without it, the consumer would be delayed up to the aggregate of all retry attempt delays.

            However, retry in the listener adapter (including stateful retry) has now been deprecated because the error handler can now do everything the RetryTemplate can do (back off, exception classification, etc, etc).

            With stateful retry (or backoffs in the error handler), the longest back off must be less than max.poll.interval.ms.

            A 24 hour backoff is, frankly, ridiculous - it would be better to just stop the container and restart it a day later.

            Source https://stackoverflow.com/questions/69514238

            QUESTION

            PySpark - Struggling to arrange the data by a specific format
            Asked 2021-Oct-05 at 13:26

            I am working on outputting total deduplicated counts from a pre-aggregated frame as follows.

            I currently have a data frame that displays like so. It's the initial structure and the point that I have gotten to by filtering out unneeded columns.

            ID Source 101 Grape 101 Flower 102 Bee 103 Peach 105 Flower

            We can see from the example above that 101 is found in both Grape and Flower. I would like to arrange the format so that the distinct string values from the "Source" column become their own sources, as from there I can perform a groupBy for a specific arrangement of yes's and no's as so.

            ID Grape Flower Bee Peach 101 Yes Yes No No 102 No No Yes No 103 No No No Yes

            I agree that creating this manually via the above example is a good fit, but I am working with +100m rows and need something more susinct.

            What I've extracted so far is a list of distinct Source values and arranged them into a list:

            ...

            ANSWER

            Answered 2021-Oct-05 at 13:26

            QUESTION

            java.lang.NullPointerException: null at org.apache.camel.model.ModelHelper.getNamespaceAwareFromExpression(ModelHelper.java:263)
            Asked 2021-Sep-30 at 12:01

            We have the NPE at the line of coe mentioned at the topic when calling for

            ...

            ANSWER

            Answered 2021-Sep-30 at 07:50

            It was missing the key part of :

            Source https://stackoverflow.com/questions/69374886

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install deduplicated

            You can install using 'pip install deduplicated' or download it from GitHub, PyPI.
            You can use deduplicated like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            Install
          • PyPI

            pip install deduplicated

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            https://github.com/eduardoklosowski/deduplicated.git

          • CLI

            gh repo clone eduardoklosowski/deduplicated

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            git@github.com:eduardoklosowski/deduplicated.git

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