relationships | redis backed user relationships on its simplest form

 by   emre Python Version: 0.0.2 License: MIT

kandi X-RAY | relationships Summary

kandi X-RAY | relationships Summary

relationships is a Python library. relationships has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has high support. You can install using 'pip install relationships' or download it from GitHub, PyPI.

redis backed user relationships on its simplest form.
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            kandi-support Support

              relationships has a highly active ecosystem.
              It has 77 star(s) with 5 fork(s). There are 6 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 0 open issues and 2 have been closed. There are 1 open pull requests and 0 closed requests.
              It has a positive sentiment in the developer community.
              The latest version of relationships is 0.0.2

            kandi-Quality Quality

              relationships has 0 bugs and 0 code smells.

            kandi-Security Security

              relationships has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              relationships code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              relationships is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              relationships releases are available to install and integrate.
              Deployable package is available in PyPI.
              Build file is available. You can build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              relationships saves you 89 person hours of effort in developing the same functionality from scratch.
              It has 227 lines of code, 42 functions and 5 files.
              It has high code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed relationships and discovered the below as its top functions. This is intended to give you an instant insight into relationships implemented functionality, and help decide if they suit your requirements.
            • Get the network of the actor
            • Get actor
            • List all calls to the user
            • Returns a list of followers of this key
            • Get a list of following keys
            Get all kandi verified functions for this library.

            relationships Key Features

            No Key Features are available at this moment for relationships.

            relationships Examples and Code Snippets

            Relationships
            npmdot img1Lines of Code : 6dot img1no licencesLicense : No License
            copy iconCopy
            GET /posts?_embed=comments
            GET /posts/1?_embed=comments
            
            
            GET /comments?_expand=post
            GET /comments/1?_expand=post
            
            
            GET  /posts/1/comments
            POST /posts/1/comments
            
              
            Initializes the union with the given set of people and relationships
            javadot img2Lines of Code : 13dot img2License : Permissive (MIT License)
            copy iconCopy
            public static void startUnion(int numberOfPeople, int[] people, int[] relationships) {
            
                    for(int i = 0; i <= numberOfPeople; i++) {
            
                        //initialize each individual person
                        people[i] = i;
            
                        //each person initi  
            Gets the relationships .
            javadot img3Lines of Code : 10dot img3License : Permissive (MIT License)
            copy iconCopy
            public List getRelations() {
                    List relationships = new ArrayList<>();
                    relationships.add(new Relationship("Friend", "1", "2"));
                    relationships.add(new Relationship("Following", "1", "4"));
                    relationships.add(new Rela  

            Community Discussions

            QUESTION

            How would you set up a database to handle comments for a blogging site?
            Asked 2021-Jun-15 at 19:59

            I'm a student learning about database design and currently learning about the relationships of - one-to-one, one-to-many, many-to-many. I understand the concept well enough, but feel like I'm lacking experience/information on how it would be implemented in a real production scenario.

            My question is this

            If I have a blog website with a Blog Post as an entity and comments for each blog post, how would you handle the comments in the database?`

            Would you use a one-to-many relationship and just store all the comments in a single table. Then link those comments to each blog post and user who created it?

            What if each comment had a sub-comment? Would you create a separate table for sub-comments and link it to a single comment? Would that cause too much overhead and confusion within the DB itself?

            I get the concepts and all, but don't understand best practices for handling what seems like basic stuff.

            Thanks in advance!

            ...

            ANSWER

            Answered 2021-Jun-15 at 16:06

            The simplest solution is to stick with a one-to-many relationship. Use one table and store one comment per row, with references to the post and the comment author, and a timestamp so you can sort the comments chronologically.

            You seem uncertain about whether you need a "threaded comment" hierarchy. This is more complex, so if you don't need it, don't bother.

            If you do need to show comment threads, then you should learn about running recursive queries in MySQL 8.0: https://dev.mysql.com/doc/refman/8.0/en/with.html#common-table-expressions-recursive

            You still only need one table. Don't create a second table for sub-comments. Just store comments like in your one-to-many example, but each comment may link to its "parent" comment when it is a reply.

            Another solution that many sites use is to skip implementing their own comment system, and just embed a comment service like Disqus. That's likely to be much more reliable and safe than yours. But if you're doing this as a learning exercise, that's worthwhile too.

            Source https://stackoverflow.com/questions/67989645

            QUESTION

            Rspec: How to verify if a record has been deleted?
            Asked 2021-Jun-15 at 15:40

            I have created a simple Rspec test to verfiy if a model created has been deleted. However, the test fails because the model still exists. Can anyone provide any assistance on how to determine if the record was actually deleted?

            ...

            ANSWER

            Answered 2021-Feb-08 at 20:41

            When you delete a record from a database, an object still persists in memory. That's why expect(person).to be_empty() fails.

            RSpec has the change matcher. ActiveRecord has the persisted? method. It returns false if a record is not persisted in a database.

            Source https://stackoverflow.com/questions/66108221

            QUESTION

            UML class diagram for domain with movies
            Asked 2021-Jun-15 at 11:58

            I am currently creating class diagrams in UML for a movie test domain. I would like to know if I am doing it right. Well, I have two alternatives (the first version in the first picture, the second in the second - I think the first one is better). I'm wondering if I've established the so-called "relationship owner" correctly, that is, from which class to which direction the relationships go. I also don't know if I didn't get multiplicity wrong (one to one, one to many etc.).

            So on my domain I would like to have movies of course, the actors starring in those movies and directors. I wonder if the class name "Character" is good in this case, because I mean all the characters that take part in a movie - it can be director, actor but also for example "Batman". Maybe I should make a distinction here between "Movie Character" and then "Human", "Monster", whatever. But I don't know how to do it elegantly, will I then inherit from the Character class? I'm also wondering if I shouldn't put classes like City or Country together in one class called Address - but I wanted the classes to take attributes like in this case, that one is Master and the other is detail - and the relationship set in the right direction. I use only relations such as Inheritance and Dependency, I do not know if I should change something in this case.

            Version 1

            Version 2

            Thanks in advance for any suggestions or advice!

            ...

            ANSWER

            Answered 2021-Jun-15 at 11:58
            In short

            Use inheritance very carefully. Prefer association over inheritance whenever your inheritance is not a permanent truth from the birth to the death of an object. ANd keep in mind that dependencies between classes do not make any promises about objects of those classes.

            Some more explanations

            Some clarifications on the UML syntax:

            • I understand that your plain thick lines ended with a small hollow triangle represent a specialization/generalization relationship (aka inheritance). If this is correct, the triangle should be larger to avoid visual confusion. Moreover multiplicity makes no sense with inheritance and should be removed.
            • I understand that with the dotted line you intend to represent an association with multiplicity. If this is correct:
              • the association should be plain lines, because dotted lines are for dependencies, and multiplicity would make no sense.
              • the meaning you give to the arrow head would be unclear. Do you use them to document navigability? In case of doubt, remove them. If you want to document ownership of the association end, use the dot notation instead. (we cannot say if it’s right or wrong, since it’s a decision on how your model sees the associations)

            In view of your comments and the third model linked therein, there are some key UML semantics you need to keep in mind:

            • Inheritance is an ultra-strong relationship which means "is (always) a". In your example, you may say that an Actor is always a Person, and hence, everything you say about a Person is also true for an Actor. By the way, you should avoid repeating inherited properties or methods, since it could create some ambiguity.
            • Inheritance is not a substitute for aggregation, composition or association. You can for example not say that a CrewMember (one person) is always a Crew (a group of persons). A CrewMember belongs to a Crew but there are things that the crew can do together that the individual member can't.
            • Inheritance is not suitable if it's not always true. A Character for example may often be a Person. But not always;: you can have ghost characters, comic characters, robot characters, or animals.
            • Association means that there is some structural relation between some instances of the associated classes. For example, that one ore several persons live in one city, seems a very relevant assocaition.
            • Dependency means that a class is dependent on another, i.e. without the other class it would not work or something would be missing. It's a statement about the classes and not the objects. I.e. If you meant to say that Person is dependent on City you just say that the class Person would not work without knowing about City (for example, because the operation sendPostCardFrom(city: City) needs an argument of that type) but you do not say anything about persons X, Y and Z. If you want that X, Y and Z are related to city a, b, and c, you need an association.

            About the model content, I'll not decide for you and there is no single truth. I therefore prefer to draw your attention at potential issues. I raise them in form of a question, up-to you to adjust the model based on your own answer:

            • Common issues between the both variants:

              • Are Actor and Director really Persons ? In this case, what with the Persons that are Actors and Directors at the same time (g.g. Clint Eastwood) ? Or are Actor and Director just roles that a Persons takes for a given Movie ?
              • Is a Character really related only to 1 Movie? What to do with Indiana Jones, where the same character appears in several movies?
              • In a similar way, I wonder if there's really a single Person who lives in a City or if this should not be a many-to-many association?
            • Issues regarding the differences: `

              • Is a Person in version 1 a Character (inheritance) ? Or is a Character a representation of a Person (association: represents) ?
              • Is a Character in version 2 really an Actor and by transitivity also a Person (inheritance)? Or is the Character only associated with an Actor (association: plays) ?

            It's up to you to decide, but wherever I asked a question about association or inheritance, you should better think twice before using inheritance (i.e. prefer association/composition over inheritance)

            Source https://stackoverflow.com/questions/67912042

            QUESTION

            Eloquent::where() condition is not working as expected, but Collection::where() does work
            Asked 2021-Jun-15 at 05:32

            I've been playing around with Eloquent for a while, but I met a case where Eloquent::where() is not working as I expected. I managed to get Collection::where() worked instead though. However, I'm still wondering why Eloquent::where() didn't work in my case. I will keep the problem as simple as I can, here it goes:

            • I have Product and ProductCategory as many-to-many relationships and the pivot table name is "product_relate_category".
            • Here is the relationship between them. It's still working so you can skip
            ...

            ANSWER

            Answered 2021-Jun-15 at 05:32

            in your where in the query, you have used the column 'id' which is existed in the product_relate_category table and products table, so the database can't determine exactly what column you mean ... in this case you should write the full column name:

            Source https://stackoverflow.com/questions/67980265

            QUESTION

            transform file/directory structure into 'tree' in vue json
            Asked 2021-Jun-15 at 01:45

            transform file/directory structure into 'tree' in vue json

            I have an array of objects that looks like this:

            ...

            ANSWER

            Answered 2021-Jun-11 at 09:55

            EDIT

            Here is the full implementation, based upon my initial answer. I changed the forEach() into map() as it is more suitable in this case.

            Source https://stackoverflow.com/questions/67915991

            QUESTION

            Laravel relationships, Many to Many or Has Many Through?
            Asked 2021-Jun-14 at 23:46

            I'm building a web app using Laravel 8 and one thing I tend to struggle with is the complex relationships and accessing the data. I've started reading on hasManyThrough relationships but I'm not convinced that's the correct way to do it for my scenario.

            The app is used by travelling salesmen to check in to a location when they arrive safely.

            I have three main tables:

            • Locations (where they are visiting),
            • Checkins (where their check in data is stored, e.g. time),
            • Users

            This is where it gets a little complex and where I find myself not being able to see the wood for the trees...

            • Locations have many users, users have many locations. Many-to-many pivot table created.
            • Locations have many check ins, check ins have many locations. Many-to-many pivot table created.
            • Check ins have many users, users have many check ins. Many-to-many pivot table created.

            As such they're all created using a belongsToMany relationship.

            Now what I'd like to do is access the user of the check in so I can call something similar to on my show.blade.php:

            ...

            ANSWER

            Answered 2021-Jun-14 at 23:46

            You said "Check ins have many users", you seem to want the singular user for a check-in, but currently that would result in many users. It sounds like users check-in in a many to one relationship

            Also $checkin->created_at will be by default a carbon object, so you can just go $checkin->created_at->format('jS F Y')

            Also don't mix using compact and with, stay consistent and use only 1 as they achieve the same thing

            Also $checkin->users()->name won't work, if you use the brackets on syntax is only returns a query builder instance, which you would need to call get on like $checkin->users()->get(), or you could use $checkin->users which will fetch them anyway. You may want to look into using with('relation') on query builder instances to stop N+1 queries if you want to dive a little deeper. Lastly $checkin->users()->get()->name also won't work as your user relation is many to many which returns a collection, which again points to you should have a belongsTo relationship called user without a pivot table

            Source https://stackoverflow.com/questions/67975663

            QUESTION

            Cypher query in a neo4j graph
            Asked 2021-Jun-14 at 23:24

            I have the following graph in Neo4j:
            Book: book_id, isbn, language_code, title, image_url, small_image_url, avg_ratings,
            Author: name,
            Reader: id,
            with 3 relationships:
            (Reader)-[:Rated]->(Book) that has the property {rating: value},
            (Reader)-[:Recommend]->(Book),
            (Author)-[:Write]->(Book).

            I want to find the book that has been most recommended with a query in Cypher.
            I wrote a query but I'm not too sure about it because I'm not familiar using count() and max() operators.

            Here is my attempt:

            ...

            ANSWER

            Answered 2021-Jun-14 at 22:16

            QUESTION

            Display a list of items of a specific user (by id) in One to many relationship Spring Boot
            Asked 2021-Jun-14 at 21:02

            in my example here i want to display a list of appointments of a specific patient in a one to many relationships .. the process is going well but the problem is how to display this list which is in patient as an attribute.

            Appointment Entity

            ...

            ANSWER

            Answered 2021-Jun-14 at 21:02

            As you have many to one mapping in Appointment entity. you could write the below query in AppointmentRep

            List findAllByPatientId(int id);

            https://docs.spring.io/spring-data/jpa/docs/current/reference/html/#repositories.query-methods.query-creation

            Source https://stackoverflow.com/questions/67976535

            QUESTION

            Automatically running AnyLogic sliders so that different combinations are chosen
            Asked 2021-Jun-14 at 01:24

            I am creating a system dynamics model in AnyLogic to be representative of a water mass balance for a city. One of the important aspects of this is to understand how different conservation measures affect supply-demand relationships. There are 3 different conservation measures and there are five different levels of adoption for each: 0%, 25%, 50%, 75%, and 100%. This makes a total of 125 combinations. I was thinking of linking the 3 parameters to sliders in order to choose the level of adoption, but going through each combination manually appears to be unnecessarily grueling. Does anyone know if it is possible that during run time the model is able to choose the different combinations on its own? If so, how can this be accomplished?

            ...

            ANSWER

            Answered 2021-Jun-14 at 01:24

            Parameter variation experiment should be ideal for what you need: https://anylogic.help/anylogic/experiments/parameter-variation.html#parameter-variation-experiment

            Create a parameter in main for each measure you want to vary. Then, in the experiment's properties, you can specify the range and step to define the different values you want the parameters to take.

            Then, when you run it, all possible combinations will be run.

            Source https://stackoverflow.com/questions/67961500

            QUESTION

            Recursive Web Scraping Pagination
            Asked 2021-Jun-13 at 15:18

            I'm trying to scrape some real estate articles from the following website:

            Link

            I manage to get the links I need,but I am struggling with pagination on the web page.I'm trying to scrape every link under each category 'building relationships', 'building your team', 'capital rising' etc.Some of these categories pages have pagination and some of them do not contain pagination.I tried with the following code but it just gives me the links from 2 page.

            ...

            ANSWER

            Answered 2021-Jun-13 at 15:18

            To print title of every article under each tag and each page under the tag you can use this example:

            Source https://stackoverflow.com/questions/67954473

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install relationships

            You can install using 'pip install relationships' or download it from GitHub, PyPI.
            You can use relationships like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            Install
          • PyPI

            pip install relationships

          • CLONE
          • HTTPS

            https://github.com/emre/relationships.git

          • CLI

            gh repo clone emre/relationships

          • sshUrl

            git@github.com:emre/relationships.git

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