falcon | magic web data plane API and microservices framework | REST library
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- Register an error handler
- Determines if we should wrap non - coroutines
- Check if a function is a python function
- Wrap non - coroutine functions
- Create a WS_ACESS event
- Translate a webSocket error into an error message
- Send a message
- Pump messages from the websocket
- Validate Range header
- Create a resolver function
- Receive a message from the server
- Creates a property property
- Inspect a compiled router
- Profile a VM
- Profile a benchmark
- The access route
- Find wheels and source dist
- Return a string representation of the middleware tree
- Create a function to encode uri
- Add a sink
- Creates a function to run before the given action
- Add a static route
- Default serialize error handler
- Decode a URI
- Creates a function that will be called after the given action
- Run the benchmarks
falcon Key Features
falcon Examples and Code Snippets
Lines of Code : 15
License : No License
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$ cat plugin.test.json { "exporter_urls": [ "http://127.0.0.1:9121/metrics" ], "append_tags": ["region=bj", "dept=cloud"], "endpoint": "127.0.0.100", "ignore_metrics_prefix": ["go_"], "metric_prefix": "", "metric_type": {}, "default_mapping_metric_type": "COUNTER", "timeout": 500 }
cat plugin.test.json | ./prometheus-exporter-collector -b falcon -s 60 | curl -X POST -d @- http://127.0.0.1:1988/v1/pushexp_g = df['Emails'].explode().groupby(level=0)
df['Emails_final1'] = exp_g.first()
msk = df['Emails_final1'].notna()
df['Emails_final1'] = df['Emails_final1'].fillna(df['Emails 2'])
df['Emails_final2'] = exp_g.nth(1)
df['Emails_final2'] = df['Emails_final2'].mask(lambda x: ((x == df['Emails_final1']) | x.isna()) & msk, df['Emails 2'])
Emails_final1 Emails_final2
falcon jjj@gmail.com jp@gmail.com
dog www@gmail.com zzz@gmail.com
cat ccc@gmail.com None
df2.columns = df2.columns.str[0]
df3.columns = df3.columns.str[0]
out = pd.concat([df1, df2, df3])
out = pd.concat([df1, df2.rename(columns=lambda x:x[0]), df3.rename(columns=lambda x:x[0])])
A B C D
0 A0 B0 C0 D0
1 A1 B1 C1 D1
2 A2 B2 C2 D2
3 A3 B3 C3 D3
4 A4 B4 C4 D4
5 A5 B5 C5 D5
6 A6 B6 C6 D6
7 A7 B7 C7 D7
8 A8 B8 C8 D8
9 A9 B9 C9 D9
10 A10 B10 C10 D10
11 A11 B11 C11 D11
df['Contact phone number'] = '+' + df['Contact phone number'].dropna().astype(str).str.extract(r'(\d)(\d{3})(\d{3})(\d{3})').apply(list, axis=1).str.join('-')
>>> df
Company phone number Contact phone number num_specimen_seen
falcon +1-541-296-2271 +1-511-296-227 10
dog +1-542-296-2271 NaN 2
cat +1-543-296-2271 +1-531-296-227 3
df['Contact phone number'] = df['Contact phone number'].str.replace(r'^(\d)(\d{3})(\d{3})(\d+)$', r'+1-\1-\2-\3-\4', regex=True)
>>> df['Contact phone number']
falcon +1-1-511-296-2271
dog None
cat +1-1-531-296-2271
df['Emails'] = df['Emails'].explode().groupby(level=0).first()
>>> df
Emails num_wings num_specimen_seen
falcon j@gmail.com 2 10
dog jzp@gmail.com 0 2
df['index'].diff().ne(1).cumsum()
Trending Discussions on falcon
Trending Discussions on falcon
QUESTION
I am doing a query on Google Big query, I have joined the 2 tables and created a new column "total gmv" using "SUM" to represent the total revenue, now I wanted to show only the top 2 vendors , GROUP BY country in my query.
I manage to show total_gmv group by COUNTRY and vendor_name, but I would like to filter to show top 2 vendors for each country only.
Code I used
SELECT Ord.country_name, vn.vendor_name, round(sum(Ord.gmv_local),2) as total_gmv FROM ORDERS as Ord
left join `primeval-falcon-306603.foodpanda_BI_Exercise.Vendors` as vn
ON Ord.vendor_id = vn.id
GROUP BY Ord.country_name, vn.vendor_name
ORDER BY Ord.country_name, total_gmv desc
Is there a way to show only the top 2 vendors per country?
My target table should look like this, showing top 2 only
I am using Google bigquery and it seems the "TOP 2" function doesn't work?
country_name vendor_name total_gmv Singapore A House 1583.25 Singapore B House 1236.35 Hong Kong H House 1888.75 Hong Kong K House 755.78 Bangkok BB House 936.12ANSWER
Answered 2021-Jun-10 at 02:56Use ROW_NUMBER:
WITH cte AS (
SELECT Ord.country_name, vn.vendor_name, ROUND(SUM(Ord.gmv_local), 2) AS total_gmv,
ROW_NUMBER() OVER (PARTITION BY Ord.country_name
ORDER BY SUM(Ord.gmv_local) DESC) rn
FROM ORDERS AS Ord
LEFT JOIN `primeval-falcon-306603.foodpanda_BI_Exercise.Vendors` AS vn
ON Ord.vendor_id = vn.id
GROUP BY Ord.country_name, vn.vendor_name
)
SELECT country_name, vendor_name, total_gmv
FROM cte
WHERE rn <= 2
ORDER BY country_name, total_gmv DESC;
QUESTION
I have an assignment for a car rental system which requires the program to read the from a CSV file, which contains each car and its specifications.
I will need to store the values into an array, as I will need to count how many cars are left after one is hired, as well as calculate the cost which is listed for each car.
1,Mazda CX-9,7,Automatic,Premium,150
2,VW Golf,5,Automatic,Standard,59
3,Toyota Corolla,5,Automatic ,Premium,55
4,VW Tiguan,7,Automatic,Premium,110
5,Ford Falcon,5,Manual,Standard,60
So far I've only been able to use line.split(",") to assign each column into a 1 dimensions array, which would output each number in index [0], each make in index[1], etc.
If I try line.split("\n") it assigns the whole file as is in index[0].
Please let me know what the best way to go about this would be.
I have been able to output the cars as I'd like to in code that I have not included here. The main problem is how to store the values appropriately.
public static void main(String[] args) throws FileNotFoundException, IOException {
String path = "carlist.csv";
String line = "";
long lines = 0;
BufferedReader br = new BufferedReader(new FileReader(path));
while ((line = br.readLine()) != null) {
lines++;
String[] menu = line.split(",");
System.out.println(menu[0]);
}
}
ANSWER
Answered 2021-Jun-06 at 06:01Splitting by comma, is the right way, you just need to store the the array returned from the split function into an ArrayList or an array of Strings array, like this:
public static void main(String[] args) throws FileNotFoundException, IOException {
String path = "carlist.csv";
String line = "";
long lines = 0;
BufferedReader br = new BufferedReader(new FileReader(path));
ArrayList list = new ArrayList<>();
while ((line = br.readLine()) != null) {
lines++;
list.add(line.split(","));
System.out.println(menu[0]);
}
}
Or like this:
public static void main(String[] args) throws FileNotFoundException, IOException {
String path = "carlist.csv";
String line = "";
long lines = 0;
BufferedReader br = new BufferedReader(new FileReader(path));
String[][] cars = new String[100][6];
while ((line = br.readLine()) != null) {
cars[lines++] = line.split(",");
System.out.println(menu[0]);
}
}
Here, I have taken 100 as the maximum number of records that will be in a CSV file, and 6 is the maximum length of the array, that will be obtained after splitting by comma. Both of these can be modified according to your use-case. Now, you can get any car and its specific elements like this cars[0][3], or like this list.get(0)[3], depending on which implementation you use.
QUESTION
We think we have an issue with our inheritance, but we don't know how to solve it. (We have Class OOP)
Console prints...
clang++-7 -pthread -std=c++17 -o main Pelicula.cpp Serie.cpp Video.cpp main.cpp
Pelicula.cpp:7:115: error: expected class member or base class name
...int e, int f, string pa, string direct, string distrib) : public Video(a...
^
1 error generated.
Serie.cpp:7:83: error: expected class member or base class name
...b, string c, int d, int e, int f, int ab, int cd) : public Video(a,b,c,d...
^
1 error generated.
exit status 1
Using this code:
main.cpp
#include
#include "Video.h"
#include "Serie.h"
#include "Pelicula.h"
using namespace std;
int main(){
Video *catalogo[2];
catalogo[0]= new Serie("Serie Narrativa","Stranger Things","Fantastico",8,50,120,25,4);
//vector[1]= new Serie("Falcon & The Winter Soldier",6,1);
catalogo[0]->muestraDatos();
int sel;
cout<<"+++++++++++++++\n\n=== Bienvenido a La plataforma SAJ ===\n\nElija las opciones\n1)Consultar peliculas y series\n2)Calificar"<>sel;
switch(sel){
case 1:
cout<<"CONSULTAR TOTAL DE VIDEO"<getTipoVideo()==busqueda)
busqueda=i;
}
automotor[busqueda];
*/
break;
case 2:
cout<<"Calificar video"< Video.h
#ifndef VIDEO_H
#define VIDEO_H
#include
using namespace std;
class Video{
public:
Video(string a, string b, string c, int d, int e, int f);
void calificaVideo();
virtual void muestraDatos(); //agrega virtual luego Herencia
string getTipoVideo();
private:
string tipoVideo;
string nombreVideo;
string genero;
int calif;
int anioLanz;
int duracion;
};
#endif
Video.cpp
#include
#include "Video.h"
//#include "Serie.h"
//#include "Pelicula.h"
using namespace std;
Video::Video(string a, string b, string c, int d, int e, int f){
tipoVideo=a;
nombreVideo=b;
genero=c;
if(d<0){d=0;}
else if(d>10){d=10;}
calif=d;
anioLanz=e;
duracion=f;
}
void Video::muestraDatos(){
cout<<"IMPRIMIR REGISTRO\nTipo de video: "<<<"\nTítulo: "<<<"\nGenero: "<<<"\nCalificacion: "<<<"\nAño de lanzamiento: "<<<"\nDuracion: "<<>d;
if(d<0){d=0;}
else if(d>10){d=10;}
calif=d;
cout<<<" - Guardado!"< Serie.h
#ifndef SERIE_H
#define SERIE_H
#include
#include "Video.h"
using namespace std;
class Serie : public Video{
public:
Serie(string, string, string, int, int, int, int, int);
void muestraDatos();
private:
int episod_portemp;
int temporadas;
};
#endif
Serie.cpp
#include
#include "Serie.h"
//#include "Video.h"
using namespace std;
Serie::Serie(string a, string b, string c, int d, int e, int f, int ab, int cd) : public Video(a,b,c,d,e,f){
episod_portemp=ab;
temporadas=cd;
}
void Serie::muestraDatos(){
Video::muestraDatos();
cout<<"Episodios por temporada: "<< Pelicula.h
#ifndef PELICULA_H
#define PELICULA_H
#include
#include "Video.h"
using namespace std;
class Pelicula : public Video{
public:
Pelicula(string, string, string, int, int, int, string, string, string);
void muestraDatos();
private:
string pais;
string director;
string distribuidor;
};
#endif
Pelicula.cpp
#include
#include "Pelicula.h"
//#include "Video.h"
using namespace std;
Pelicula::Pelicula(string a, string b, string c, int d, int e, int f, string pa, string direct, string distrib) : public Video(a,b,c,d,e,f){
pais=pa;
director=direct;
distribuidor=distrib;
}
void Pelicula::muestraDatos(){
Video::muestraDatos();
cout<<"Pais: "<< Befora causing this problem, printed another problem where it was "re-declarating" class Video, idk if this could be related.
ANSWER
Answered 2021-May-30 at 15:43You declare inheritance as public. You do not declare constructors the same way.
In other words:
Serie::Serie(string a, string b, string c, int d, int e, int f, int ab, int cd) : Video(a,b,c,d,e,f) { ...
}
Note: To avoid extraneous copies, use
const std::string&as your default argument type.
QUESTION
EXAMPLE DF
df = pd.DataFrame({'Animal': ['Falcon', 'Falcon', 'Falcon',
'Parrot', 'Parrot', 'Parrot'],
'Max Speed': [380., 370., 25., 24., 26., 29.]})
DESIRED OUTPUT
2 (because the smallest difference is between 24 and 26 of Parrot)
EVEN BETTER (so I can check)
'Parrot, 2'
WHAT I WAS THINKING
'I need to sort by animal and max speed, and then a window function, but there must be a better solution...'
ANSWER
Answered 2021-May-26 at 14:06We can check groupby with diff
df['new'] = df.sort_values('Max Speed').groupby('Animal')['Max Speed'].diff().abs()
out = df[df.new==df.new.min()]
Out[249]:
Animal Max Speed new
4 Parrot 26.0 2.0
QUESTION
I am looking to build a simple logic to let user define which templates that should be called upon. The code illustrates a minimized example. The setup is very useful when having many templates, e.g. the output I am building is about 2.600 lines of XHTML code. Then it is very good being able to exclude several templates to focus on only some of the templates.
I have created above setup (previously) successfully having XML as source file and modularized code. I suspect it is my setup with having JSON as source file and the adaption of code that causes the problem.
Below code should allow the user to switch variable "build-with-books" from 0 to 1, and if set to 1, the "if" element should call the included template.
I am sure that there are many "smarter" way of solving my needs. Currently I am just looking to understand why my code does not follow the wanted logics of switching on/off the build of elements.
XSLT fiddle is down so I just paste my code below:
data:
{
"books": {
"Wonderland": 43
},
"beverage": {
"Falcon": 12
}
}
principal.xsl:
0
Adventure
Supporting module: books.xsl
{.}
Result:
43
Expected result if variable "build-with-books" set to 0
Expected result if variable "build-with-books" set to 1
43
ANSWER
Answered 2021-May-21 at 07:21Start
Delete this part from principal.xsl: (call-template uses the current context and that is still your match on data)
And remove the @name attribute from
Option: 1
Change match template in books.xls to look like this (it will use your global $build-with-books directly)
{.}
Option: 2
Make use of xsl:next-match in your principal.xsl: (it will first use the template with a higher priority where it checkes that global $build-with-books)
Add this:
QUESTION
I am miserably stuck at Pandas Data Cleaning. I have made a very simple example to demonstrate my problem. For each row, I want to delete/alter the duplicate and keep the last one. Currently, my DataFrame is 'animals'. And I want it to be the DataFrame 'animals_clean'
Imagine this DataFrame. You can see duplicates along axis=0, e.g. 'cat' is repeated in row 0
list_of_animals = [['cat','dog','monkey','sparrow', 'cat'],['cow', 'eagle','rat', 'eagle', 'owl'],['deer', 'horse', 'goat', 'falcon', 'falcon']]
animals = pd.DataFrame(list_of_animals)
How it looks:
This is the result I want. You can see the duplicates in each row is marked 'X' keeping the last one.
list_of_animals_clean = [['X','dog','monkey','sparrow', 'cat'],['cow', 'X','rat', 'eagle', 'owl'], ['deer', 'horse', 'goat', 'X', 'falcon']]
animals_clean = pd.DataFrame(list_of_animals_clean)
ANSWER
Answered 2021-May-17 at 23:52Try apply + mask + duplicated with keep='last':
import pandas as pd
list_of_animals = [['cat', 'dog', 'monkey', 'sparrow', 'cat'],
['cow', 'eagle', 'rat', 'eagle', 'owl'],
['deer', 'horse', 'goat', 'falcon', 'falcon']]
animals = pd.DataFrame(list_of_animals)
animals = animals.apply(
lambda s: s.mask(s.duplicated(keep='last'), 'x'),
axis=1
)
print(animals)
Output:
0 1 2 3 4
0 x dog monkey sparrow cat
1 cow x rat eagle owl
2 deer horse goat x falcon
QUESTION
I would like to split variables into the different types. For example:
Tweets ID Registration Date num_unique_words photo_profile range
object int64 object float64 int64 category
What I did is:
type_dct = {str(k): list(v) for k, v in df.groupby(df.dtypes, axis=1)} but I have got a TypeError:
TypeError: Cannot interpret 'CategoricalDtype(categories=['<5',
'>=5'], ordered=True)' as a data type
range can take two values: '<5' and '>=5'.
I hope you can help to handle this error.
df = pd.DataFrame({'Tweets': ['Tweet 1 from user 1', 'Tweet 2 from user 1',
'Tweet 1 from user 3', 'Tweet 10 from user 1'],
'ID': [124, 124, 12, 124],
'Registration Date': ['2020-12-02', '2020-11-21',
'2020-12-02', '2020-12-02'],
'num_unique_words': [41, 42, 12, 69],
'photo_profile': [1, 0, 1, 1],
'range': ['<5', '<5', '>=5', '<5']},
index=['falcon', 'dog', 'spider', 'fish'])
ANSWER
Answered 2021-May-14 at 02:12That was surprisingly more complicated that I thought it would be, but here is a work around using list comprehension:
type_dct = {str(k): list(v) for k, v in df.groupby([i.name for i in df.dtypes], axis=1)}
Output:
{'category': ['range'],
'int64': ['ID', 'num_unique_words', 'photo_profile'],
'object': ['Tweets', 'Registration Date']}
pd.CategorialDtypes by itself doesn't work well in the groupby, we must use the name attribute of that object.
Use pd.DataFrame.select_dtypes
Example from docs.
df = pd.DataFrame({'a': [1, 2] * 3,
'b': [True, False] * 3,
'c': [1.0, 2.0] * 3})
df
a b c
0 1 True 1.0
1 2 False 2.0
2 1 True 1.0
3 2 False 2.0
4 1 True 1.0
5 2 False 2.0
df.select_dtypes(include='bool')
b
0 True
1 False
2 True
3 False
4 True
5 False
df.select_dtypes(include=['float64'])
c
0 1.0
1 2.0
2 1.0
3 2.0
4 1.0
5 2.0
df.select_dtypes(exclude=['int64'])
b c
0 True 1.0
1 False 2.0
2 True 1.0
3 False 2.0
4 True 1.0
5 False 2.0
QUESTION
I have created lambda function in AWS which send mail to various recipients. I need to add company logo/banner at bottom of the mail. Below is the code
var nodemailer = require('nodemailer');
var transporter = nodemailer.createTransport({
host: 'xxxxxx.xxxx.com',
port:587,
secure : true
});
var text = 'xxxxxxxxxx ';
var mailOptions = {
from: 'donotreplyhere@xxxx.com',
to: 'skumar@xxx.com',
subject: 'Test subject',
html: text
};
exports.handler = async (event, context, callback) => {
return new Promise((resolve,reject)=>{
transporter.sendMail(mailOptions, function (error, info) {
if (error) {
console.log("Error " +error);
} else {
console.log('Email sent: ' + info.response);
}
});
});
}
I am receiving the mail but image is not being displayed getting error : The linked image can't be displayed.
I also tried with s3 url by uploading images in s3 bucket but using its url like
';
But this didn't worked, may be because its not public and i can't make it public.
Any other way that i can use to accomplish this task.
Thank for looking
ANSWER
Answered 2021-May-13 at 04:06Here are some of the options:
- If you can use
CloudFrontin-front of S3 and use the CloudFront URL for the static content, do so. Here is more information. - You can also host the static content on any publicly accessible website e.g. on Github pages which is also a CDN for free.
- You can use Data URLs in place of the images. You must convert the images to the Base64 encoded version and use them directly in the HTML.
- You can use SVG as an image. You must convert your existing images to SVG and directly embed the contents in the HTML.
QUESTION
Input
df=pd.DataFrame({'Name':['JOHN','ALLEN','BOB','NIKI','CHARLIE','CHANG'],
'Age':[35,42,63,29,47,51],
'Salary_in_1000':[100,93,78,120,64,115],
'FT_Team':['STEELERS','SEAHAWKS','FALCONS','FALCONS','PATRIOTS','STEELERS']})
n1=(df['Age']< 60)
n2=(df['Salary_in_1000']>=100)
n3=(df['FT_Team'].str.startswith('S'))
Using these conditions to select, it will return JOHN and CHANG.
Goal
I want to create dataframe where data is not selected and a new column which returns which conditions is not expected. For example,
* ALLEN: n1, n2
* BOB: n2,n3
* NIKI: n3
* CHANG: n2,n3
The new column name is reason. The value is the condition variable and the type is string.
Try
I have to try each condition and record each variable violates which rules by hand.
ANSWER
Answered 2021-May-03 at 00:43If you put the conditions into a dictionary, you can automatically assign() an arbitrary number of conditions as columns:
conditions = dict(
n1 = (df['Age'] < 60),
n2 = (df['Salary_in_1000'] >= 100),
n3 = (df['FT_Team'].str.startswith('S')),
)
df = df.assign(**{key: value for key, value in conditions.items()})
# Name Age Salary_in_1000 FT_Team n1 n2 n3
# 0 JOHN 35 100 STEELERS True True True
# 1 ALLEN 42 93 SEAHAWKS True False True
# 2 BOB 63 78 FALCONS False False False
# 3 NIKI 29 120 FALCONS True True False
# 4 CHARLIE 47 64 PATRIOTS True False False
# 5 CHANG 51 115 STEELERS True True True
Then create reason based on which of those conditions (last n columns) are False:
n = len(conditions)
df['reason'] = df.apply(lambda x: x[-n:].loc[x[-n:] == False].index.values, axis=1)
df = df.drop(columns=conditions.keys())
# Name Age Salary_in_1000 FT_Team reason
# 0 JOHN 35 100 STEELERS []
# 1 ALLEN 42 93 SEAHAWKS [n2]
# 2 BOB 63 78 FALCONS [n1, n2, n3]
# 3 NIKI 29 120 FALCONS [n3]
# 4 CHARLIE 47 64 PATRIOTS [n2, n3]
# 5 CHANG 51 115 STEELERS []
QUESTION
So I have a json list and use two input request.args.get('sport') and request.args.get('team') to find those values in my list. If the value is found I want to output more info on the team and sport.
This is what I tried to do:
for a_team in scores_list['scores']:
if a_team['sport'].lower() == request.args.get('sport').lower() \
and a_team['team'].lower() == request.args.get('team').lower():
teams_list = []
for a_team['team'] in scores_list['scores']:
teams_list.append("{} ({}) ({}) {} ({}) - ({}) {}".format(a_team['full_name'], a_team['date'],
a_team['sport'], a_team['home_name'],
a_team['home_score'], a_team['away_score'],
a_team['away_name']))
The problem is that this way is outputting the same set of values over. I want to output all different games with the the team from request.args.get('team'). I am new to python and I have searched everyone but couldn't find an answer.
Below is a sample of my json file:
{
"scores": [
{
"sport": "football",
"team": "packers",
"full_name": "Green Bay Packers",
"week": "15-2020",
"boxscore": "202012190gnb",
"away_name": "Carolina Panthers",
"away_abbr": "car",
"away_score": 16,
"home_name": "Green Bay Packers",
"home_abbr": "gnb",
"home_score": 24,
"winning_name": "Green Bay Packers",
"winning_abbr": "gnb",
"losing_name": "Carolina Panthers",
"losing_abbr": "car"
},
{
"sport": "football",
"team": "packers",
"full_name": "Green Bay Packers",
"week": "19-2020",
"boxscore": "202101160gnb",
"away_name": "Los Angeles Rams",
"away_abbr": "ram",
"away_score": 18,
"home_name": "Green Bay Packers",
"home_abbr": "gnb",
"home_score": 32,
"winning_name": "Green Bay Packers",
"winning_abbr": "gnb",
"losing_name": "Los Angeles Rams",
"losing_abbr": "ram"
},
{
"sport": "football",
"team": "packers",
"full_name": "Green Bay Packers",
"week": "20-2020",
"boxscore": "202101240gnb",
"away_name": "Tampa Bay Buccaneers",
"away_abbr": "tam",
"away_score": 31,
"home_name": "Green Bay Packers",
"home_abbr": "gnb",
"home_score": 26,
"winning_name": "Tampa Bay Buccaneers",
"winning_abbr": "tam",
"losing_name": "Green Bay Packers",
"losing_abbr": "gnb"
},
{
"sport": "football",
"team": "chiefs",
"full_name": "Kansas City Chiefs",
"week": "16-2020",
"boxscore": "202012270kan",
"away_name": "Atlanta Falcons",
"away_abbr": "atl",
"away_score": 14,
"home_name": "Kansas City Chiefs",
"home_abbr": "kan",
"home_score": 17,
"winning_name": "Kansas City Chiefs",
"winning_abbr": "kan",
"losing_name": "Atlanta Falcons",
"losing_abbr": "atl"
},
{
"sport": "football",
"team": "chiefs",
"full_name": "Kansas City Chiefs",
"week": "17-2020",
"boxscore": "202101030kan",
"away_name": "Los Angeles Chargers",
"away_abbr": "sdg",
"away_score": 38,
"home_name": "Kansas City Chiefs",
"home_abbr": "kan",
"home_score": 21,
"winning_name": "Los Angeles Chargers",
"winning_abbr": "sdg",
"losing_name": "Kansas City Chiefs",
"losing_abbr": "kan"
},
{
"sport": "football",
"team": "chiefs",
"full_name": "Kansas City Chiefs",
"week": "19-2020",
"boxscore": "202101170kan",
"away_name": "Cleveland Browns",
"away_abbr": "cle",
"away_score": 17,
"home_name": "Kansas City Chiefs",
"home_abbr": "kan",
"home_score": 22,
"winning_name": "Kansas City Chiefs",
"winning_abbr": "kan",
"losing_name": "Cleveland Browns",
"losing_abbr": "cle"
},
{
"sport": "football",
"team": "chiefs",
"full_name": "Kansas City Chiefs",
"week": "19-2020",
"boxscore": "202101240kan",
"away_name": "Buffalo Bills",
"away_abbr": "buf",
"away_score": 24,
"home_name": "Kansas City Chiefs",
"home_abbr": "kan",
"home_score": 38,
"winning_name": "Kansas City Chiefs",
"winning_abbr": "kan",
"losing_name": "Buffalo Bills",
"losing_abbr": "buf"
},
{
"sport": "football",
"team": "buccaneers",
"full_name": "Tampa Bay Buccaneers",
"week": "21-2020",
"boxscore": "202102070tam",
"away_name": "Kansas City Chiefs",
"away_abbr": "kan",
"away_score": 9,
"home_name": "Tampa Bay Buccaneers",
"home_abbr": "tam",
"home_score": 31,
"winning_name": "Tampa Bay Buccaneers",
"winning_abbr": "tam",
"losing_name": "Kansas City Chiefs",
"losing_abbr": "kan"
},
{
"sport": "baseball",
"team": "giants",
"full_name": "San Francisco Giants",
"date": "7-23-2020",
"boxscore": "LAN/LAN202007230",
"away_name": "San Francisco Giants",
"away_abbr": "SFG",
"away_score": 1,
"home_name": "Los Angeles Dodgers",
"home_abbr": "LAD",
"home_score": 8,
"winning_name": "Los Angeles Dodgers",
"winning_abbr": "LAD",
"losing_name": "San Francisco Giants",
"losing_abbr": "SFG"
},
{
"sport": "baseball",
"team": "giants",
"full_name": "San Francisco Giants",
"date": "7-24-2020",
"boxscore": "LAN/LAN202007240",
"away_name": "San Francisco Giants",
"away_abbr": "SFG",
"away_score": 1,
"home_name": "Los Angeles Dodgers",
"home_abbr": "LAD",
"home_score": 9,
"winning_name": "Los Angeles Dodgers",
"winning_abbr": "LAD",
"losing_name": "San Francisco Giants",
"losing_abbr": "SFG"
},
{
"sport": "baseball",
"team": "giants",
"full_name": "San Francisco Giants",
"date": "7-25-2020",
"boxscore": "LAN/LAN202007250",
"away_name": "San Francisco Giants",
"away_abbr": "SFG",
"away_score": 5,
"home_name": "Los Angeles Dodgers",
"home_abbr": "LAD",
"home_score": 4,
"winning_name": "San Francisco Giants",
"winning_abbr": "SFG",
"losing_name": "Los Angeles Dodgers",
"losing_abbr": "LAD"
},
{
"sport": "baseball",
"team": "giants",
"full_name": "San Francisco Giants",
"date": "8-5-2020",
"boxscore": "COL/COL202008050",
"away_name": "San Francisco Giants",
"away_abbr": "SFG",
"away_score": 4,
"home_name": "Colorado Rockies",
"home_abbr": "COL",
"home_score": 3,
"winning_name": "San Francisco Giants",
"winning_abbr": "SFG",
"losing_name": "Colorado Rockies",
"losing_abbr": "COL"
},
{
"sport": "baseball",
"team": "giants",
"full_name": "San Francisco Giants",
"date": "8-6-2020",
"boxscore": "COL/COL202008060",
"away_name": "San Francisco Giants",
"away_abbr": "SFG",
"away_score": 4,
"home_name": "Colorado Rockies",
"home_abbr": "COL",
"home_score": 6,
"winning_name": "Colorado Rockies",
"winning_abbr": "COL",
"losing_name": "San Francisco Giants",
"losing_abbr": "SFG"
},
{
"sport": "baseball",
"team": "rays",
"full_name": "Tampa Bay Rays",
"date": "10-27-2020",
"boxscore": "LAN/LAN202010270",
"away_name": "Tampa Bay Rays",
"away_abbr": "TBR",
"away_score": 1,
"home_name": "Los Angeles Dodgers",
"home_abbr": "LAD",
"home_score": 3,
"winning_name": "Los Angeles Dodgers",
"winning_abbr": "LAD",
"losing_name": "Tampa Bay Rays",
"losing_abbr": "TBR"
}
]
}
ANSWER
Answered 2021-Apr-25 at 17:58 for team in scores_list['scores']:
teams_list.append("{} ({}) ({}) {} ({}) - ({}) {}".format(team['full_name'], team['date'],
team['sport'], team['home_name'],
team['home_score'], team['away_score'],
team['away_name']))
You're iterating over scores_list['scores'] at two locations in your source code:
for a_team in scores_list['scores']:
# ^^^^^^^^^^^^^^^^^^^^^ here
if a_team['sport'].lower() == request.args.get('sport').lower() \
and a_team['team'].lower() == request.args.get('team').lower():
teams_list = []
for a_team['team'] in scores_list['scores']:
# ^^^^^^^^^^^^^^^^^^^^^ and here
teams_list.append("{} ({}) ({}) {} ({}) - ({}) {}".format(a_team['full_name'], a_team['date'],
a_team['sport'], a_team['home_name'],
a_team['home_score'], a_team['away_score'],
a_team['away_name']))
This is probably not what you want. When the if is true you already have an a_team in your hand you're interested in and you can just use it:
for a_team in scores_list['scores']:
if a_team['sport'].lower() == request.args.get('sport').lower() \
and a_team['team'].lower() == request.args.get('team').lower():
teams_list = []
teams_list.append("{} ({}) ({}) {} ({}) - ({}) {}".format(a_team['full_name'], a_team['date'],
a_team['sport'], a_team['home_name'],
a_team['home_score'], a_team['away_score'],
a_team['away_name']))
Now you just need to figure out where you want to put teams_list = []. Probably before the for-loop starts.
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